Trigonometric Equations 4
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Homework Question
Solve : 3cosx + 3sinx + sin3x - cos3x = 0
7. Use of limited range of sinx and cosx
If x, y ∈ [0, 2π], then total number of ordered pairs (x, y)
satisfying the equation, sin x. cos y = 1, is equal to:
A. 1 B. 3 D. 7
C. 5
Solve: sin3x + cos2x = - 2
A. (4n - 1) π/2 B. (4n + 1) π/2
C. (2n - 1) π/2 D. None of these
The general solution of the equation, cos x cos 6x = -1 is
A.
C.
B.
D.
x = (2n + 1)π, n ∈ I x = 2nπ, n ∈ I
None of these
x = (2n - 1)π, n ∈ I
8. Use of limited range trigonometric expressions
The value of ‘a’ for which of the equation, a2 - 2a + sec2π (a + x) = 0
has solution is :
A. 1 B. 2 C. 0 or 1 D. 1 or 2
sin θ + √3 cos θ = 6x - x2 - 11 ; 0 < θ < 4π, x ∈ R, holds for
C.
D.
A. No value of x and θ
Two values of x and two values of θ
B. Two pairs of values of (x, θ)
One values of x and one values of θ
If x and y are the solutions of the equation, 12 sinx + 5 cosx = 2y2 - 8y + 21.
Then find the value of
Trigonometric
Inequalities
Solve for x: 1/2 < cosx < √3/2.
Let 2 sin2x + 3 sin x - 2 > 0 . Then find the general solution of x.
The solution of inequality cos 2x ≤ cos x is
B.
D.
A.
C.
Which of the following set of values of x satisfy the inequation
B.
D.
A.
C.
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@sameer_iitr

trignometry notes by me very improtant for jee mains