Scrapie is a degenerative disease of the nervous system. A study of t.pdf
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Scrapie is a degenerative disease of the nervous system. A study of the substance IDX as a treatment for scrapie used as subjects 16 infected hamsters. Eight, chosen at random, were injected with IDX. The other 8 were untreated. The researchers recorded how long each hamster lived. They reported: Thus, although all infected control hamsters had died by 94 days after infection (mean SEM=87.91.8), IDX-treated hamsters lived up to 114 days (mean SEM=106.22.62 ). Readers are supposed to know that SEM stands for the standard error of the mean. (a) For the group injected with IDX , find: The mean, x= The standard deviation, s= (b) For the untreated group, find: The mean, x= The standard deviation, s=.
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public class SLL {
private class SLLNode {
private T info;
private SLLNode next;
public SLLNode() {
this(null,null);
}
public SLLNode(T el) {
this(el,null);
}
public SLLNode(T el, SLLNode ptr) {
info = el; next = ptr;
}
}
protected SLLNode head, tail;
public SLL() {
head = tail = null;
}
public boolean isEmpty() {
return head == null;
}
public void addToHead(T el) {
head = new SLLNode(el,head);
if (tail == null)
tail = head;
}
public void addToTail(T el) {
if (!isEmpty()) {
tail.next = new SLLNode(el);
tail = tail.next;
}
else head = tail = new SLLNode(el);
}
public T deleteFromHead() { // delete the head and return its info;
if (isEmpty())
return null;
T el = head.info;
if (head == tail) // if only one node on the list;
head = tail = null;
else head = head.next;
return el;
}
public T deleteFromTail() { // delete the tail and return its info;
if (isEmpty())
return null;
T el = tail.info;
if (head == tail) // if only one node in the list;
head = tail = null;
else { // if more than one node in the list,
SLLNode tmp; // find the predecessor of tail;
for (tmp = head; tmp.next != tail; tmp = tmp.next);
tail = tmp; // the predecessor of tail becomes tail;
tail.next = null;
}
return el;
}
public void delete(T el) { // delete the node with an element el;
if (!isEmpty())
if (head == tail && el.equals(head.info)) // if only one
head = tail = null; // node on the list;
else if (el.equals(head.info)) // if more than one node on the list;
head = head.next; // and el is in the head node;
else { // if more than one node in the list
SLLNode pred, tmp;// and el is in a nonhead node;
for (pred = head, tmp = head.next;
tmp != null && !tmp.info.equals(el);
pred = pred.next, tmp = tmp.next);
if (tmp != null) { // if el was found;
pred.next = tmp.next;
if (tmp == tail) // if el is in the last node;
tail = pred;
}
}
}
@Override
public String toString() {
if(head == null)
return "[ ]";
String str = "[ ";
SLLNode tmp = head;
while(tmp != null){
str += tmp.info + " ";
tmp = tmp.next;
}
return str+"]";
}
public boolean contains(T el) {
if(head == null)
return false;
SLLNode tmp = head;
while(tmp != null){
if(tmp.info.equals(el))
return true;
tmp = tmp.next;
}
return false;
}
public int size(){
if(head == null)
return 0;
int count = 0;
SLLNode p = head;
while(p != null) {
count++;
p = p.next;
}
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times remain similar, then the number of neutral molecular differences between two taxa should
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diverged. Although the possibility of dating events from estimates of genetic divergence is
tantalizing, there are several important caveats. For example, it is critical to realize that the
mutation rate to neutral alleles will vary from gene to gene and lineage to lineage, and even from
base to base. For reasons explained in another chapter, silent site changes in the third positions of
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allele frequencies change rapidly due to strong selection at a particular gene, it is unlikely that
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Solve using java and using this Singly linked list class:
public class SLL {
private class SLLNode {
private T info;
private SLLNode next;
public SLLNode() {
this(null,null);
}
public SLLNode(T el) {
this(el,null);
}
public SLLNode(T el, SLLNode ptr) {
info = el; next = ptr;
}
}
protected SLLNode head, tail;
public SLL() {
head = tail = null;
}
public boolean isEmpty() {
return head == null;
}
public void addToHead(T el) {
head = new SLLNode(el,head);
if (tail == null)
tail = head;
}
public void addToTail(T el) {
if (!isEmpty()) {
tail.next = new SLLNode(el);
tail = tail.next;
}
else head = tail = new SLLNode(el);
}
public T deleteFromHead() { // delete the head and return its info;
if (isEmpty())
return null;
T el = head.info;
if (head == tail) // if only one node on the list;
