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Principles of presentation of data:
1. Increase interest of reader.
2. Concise without losing important details.
3. Presented in simple form.
4. Facilitate further analysis.
5. Define the problem & suggest it’s solution.
 Text
 Tabulation
 Diagrams & Graphs
Tabulation is the first step in the analysis of
data
In statistics, a frequency distribution is a table that displays the frequency of various
outcomes in a sample. Each entry in the table contains the frequency or count of the
occurrences of values within a particular group or interval, and in this way, the table
summarizes the distribution of values in the sample.
A frequency distribution shows us a summarized grouping of data divided into
mutually exclusive classes and the number of occurrences in a class. It is a way of
showing unorganized data.
 After collecting data, the first task for a
researcher is to organize and simplify the data
so that it is possible to get a general overview
of the results.
 This is the goal of descriptive statistical
techniques.
 One method for simplifying and organizing
data is to construct a frequency distribution.
5
 A frequency distribution is an organized
tabulation showing exactly how many
individuals are located in each category on the
scale of measurement. A frequency
distribution presents an organized picture of
the entire set of scores, and it shows where
each individual is located relative to others in
the distribution.
6
 A frequency distribution table consists of at
least two columns - one listing categories on
the scale of measurement (X) and another for
frequency (f).
 In the X column, values are listed from the
highest to lowest, without skipping any.
 For the frequency column, tallies are
determined for each value (how often each X
value occurs in the data set). These tallies are
the frequencies for each X value.
 The sum of the frequencies should equal N.
7
The way, in which observations are distributed
into various classes.
Frequency distribution
discrete frequency distribution continuous frequency distribution
To make the work easy, we use tally marks.
 When a frequency distribution table lists
all of the individual categories (X values-
i.e. Variables is Discrete) it is called a
Discrete frequency distribution.
9
Ex:- II MBBS students conducted family health
survey(FHS) and recorded number of children's
among 40 families as below:
Prepare the frequency table for given data & draw
your conclusion from the same.
10
0 2 1 3 2 1 2 1
2 1 2 2 1 2 1 2
2 2 1 0 2 1 2 1
2 2 1 2 1 2 1 2
2 1 2 3 1 2 1 0
Soln : Let us consider the variable
X : Number of children's in family
S= Smallest value=Minimum value number of children’s =0,
L= Largest Value= Maximum value number of children’s =3,
11
No. of
children’s(X)
Tally Marks Frequency (f)
0 III 3
1 IIII IIII II 12
2 IIII IIII IIII IIII III 23
3 II 2
Total N= 40
No. of family
members
Tally bars frequency
1 IIII 5
2 IIII IIII 10
3 IIII IIII IIII 15
4 IIII IIII IIII IIII 20
5 IIII IIII 10
6 & more IIII 5
Total N= 65
 Sometimes, however, a set of scores covers a
wide range of values. In these situations, a
list of all the X values would be quite long -
too long to be a “simple” presentation of the
data.
 To remedy this situation, a grouped
frequency distribution table is used.
13
 In a grouped table, the X column lists groups
of scores, called class intervals, rather than
individual values.
 These intervals all have the same width,
usually a simple number such as 2, 5, 10, and
so on.
 Interval must same throughout the all classes.
 Groups should not be too broad or too short.
 Group should be between 5 and 15.
14
1. Range (R) – the difference between the highest
score and the lowest score.
2. Class Interval (k) – a grouping or category defined
by a lower limit and an upper limit.
3. Class Boundaries (CB) – these are also known as the
exact limits, and can be obtained by subtracting 0.5
from the lower limit of an interval and adding 0.5 to
the upper limit interval.
4. Class Mark (x) – is the middle value or the midpoint of a
class interval. It is obtained by getting the average of the
lower class limit and the upper class limit.
5. Class Size (i) – is the difference between the upper
class boundary and the lower class boundary of a
class interval
7. Class Frequency – it refers to the number of
observations belonging to a class interval, or the
number of items within a category.
