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GUESS THE JUMBLED WORD
MISLEP
TESTREIN
GUESS THE JUMBLED WORD
MISLEP
TESTREIN
SIMPLE INTEREST
GUESS THE JUMBLED WORD
XIATEMROXPPA
GUESS THE JUMBLED WORD
APPROXIMATE
XIATEMROXPPA
GUESS THE JUMBLED WORD
MITE
GUESS THE JUMBLED WORD
TIME
MITE
GUESS THE JUMBLED WORD
LUTACA
GUESS THE JUMBLED WORD
ACTUAL
LUTACA
GUESS THE JUMBLED WORD
DINARORY
GUESS THE JUMBLED WORD
ORDINARY
DINARORY
GUESS THE JUMBLED WORD
XATEC
GUESS THE JUMBLED WORD
EXACT
XATEC
LESSON 5:
Simple
Interest
Business Math Lesson
11th
Grade
LESSON OBJECTIVES
At the end of the lesson, students should be able to:
1. Explain the role interest plays in a loan transaction;
2. compute the interest due on a loan;
3. find the maturity value on a loan or the future value on invested capital;
4. differentiate ordinary interest and exact interest, and be able to compute for
the same;
5. compute for the actual time and approximate time;
6. use the knowledge in (4) and (5), and compute for the four different types of
simple interest
7. be conversant with the 60-day 6% method of computing simple interest; and
8. explain the concept of promissory note
SIMPLE INTEREST
In business, capital is very important. However, not all business
owners always have enough capital to sustain their business.
More often than not, they have to borrow money for use in the
business. It is in this context that interests plays an important
role. Borrowers need to pay interest on the money that they
borrow.
REPORTER 1
Athea Keisha G. Geocallo
REPORTER 3
Joshua Gentolia
REPORTER 2
Liezell Joy Patenio
REPORTER 4
Raileyice Cal
MEET THE TEAM!
WHAT IS SIMPLE
INTEREST?
01
Simple Interest
Simple interest is a quick and easy method of
calculating the interest charge on a loan. Simple interest
is determined by multiplying the daily interest rate by
the principal by the number of days that elapse
between payments.
Basic formula to compute
Simple Interest
I=Prt
I - Interest (amount paid for the use of money)
P - Principal (amount borrowed/lent/invested)
r - rate (percent of interest being changed)
t - time (number of periods for which the money will
be borrowed/lent/invested)
The rate and the time should always agree, that is, if rate
is per annum, time should be in years, if rate is per
month, time should be in months; and if rate is per day;
time should be in days. In the absence of stipulation to
the contrary, a stated rate of interest is understood to
be on a per annum or annual basis.
Maturity value or value F Formula
F=P+I
IF WE SUBSTITUTE OUR BASIC FORMULA
FOR INTEREST IN FORMULA 2, WE WILL
HAVE:
F=P+I
F=P+Prt
F=P(I+rt)
EXAMPLE 1
P= 2,000
Tessa borrowed 2,000 at 12% interest rate for 2 years, find the
interest and maturity value.
GIVEN: SOLUTION:
Formula: I=Prt
I=2,000(0.12)(2)
I=240(2)
I=480
R= 12% OR 0.12
T= 2
Find: I=?
EXAMPLE 1
P= 2,000
Tessa borrowed 2,000 at 12 % interest rate for 2 years, find the
interest and maturity value.
GIVEN: SOLUTION:
Formula: F=P+I
F=2,000+480
F=2,480
R= 12% OR 0.12
T= 2
Find: F=?
EXAMPLE 2
P= 150,000
If cristina borrowed Php150,000 from wally, if cristina agreed to pay 6% annually interest
rate calculate the amount of interest she must pay if the pay loan period is: One year, 6
months and 21 months
GIVEN: SOLUTION:
Formula: I=Prt
A. I=150,000(0.06)(1)
I=9,000
R= 6% or 0.06
T= 1, 6, 21
Find: I=?
EXAMPLE 2
P= 150,000
If cristina borrowed Php150,000 from wally, if cristina agreed to pay 6% annually interest
rate calculate the amount of interest she must pay if the pay loan period is: One year, 6
months and 21 months
GIVEN: SOLUTION:
Formula: I=Prt
B. I=150,000(0.06)(6/12)
I=4,500
R= 6% or 0.06
T= 1, 6, 21
Find: I=?