head = tail = null;
else head = head.next;
return el;
}
public T deleteFromTail() { // delete the tail and return its info;
if (isEmpty())
return null;
T el = tail.info;
if (head == tail) // if only one node in the list;
head = tail = null;
else { // if more than one node in the list,
SLLNode tmp; // find the predecessor of tail;
for (tmp = head; tmp.next != tail; tmp = tmp.next);
tail = tmp; // the predecessor of tail becomes tail;
tail.next = null;
}
return el;
}
public void delete(T el) { // delete the node with an element el;
if (!isEmpty())
if (head == tail && el.equals(head.info)) // if only one
head = tail = null; // node on the list;
else if (el.equals(head.info)) // if more than one node on the list;
head = head.next; // and el is in the head node;
else { // if more than one node in the list
SLLNode pred, tmp;// and el is in a nonhead node;
for (pred = head, tmp = head.next;
tmp != null && !tmp.info.equals(el);
pred = pred.next, tmp = tmp.next);
if (tmp != null) { // if el was found;
pred.next = tmp.next;
if (tmp == tail) // if el is in the last node;
tail = pred;
}
}
}
@Override
public String toString() {
if(head == null)
return "[ ]";
String str = "[ ";
SLLNode tmp = head;
while(tmp != null){
str += tmp.info + " ";
tmp = tmp.next;
}
return str+"]";
}
public boolean contains(T el) {
if(head == null)
return false;
SLLNode tmp = head;
while(tmp != null){
if(tmp.info.equals(el))
return true;
tmp = tmp.next;
}
return false;
}
public int size(){
if(head == null)
return 0;
int count = 0;
SLLNode p = head;
while(p != null) {
count++;
p = p.next;
}
return count;
}
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fashion. Many mutations change an individual's DNA but not its phenotype In most cases,
mutations like these are not exposed to natural selection. Instead, these neutral @ changes evolve
by a random process called genetic drift As we will discuss elsewhere, the neutral theory of
molecular evolution predicts that neutral changes in DNA should accumulate in populations at a
rate equal to the mutation rate If the mutation rate stays reasonably constant, and if generation
times remain similar, then the number of neutral molecular differences between two taxa should
be proportional to the age of their most recent common ancestor By counting distinct neutral
mutations observed in two species and multiplying by a calibration rate representing how
frequently neutral changes occur per million years, researchers can estimate when the species
diverged. Although the possibility of dating events from estimates of genetic divergence is
tantalizing, there are several important caveats. For example, it is critical to realize that the
mutation rate to neutral alleles will vary from gene to gene and lineage to lineage, and even from
base to base. For reasons explained in another chapter, silent site changes in the third positions of
codons are more likely to be neutral with respect to fitness, and thus to accumulate at a clocklike
rate, than replacement changes that occur at the first and second positions in codons. And if
allele frequencies change rapidly due to strong selection at a particular gene, it is unlikely that
the mutations involved are accumulating in a clocklike fashion. Finally rates of change calibrated
for a particular gene and lineage are unlikely to work for other groups, which may have different
generation times and selection histories (Martin et al. 1992; Martin and Palumbi 1993; Hillis et
al. 1996). Even if clocklike change occurs in a particular gene and lineage, how can the rate be
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A
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Archaea Membrane-bound nucleus Protostome development
B
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
C
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Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
D
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
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Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
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Archaea Membrane-bound nucleus Protostome development
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Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
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// Chapter 7 Validate Password
import java.util.*;
public class ch7
{
public static void main(String[] args)
{
// Define variables
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String userPassword; // for input
int userPasswordLength;
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least 2 Please enter password >> coast2 The password was invalid. It did not have enough of the
following: Please enter password cCoastz Valid password.