Statistics Test Scores of 50 students. Construct a frequency
distribution
51 65 68 87 76
56 69 75 89 80
61 66 73 86 79
70 71 54 87 78
68 74 66 88 77
67 73 64 90 77
72 52 67 86 79
74 59 70 89 85
55 63 74 82 84
57 68 72 81 83
Steps in Constructing a Frequency Distribution
1. Find the range R, using the formula:
R = Highest Score – Lowest Score k
2. Compute for the number of class intervals, n, by
using the formula:
k = 1+3.3 log n
Note: The ideal number of class intervals
should be 5 to 15. Less than 8 intervals are
recommended for a data with less than 50
observations/values. For a data with 50 to
100 observations/values, the suggested
number should be greater than 8.
3. Compute for the class size, I, using the formula:
i = R/k
Please note also that the few number of class intervals
will result to crowded data while too many number of
class intervals tend to spread out the data too much.
4. Using the lowest score as lower limit, add (i – 1)to
it to obtain the higher limit of the desired class
interval.
5. The lower limit of the second interval may be obtained by
adding the class size to the lower limit of the first interval.
Add (i – 1) to the result to obtain the higher limit of the
second interval.
6. Repeat step 5 to obtain the third class interval, and so on,
and so forth.
7. When the n class intervals are completed, determine the
frequency for each class interval by counting the
elements.
Solution:
1. R = Highest Score – Lowest Score
R = 90 – 51
R = 39
2. k = 8 (desired interval)
3. i = R/k
i = 39/8
i = 4.875
i = 5
The Frequency Distribution of the Statistics Score of 50
Students
Class Interval Tally Marks f
LL - UL
50 - 55 IIII 4
55 - 60 III 3
60 - 65 IIII 4
65 - 70 IIII IIII 10
70 - 75 IIII IIII 9
75 - 80 IIII II 7
80 - 85 IIII 5
85 - 90 IIII III 8
Total N=50
Cumulative Frequency
Distribution
Class Interval f <cf >cf
LL - UL
50 - 55 4 4 50
55 - 60 3 7 46
60 - 65 4 11 43
65 - 70 10 21 39
70 - 75 9 30 29
75 - 80 7 37 20
80 - 85 5 42 13
85 - 90 8 50 8
50
The Frequency Distribution of the Statistics Score of 50 Students
Cumulative frequency
Less than cumulative frequency Greater than cumulative frequency
(l.c.f.) (g.c.f.)
l.c.f. denotes no. of observation whose values
are less than upper limits.
g.c.f. denotes no. of observation whose values
are greater than lower limits.
Cumulative Frequency distribution
Marks Frequency
Cumulative frequency
l.c.f. g.c.f.
0-50 5 5 60+5=N=65
50 - 60 10 5+10=15 50+10=60
60 - 70 15 15+15=30 35+15=50
70 – 80 20 30+20=50 15+20=35
80 - 90 10 50+10=60 10+5=15
90 – 100 5 N=65 5
27
A two-way table presents categorical data by
counting the number of observations that fall
into each group for two variables, one divided
into rows and the other divided into columns.
There are 40 students in batch D of II
MBBS out of which 25 are boys. The 18
boys and 13 girls lives in hostel. Prepare
contingency table for gender wise
current residential status for batch D.
SexResidential
Status
Hostelite
Day
Scholar
Total
Male 18 ?? 25
Female 13 ?? ??
Total ?? ?? N= 40
Ex. In study of susceptibility to diphtheria, 982
children were studied in Mumbai. Out of 494 boys
63 were Schick positive i.e. susceptible. 807
children were schick negative and out of these 376
were girls.
Prepare table for Given Information
Classification of children according to sex and
susceptibility to diphtheria
Schick Test
Sex
+ ve -ve Total
Boys 63 ?? 494
Girls ?? 376 ??
Total ?? 807 N= 982
Schick Test
Sex
+ ve -ve Total
Boys 63 =494 -63
=431
494
Girls =492-376
=112
376 =982-492
=488
Total =63+112
=175
807 N= 982
L= largest Value=10.1
S= Smallest value=13.9
R=L-S=13.9-10.1=3.8
k=1+1.3322* log(N)=1+3.322*2 ≈8
i=R/k=3.8/8=0.475≈0.5
34
Thank You
35

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Tabulation of Data, Frequency Distribution, Contingency table

  • 1.