EXAMPLE 2
P= 150,000
If cristina borrowed Php150,000 from wally, if cristina agreed to pay 6% annually interest
rate calculate the amount of interest she must pay if the pay loan period is: One year, 6
months and 21 months
GIVEN: SOLUTION:
Formula: I=Prt
C. I=150,000(0.06)(21/12)
I=15,750
R= 6% or 0.06
T= 1, 6, 21
Find: I=?
EXAMPLE 3
P= 9,000
Chester borrowed 9,000 at 12% interest for 3 years. Find the interest and the
maturity value.
GIVEN: SOLUTION:
Formula: I=Prt
I=9,000(0.12)(3)
I=3,240
R= 12% or 0.12
T= 3
Find: I=?
EXAMPLE 3
P= 9,000
Chester borrowed 9,000 at 12% interest for 3 years. Find the interest and the
maturity value.
GIVEN: SOLUTION:
Formula: F=P+I
I=9,000+3,240
I=12,340
R= 12% or 0.12
T= 3
Find: F=?
Actual Time and
Approximate Time
02
Actual Time
Number of days in a calendar for a month and February
is 28 days.
1 year = 365 days
Approximate Time
Number of days in a calendar assumes that each month
has 30 days.
1 year = 360 days
How To Find Actual Time and Approximate Time?
ACTUAL TIME
Get the actual time and approximate time from May 19, 2020 to
December 25, 2020
APPROXIMATE
TIME
Months
Year Days
12
2020 25
19
5
2020
May 31-19=12
June=30
July=31
Aug=31
Sept=30
Oct=31
Nov=30
Dec=25
7 6
x30
0
=210
+ 6 }216 days +
Actual Time
=220 days
How To Find Actual Time and Approximate Time?
Get the actual time and approximate time from October 20, 2018 to April
19, 2020
APPROXIMATE
TIME
Months
Year Days
4
2020 19
20
10
2018
1 month=30 days
1 year=12 months
19+30
49
20
3
3+12
2019
15
10
2019
2018
5 29
1
x30
=150
+ 29
1year
=360 days
}179+360
Approximate
Time
=539 days
How To Find Actual Time and Approximate Time?
ACTUAL TIME
Oct=31-20=11
Nov=30
Dec=30
Jan=31
Feb=28
Mar=31
Apr=30
May=31
June=30 April=19 +
Actual Time
=545 days
Get the actual time and approximate time from October 20, 2018 to April
19, 2020
July=31
August=31
Sept=30
Oct=31
Nov=30
Dec=31
Jan=31
Feb=28
Mar=31
Ordinary Interest
and
Exact Interest
03
Ordinary Interest
Ordinary simple interest is a simple interest that uses
360 days as the equivalent number of days in a year.
Exact Interest
Exact simple interest is a simple interest that uses exact
number of days in a year which is 365 (or 366 for leap
year).
FORMULA FOR ORDINARY INTEREST
Io= P × r × D/360
FORMULA FOR EXACT INTEREST
Ie= P × r × D/365
P-Principal
r- rate or the percentage
D- time expressed in days
EXAMPLE 1
P= 8,000
Find the exact interest and ordinary interest given the following
values, P8,000 for 120 days at 5%
GIVEN: SOLUTION:
Formula: P × r × D/360
Io=8,000(0.05)(120/360)
R= 5% or 0.05
T= 120
Find: Io=?
Io=4,000(⅓)
Io=1,333
EXAMPLE 1
P= 8,000
Find the exact interest and ordinary interest given the following
values, P8,000 for 120 days at 5%
GIVEN: SOLUTION:
Formula: P × r × D/365
Ie=8,000(0.05)(120/365)
R= 5% or 0.05
T= 120
Find: Ie=?
