The code should add the polynomial numbers using a linked list- Java -.pdf
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The code should add the polynomial numbers using a linked list. Java . Keep in mind the polynomials will be gotten from a file. Things to keep in mind the list should be in decending order and traverse the list after all coefficient/exponent pair Term nodes from one input line have been inserted. Here are the specifications //The Polynomial class would likely have a single private data member (reference to class Term) called head. //The Term class would likely have three private data members (coefficient and exponent of type int) and next of type reference to Term. //The latter class would also have the following public methods: constructor(s), gets and sets for each data member, and perhaps a formatting method with the special output requirements. An example of input is 7 1 2 4 6 2 -3 2 -1 -1 3 5 1 2 3 6 0 -3 2 -1 -1 3 Negative negative pair signals the termination.
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Main issues with the following code-Im not sure if its reading the fil.pdf
Main issues with the following code:Im not sure if its reading the file correctly because its
adding all terms together. In other words the the first line of terms is adding the second line of
terms but thats not my intention. Each line of term should have their own polynomial expression
as shown below
Basic specifications :
The code should add the polynomial numbers using a linked list. Java . Keep in mind the
polynomials will be gotten from a file.
Things to keep in mind the list should be in decending order and traverse the list after
all coefficient/exponent pair Term nodes from one input line have been
inserted.
Here are the specifications
//The Polynomial class would likely have a single private data member (reference to
class Term) called head.
//The Term class would likely have three private data
members (coefficient and exponent of type int) and next of type reference to
Term.
//The latter class would also have the following public methods:
constructor(s), gets and sets for each data member, and perhaps a formatting
method with the special output requirements.
An example of input is 7 1 2 4 6 2 -3 2 -1 -1 3
Negative negative
pair signals the termination
***NO doubly linked list , it should be a single linked list **
Input file contains the following :
7 1 2 4 6 2 -3 2 -1 -1 3 ----> 2x^4 - 3x^2 +6x^2 + 7x
5 1 2 3 6 0 -3 2 -1 -1 3 ----> 2*X^3 + (-3)*X^2 + 5*X + 6 // thats the ouput for one line of the
the file , each line of the file should have one polynomial output
Code
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class Polynomial {
private Term head;
// Constructor for creating an empty polynomial object
public Polynomial() {
head = null;
}
// Method for adding a term to the polynomial, this is inside the polynomial term
public void addTerm(int coefficient, int exponent) {
// Create a new term object
Term newTerm = new Term(coefficient, exponent);
// If the polynomial is empty, set the new term as the head
if (head == null) {
head = newTerm;
} else {
// Traverse the polynomial until we find the correct position for the new term
Term current = head;
Term previous = null;
while (current != null && current.getExponent() > exponent) {
previous = current;
current = current.getNext();
}
// If a term with the same exponent already exists, add the coefficients
if (current != null && current.getExponent() == exponent) {
current.setCoefficient(current.getCoefficient() + coefficient);
} else {
// Otherwise, insert the new term into the polynomial
if (previous == null) {
head = newTerm;
} else {
previous.setNext(newTerm);
}
newTerm.setNext(current);
}
}
// Method for formatting the polynomial as a string
public String toString() {
StringBuilder sb = new StringBuilder();
if (head != null) {
sb.append(head.toString());
Term current = head.getNext();
while (current != null) {
if (current.getCoefficient() > 0) {
sb.append(" + ");
} else {
sb.append(" - ");
}
sb.append(current.toString());
current = cur.
Recommended
Main issues with the following code-Im not sure if its reading the fil.pdf
Main issues with the following code:Im not sure if its reading the file correctly because its
adding all terms together. In other words the the first line of terms is adding the second line of
terms but thats not my intention. Each line of term should have their own polynomial expression
as shown below
Basic specifications :
The code should add the polynomial numbers using a linked list. Java . Keep in mind the
polynomials will be gotten from a file.
Things to keep in mind the list should be in decending order and traverse the list after
all coefficient/exponent pair Term nodes from one input line have been
inserted.
Here are the specifications
//The Polynomial class would likely have a single private data member (reference to
class Term) called head.
//The Term class would likely have three private data
members (coefficient and exponent of type int) and next of type reference to
Term.
//The latter class would also have the following public methods:
constructor(s), gets and sets for each data member, and perhaps a formatting
method with the special output requirements.
