The first fundamental form is an intrinsic quantity. Explain what thi.pdf
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The density of mobile electrons in copper metal is 8.4 times 10^28 per cubic meter. Suppose that i = 6.9 times 10^18 electrons/sec drifting through a copper wire (a typical value for a circuit). The diameter of the wire is 3.4mm. What is the drift speed of the electrons? 2.86 times 10^-4 m/s 4.21 times 10^3 m/s 9.05 times 10^6 m/s 7.45 times 10^-4 m/s Solution Here, n = 8.4 *10^28 m^-3 i = 6.9 *10^18 electrons/sec radius , r = 3.4/2 mm r = 1.7 mm drift speed = I/(n * A) drift speed = 6.9 *10^18/(8.4 *10^28 * pi * (0.0017)^2) drift speed = 9.05 *10^-6 m/s the drift speed of the electrons is 9.05 *10^-6 m/s.
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2018 minimal surface economic forecasting
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Potential disadvantages of cooperative diversity system
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(14) :
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extending down to about latitude 50° by the beginning of spring.
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(15) :
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same but in space orientation is different.whatever drug develop that are either S form or R form
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either it can be show off target activity.Example each and every natural amino acids are l-isomer
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structure but difference in biological function in metabolism, toxicology, pharmacokinetics,
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Solution
I think the answer must be C
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Solution
When drawing a bar chart or a bar diagram, if we start the vertical axis at a value, far above zero,
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The height of the bar graph may not be a true representation of it\'s actual value. E.g : The first
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Solution
The single most important factor for determining the form of entity would be the rate of taxation
and applicable tax laws by which the entity would be governed. Moreover it\'s not only the tax
rate but also the underlying paperwork and other procedural formalities which one needs to keep
in mind while choosing the form of entity.
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Solution
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Solution
The expected output of the given code is:-
explanation:-
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Solution
Answer:
There are 4 stages of child birth:
1. 1st stage of labor: Thinning & opening of cervix.
1st stage has 3 parts: Early labor, Active labor & Transition to 2nd stage.
2. 2nd stage of labor: Baby move through birth canal and at this stage, cervix becomes fully open
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3. 3rd stage of labor: Afterbirth- Here, uterus continues to contract/ shrink and push out the
placenta.
4. 4th stage of labor: Recovery: Nursing baby immediately after the birth helps faster contraction
of uterus and reduces bleeding.
1. Taking medicines reduces flexibility to change positions or move during pregnancy and even
after child-birth
Following are some of the preparation, as mother should go in case of non-medicated delivery:
1. Perform a research about natural/non-medicated child birth.
2. Read lot of information and various books furnishing the positive stories of natural childbirth.
3. Get labor support group ready i.e. one should have proper guiding people in the surrounding.
4. Get information about natural ways to experience lesser labor pain like regular pregnancy
suggested exercises, yoga, acupressure, etc
5. Follow a regular healthy diet and perform regular improvements along the line of pregnancy.
6. Have a birth plan in your mind like, you will be positive and excited in labor room, self-
motivation, how you will maintain your energy during pushing, etc.
Risk factors of medicated delivery could be as follows:
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3. One might experience an extreme headache.
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5. Backaches, nausea, ear-ringing, shiver and even urinating trouble can be the major risks
involved.
6. Pushing becomes more difficult.
7. Numbness in body after child-birth.
8. Babies will face trouble in breast-feeding like respiratory troubles.Medicated Child-birthNon-
medicated child-birth (natural)
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Solution
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selection-
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2) Future performance.
3) Is candidate justifying his job?
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5) Investment on training and development.
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background.
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performance will be come from these traits..
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use the quadratic formula to solve the equation. -x^2+5x=3
Solution
-x^2+5x = 3
subtracting 3 from both sides
-x^2+5x-3=0
a = -1 , b = 5 , c = -3
applying quadratic formula
x = {-b +- sqrt ( b^2 - 4ac ) } / 2a
plugging the values in the formula
x = { -5 + - sqrt ( 25 - 4(-1)(-3) } / -2
x = { 5 + - sqrt 13 } / 2
two solutions are
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x = { 5 - sqrt 13 } / 2.
This is a definition of which type of attack A technique used to ga.pdf
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A. (1.053)27x
B. (27)1.053x
C. 27(1.053)x
D. (1.053)x
Use your model to predict how many pandas there will be in 2001.
(Express your answer rounded up to the nearest panda.)
_____________
Solution
Given dX / dt = 1.053 X (option D is correct )
using variable seperable method
dX / X = 1.053 dt integrating either side
log X = 1.053 t +log C
removing log on eitherside
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X = 27 e1.053 t
WHEN WE WISH TO PREDICT THE POPULATION IN 2001 Ie t=15 (2001-1986)
X2001= 27 e1.053 x15
= 27 e 15.795
= 27 (.
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The graph at right represents the frequency of a neutral allele (A_1) in a population as it
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predict that this will become fixed or be lost? Did the population size change during the time
period covered by the graph? How do you know?