  • 2. Principles of presentation of data: 1. Increase interest of reader. 2. Concise without losing important details. 3. Presented in simple form. 4. Facilitate further analysis. 5. Define the problem & suggest it’s solution.
  • 3.  Text  Tabulation  Diagrams & Graphs Tabulation is the first step in the analysis of data
  • 4. In statistics, a frequency distribution is a table that displays the frequency of various outcomes in a sample. Each entry in the table contains the frequency or count of the occurrences of values within a particular group or interval, and in this way, the table summarizes the distribution of values in the sample. A frequency distribution shows us a summarized grouping of data divided into mutually exclusive classes and the number of occurrences in a class. It is a way of showing unorganized data.
  • 5.  After collecting data, the first task for a researcher is to organize and simplify the data so that it is possible to get a general overview of the results.  This is the goal of descriptive statistical techniques.  One method for simplifying and organizing data is to construct a frequency distribution. 5
  • 6.  A frequency distribution is an organized tabulation showing exactly how many individuals are located in each category on the scale of measurement. A frequency distribution presents an organized picture of the entire set of scores, and it shows where each individual is located relative to others in the distribution. 6
  • 7.  A frequency distribution table consists of at least two columns - one listing categories on the scale of measurement (X) and another for frequency (f).  In the X column, values are listed from the highest to lowest, without skipping any.  For the frequency column, tallies are determined for each value (how often each X value occurs in the data set). These tallies are the frequencies for each X value.  The sum of the frequencies should equal N. 7
  • 8. The way, in which observations are distributed into various classes. Frequency distribution discrete frequency distribution continuous frequency distribution To make the work easy, we use tally marks.
  • 9.  When a frequency distribution table lists all of the individual categories (X values- i.e. Variables is Discrete) it is called a Discrete frequency distribution. 9
  • 10. Ex:- II MBBS students conducted family health survey(FHS) and recorded number of children's among 40 families as below: Prepare the frequency table for given data & draw your conclusion from the same. 10 0 2 1 3 2 1 2 1 2 1 2 2 1 2 1 2 2 2 1 0 2 1 2 1 2 2 1 2 1 2 1 2 2 1 2 3 1 2 1 0
  • 11. Soln : Let us consider the variable X : Number of children's in family S= Smallest value=Minimum value number of children’s =0, L= Largest Value= Maximum value number of children’s =3, 11 No. of children’s(X) Tally Marks Frequency (f) 0 III 3 1 IIII IIII II 12 2 IIII IIII IIII IIII III 23 3 II 2 Total N= 40
  • 12. No. of family members Tally bars frequency 1 IIII 5 2 IIII IIII 10 3 IIII IIII IIII 15 4 IIII IIII IIII IIII 20 5 IIII IIII 10 6 & more IIII 5 Total N= 65
  • 13.  Sometimes, however, a set of scores covers a wide range of values. In these situations, a list of all the X values would be quite long - too long to be a “simple” presentation of the data.  To remedy this situation, a grouped frequency distribution table is used. 13
  • 14.  In a grouped table, the X column lists groups of scores, called class intervals, rather than individual values.  These intervals all have the same width, usually a simple number such as 2, 5, 10, and so on.  Interval must same throughout the all classes.  Groups should not be too broad or too short.  Group should be between 5 and 15. 14
  • 15. 1. Range (R) – the difference between the highest score and the lowest score. 2. Class Interval (k) – a grouping or category defined by a lower limit and an upper limit. 3. Class Boundaries (CB) – these are also known as the exact limits, and can be obtained by subtracting 0.5 from the lower limit of an interval and adding 0.5 to the upper limit interval.
  • 16. 4. Class Mark (x) – is the middle value or the midpoint of a class interval. It is obtained by getting the average of the lower class limit and the upper class limit. 5. Class Size (i) – is the difference between the upper class boundary and the lower class boundary of a class interval 7. Class Frequency – it refers to the number of observations belonging to a class interval, or the number of items within a category.