An example of input is 7 1 2 4 6 2 -3 2 -1 -1 3
Negative negative
pair signals the termination
***NO doubly linked list , it should be a single linked list **
Input file contains the following :
7 1 2 4 6 2 -3 2 -1 -1 3 ----> 2x^4 - 3x^2 +6x^2 + 7x
5 1 2 3 6 0 -3 2 -1 -1 3 ----> 2*X^3 + (-3)*X^2 + 5*X + 6 // thats the ouput for one line of the
the file , each line of the file should have one polynomial output
Code
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class Polynomial {
private Term head;
// Constructor for creating an empty polynomial object
public Polynomial() {
head = null;
}
// Method for adding a term to the polynomial, this is inside the polynomial term
public void addTerm(int coefficient, int exponent) {
// Create a new term object
Term newTerm = new Term(coefficient, exponent);
// If the polynomial is empty, set the new term as the head
if (head == null) {
head = newTerm;
} else {
// Traverse the polynomial until we find the correct position for the new term
Term current = head;
Term previous = null;
while (current != null && current.getExponent() > exponent) {
previous = current;
current = current.getNext();
}
// If a term with the same exponent already exists, add the coefficients
if (current != null && current.getExponent() == exponent) {
current.setCoefficient(current.getCoefficient() + coefficient);
} else {
// Otherwise, insert the new term into the polynomial
if (previous == null) {
head = newTerm;
} else {
previous.setNext(newTerm);
}
newTerm.setNext(current);
}
}
// Method for formatting the polynomial as a string
public String toString() {
StringBuilder sb = new StringBuilder();
if (head != null) {
sb.append(head.toString());
Term current = head.getNext();
while (current != null) {
if (current.getCoefficient() > 0) {
sb.append(" + ");
} else {
sb.append(" - ");
}
sb.append(current.toString());
current = cur.
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The actual illustration of values is decided by the machine design (.pdf
The actual illustration of values is decided by the machine design (strictly speaking, by the C
implementation). the particular size is accessed through the itemsize attribute. The values hold
on for \'L\' and \'I\' things are diagrammatical as Python long integers once retrieved, as a result
of Python’s plain number sort cannot represent the complete vary of C’s unsigned (long)
integers.
The module defines the subsequent type:
class array.array(typecode[, initializer])
A new array whose things ar restricted by typecode, and initialized from the nonmandatory
initializer worth, that should be a listing, string, or iterable over components of the acceptable
sort.
Changed in version two.4: at one time, solely lists or strings were accepted.
If given a listing or string, the initializer is passed to the new array’s fromlist(), fromstring(), or
fromunicode() methodology (see below) to feature initial things to the array. Otherwise, the
iterable initializer is passed to the extend() methodology.
array.ArrayType
Obsolete alias for array.
Array objects support the normal sequence operations of assortment, slicing, concatenation, and
multiplication. once mistreatment slice assignment, the assigned worth should be Associate in
Nursing array object with an equivalent sort code; all told alternative cases, TypeError is raised.
Array objects additionally implement the buffer interface, and should be used where buffer
objects ar supported.
The following information things and ways also are supported:
array.typecode
The typecode character wont to produce the array.
array.itemsize
The length in bytes of 1 array item within the representation.
array.append(x)
Append a replacement item with worth x to the tip of the array.
array.buffer_info()
Return a tuple (address, length) giving the present memory address and also the length in
components of the buffer wont to hold array’s contents. the dimensions of the memory buffer in
bytes is computed as array.buffer_info()[1] * array.itemsize. this can be often helpful once
operating with low-level (and inherently unsafe) I/O interfaces that need memory addresses, like
bound ioctl() operations. The came back numbers ar valid as long because the array exists and no
length-changing operations ar applied thereto.
Note once mistreatment array objects from code written in C or C++ (the solely thanks to
effectively create use of this information), it makes a lot of sense to use the buffer interface
supported by array objects. This methodology is maintained for backward compatibility and may
be avoided in new code. The buffer interface is documented in Buffers and Memoryview
Objects.
array.byteswap()
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Return the amount of occur.
The following data was extracted from the accounting records of Wise C.pdf
The following data was extracted from the accounting records of Wise Company: Adjusting
journal entries made by Wise after preparing the December bank reconciliation were as follows:
Dr. Cash 1,995.00 Dr. Bank Service Charges 5.00 Cr. Notes Receivable 2,000.00
Dr. Cash 27.00 Cr. Advertising Expense 27.00
Dr. Accounts Receivable 450.00 Cr. Cash 450.00
Dr. Bank Service Charges Expense 42.50 Cr. Cash 42.50
Other information:
The Balance Per books November 30 was $18,434.27
Deposits in transit at December 31 were $2,145.40
An error made by the bank on the December bank statement was detected. It had charged a
cheque written by another bank client (Wiese Company) against Wise Company's bank balance.
The Bank has been notified and agrees it is indeed their error. The amount was $30.50
Outstanding cheques were $1,938.53 There were no other reconciling items not reflected above
The journal entry for the $450 probably represents:
Multiple Choice
An outstanding cheque written by Wise which has not cleared the bank in December
An NSF cheque
Some other explanation
A deposit made by Wise which was not recorded on the bank statement
Collection of a receivable on Wise's behalf.