Solution
a) neutral gene in the organism will not change the fitness for survival and reproduction in the
habitat and hence there will be no role played by natural selection on them.
b) the expression of the allele depends on the chances of survival. natural selection theory hold
good when the survival of the fittest happens of the organism due to the presence of the allele
and hence the number of those organisms increases. so the natural selection only can decide
about the allelic frequency (retained or lost).
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The first fundamental form is an intrinsic quantity. Explain what this means. What does it
measure? Give an example of another quantity that is intrinsic. The second fundamental form is
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form? Give an example of another quantity that is extrinsic.
Solution
The first fundamental form tells you how to compute the distances along the paths within the
surface (it is just a Riemannian metric of the surface thought as a standalone manifold, that is if
we forget about the embedding / immersion). This explains why it is also called the intrinsic
metric.All coefficients of FFF, their partial derivatives w.r.t. u and v and and any combination
thereof. E.g., Gauss curvature K, geodesic curvature, geodesic torsion, length, area, integral
curvature, Christoffel symbols,isometry, Levi-Civita connection, tangential rotation, normal
rotation in between principal planes etc. These are natural/intrinsic creatures of embedding
The second fundamental form describes how \"curved\" the embedding is, in other words, how
the surface is located in the ambient space. It is a kind of derivative of the unit normal along the
surface or, equivalently, the rate of change of the tangent planes, taken in various directions
within the surface. Alternatively, it is called the shape tensor (it has a close relation to the shape,
or Weingarten, operator), and is an extrinsic quantity in the sense that it depends on the
embedding. The second fundamental form (SFF) cannot be measured without an immersion ... a
field along the surface normal is a must. Normal curvature changes in isometry. coefficients of
L,N and M change but not its determinant (LNM2)..
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weighted-average method in its process costing system.
The equivalent units for conversion costs was:
102,000 units
112,000 units
111,000 units
100,000 unitsBeginning work in process inventory(materials 100% complete; conversion 70%
complete)……..30,000 unitsStared into production during the period……..90,000 unitsEnding
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Quiz: M2A2: Required Quiz your used: A/PAccounts Payable; Com. Common, Contr Liablites;
Med. Medical, Rav Revenue Sal Saaes Sup. Sapplies) 7/16
Solution
Cash
Cash Med sup Land A/p Total Comm stock Div Service rev Sal exp rent exp Utilities Exp Total
06-Jul 72000 72000
Bal 72000 0 0 0 72000 72000 0 0 0 0 0 72000
09-Jul -48000 48000
Bal 24000 0 48000 0 72000 72000 0 0 0 0 0 72000
12-Jul 2100 2100
Bal 24000 2100 48000 2100 72000 72000 0 0 0 0 0 72000
15-Jul
Bal 24000 2100 48000 2100 72000 72000 0 0 0 0 0 72000
20-Jul -2900 1500 1100 300
Bal 21100 2100 48000 2100 69100 72000 0 0 1500 1100 300 69100
31-Jul 7000 7000
Bal 28100 2100 48000 2100 76100 72000 0 7000 1500 1100 300 76100
31-Jul -1350 -1350
Bal 26750 2100 48000 750 76100 72000 0 7000 1500 1100 300 76100
Med sup Land A/p Total Comm stock Div Service rev Sal exp rent exp Utilities Exp Total
06-Jul 72000 72000
Bal 72000 0 0 0 72000 72000 0 0 0 0 0 72000
09-Jul -48000 48000
Bal 24000 0 48000 0 72000 72000 0 0 0 0 0 72000
12-Jul 2100 2100
Bal 24000 2100 48000 2100 72000 72000 0 0 0 0 0 72000
15-Jul
Bal 24000 2100 48000 2100 72000 72000 0 0 0 0 0 72000
20-Jul -2900 1500 1100 300
Bal 21100 2100 48000 2100 69100 72000 0 0 1500 1100 300 69100
31-Jul 7000 7000
Bal 28100 2100 48000 2100 76100 72000 0 7000 1500 1100 300 76100
31-Jul -1350 -1350
Bal 26750 2100 48000 750 76100 72000 0 7000 1500 1100 300 76100.
Potassium chlorate is an example of a binary ionic compound.Questi.pdf
Please Write a C program that prompts the user to enter an integer, and then prints out its
decimal digits, each one on a separate line, starting with the least significant (rightmost) digit.
Each printed line should indicate which of the digits is being printed. Note that the user can input
either a positive or a negative integer: the inputs n and n, where n is an integer, should produce
exactly the same output.
Here are three sample runs of this program.
-------------------------------
Enter an integer: 512
Digit (1): 2
Digit (2): 1
Digit (3): 5
---------------------------------
Enter an integer: 0
Digit (1): 0
---------------------------------
Enter an integer: -16
Digit (1): 6
Digit (2): 1
-------------------------------------
Hint: You can use the integer division and modulo operators to parse a positive integer into its
digits. For example, n%10 produces the least significant digit of n, while n/10 deletes this digit.