Ie=4,000(24/73)
Ie=1,315
Example 2
ACTUAL TIME
A loan of php 6,700 was made last march 10, 2020 and is to be paid in oct 13, 2020 if the interest
rate is 6% compute the following
a)ordinary interest using approximate and actual time
b)exact interest using approximate and actual time
APPROXIMATE
TIME
Months
Year Days
10
2020 13
10
3
2020
Mar 31-10=21
Apr=30
May=31
June=30
July=31
Aug=31
Sept=30
Oct=13
7 3
x30
0
=210
+ 3 }213 days +
Actual Time
=217 days
EXAMPLE 2
P= 6,700
GIVEN: SOLUTION:
Formula: P × r × D/360
Io=6,700(0.06)(213/360)
R= 6% or 0.06
Approximate=213 days
Find: Io=?(approximate)
Io=402(213/360)
Io=237.85
A loan of php 6,700 was made last march 10, 2020 and is to be paid in oct 13, 2020 if the interest
rate is 6% compute the following
a)ordinary interest using approximate and actual time
b)exact interest using approximate and actual time
Actual=217 days
EXAMPLE 2
P= 6,700
GIVEN: SOLUTION:
Formula: P × r × D/360
Io=6,700(0.06)(217/360)
R= 6% or 0.06
Approximate=213 days
Find: Io=?(actual)
Io=402(217/360)
Io=242.31
A loan of php 6,700 was made last march 10, 2020 and is to be paid in oct 13, 2020 if the interest
rate is 6% compute the following
a)ordinary interest using approximate and actual time
b)exact interest using approximate and actual time
Actual=217 days
EXAMPLE 2
P= 6,700
GIVEN: SOLUTION:
Formula: P × r × D/365
Ie=6,700(0.06)(213/365)
R= 6% or 0.06
Approximate=213 days
Find: Ie=?(approximate)
Ie=402(213/365)
Ie=234.59
A loan of php 6,700 was made last march 10, 2020 and is to be paid in oct 13, 2020 if the interest
rate is 6% compute the following
a)ordinary interest using approximate and actual time
b)exact interest using approximate and actual time
Actual=217 days
EXAMPLE 2
P= 6,700
GIVEN: SOLUTION:
Formula: P × r × D/365
Ie=6,700(0.06)(217/365)
R= 6% or 0.06
Approximate=213 days
Find: Ie=?(actual)
Ie=402(217/365)
Ie=238.99 or 239
A loan of php 6,700 was made last march 10, 2020 and is to be paid in oct 13, 2020 if the interest
rate is 6% compute the following
a)ordinary interest using approximate and actual time
b)exact interest using approximate and actual time
Actual=217 days
THANKYOU
FOR
LISTENING!
Any questions?

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SIMPLE INTEREST (1).pptx

  • 1. GUESS THE JUMBLED WORD MISLEP TESTREIN
  • 2. GUESS THE JUMBLED WORD MISLEP TESTREIN SIMPLE INTEREST
  • 3. GUESS THE JUMBLED WORD XIATEMROXPPA
  • 4. GUESS THE JUMBLED WORD APPROXIMATE XIATEMROXPPA
  • 5. GUESS THE JUMBLED WORD MITE
  • 6. GUESS THE JUMBLED WORD TIME MITE
  • 7. GUESS THE JUMBLED WORD LUTACA
  • 8. GUESS THE JUMBLED WORD ACTUAL LUTACA
  • 9. GUESS THE JUMBLED WORD DINARORY
  • 10. GUESS THE JUMBLED WORD ORDINARY DINARORY
  • 11. GUESS THE JUMBLED WORD XATEC
  • 12. GUESS THE JUMBLED WORD EXACT XATEC
  • 14. LESSON OBJECTIVES At the end of the lesson, students should be able to: 1. Explain the role interest plays in a loan transaction; 2. compute the interest due on a loan; 3. find the maturity value on a loan or the future value on invested capital; 4. differentiate ordinary interest and exact interest, and be able to compute for the same; 5. compute for the actual time and approximate time; 6. use the knowledge in (4) and (5), and compute for the four different types of simple interest 7. be conversant with the 60-day 6% method of computing simple interest; and 8. explain the concept of promissory note
  • 15. SIMPLE INTEREST In business, capital is very important. However, not all business owners always have enough capital to sustain their business. More often than not, they have to borrow money for use in the business. It is in this context that interests plays an important role. Borrowers need to pay interest on the money that they borrow.
  • 16. REPORTER 1 Athea Keisha G. Geocallo REPORTER 3 Joshua Gentolia REPORTER 2 Liezell Joy Patenio REPORTER 4 Raileyice Cal MEET THE TEAM!
