Silas, Cole, and Addison are on the same Learning Team at UOP. If each worked on the team assignments alone, it would take Silas 10 hours, Cole 8 hours, and Addison 12 hours to finish the assignments. They usually started the same time on Monday night after work. But last week, Silas started early and he had worked for 2 hours on the assignments when Cole and Addison began. Later, all three finished the team assignments. How long did they take to finish by working together? Solution In one hour Silas would finish 1/10th work In two hours Silas would finish 2/10th work Remaining (1-2/10) = 8/10th work is finished by all of them If all of them started at same time the would finish the entire work in 1/(1/10+1/8+1/12) =1/(80+120+96)/960 =960/296days 0.8 work they finish in 960*0.8/296 days 768/296 In one hour Silas would finish 1/10th work In two hours Silas would finish 2/10th work Remaining (1-2/10) = 8/10th work is finished by all of them If all of them started at same time the would finish the entire work in 1/(1/10+1/8+1/12) =1/(80+120+96)/960 =960/296days 0.8 work they finish in 960*0.8/296 days 768/296.