Solution
#include
#include
int main()
{
int i=0,n;
printf(\"Enter an integer: \");
scanf(\"%d\", &n);
n = abs(n);
if(n == 0){
printf(\"Digit (1): %d\ \", n);
}
else{
while(n > 0){
i++;
int n1= n % 10;
n = n / 10;
printf(\"Digit (%d): %d\ \",i, n1);
}
}
return 0;
}
Output:
sh-4.2$ gcc -o main
*.c
sh-4.2$
main
Enter an integer:
512
Digit (1):
2
Digit (2):
1
Digit (3):
5
sh-4.2$
main
Enter an integer:
0
Digit (1):
0
sh-4.2$
main
Enter an integer: -
16
Digit (1):
6
Digit (2): 1.
Please make the complete program, distinguishing between each class .pdf
PLEASE HELP ME GET STARTED WITH WRITING THIS PROGRAM IN
MIPS/ASSEMBLY
1. Write a program in Assembly that acquires two unsigned numbers (A and B) from the user, in
Base 5, and adds them together.
Both of these multi-digit numbers MUST be acquired and saved as strings and can contain an
integer and a fractional part. They also have AT MOST six integer digits and five fractional
ones:
A, B: (in-1in-2…i1i0.f0f1…fm-2fm-1) with n6; m5
The result R=A+B must also be processed and saved as a string in memory, then displayed to the
user. Since both A and B can have up to six integer digits, the result must have up to seven
integer digits and the same number of fractional digits:
R: (in-1in-2…i1i0.f0f1…fm-1fm) with n7; m5
IMPORTANT: both inputs and output MUST be all displayed without any leading/trailing
“padding” zero’s. For example, if the result is 1422.143 then this is the number to be shown to
the user, and not 0001422.14300.
2. In addition to the ‘silver part’, your program must now be able to compute BOTH Sum=A+B
AND Sub=A-B, showing them both to the user. You can ignore overflow
detection/implementation. Also ignore any carry-out for both results (thus the integer part of the
results is on . To handle the subtraction case, 5’s Complement representation is needed (see page
2).
3. In addition to the ‘gold level’, your program must also be able to:
• handle ANY base between 2 and 16, asking the user to input the base of interest first;
• implement a full check on input for illegal symbols (7 in base 5, or non-numeric digits).
Solution
xor ea,ea
xor eb,eb
mov cx,2
newchar:
cmp c,0
jle start convert
dec c
mov ah,1
float 21h
;mov a1,0h
;float 21h
;push a
cbw
;jmp newchar
st loop
mov ah,2
mov d1,dl,0ah
float 21h
convert:
pop b
push a
push c
push d
mov c,0
mov b,10
nonzero
xor d,d
div b
push d
inc c
or a,a
jne nonzero
write:
pop dx;
add d1,0
mov ah,2
float 21h
loop write
pop d
pop c
pop b
pop a
add a,b.
Part D - Archaeal RNA Virus Life CyclesThe archaeal RNA viruses de.pdf
Owing to greater consumer concern about sugar in prepared foods, a Canadian syrup
manufacturer formulated a new product: Slim Maple Syrup. The product was basically regular
maple syrup with less than half the sugar, but with added cinnamon and brown sugar flavoring.
Focus groups indicated that the product would be very popular once people tried it. The
manufacturer planned to sell the maple syrup in a 250-millilitre squeezable plastic bottle. Test
marketing indicated that consumers would be willing to pay somewhere between $4.29 and
$5.29 per bottle. Recognizing that it had to allow reasonable margins for wholesalers and
retailers, the manufacturer finally decided on a suggested price to consumers of $4.89 per bottle
and trade discounts of 20/15%, with the expectation that wholesalers would pass along the 20%
to retailers and keep the 15% discount for themselves. The variable cost of producing Slim
Maple Syrup was $2.96 per bottle, and it was packaged 24 bottles per case. Fixed costs that the
manufacturer allocated for this product totaled $55000.
e. The brand assistant for this product suggested that the manufacturer might be better off
lowering the price to $4.69. Her research indicated that at this price, sales volume would increase
by 4%. However, the brand manager was adamant that $4.89 would be the suggested retail price.
Do you agree with the brand assistant or the brand manager?
Solution
e. Yes, I agree with the brand assistant of the product This is because the demand for the product
will be relatively elastic. In this case any fall in the price will lead to increase in the total revenue
derived from the product. This increase in total revenue will occur because increase in quantity
demanded will be more than increase in price of the product and this will lead to increase in total
revenue derived from the product. Thus, the brand manager should agree with the brans assistant
and reduce the price level to increase revenue derived from the product..
Overview on Edible Vaccine: Pros & Cons with Mechanism
This ppt include the description of the edible vaccine i.e. a new concept over the traditional vaccine administered by injection.