  • 18. Simple Interest Simple interest is a quick and easy method of calculating the interest charge on a loan. Simple interest is determined by multiplying the daily interest rate by the principal by the number of days that elapse between payments.
  • 19. Basic formula to compute Simple Interest I=Prt I - Interest (amount paid for the use of money) P - Principal (amount borrowed/lent/invested) r - rate (percent of interest being changed) t - time (number of periods for which the money will be borrowed/lent/invested)
  • 20. The rate and the time should always agree, that is, if rate is per annum, time should be in years, if rate is per month, time should be in months; and if rate is per day; time should be in days. In the absence of stipulation to the contrary, a stated rate of interest is understood to be on a per annum or annual basis. Maturity value or value F Formula F=P+I
  • 21. IF WE SUBSTITUTE OUR BASIC FORMULA FOR INTEREST IN FORMULA 2, WE WILL HAVE: F=P+I F=P+Prt F=P(I+rt)
  • 22. EXAMPLE 1 P= 2,000 Tessa borrowed 2,000 at 12% interest rate for 2 years, find the interest and maturity value. GIVEN: SOLUTION: Formula: I=Prt I=2,000(0.12)(2) I=240(2) I=480 R= 12% OR 0.12 T= 2 Find: I=?
  • 23. EXAMPLE 1 P= 2,000 Tessa borrowed 2,000 at 12 % interest rate for 2 years, find the interest and maturity value. GIVEN: SOLUTION: Formula: F=P+I F=2,000+480 F=2,480 R= 12% OR 0.12 T= 2 Find: F=?
  • 24. EXAMPLE 2 P= 150,000 If cristina borrowed Php150,000 from wally, if cristina agreed to pay 6% annually interest rate calculate the amount of interest she must pay if the pay loan period is: One year, 6 months and 21 months GIVEN: SOLUTION: Formula: I=Prt A. I=150,000(0.06)(1) I=9,000 R= 6% or 0.06 T= 1, 6, 21 Find: I=?
  • 25. EXAMPLE 2 P= 150,000 If cristina borrowed Php150,000 from wally, if cristina agreed to pay 6% annually interest rate calculate the amount of interest she must pay if the pay loan period is: One year, 6 months and 21 months GIVEN: SOLUTION: Formula: I=Prt B. I=150,000(0.06)(6/12) I=4,500 R= 6% or 0.06 T= 1, 6, 21 Find: I=?
  • 26.
  • 27.
  • 28. EXAMPLE 2 P= 150,000 If cristina borrowed Php150,000 from wally, if cristina agreed to pay 6% annually interest rate calculate the amount of interest she must pay if the pay loan period is: One year, 6 months and 21 months GIVEN: SOLUTION: Formula: I=Prt C. I=150,000(0.06)(21/12) I=15,750 R= 6% or 0.06 T= 1, 6, 21 Find: I=?
  • 29. EXAMPLE 3 P= 9,000 Chester borrowed 9,000 at 12% interest for 3 years. Find the interest and the maturity value. GIVEN: SOLUTION: Formula: I=Prt I=9,000(0.12)(3) I=3,240 R= 12% or 0.12 T= 3 Find: I=?
  • 30. EXAMPLE 3 P= 9,000 Chester borrowed 9,000 at 12% interest for 3 years. Find the interest and the maturity value. GIVEN: SOLUTION: Formula: F=P+I I=9,000+3,240 I=12,340 R= 12% or 0.12 T= 3 Find: F=?
  • 32. Actual Time Number of days in a calendar for a month and February is 28 days. 1 year = 365 days Approximate Time Number of days in a calendar assumes that each month has 30 days. 1 year = 360 days
  • 33. How To Find Actual Time and Approximate Time? ACTUAL TIME Get the actual time and approximate time from May 19, 2020 to December 25, 2020 APPROXIMATE TIME Months Year Days 12 2020 25 19 5 2020 May 31-19=12 June=30 July=31 Aug=31 Sept=30 Oct=31 Nov=30 Dec=25 7 6 x30 0 =210 + 6 }216 days + Actual Time =220 days
  • 34. How To Find Actual Time and Approximate Time? Get the actual time and approximate time from October 20, 2018 to April 19, 2020 APPROXIMATE TIME Months Year Days 4 2020 19 20 10 2018 1 month=30 days 1 year=12 months 19+30 49 20 3 3+12 2019 15 10 2019 2018 5 29 1 x30 =150 + 29 1year =360 days }179+360 Approximate Time =539 days
  • 35. How To Find Actual Time and Approximate Time? ACTUAL TIME Oct=31-20=11 Nov=30 Dec=30 Jan=31 Feb=28 Mar=31 Apr=30 May=31 June=30 April=19 + Actual Time =545 days Get the actual time and approximate time from October 20, 2018 to April 19, 2020 July=31 August=31 Sept=30 Oct=31 Nov=30 Dec=31 Jan=31 Feb=28 Mar=31
  • 37. Ordinary Interest Ordinary simple interest is a simple interest that uses 360 days as the equivalent number of days in a year. Exact Interest Exact simple interest is a simple interest that uses exact number of days in a year which is 365 (or 366 for leap year).