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comments and explanations to them to sort the list elements from high to low value. The index
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JAVA programs), the two modified programs to sort the values from high to low value for
selection and insertion sorts, and the results for the modified programs.
This program uses the selection sort algorithm to sort an array. The code has been modified to
also calculate how many item comparisons are done. You can try running the program with
different arrays to see how the total number of comparisons changes (or doesn't change).
CODE 3.3 ---
import java.util.Arrays;
public class SelectionSortDemo {
private static int selectionSort(int[] numbers) {
// A variable to hold the number of item comparisons
int comparisons = 0;
for (int i = 0; i < numbers.length - 1; i++) {
// Find index of smallest remaining element
int indexSmallest = i;
for (int j = i + 1; j < numbers.length; j++) {
comparisons++;
if (numbers[j] < numbers[indexSmallest]) {
indexSmallest = j;
}
}
// Swap numbers[i] and numbers[indexSmallest]
int temp = numbers[i];
numbers[i] = numbers[indexSmallest];
numbers[indexSmallest] = temp;
}
return comparisons;
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the selectionSort method
int comparisons = selectionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
System.out.println("Total comparisons: " + comparisons);
}
}
CODE 3.5 ---
import java.util.Arrays;
public class InsertionSortDemo {
private static void insertionSort(int[] numbers) {
for (int i = 1; i < numbers.length; i++) {
int j = i;
while (j > 0 && numbers[j] < numbers[j - 1]) {
// Swap numbers[j] and numbers [j - 1]
int temp = numbers[j];
numbers[j] = numbers[j - 1];
numbers[j - 1] = temp;
j--;
}
}
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the insertionSort method
insertionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
}
}.
step by step in detail on how to configure a firewall that blocks in.pdf
step by step in detail on how to configure a firewall that blocks incoming traffic to the server.
that is set up on a router..
Step 1 Implement the getSortedRunLength() methodImplement the get.pdf
Step 1: Implement the getSortedRunLength() method
Implement the getSortedRunLength() method in NaturalMergeSorter.java. Access
NaturalMergeSorter.java by clicking on the orange arrow next to NaturalMerge.java at the top of
the coding window.
getSortedRunLength() has three parameters:
array: a reference to an array of integers,
arrayLength: an integer for the array's length, and
startIndex: an integer for the run's starting index.
The method returns the number of array elements sorted in ascending order, starting at startIndex
and ending either at the end of the sorted run, or the end of the array, whichever comes first. The
method returns 0 if startIndex is out of bounds.
File NaturalMerge.java has several test cases for getSortedRunLength() that can be run by
clicking the "Run program" button. One test case also exists for naturalMergeSort(), but that can
be ignored until step two is completed.
The program's output does not affect grading.
Submit for grading to ensure that the getSortedRunLength() unit tests pass before proceeding.