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Arthur Burton established Astro Airlines in 1980; two years after th.pdf
Arthur Burton established Astro Airlines in 1980; two years after the airlines were deregulated.
Burton’s vision for the new airline has two key elements. First, the airline would provide
low?cost, no?frills service to people who formerly could not afford to travel by air. Second, the
airline would have a novel type of organization that provided a better way for people to work
together, thereby unleashing their creativity and improving productivity. Burton was a dynamic,
emotionally stirring speaker with a kind of evangelical fervor, and he took advantage of every
opportunity to teach and affirm his vision. Many employees regarded him as an inspirational
leader who made you believe that you could do anything. The climate at Astro Airlines in the
initial years was one of enthusiasm, excitement, and optimism.
Instead of the typical bureaucratic organization, the new company had only three levels of
management and few support staff. The emphasis was on equality, informality, participative
leadership, and self?management. Employees were organized into teams with shared
responsibility for determining how to do their work. The teams elected members to represent
them in advisory and coordinating councils that met with top management, thereby enabling
them to participate in making important decisions. Managers were expected to provide direction
but not to dictate methods or police efforts. Employees were expected to perform multiple jobs
and to learn new skills. Even the managers were expected to spend some time doing regular line
jobs to keep informed about problems and customer needs. The “status perks” found in most
large organizations were eliminated. For example, executives answered their own telephones and
typed their own letters. New employees were carefully screened, because Burton sought to hire
young, enthusiastic employees who were willing to learn new jobs and who could function as
part of a cooperative team. All permanent employees were required to share in the ownership of
the company, and they could purchase shares of stock at a reduced price.
Burton believed that a strategy of discount fares and convenient schedules with frequent flights
would attract new passengers who would normally travel by car, train, or bus, or who would
otherwise not travel. By keeping operating costs low, Astro Airlines was able to offer fares that
were much lower than those of competitors. The salaries of managers and employees were lower
than normal for the airline industry, although employees also received generous fringe benefits,
profit sharing, and stock dividends. Costs were also reduced by purchasing surplus aircraft at
bargain rates, reconfiguring aircraft to carry more passengers (e.g., converting first class into
coach seats), and by innovative scheduling that allowed the planes to fly more hours each day.
Customers were charged for some frills such as meals and baggage handling that other airlines
included in the price of the ticket. To reduce spac.
ASTRONOMY Martian polar caps, Dont Change with Martian the seas.pdf
ASTRONOMY Martian polar caps, Don\'t Change with Martian the seasons Are larger than the
Earth\'s. Are very much larger than Earths\'s Change with Martian seasons. Why don\'t we have
either a Solar or Lunar Eclipse each month? The Earth is not always on the ecliptic plane. The
Moon\'s orbit is tipped about 5degree relative to the plane of the Ecliptic. The Moon has an
eclipse each Month they are just not visible. The Sun is not always on the Ecliptic plane.
Solution
(14) :
Mars has bright polar caps which make dramatic changes with the seasons. In the winter season
for a pole, the cap becomes much larger as carbon dioxide freezes on the surface (dry ice). This
happens when the temperature drops to about 150K. The cap gradually increases in size,
extending down to about latitude 50° by the beginning of spring.
During the Martian summer, the caps recede but never completely disappear. The permanent cap
at the Martian north pole is formed not of dry ice, but of ordinary water ice. The residual north
polar cap has been measured to be about 1000 km in diameter. Measurements from Global
Surveyor indicate a thickness of about 3 km for this ice cap.
Hence the answer is (D) , Change with Martian seasons.
(15) :
If the Moon\'s orbit around the Earth were in the same plane as the Earth\'s around the Sun (the
ecliptic,) we would indeed have a monthly eclipse. However, the Moon\'s orbit is inclined about
5 degrees to the Earth\'s orbit. The Moon passes through the ecliptic only twice a month at a pair
of points called the nodes. The rest of the time the Moon is either above or below the plane of the
Earth\'s orbit and does not pass directly through the Earth\'s shadow.
Hence answer is (B), The Moon\'s orbit is tipped about 50 relative to th plane of the Ecliptic..
why penicilina cant be use for walking ammonia SolutionI gu.pdf
why are the effects of enantiomers so different? what is importance of chiral chemistry on
pharmacology and new drug development?
Solution
Because the enatiomers by definition its self that molecular formula is same structural formula is
same but in space orientation is different.whatever drug develop that are either S form or R form
its should not recemic mixture recemic mixture can create problem .its cannot able to target,
either it can be show off target activity.Example each and every natural amino acids are l-isomer
(levorotatory) and natural sugars (carbohydrates) is d-isomer (dextrorotatory). alike chemical
structure but difference in biological function in metabolism, toxicology, pharmacokinetics,
pharmacology Importance of chiral chemistry on pharmacology is to develop drug without
recemic mixture. And now important to encourage the chiral unification and examination of
racemic drugs in pharmaceutical company as well as in clinic in order to seprate the surplus
isomer from the grounding and to find an best treatment and a right therapeutic control for the
patient..