  • 38. FORMULA FOR ORDINARY INTEREST Io= P × r × D/360 FORMULA FOR EXACT INTEREST Ie= P × r × D/365 P-Principal r- rate or the percentage D- time expressed in days
  • 39. EXAMPLE 1 P= 8,000 Find the exact interest and ordinary interest given the following values, P8,000 for 120 days at 5% GIVEN: SOLUTION: Formula: P × r × D/360 Io=8,000(0.05)(120/360) R= 5% or 0.05 T= 120 Find: Io=? Io=4,000(⅓) Io=1,333
  • 40. EXAMPLE 1 P= 8,000 Find the exact interest and ordinary interest given the following values, P8,000 for 120 days at 5% GIVEN: SOLUTION: Formula: P × r × D/365 Ie=8,000(0.05)(120/365) R= 5% or 0.05 T= 120 Find: Ie=? Ie=4,000(24/73) Ie=1,315
  • 41. Example 2 ACTUAL TIME A loan of php 6,700 was made last march 10, 2020 and is to be paid in oct 13, 2020 if the interest rate is 6% compute the following a)ordinary interest using approximate and actual time b)exact interest using approximate and actual time APPROXIMATE TIME Months Year Days 10 2020 13 10 3 2020 Mar 31-10=21 Apr=30 May=31 June=30 July=31 Aug=31 Sept=30 Oct=13 7 3 x30 0 =210 + 3 }213 days + Actual Time =217 days
  • 42. EXAMPLE 2 P= 6,700 GIVEN: SOLUTION: Formula: P × r × D/360 Io=6,700(0.06)(213/360) R= 6% or 0.06 Approximate=213 days Find: Io=?(approximate) Io=402(213/360) Io=237.85 A loan of php 6,700 was made last march 10, 2020 and is to be paid in oct 13, 2020 if the interest rate is 6% compute the following a)ordinary interest using approximate and actual time b)exact interest using approximate and actual time Actual=217 days
  • 43. EXAMPLE 2 P= 6,700 GIVEN: SOLUTION: Formula: P × r × D/360 Io=6,700(0.06)(217/360) R= 6% or 0.06 Approximate=213 days Find: Io=?(actual) Io=402(217/360) Io=242.31 A loan of php 6,700 was made last march 10, 2020 and is to be paid in oct 13, 2020 if the interest rate is 6% compute the following a)ordinary interest using approximate and actual time b)exact interest using approximate and actual time Actual=217 days
  • 44. EXAMPLE 2 P= 6,700 GIVEN: SOLUTION: Formula: P × r × D/365 Ie=6,700(0.06)(213/365) R= 6% or 0.06 Approximate=213 days Find: Ie=?(approximate) Ie=402(213/365) Ie=234.59 A loan of php 6,700 was made last march 10, 2020 and is to be paid in oct 13, 2020 if the interest rate is 6% compute the following a)ordinary interest using approximate and actual time b)exact interest using approximate and actual time Actual=217 days
  • 45. EXAMPLE 2 P= 6,700 GIVEN: SOLUTION: Formula: P × r × D/365 Ie=6,700(0.06)(217/365) R= 6% or 0.06 Approximate=213 days Find: Ie=?(actual) Ie=402(217/365) Ie=238.99 or 239 A loan of php 6,700 was made last march 10, 2020 and is to be paid in oct 13, 2020 if the interest rate is 6% compute the following a)ordinary interest using approximate and actual time b)exact interest using approximate and actual time Actual=217 days