  • 17. Statistics Test Scores of 50 students. Construct a frequency distribution 51 65 68 87 76 56 69 75 89 80 61 66 73 86 79 70 71 54 87 78 68 74 66 88 77 67 73 64 90 77 72 52 67 86 79 74 59 70 89 85 55 63 74 82 84 57 68 72 81 83
  • 18. Steps in Constructing a Frequency Distribution 1. Find the range R, using the formula: R = Highest Score – Lowest Score k 2. Compute for the number of class intervals, n, by using the formula: k = 1+3.3 log n
  • 19. Note: The ideal number of class intervals should be 5 to 15. Less than 8 intervals are recommended for a data with less than 50 observations/values. For a data with 50 to 100 observations/values, the suggested number should be greater than 8.
  • 20. 3. Compute for the class size, I, using the formula: i = R/k Please note also that the few number of class intervals will result to crowded data while too many number of class intervals tend to spread out the data too much. 4. Using the lowest score as lower limit, add (i – 1)to it to obtain the higher limit of the desired class interval.
  • 21. 5. The lower limit of the second interval may be obtained by adding the class size to the lower limit of the first interval. Add (i – 1) to the result to obtain the higher limit of the second interval. 6. Repeat step 5 to obtain the third class interval, and so on, and so forth. 7. When the n class intervals are completed, determine the frequency for each class interval by counting the elements.
  • 22. Solution: 1. R = Highest Score – Lowest Score R = 90 – 51 R = 39 2. k = 8 (desired interval) 3. i = R/k i = 39/8 i = 4.875 i = 5
  • 23. The Frequency Distribution of the Statistics Score of 50 Students Class Interval Tally Marks f LL - UL 50 - 55 IIII 4 55 - 60 III 3 60 - 65 IIII 4 65 - 70 IIII IIII 10 70 - 75 IIII IIII 9 75 - 80 IIII II 7 80 - 85 IIII 5 85 - 90 IIII III 8 Total N=50
  • 24. Cumulative Frequency Distribution Class Interval f <cf >cf LL - UL 50 - 55 4 4 50 55 - 60 3 7 46 60 - 65 4 11 43 65 - 70 10 21 39 70 - 75 9 30 29 75 - 80 7 37 20 80 - 85 5 42 13 85 - 90 8 50 8 50 The Frequency Distribution of the Statistics Score of 50 Students
  • 25. Cumulative frequency Less than cumulative frequency Greater than cumulative frequency (l.c.f.) (g.c.f.) l.c.f. denotes no. of observation whose values are less than upper limits. g.c.f. denotes no. of observation whose values are greater than lower limits.
  • 26. Cumulative Frequency distribution Marks Frequency Cumulative frequency l.c.f. g.c.f. 0-50 5 5 60+5=N=65 50 - 60 10 5+10=15 50+10=60 60 - 70 15 15+15=30 35+15=50 70 – 80 20 30+20=50 15+20=35 80 - 90 10 50+10=60 10+5=15 90 – 100 5 N=65 5
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  • 28. A two-way table presents categorical data by counting the number of observations that fall into each group for two variables, one divided into rows and the other divided into columns.
  • 29. There are 40 students in batch D of II MBBS out of which 25 are boys. The 18 boys and 13 girls lives in hostel. Prepare contingency table for gender wise current residential status for batch D.
  • 30. SexResidential Status Hostelite Day Scholar Total Male 18 ?? 25 Female 13 ?? ?? Total ?? ?? N= 40
  • 31. Ex. In study of susceptibility to diphtheria, 982 children were studied in Mumbai. Out of 494 boys 63 were Schick positive i.e. susceptible. 807 children were schick negative and out of these 376 were girls. Prepare table for Given Information
  • 32. Classification of children according to sex and susceptibility to diphtheria Schick Test Sex + ve -ve Total Boys 63 ?? 494 Girls ?? 376 ?? Total ?? 807 N= 982
  • 33. Schick Test Sex + ve -ve Total Boys 63 =494 -63 =431 494 Girls =492-376 =112 376 =982-492 =488 Total =63+112 =175 807 N= 982
  • 34. L= largest Value=10.1 S= Smallest value=13.9 R=L-S=13.9-10.1=3.8 k=1+1.3322* log(N)=1+3.322*2 ≈8 i=R/k=3.8/8=0.475≈0.5 34