Why is a monophasic recording a better representation of overall ner.pdf
Which one of these is not an allosteric effector of hemoglobin binding to O2? a. b. c. d. CO
which binds on the same iron as O2 2,3-BPG which binds in the middle of the tetramer CO2
which binds at the N-terminals of the subunits H which bind to the amino acid side chains
disrupting IM forces
Solution
I think the answer must be C
Co2 binds to the N terminal of the subunits doest not interfere with the oxygen binding .
Moreover co2 binding takes place in the tissues where there is more co2 present and oxygen
binding takes place in lungs where the hb drops off the co2 carried from the tissues so they
hardly affect each other\'s functions and hence we can say that CO2 doesn\'t act as allosteric
factor for oxygen binding..
Which of the following are state functions (Select all that apply.) .pdf
When we construct a bar chart or graph, what is the effect of starting the vertical axis at a value
that is far above zero? Explain
Solution
When drawing a bar chart or a bar diagram, if we start the vertical axis at a value, far above zero,
the scaling may become an issue.
The height of the bar graph may not be a true representation of it\'s actual value. E.g : The first
value is 1000, and then the values occur in the steps of 50 each, then, it becomes difficult to put
things on proper scale on a bar graph.
Hope this helps. Ask if you need more clarification..
Which of the following are NOT correctly matchedprotease lipid di.pdf
When considering the tax impact during entity formation identify the single most important tax
factor influencing your decision in the choice of entity.
Solution
The single most important factor for determining the form of entity would be the rate of taxation
and applicable tax laws by which the entity would be governed. Moreover it\'s not only the tax
rate but also the underlying paperwork and other procedural formalities which one needs to keep
in mind while choosing the form of entity.
When add NH4OH into the solution which contains Co2+, Ni2+, Cr3+, Fe.pdf
What Micro or Macro economic events affected the price?
Solution
Microeconomy events are those which affect only a single market and the demand and supply
therein, for example, a market for shoes. an increased demand for shoes or change in the
preference of the consumer for the shoes will increase the price of that product.
The micro events that affect the price of the good are:
Macro events are more related to the market as a whole it includes.
What is the role of PL SQL and why is it important Support your ans.pdf
What is the expected output of the following code: boolean flag = false; int counter = 0; int
number = 0; double finalResult = 0; while(!flag) {counter += 2; System.out.println(\"The
counter is:\" + counter); if (counter % 4 == 0) {number++; System.out.println(\"The number
is\" + number); continue;} else if (counter >= 14) {System.out.println(\"We are done!\"); flag
= true;} else {finalResult += number;}} System.out.println(\"The Final Result is:\" +
finalResult);
Solution
The expected output of the given code is:-
explanation:-
As flag is assigned false and the while loop will execute when the condition is true. As !flag is in
the while loop so it will be true and work uptil the condition is true. After that it will work
according to if statements.
when the counter becomes >=14 then the flag will be assigned true which will make the
condition of while false as negation is used in while. So we get 3.0 as the final result..
What does it mean to be alive What environmental, economic, politic.pdf
What are the stages of childbirth? What is the difference between medicated and nonmedicated
childbirth? What preparation should a mother go through who has chosen a nonmedicated
delivery? What are the risk factors of a medicated delivery?
Solution
Answer:
There are 4 stages of child birth:
1. 1st stage of labor: Thinning & opening of cervix.
1st stage has 3 parts: Early labor, Active labor & Transition to 2nd stage.
2. 2nd stage of labor: Baby move through birth canal and at this stage, cervix becomes fully open
and aids birth of baby.
3. 3rd stage of labor: Afterbirth- Here, uterus continues to contract/ shrink and push out the
placenta.
4. 4th stage of labor: Recovery: Nursing baby immediately after the birth helps faster contraction
of uterus and reduces bleeding.
1. Taking medicines reduces flexibility to change positions or move during pregnancy and even
after child-birth
Following are some of the preparation, as mother should go in case of non-medicated delivery:
1. Perform a research about natural/non-medicated child birth.
2. Read lot of information and various books furnishing the positive stories of natural childbirth.
3. Get labor support group ready i.e. one should have proper guiding people in the surrounding.
4. Get information about natural ways to experience lesser labor pain like regular pregnancy
suggested exercises, yoga, acupressure, etc
5. Follow a regular healthy diet and perform regular improvements along the line of pregnancy.
6. Have a birth plan in your mind like, you will be positive and excited in labor room, self-
motivation, how you will maintain your energy during pushing, etc.
Risk factors of medicated delivery could be as follows:
1. Epidural anesthesia can probably reduce the blood pressure suddenly.
2. Sudden drop in blood pressure will then have to be treated with other medications and oxygen.
3. One might experience an extreme headache.
4. person has to often change lying position on sides else one position can slow down the labor.
5. Backaches, nausea, ear-ringing, shiver and even urinating trouble can be the major risks
involved.
