Solving Quadratic
Equations by Factoring
PERFECT SQUARE TRINOMIALS
Recognizing Perfect Square Trinomials
1. Must have three terms.
2. The first and third term must be a perfect square.
3. The middle term must be twice the product of the
square roots of the first and last terms.
Step 1: Transform the equation into its Standard Form.
Steps in Solving Quadratic Equations by Factoring
(Perfect Square Trinomials)
Step 2: Inspect if the first and last terms are perfect squares and positive.
Step 3: Get the square root of the first term.
Step 4: Get the square root of the second term.
Step 5: Look at the middle term if it is twice the product of the square roots of
the first and last terms.
Step 6: Express the factor as a square of a binomial. The sign in between the
binomial depends on the sign of the middle term of the perfect
square trinomial. The terms in the binomial are the square roots of
the first and last terms of the perfect square trinomial.
Step 7: Apply the zero product property.
1. x2
- 24x = -144
= x
= 12
x2
- 24x + 144 = 0
(2)(x)(12) =
( - )( - ) = 0
x x 12
12
(x - 12)2
= 0
x - 12 = 0 x - 12 = 0
x = 12 x = 12
Step 1: Transform the equation into its Standard Form.
Step 2: Inspect if the first and last terms
are
perfect squares and positive.
Step 3: Get the square root of the first term.
Step 4: Get the square root of the second term.
Step 5: Look at the middle term if it is twice the
product of the square roots of the first and last terms.
Step 6: Express the factor as a square of a binomial.
The sign in between the binomial depends on the sign
of the middle term of the perfect square trinomial.
The terms in the binomial are the square roots of the
first and last terms of the perfect square trinomial.
Step 7: Apply the zero product property by equating
each factor to zero.
24x
2. x2
+ 4x + 4 = 0
= x
= 2
(2)(x)(2) =
( + )( + ) = 0
x x 2
2
(x + 2)2
= 0
x + 2 = 0 x + 2 = 0
x = -2 x = -2
Step 1: Transform the equation into its Standard Form.
Step 2: Inspect if the first and last terms
are
perfect squares and positive.
Step 3: Get the square root of the first term.
Step 4: Get the square root of the second term.
Step 5: Look at the middle term if it is twice the
product of the square roots of the first and last terms.
Step 6: Express the factor as a square of a binomial.
The sign in between the binomial depends on the sign
of the middle term of the perfect square trinomial.
The terms in the binomial are the square roots of the
first and last terms of the perfect square trinomial.
Step 7: Apply the zero product property by equating
each factor to zero.
4x
3. t2
– 16 = 8t Step 1: Transform the equation into its Standard Form.
Step 2: Inspect if the first and last terms
are
perfect squares and positive.
t2
– 8t – 16 = 0
Not applicable because the last term is negative.
Identify whether the following Quadratic
Equation is a perfect square trinomial.
1. = -16
2. = 0
3. = 0
4. 0
5. = -36
Assignment:
Solve for the value of
x for those that are
difference of two
squares.
(r2
- 4)
(x − 7)
NO
(x + 1)
NO

Solving Quadratic Equations by Factoring Perfect Square Trinomials.pptx

  • 1.
    Solving Quadratic Equations byFactoring PERFECT SQUARE TRINOMIALS
  • 2.
    Recognizing Perfect SquareTrinomials 1. Must have three terms. 2. The first and third term must be a perfect square. 3. The middle term must be twice the product of the square roots of the first and last terms.
  • 3.
    Step 1: Transformthe equation into its Standard Form. Steps in Solving Quadratic Equations by Factoring (Perfect Square Trinomials) Step 2: Inspect if the first and last terms are perfect squares and positive. Step 3: Get the square root of the first term. Step 4: Get the square root of the second term. Step 5: Look at the middle term if it is twice the product of the square roots of the first and last terms. Step 6: Express the factor as a square of a binomial. The sign in between the binomial depends on the sign of the middle term of the perfect square trinomial. The terms in the binomial are the square roots of the first and last terms of the perfect square trinomial. Step 7: Apply the zero product property.
  • 4.
    1. x2 - 24x= -144 = x = 12 x2 - 24x + 144 = 0 (2)(x)(12) = ( - )( - ) = 0 x x 12 12 (x - 12)2 = 0 x - 12 = 0 x - 12 = 0 x = 12 x = 12 Step 1: Transform the equation into its Standard Form. Step 2: Inspect if the first and last terms are perfect squares and positive. Step 3: Get the square root of the first term. Step 4: Get the square root of the second term. Step 5: Look at the middle term if it is twice the product of the square roots of the first and last terms. Step 6: Express the factor as a square of a binomial. The sign in between the binomial depends on the sign of the middle term of the perfect square trinomial. The terms in the binomial are the square roots of the first and last terms of the perfect square trinomial. Step 7: Apply the zero product property by equating each factor to zero. 24x
  • 5.
    2. x2 + 4x+ 4 = 0 = x = 2 (2)(x)(2) = ( + )( + ) = 0 x x 2 2 (x + 2)2 = 0 x + 2 = 0 x + 2 = 0 x = -2 x = -2 Step 1: Transform the equation into its Standard Form. Step 2: Inspect if the first and last terms are perfect squares and positive. Step 3: Get the square root of the first term. Step 4: Get the square root of the second term. Step 5: Look at the middle term if it is twice the product of the square roots of the first and last terms. Step 6: Express the factor as a square of a binomial. The sign in between the binomial depends on the sign of the middle term of the perfect square trinomial. The terms in the binomial are the square roots of the first and last terms of the perfect square trinomial. Step 7: Apply the zero product property by equating each factor to zero. 4x
  • 6.
    3. t2 – 16= 8t Step 1: Transform the equation into its Standard Form. Step 2: Inspect if the first and last terms are perfect squares and positive. t2 – 8t – 16 = 0 Not applicable because the last term is negative.
  • 7.
    Identify whether thefollowing Quadratic Equation is a perfect square trinomial. 1. = -16 2. = 0 3. = 0 4. 0 5. = -36 Assignment: Solve for the value of x for those that are difference of two squares. (r2 - 4) (x − 7) NO (x + 1) NO