Step 2: Implement the naturalMergeSort() method
Implement the naturalMergeSort() method in NaturalMergeSorter.java. naturalMergeSort() must:
Start at index i=0
Get the length of the first sorted run, starting at i
Return if the first run's length equals the array length
If the first run ends at the array's end, reassign i=0 and repeat step 2
Get the length of the second sorted run, starting immediately after the first
Merge the two runs with the provided merge() method
Reassign i with the first index after the second run, or 0 if the second run ends at the array's end
Go to step 2
NaturalMergeSorter.java
public class NaturalMergeSorter {
public static int getSortedRunLength(int[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
} else {
break;
}
}
return length;
}
public static int getSortedRunLength(double[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
} else {
break;
}
}
return length;
}
public static void naturalMergeSort(int[] array, int arrayLength) {
int i = 0;
while (i < arrayLength) {
int firstRunLength = getSortedRunLength(array, arrayLength, i);
if (firstRunLength == arrayLength) {
return;
}
int secondRunLength = getSortedRunLength(array, arrayLength, i + firstRunLength);
merge(array, i, i + firstRunLength - 1, i + firstRunLength + secondRunLength - 1);
if (i + firstRunLength + secondRunLength == arrayLength) {
i = 0;
} else {
i = i + firstRunLength + secondRunLength;
}
}
}
public static void naturalMergeSort(double[] array, int arrayLength) {
int i = 0;
while (i < arrayLength) {
int firstRunLength = getSortedRunLength(array, arrayLength, i);
if (firstRunLength == arrayLen.
STATs areA. Cytoplasmic transcription activators that are activat.pdf
STATs are:
A. Cytoplasmic transcription activators that are activated by dephosphorylation of an inactive
complex
B. Are activated by a tyrosine kinase complex that is found in the nucleus
C. Extracellular ligands that stimulate T-cell differentiation.
D. Are activated by a cytoplasmic tyrosine kinase complex that results in phosphorylation and
dimerization of the phosphorylated STATs that can now enter the nucleus.
Stats project question In a study conducted by Zogby Internati.pdf
Stats project question
In a study conducted by Zogby International for the Democrat and Chronicle, more than 700
New Yorkers were polled to determine whether the New York state government works,
Respondents surveyed were asked questions involving pay cuts for state legis-lators, restrictions
on lobbyists. term limits for legislators, and whether state citizens should be able to put matters
directly on the state ballot for a vote. The results regarding lines.
several proposed reforms had broad support, crossing all demographic and political New. York
was conducted. The part y athliation (Democrat, Independent, Republican) of Suppose that a
follow -up survey of 100 individuals who live in the western region of
each individual surveyed was recorded, as well as their responses to the following three
questions
I. Should legislative pay be cut for every day the state budget is late?
2. Should there be more restrictions on lobbyists?
Yes
No
Yes
.
No
Should there be term limits requiring that legislators serve a fixed number of years?
Yes
No
Managerial Report
1. Use descriptive statistic
irize the data from this study. What are your prelimi-
nary conclusions abor
adence of the response (Yes or No) and party affilia-
tion for each of the three
in the survey?
2. With regard to question 1, test for the independence of the response (Yes and No) and party
affiliation. Use a =
0.5
3. With regard to question 2, test for the independence of the response (Yes and No) and
party affiliation. Use a = 05
4. With regard to question 3, test for the independence of the response (Yes and No) and
party affiliation. Use a = 05.
5. Does it appear that there is broad support for change across all political lines? Explain..
Spotify es un servicio de transmisi�n de m�sica utilizado por m�s de.pdf
Spotify es un servicio de transmisin de msica utilizado por ms de 200 millones de usuarios en
todo el mundo. Spotify ofrece una versin gratuita que proporciona transmisin bsica e incluye
anuncios. Tambin ofrecen Spotify Premium por una tarifa mensual que brinda a los usuarios
audio de mayor calidad, descargas de canciones y sin anuncios.
Ofrecer msica como un servicio de suscripcin en lugar de algo que compras y posees es un
nuevo modelo para la industria de la msica, pero est creciendo rpidamente. Otros competidores
incluyen Apple Music y Pandora. Veamos algunos aspectos nicos de este modelo:
Dado que las tasas de regalas son ms bajas para la transmisin, artistas como Taylor Swift y
AC/DC inicialmente se negaron a ofrecer su msica en el servicio. Pero a medida que Spotify ha
crecido, los artistas ven cada vez ms el beneficio de que sus canciones se transmitan en el
servicio.
Los 100 millones de clientes que usan Spotify Premium pueden descargar canciones y
escucharlas en lnea. Sin embargo, si cancelan el servicio, esas descargas ya no estn disponibles.