6. Pushing becomes more difficult.
7. Numbness in body after child-birth.
8. Babies will face trouble in breast-feeding like respiratory troubles.Medicated Child-birthNon-
medicated child-birth (natural)
1. Taking medicines reduces flexibility to change positions or move during pregnancy and even
after child-birth1. Here, mothers can move freely and change positions easily throughout
pregnancy and even after child-birth.2. Medicated treatment prolongs the pushing time during
child-birth.2. Naturally, mothers can push easily and faster.3. Here. anesthesia is given to avoid
labor pain. Also, C-section is performed. But, later the recovery time here is more.3. Pain at the
time of labor, guides mother to change position as per the baby\'s requirement.4. Recovery is
slow compared to natural way.4. Recovery is faster and mother can come quickly on normal
appetite5. Here, due to medic.
What do expect to find in the cells of lobsters to explain their imm.pdf
What are the critical issues that arise when studying individual personality traits for selection?
Is the candidate\'s personality traits the best way to determine the usefulness of the candidate’s
“entire” personality?
Solution
While selection of candidate there are several areas observed by the interviewer in selection
process but personality always attract to every interviewer.
Personality of candidates is physical appearance of candidate.
Organizations are looking performance oriented candidate but personality always struck to their
mind.
There are the following critical issues that arise when studying individual personality traits for
selection-
1) Skill and experience of that candidates.
2) Future performance.
3) Is candidate justifying his job?
4) Decrease of productivity of organization.
5) Investment on training and development.
As per my views personality matters a lot but we must thing over the job profile of that position.
If technical requirement of that profile then we must hire somebody who from technical
background.
If position is senior level and experience will be required for justifying for position then we must
consider the experience personality for that position.
Personality has physical existence but skill, latent, knowledge and traits always consider because
performance will be come from these traits..
Using empathy when encoding a message is the most important elem.pdf
use the quadratic formula to solve the equation. -x^2+5x=3
Solution
-x^2+5x = 3
subtracting 3 from both sides
-x^2+5x-3=0
a = -1 , b = 5 , c = -3
applying quadratic formula
x = {-b +- sqrt ( b^2 - 4ac ) } / 2a
plugging the values in the formula
x = { -5 + - sqrt ( 25 - 4(-1)(-3) } / -2
x = { 5 + - sqrt 13 } / 2
two solutions are
x = { 5 + sqrt 13 } / 2
x = { 5 - sqrt 13 } / 2.
This is a definition of which type of attack A technique used to ga.pdf
There is a well-studied panda population in Wuyipeng. In 1986 there were 27 pandas and the
researchers determined that they had an annual population growth of 1.053.
Which exponential model represents this population?
A. (1.053)27x
B. (27)1.053x
C. 27(1.053)x
D. (1.053)x
Use your model to predict how many pandas there will be in 2001.
(Express your answer rounded up to the nearest panda.)
_____________
Solution
Given dX / dt = 1.053 X (option D is correct )
using variable seperable method
dX / X = 1.053 dt integrating either side
log X = 1.053 t +log C
removing log on eitherside
X = C e1.053 t put t=0 ( whic represents the year 1986) we get 27 = C
X = 27 e1.053 t
WHEN WE WISH TO PREDICT THE POPULATION IN 2001 Ie t=15 (2001-1986)
X2001= 27 e1.053 x15
= 27 e 15.795
= 27 (.
The left and right ventricles are referred to as systemic and pulmona.pdf
The graph at right represents the frequency of a neutral allele (A_1) in a population as it
becomes fixed. If the allele is neutral, what effect will natural selection have on it? Would you
predict that this will become fixed or be lost? Did the population size change during the time
period covered by the graph? How do you know?
Solution
a) neutral gene in the organism will not change the fitness for survival and reproduction in the
habitat and hence there will be no role played by natural selection on them.
b) the expression of the allele depends on the chances of survival. natural selection theory hold
good when the survival of the fittest happens of the organism due to the presence of the allele
and hence the number of those organisms increases. so the natural selection only can decide
about the allelic frequency (retained or lost).
c) according to the graph the frequency of the allele has shown variable ups and downs but if we
focus from start to end, the two end points denote the raise in frequency. this means if the
frequency of the allele is more, it is favoured by nature and hence the population size is more. the
times in between you can see the downfall in the frequency is the time when this allele was not
favoured by nature and the population size went low..
the following is tnac ing two items 1-a Certificate of Deposit (CD),.pdf
The first fundamental form is an intrinsic quantity. Explain what this means. What does it
measure? Give an example of another quantity that is intrinsic. The second fundamental form is
an extrinsic quantity. Explain what, this means. What, is measured by the second fundamental
form? Give an example of another quantity that is extrinsic.
