2. Finding a
• log2(log3(log4(a))) = 0 • Original equation.
• Take the 2 in log2, and raise it to
log3(log4(a)) = 20 = 1 the power of what ever the entire
expression equals (0; 20=1).
log4(a) = 31 = 3
• Repeat the same method for the
a = 4 3 resulting equation, which is
log3(log4(a))=1. 31=3, which is the
a = 64 value of log4(a).
• Thus, if log4(a)=3, then a=43=64.
• a = 64
3. Finding b
• log3(log4(log2(b))) = 0 • Original equation.
• Take the base (3) in log3 and raise
log4(log2(b)) = 30 = 1 it to the power of whatever the
entire expression is set equal to
log2(b) = 41 = 4 (0; 30=1).
b = 24 = 16 • Do the same with the resulting
equation, which is log4(log2(b))=1.
b = 16 41=4, which is the value of log2(b).
• Thus, with log2(b) being equal to 4,
b=24=16.
• b = 16
4. Finding c
• log4(log2(log3(c))) = 0 • Original equation.
• Raise the base of log4 to what ever
log2(log3(c)) = 40 = 1 the entire expression is set equal
to, which is 0. 40=1.
log3(c) = 21 = 2
• Repeat for log2 and 1. 21=2=log3(c).
c = 3 = 9
2
• Thus, with log3(c) being equal to 2,
c = 9 c=32=9.
• c = 9
5. The Answer.
• Since a=64, b=16, and c=9,
a_ +c = 4+9 = 13
b