Spotify ofrece planes familiares y para estudiantes con un precio para mltiples usuarios. El
precio de estos planes representa un descuento significativo en comparacin con tener varias
cuentas individuales.
Debido a que Spotify puede realizar un seguimiento de la msica que escucha, puede ofrecer
promociones especiales, como entradas de conciertos premium para los artistas que disfruta.
R. Si Spotify anunciara que puedes escuchar "cualquier cancin", pero descubriste que Taylor
Swift no estaba en el servicio, este sera un ejemplo de qu brecha en la calidad del servicio?
brecha 3
brecha 1
brecha 2
brecha 4
B. Suponga que un suscriptor de Spotify Premium descarg una lista de reproduccin en su telfono
pero nunca escuch las canciones. Luego cancelaron su suscripcin y se sintieron decepcionados al
descubrir que sus canciones ya no estaban disponibles en su telfono. El hecho de que el
consumidor solo pudiera escuchar esas canciones cuando estaba suscrito activamente al servicio
demuestra qu caracterstica distingue a los productos de los bienes.
Estrategia para colocar precios
Fiabilidad
caducidad
Heterogeneidad
C. Al ofrecer descuentos en los precios, crear conexiones sociales, ofrecer personalizacin y
ofrecer servicios de valor agregado, como asientos premium en eventos, Spotify est demostrando
qu nivel de marketing relacional para los servicios.
Nivel 4
Nivel 3
Nivel 1
Nivel 2.
State the degrees of freedom used in this test Write the formula .pdf
State the degrees of freedom used in this test?
Write the formula for the pooled variance and interpret it.
What is the formula for the test statistic? Unknown Variances, Assumed Equal
tcalc=n1sp2+n2sp2where(x1x2)sp2=n1+n22(n11)s12+(n21)s22 For critical value, use Student's
twith d.f. =n1+n22.
Short Answer Identify the 4 Main Animal Tissue Types (Connective, Ne.pdf
Short Answer: Identify the 4 Main Animal Tissue Types (Connective, Nervous, Epithelial,
Muscle) 4. Which type of tissue includes bones, blood and cushions and binds? 5. Which type of
tissue produces voluntary and involuntary movements by contracting? 6. Which type of tissue
lines internal surfaces and secretes mucus, enzymes, and hormones? 7. Which type of tissue
consists of neurons and receives and transmits chemical and electrical impulses?.
Unit 8 - Information and Communication Technology (Paper I).pdf
This slides describes the basic concepts of ICT, basics of Email, Emerging Technology and Digital Initiatives in Education. This presentations aligns with the UGC Paper I syllabus.
Acetabularia Information For Class 9 .docx
Acetabularia acetabulum is a single-celled green alga that in its vegetative state is morphologically differentiated into a basal rhizoid and an axially elongated stalk, which bears whorls of branching hairs. The single diploid nucleus resides in the rhizoid.
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CODE 3.3 ---
import java.util.Arrays;
public class SelectionSortDemo {
private static int selectionSort(int[] numbers) {
// A variable to hold the number of item comparisons
int comparisons = 0;
for (int i = 0; i < numbers.length - 1; i++) {
// Find index of smallest remaining element
int indexSmallest = i;
for (int j = i + 1; j < numbers.length; j++) {
comparisons++;
if (numbers[j] < numbers[indexSmallest]) {
indexSmallest = j;
}
}
// Swap numbers[i] and numbers[indexSmallest]
int temp = numbers[i];
numbers[i] = numbers[indexSmallest];
numbers[indexSmallest] = temp;
}
return comparisons;
}
public static void main(String[] args) {
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int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the selectionSort method
int comparisons = selectionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
System.out.println("Total comparisons: " + comparisons);
}
}
CODE 3.5 ---
import java.util.Arrays;
public class InsertionSortDemo {
private static void insertionSort(int[] numbers) {
for (int i = 1; i < numbers.length; i++) {
int j = i;
while (j > 0 && numbers[j] < numbers[j - 1]) {
// Swap numbers[j] and numbers [j - 1]
int temp = numbers[j];
numbers[j] = numbers[j - 1];
numbers[j - 1] = temp;
j--;
}
}
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the insertionSort method
insertionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
}
}.