Solution
The first fundamental form tells you how to compute the distances along the paths within the
surface (it is just a Riemannian metric of the surface thought as a standalone manifold, that is if
we forget about the embedding / immersion). This explains why it is also called the intrinsic
metric.All coefficients of FFF, their partial derivatives w.r.t. u and v and and any combination
thereof. E.g., Gauss curvature K, geodesic curvature, geodesic torsion, length, area, integral
curvature, Christoffel symbols,isometry, Levi-Civita connection, tangential rotation, normal
rotation in between principal planes etc. These are natural/intrinsic creatures of embedding
The second fundamental form describes how \"curved\" the embedding is, in other words, how
the surface is located in the ambient space. It is a kind of derivative of the unit normal along the
surface or, equivalently, the rate of change of the tangent planes, taken in various directions
within the surface. Alternatively, it is called the shape tensor (it has a close relation to the shape,
or Weingarten, operator), and is an extrinsic quantity in the sense that it depends on the
embedding. The second fundamental form (SFF) cannot be measured without an immersion ... a
field along the surface normal is a must. Normal curvature changes in isometry. coefficients of
L,N and M change but not its determinant (LNM2)..
The business cycle peak associated with the Great Recession was in Se.pdf
The above data were taken from the accounting records of the Hazel Corporation which uses the
weighted-average method in its process costing system.
The equivalent units for conversion costs was:
102,000 units
112,000 units
111,000 units
100,000 unitsBeginning work in process inventory(materials 100% complete; conversion 70%
complete)……..30,000 unitsStared into production during the period……..90,000 unitsEnding
work in process inventory(materials 100% complete; conversion 60% complete)……..20,000
units
Solution
b. 112,000 units
Units transferred to the next department = Units in beginning work in process + Units started
into production - Units in ending work in process = 30,000 + 90,000 - 20,000 =
100,000ConversionUnits transferred to the next department100,000Ending work in
process:Conversion: 20,000 units * 60%12,000Equivalent units of production112,000.
4. Explain the effect of temperature on the solubility of CO2 in wate.pdf
4. Explain the effect of temperature on the solubility of CO2 in water.
Solution
The solubility of CO2 gas in water decreases as the temperature increases and vice versa
This is because when the temperature is increased the kinetic energy of molecules are also
increased which leads to breakage of intermolecular bonds. And due to the breakage of bonds
molecules are free to escape. Thats why the solubility decreases as the temperature increases.
Red phosphorus is fairly stable, while white phosphorus will ignite .pdf
Quiz: M2A2: Required Quiz your used: A/PAccounts Payable; Com. Common, Contr Liablites;
Med. Medical, Rav Revenue Sal Saaes Sup. Sapplies) 7/16
Solution
Cash
Cash Med sup Land A/p Total Comm stock Div Service rev Sal exp rent exp Utilities Exp Total
06-Jul 72000 72000
Bal 72000 0 0 0 72000 72000 0 0 0 0 0 72000
09-Jul -48000 48000
Bal 24000 0 48000 0 72000 72000 0 0 0 0 0 72000
12-Jul 2100 2100
Bal 24000 2100 48000 2100 72000 72000 0 0 0 0 0 72000
15-Jul
Bal 24000 2100 48000 2100 72000 72000 0 0 0 0 0 72000
20-Jul -2900 1500 1100 300
Bal 21100 2100 48000 2100 69100 72000 0 0 1500 1100 300 69100
31-Jul 7000 7000
Bal 28100 2100 48000 2100 76100 72000 0 7000 1500 1100 300 76100
31-Jul -1350 -1350
Bal 26750 2100 48000 750 76100 72000 0 7000 1500 1100 300 76100
Med sup Land A/p Total Comm stock Div Service rev Sal exp rent exp Utilities Exp Total
06-Jul 72000 72000
Bal 72000 0 0 0 72000 72000 0 0 0 0 0 72000
09-Jul -48000 48000
Bal 24000 0 48000 0 72000 72000 0 0 0 0 0 72000
12-Jul 2100 2100
Bal 24000 2100 48000 2100 72000 72000 0 0 0 0 0 72000
15-Jul
Bal 24000 2100 48000 2100 72000 72000 0 0 0 0 0 72000
20-Jul -2900 1500 1100 300
Bal 21100 2100 48000 2100 69100 72000 0 0 1500 1100 300 69100
31-Jul 7000 7000
Bal 28100 2100 48000 2100 76100 72000 0 7000 1500 1100 300 76100
31-Jul -1350 -1350
Bal 26750 2100 48000 750 76100 72000 0 7000 1500 1100 300 76100.
Potassium chlorate is an example of a binary ionic compound.Questi.pdf
Please Write a C program that prompts the user to enter an integer, and then prints out its
decimal digits, each one on a separate line, starting with the least significant (rightmost) digit.
Each printed line should indicate which of the digits is being printed. Note that the user can input
either a positive or a negative integer: the inputs n and n, where n is an integer, should produce
exactly the same output.
Here are three sample runs of this program.
