When should we multiply?
When we need to add the same
number many times, we need to
multiply
Standard Algorithm (long)
multiplication method
Multiplyby2digitnumber
Ex: 5 3 4 X 4 6
Step 1 Write theproblem – liningup the place values ( ones under ones) and tens
under tens
X
5 3 4 4 6
X
5 3 4
4 6
Step 2
Multiplythe bottom number in the ones palceby the topnumber in the ones
place, tens placeand hundreds place.
4 X 6 = 4
2
3 X 6 =18 +2= 2 0
5 X 6 = 30 +2 = 3 2
X
5 3 4
4 6
Step 3
As we are going to multiplyby tens place number 0 shouldbe addedin ones
placeof answer
3 2 0 4
0
2 2
X
5 3 4
4 6
Step 4
Multiply the bottom number in the tens place by the top number in the ones place , tens place and hundreds
place.
3 2 0 4
0
2 2
3 X 4 = 12 +1 = 1 3
4 X 4 = 6
1
5 X 4= 20+1 = 2 1
X
5 3 4
4 6
Step 4
Add the numbers in answer part
3 2 0 4
2 1 3 6 0
2 2
1 1
+
4
6
5
4
2
5 3 4 X 4 6 = 24564
2 1 7 X 5 3
Answer 1 1,5 0 1

Standard algorithm multiplication

  • 1.
    When should wemultiply? When we need to add the same number many times, we need to multiply
  • 2.
  • 3.
    Multiplyby2digitnumber Ex: 5 34 X 4 6 Step 1 Write theproblem – liningup the place values ( ones under ones) and tens under tens X 5 3 4 4 6
  • 4.
    X 5 3 4 46 Step 2 Multiplythe bottom number in the ones palceby the topnumber in the ones place, tens placeand hundreds place. 4 X 6 = 4 2 3 X 6 =18 +2= 2 0 5 X 6 = 30 +2 = 3 2
  • 5.
    X 5 3 4 46 Step 3 As we are going to multiplyby tens place number 0 shouldbe addedin ones placeof answer 3 2 0 4 0 2 2
  • 6.
    X 5 3 4 46 Step 4 Multiply the bottom number in the tens place by the top number in the ones place , tens place and hundreds place. 3 2 0 4 0 2 2 3 X 4 = 12 +1 = 1 3 4 X 4 = 6 1 5 X 4= 20+1 = 2 1
  • 7.
    X 5 3 4 46 Step 4 Add the numbers in answer part 3 2 0 4 2 1 3 6 0 2 2 1 1 + 4 6 5 4 2
  • 8.
    5 3 4X 4 6 = 24564
  • 9.
    2 1 7X 5 3 Answer 1 1,5 0 1