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The integral has a pole at z=-1
Integral region is around a circle in the first quadrant with unit radius,
z=1 to z=i means
angle 0 to pi/2
Using residue theorem
the integral is 2pii (log (-1+1))
= -infty
Solution
The integral has a pole at z=-1
Integral region is around a circle in the first quadrant with unit radius,
z=1 to z=i means
angle 0 to pi/2
Using residue theorem
the integral is 2pii (log (-1+1))
= -infty

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