free

1. Ax + B
Ax+ BX + C
AX3 + BX2+CX +D
d$t....
X
=
↳
-
>
(X
-
3)(X+
1)

2. X = 2x =
-
3
(X-
2)(x +
3)
X= 2
-
-
-
X= 2X= 3
- Rumus ABC
(x -
2)b(X+3)
-
#x2+ 3X - 2
-
Contoh : Tentukan Susa Pombagian F(x) : X2
+
3x+2
Ou(x-1) + x = r
Sacrab :
FN) = 1 +3 + 2 = 6 .
-

3. --
--
X
X2-
4x-
12 =
0 -
>
Sisa =4x-3
(X+ 2)(X -
6) = 0
X = -
2x =
6
F(-2) =
4(-
2) -
3 =
- 1
5 (6) =
4(6) -
3 = 28
X
2
+ 4x- 12 - Sisa =
2x + 5
(x +6)(X-
2) = 0 + X =
-
6VX = 2
f) -
6)= 2(-
6) +5 = -
7
=(2) = 2 (2) + 5 =
9
(1) (x + 1) = (x)0h(x2-
4) = (x+2)(x-
2)
· dox = -2 :
(2 + 1) =(2) =
1 .
- 18 =
18
- dix = 2 : (2 + /F (2) = 3 .
9 : 27

4. Inget: sisa Rombagian oloh pors Kuadra
Solalu borboutch Ax
+B
-
2A + B = 18 B= +9
2A + B = 27
-
(4X +
g)
-
4A = -6
A = K
(ii)(X+3) F(y)0lch (x2-36)
(x+6)(X-
b)
·
7 dox= -6 :
1-6+3).
F1-6) :
-
3 .
-7
= 24
·
7dox= 6 :
(6+3)·
P(s) =
9.
20 =
189
-
GA + B =2
GA + B= 189 +
14x+ 105
2B =
200
B =
165
GA-189-105
GA =
84 -YA = 14

5. Sisa Fex] dat x2-
&x + 12 + (3x+3)
(X-
2)(x-
6)
-> Di X = 21
A .
2 + B
=
=(2)
2A + B =
g --.
(1)
· DrX = 6 :
GA + B =
F (6)
SA + B = 20 - - (2)
Eliminasi (1) b(2) substitus (1)
- T A = -12 2 .
43 + B =
9
A = + 3 B = 3
(3x + 3) benas
Sisa F1-x( 0loh x*+ex+ 12 -113X-3)
(x + 6)(y+2)
·
7 Dr X = -
6 : -
GA + B =
F)-
6)
-
GA + B = 20
·
7 Do X= -
2 : -
2A +B=
f(-
2)
-
2A + B = -
11
- T A =
32 -
6 . 8 + B = 21
A =
- O
B = 69
(-
8x +
69) (salah)

6. 2(4) -
5 =
3r
4 -
5 = -
1 X
↑ + 5 =
9 ~
X
g(x) ooh (x
=
-
+x+ 1) + (x -
3)
-
sisag(x) = X-
3
(x + g(x))2 =
(X + (x-
3))2 -
=
(2x-3)2 borbentuk
mx + R
hitung :
12x-31= 4x2-12x+9
x2-
4x + 1 =
0 -
1x2= Nx - 19
4x2 12x + 9 =
4(4x-
1-
12x+
9
=
16X -
4 -
12X +
9
=
(x + 5 = mx + n
m =
+ vn =
5

7. -
Teorema siga .
·
7 dobago (x-2) sisa4 = =(2) = ↑
· dibagi (x + 1) sisa3 = F(-)) = 3
·
) dibag112x+ 3) ssas= 51-3) =
J
P = 3 F(2)-
5F(-
1) + 351- 2
p = 3 .
4 -
5. 3 + 3 .
5 = 12
Q =
3 F(2) + 5f(-
1) -
3F)-)
Q =
3 .
4 + 5.
3 -
3 .
5 = 12
p = Q

8. h(X) dibag , (x2-X-2) Sisa (3x-5)
dibag , (X2-9) Sisa (2x-
8)
-
Kondisi 1 : x2-X-2 : (X-2)(X+
1)
x = 2vX =
- f
h(-
1) =
3 . ( 1) -
4 = -
7
h(2) =
3 .
2 -
4 = 2
Konds 2 ,
x2-g =
(x +3) (X-
3) = 0
X =
-
3vX =
3
h(-
3) =
2.
(-
3) -
8 = - 14
n(3) =
2 . (3) -
8 = - 2
P = 3 .
4(2) =
3.
2 =
6
Q = 3 . h(3) = 3 .
-
2 =
-
6
PTQ
=

9. X
1
. F(X) ,
dibagi ooh (x + 5)
hasil- g(x) sisa-7
x2 + 5x+7 = AX + B contoh
Get Suku banyak f()
9(x) 7
f(x) =
(x +5)9(X) +7
2
. g(x)
:
dubag, oth lex-
/
has = h(x) Sosa = 2
e(X) =
(2x-
1) (h(x)) + 2
h1z1z2 ,
has

10. F(x) = (x+5) g(x) +
7
-
F(x) = (x+
5) ((2x-
D.
(h(x))+
2)+7
-
F(x) =
(x+ 5) . (2x-
(. h(x) + 2(x+
5) +7
F(x) = (x +
5) .
(2x-
1) .
h(x)+ 2x + 10 +7
F(x) = (x + 5) .
(ex-
1). h(x)+ 2x + 17
F(j) =
(b) (5) .
2 + 6+17
F (3) =
103
F(2) = 1z) (3) · ↑+ 2.
4+57
F (2) =
109
513) (F(2) PLQ

11. X
F(x) = 3x4 - 2ax3+7x2+dax +5
dibagi X + 2 -+ Sisa
=
97
monurut feoroma Sisa
X = -2
F(-
2) =
97
Fl-
2)= 31-
2)4-
2a .
(-
2(3+ 7(-
2)++a+2)+
5
= 3(v6) -
2a)-
b) + 7(4) + -
8a+5
=
48 + 16a +28 -
8a + 5
& a + 00 =
97
8a =
16
a = 2
F(x) =
3xP -
4x3 + 7x2+ 8x+5
F(i) =
3 -
4 +7 + 8 + 5 = 19 - P

12. F-
1) =
3 +4 + 7 -
8 + 5 = N - Q
PTQ
X
F(x) = x3-
4x +1 g(x) = 2x*+5x2- 8
dobag, oloh (x+ 2) /X = -2
a =
f(x) = f) -
2) = (2)3-
4-
2)+ 1 = 1
b = g(x) = g( -
2) = 2(2)3+ 51-
2)28 = -
4
maka ,
a + b = + + (4) =
-
3
Sisa Pombagan (F(x) -
9(x)) oloh(x-a-b)
↳ (x+ 3) /X = -
3 - F -
9d + x=
-
3
·
751-
3) = ( -33-
4(3)+ 1
· g(-3) = * **
*********
·
p = -
30 =
3
PLQ