The following data was extracted from the accounting records of Wise C (1).pdf
The following data was extracted from the accounting records of Wise Company:
Adjusting journal entries made by Wise after preparing the December bank reconciliation were
as follows:
Other information:
The Balance Per books November 30 was $18,434.27
Deposits in transit at December 31 were $2,145.40
An error made by the bank on the December bank statement was detected. It had charged a
cheque written by another bank client (Wiese Company) against Wise
Company's bank balance. The Bank has been notified and agrees it is indeed their error. The
amount was $30.50
Outstanding cheques were $1,938.53
There were no other reconciling items not reflected above
The journal entry for the $450 probably represents:
Multiple Choice
A deposit made by Wise which was not recorded on the bank statement
Collection of a receivable on Wise's behalf
An NSF cheque
Some other explanation
An outstanding cheque written by Wise which has not cleared the bank in December
Dr. C ash 1,995.00
Dr. B ank Service Charges 5 .00
Cr. N otes Receivable 2,000.00
.
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initializer worth, that should be a listing, string, or iterable over components of the acceptable
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If given a listing or string, the initializer is passed to the new array’s fromlist(), fromstring(), or
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array.ArrayType
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Array objects support the normal sequence operations of assortment, slicing, concatenation, and
multiplication. once mistreatment slice assignment, the assigned worth should be Associate in
Nursing array object with an equivalent sort code; all told alternative cases, TypeError is raised.
Array objects additionally implement the buffer interface, and should be used where buffer
objects ar supported.
The following information things and ways also are supported:
array.typecode
The typecode character wont to produce the array.
array.itemsize
The length in bytes of 1 array item within the representation.
array.append(x)
Append a replacement item with worth x to the tip of the array.
array.buffer_info()
Return a tuple (address, length) giving the present memory address and also the length in
components of the buffer wont to hold array’s contents. the dimensions of the memory buffer in
bytes is computed as array.buffer_info()[1] * array.itemsize. this can be often helpful once
operating with low-level (and inherently unsafe) I/O interfaces that need memory addresses, like
bound ioctl() operations. The came back numbers ar valid as long because the array exists and no
length-changing operations ar applied thereto.
Note once mistreatment array objects from code written in C or C++ (the solely thanks to
effectively create use of this information), it makes a lot of sense to use the buffer interface
supported by array objects. This methodology is maintained for backward compatibility and may
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Objects.
array.byteswap()
“Byteswap” all things of the array. this can be solely supported for values that ar one, 2, 4, or
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The following data was extracted from the accounting records of Wise C.pdf
The following data was extracted from the accounting records of Wise Company: Adjusting
journal entries made by Wise after preparing the December bank reconciliation were as follows:
Dr. Cash 1,995.00 Dr. Bank Service Charges 5.00 Cr. Notes Receivable 2,000.00
Dr. Cash 27.00 Cr. Advertising Expense 27.00
Dr. Accounts Receivable 450.00 Cr. Cash 450.00
Dr. Bank Service Charges Expense 42.50 Cr. Cash 42.50
Other information:
The Balance Per books November 30 was $18,434.27
Deposits in transit at December 31 were $2,145.40
An error made by the bank on the December bank statement was detected. It had charged a
cheque written by another bank client (Wiese Company) against Wise Company's bank balance.
The Bank has been notified and agrees it is indeed their error. The amount was $30.50
Outstanding cheques were $1,938.53 There were no other reconciling items not reflected above
The journal entry for the $450 probably represents:
Multiple Choice
An outstanding cheque written by Wise which has not cleared the bank in December
An NSF cheque
Some other explanation
A deposit made by Wise which was not recorded on the bank statement
Collection of a receivable on Wise's behalf.
The following data was extracted from the accounting records of Wise C (1).pdf
The following data was extracted from the accounting records of Wise Company:
Adjusting journal entries made by Wise after preparing the December bank reconciliation were
as follows:
Other information:
The Balance Per books November 30 was $18,434.27
Deposits in transit at December 31 were $2,145.40
An error made by the bank on the December bank statement was detected. It had charged a
cheque written by another bank client (Wiese Company) against Wise
Company's bank balance. The Bank has been notified and agrees it is indeed their error. The
amount was $30.50
Outstanding cheques were $1,938.53
There were no other reconciling items not reflected above
The journal entry for the $450 probably represents:
Multiple Choice
A deposit made by Wise which was not recorded on the bank statement
Collection of a receivable on Wise's behalf
An NSF cheque
Some other explanation
An outstanding cheque written by Wise which has not cleared the bank in December
Dr. C ash 1,995.00
Dr. B ank Service Charges 5 .00
Cr. N otes Receivable 2,000.00
.
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