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Step 1 Implement the getSortedRunLength() methodImplement the get.pdf
Step 1: Implement the getSortedRunLength() method
Implement the getSortedRunLength() method in NaturalMergeSorter.java. Access
NaturalMergeSorter.java by clicking on the orange arrow next to NaturalMerge.java at the top of
the coding window.
getSortedRunLength() has three parameters:
array: a reference to an array of integers,
arrayLength: an integer for the array's length, and
startIndex: an integer for the run's starting index.
The method returns the number of array elements sorted in ascending order, starting at startIndex
and ending either at the end of the sorted run, or the end of the array, whichever comes first. The
method returns 0 if startIndex is out of bounds.
File NaturalMerge.java has several test cases for getSortedRunLength() that can be run by
clicking the "Run program" button. One test case also exists for naturalMergeSort(), but that can
be ignored until step two is completed.
The program's output does not affect grading.
Submit for grading to ensure that the getSortedRunLength() unit tests pass before proceeding.
Step 2: Implement the naturalMergeSort() method
Implement the naturalMergeSort() method in NaturalMergeSorter.java. naturalMergeSort() must:
Start at index i=0
Get the length of the first sorted run, starting at i
Return if the first run's length equals the array length
If the first run ends at the array's end, reassign i=0 and repeat step 2
Get the length of the second sorted run, starting immediately after the first
Merge the two runs with the provided merge() method
Reassign i with the first index after the second run, or 0 if the second run ends at the array's end
Go to step 2
NaturalMergeSorter.java
public class NaturalMergeSorter {
public static int getSortedRunLength(int[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
} else {
break;
}
}
return length;
}
public static int getSortedRunLength(double[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
} else {
break;
}
}
return length;
}
public static void naturalMergeSort(int[] array, int arrayLength) {
int i = 0;
while (i < arrayLength) {
int firstRunLength = getSortedRunLength(array, arrayLength, i);
if (firstRunLength == arrayLength) {
return;
}
int secondRunLength = getSortedRunLength(array, arrayLength, i + firstRunLength);
merge(array, i, i + firstRunLength - 1, i + firstRunLength + secondRunLength - 1);
if (i + firstRunLength + secondRunLength == arrayLength) {
i = 0;
} else {
i = i + firstRunLength + secondRunLength;
}
}
}
public static void naturalMergeSort(double[] array, int arrayLength) {
int i = 0;
while (i < arrayLength) {
int firstRunLength = getSortedRunLength(array, arrayLength, i);
if (firstRunLength == arrayLen.
STATs areA. Cytoplasmic transcription activators that are activat.pdf
STATs are:
A. Cytoplasmic transcription activators that are activated by dephosphorylation of an inactive
complex
B. Are activated by a tyrosine kinase complex that is found in the nucleus
C. Extracellular ligands that stimulate T-cell differentiation.
D. Are activated by a cytoplasmic tyrosine kinase complex that results in phosphorylation and
dimerization of the phosphorylated STATs that can now enter the nucleus.
Stats project question In a study conducted by Zogby Internati.pdf
Stats project question
In a study conducted by Zogby International for the Democrat and Chronicle, more than 700
New Yorkers were polled to determine whether the New York state government works,
Respondents surveyed were asked questions involving pay cuts for state legis-lators, restrictions
on lobbyists. term limits for legislators, and whether state citizens should be able to put matters
directly on the state ballot for a vote. The results regarding lines.
several proposed reforms had broad support, crossing all demographic and political New. York
was conducted. The part y athliation (Democrat, Independent, Republican) of Suppose that a
follow -up survey of 100 individuals who live in the western region of
each individual surveyed was recorded, as well as their responses to the following three
questions
I. Should legislative pay be cut for every day the state budget is late?
2. Should there be more restrictions on lobbyists?
Yes
No
Yes
.