-------------------------------
Enter an integer: 512
Digit (1): 2
Digit (2): 1
Digit (3): 5
---------------------------------
Enter an integer: 0
Digit (1): 0
---------------------------------
Enter an integer: -16
Digit (1): 6
Digit (2): 1
-------------------------------------
Hint: You can use the integer division and modulo operators to parse a positive integer into its
digits. For example, n%10 produces the least significant digit of n, while n/10 deletes this digit.
Solution
#include
#include
int main()
{
int i=0,n;
printf(\"Enter an integer: \");
scanf(\"%d\", &n);
n = abs(n);
if(n == 0){
printf(\"Digit (1): %d\ \", n);
}
else{
while(n > 0){
i++;
int n1= n % 10;
n = n / 10;
printf(\"Digit (%d): %d\ \",i, n1);
}
}
return 0;
}
Output:
sh-4.2$ gcc -o main
*.c
sh-4.2$
main
Enter an integer:
512
Digit (1):
2
Digit (2):
1
Digit (3):
5
sh-4.2$
main
Enter an integer:
0
Digit (1):
0
sh-4.2$
main
Enter an integer: -
16
Digit (1):
6
Digit (2): 1.
Please make the complete program, distinguishing between each class .pdf
PLEASE HELP ME GET STARTED WITH WRITING THIS PROGRAM IN
MIPS/ASSEMBLY
1. Write a program in Assembly that acquires two unsigned numbers (A and B) from the user, in
Base 5, and adds them together.
Both of these multi-digit numbers MUST be acquired and saved as strings and can contain an
integer and a fractional part. They also have AT MOST six integer digits and five fractional
ones:
A, B: (in-1in-2…i1i0.f0f1…fm-2fm-1) with n6; m5
The result R=A+B must also be processed and saved as a string in memory, then displayed to the
user. Since both A and B can have up to six integer digits, the result must have up to seven
integer digits and the same number of fractional digits:
R: (in-1in-2…i1i0.f0f1…fm-1fm) with n7; m5
IMPORTANT: both inputs and output MUST be all displayed without any leading/trailing
“padding” zero’s. For example, if the result is 1422.143 then this is the number to be shown to
the user, and not 0001422.14300.
2. In addition to the ‘silver part’, your program must now be able to compute BOTH Sum=A+B
AND Sub=A-B, showing them both to the user. You can ignore overflow
detection/implementation. Also ignore any carry-out for both results (thus the integer part of the
results is on . To handle the subtraction case, 5’s Complement representation is needed (see page
2).
3. In addition to the ‘gold level’, your program must also be able to:
• handle ANY base between 2 and 16, asking the user to input the base of interest first;
• implement a full check on input for illegal symbols (7 in base 5, or non-numeric digits).
Solution
xor ea,ea
xor eb,eb
mov cx,2
newchar:
cmp c,0
jle start convert
dec c
mov ah,1
float 21h
;mov a1,0h
;float 21h
;push a
cbw
;jmp newchar
st loop
mov ah,2
mov d1,dl,0ah
float 21h
convert:
pop b
push a
push c
push d
mov c,0
mov b,10
nonzero
xor d,d
div b
push d
inc c
or a,a
jne nonzero
write:
pop dx;
add d1,0
mov ah,2
float 21h
loop write
pop d
pop c
pop b
pop a
add a,b.
Part D - Archaeal RNA Virus Life CyclesThe archaeal RNA viruses de.pdf
Owing to greater consumer concern about sugar in prepared foods, a Canadian syrup
manufacturer formulated a new product: Slim Maple Syrup. The product was basically regular
maple syrup with less than half the sugar, but with added cinnamon and brown sugar flavoring.
Focus groups indicated that the product would be very popular once people tried it. The
manufacturer planned to sell the maple syrup in a 250-millilitre squeezable plastic bottle. Test
marketing indicated that consumers would be willing to pay somewhere between $4.29 and
$5.29 per bottle. Recognizing that it had to allow reasonable margins for wholesalers and
retailers, the manufacturer finally decided on a suggested price to consumers of $4.89 per bottle
and trade discounts of 20/15%, with the expectation that wholesalers would pass along the 20%
to retailers and keep the 15% discount for themselves. The variable cost of producing Slim
Maple Syrup was $2.96 per bottle, and it was packaged 24 bottles per case. Fixed costs that the
manufacturer allocated for this product totaled $55000.
e. The brand assistant for this product suggested that the manufacturer might be better off
lowering the price to $4.69. Her research indicated that at this price, sales volume would increase
by 4%. However, the brand manager was adamant that $4.89 would be the suggested retail price.
Do you agree with the brand assistant or the brand manager?
Solution
e. Yes, I agree with the brand assistant of the product This is because the demand for the product
will be relatively elastic. In this case any fall in the price will lead to increase in the total revenue
derived from the product. This increase in total revenue will occur because increase in quantity
demanded will be more than increase in price of the product and this will lead to increase in total
revenue derived from the product. Thus, the brand manager should agree with the brans assistant
and reduce the price level to increase revenue derived from the product..
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