No
Should there be term limits requiring that legislators serve a fixed number of years?
Yes
No
Managerial Report
1. Use descriptive statistic
irize the data from this study. What are your prelimi-
nary conclusions abor
adence of the response (Yes or No) and party affilia-
tion for each of the three
in the survey?
2. With regard to question 1, test for the independence of the response (Yes and No) and party
affiliation. Use a =
0.5
3. With regard to question 2, test for the independence of the response (Yes and No) and
party affiliation. Use a = 05
4. With regard to question 3, test for the independence of the response (Yes and No) and
party affiliation. Use a = 05.
5. Does it appear that there is broad support for change across all political lines? Explain..
Spotify es un servicio de transmisi�n de m�sica utilizado por m�s de.pdf
Spotify es un servicio de transmisin de msica utilizado por ms de 200 millones de usuarios en
todo el mundo. Spotify ofrece una versin gratuita que proporciona transmisin bsica e incluye
anuncios. Tambin ofrecen Spotify Premium por una tarifa mensual que brinda a los usuarios
audio de mayor calidad, descargas de canciones y sin anuncios.
Ofrecer msica como un servicio de suscripcin en lugar de algo que compras y posees es un
nuevo modelo para la industria de la msica, pero est creciendo rpidamente. Otros competidores
incluyen Apple Music y Pandora. Veamos algunos aspectos nicos de este modelo:
Dado que las tasas de regalas son ms bajas para la transmisin, artistas como Taylor Swift y
AC/DC inicialmente se negaron a ofrecer su msica en el servicio. Pero a medida que Spotify ha
crecido, los artistas ven cada vez ms el beneficio de que sus canciones se transmitan en el
servicio.
Los 100 millones de clientes que usan Spotify Premium pueden descargar canciones y
escucharlas en lnea. Sin embargo, si cancelan el servicio, esas descargas ya no estn disponibles.
Spotify ofrece planes familiares y para estudiantes con un precio para mltiples usuarios. El
precio de estos planes representa un descuento significativo en comparacin con tener varias
cuentas individuales.
Debido a que Spotify puede realizar un seguimiento de la msica que escucha, puede ofrecer
promociones especiales, como entradas de conciertos premium para los artistas que disfruta.
R. Si Spotify anunciara que puedes escuchar "cualquier cancin", pero descubriste que Taylor
Swift no estaba en el servicio, este sera un ejemplo de qu brecha en la calidad del servicio?
brecha 3
brecha 1
brecha 2
brecha 4
B. Suponga que un suscriptor de Spotify Premium descarg una lista de reproduccin en su telfono
pero nunca escuch las canciones. Luego cancelaron su suscripcin y se sintieron decepcionados al
descubrir que sus canciones ya no estaban disponibles en su telfono. El hecho de que el
consumidor solo pudiera escuchar esas canciones cuando estaba suscrito activamente al servicio
demuestra qu caracterstica distingue a los productos de los bienes.
Estrategia para colocar precios
Fiabilidad
caducidad
Heterogeneidad
C. Al ofrecer descuentos en los precios, crear conexiones sociales, ofrecer personalizacin y
ofrecer servicios de valor agregado, como asientos premium en eventos, Spotify est demostrando
qu nivel de marketing relacional para los servicios.
Nivel 4
Nivel 3
Nivel 1
Nivel 2.
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State the degrees of freedom used in this test?
Write the formula for the pooled variance and interpret it.
What is the formula for the test statistic? Unknown Variances, Assumed Equal
tcalc=n1sp2+n2sp2where(x1x2)sp2=n1+n22(n11)s12+(n21)s22 For critical value, use Student's
twith d.f. =n1+n22.
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