Subject Computer Architecture & Organization Q-4 Assume that .pdf
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Subject: Computer Architecture & Organization Q-4: Assume that you have a 32 bit data in a Register to and you are going to transfer the data using SW instruction to memory. (2.5 Marks) i. Which of the following memory addresses is appropriate to start storing the data. ii. Assume that you are using Big Endian Byte order to transfer the data. Show the data in the following memory locations. Swipe up for filters.
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Starware Software was founded last year to develop software for gaming applications. The
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$800,000
and received
11
million shares of stock. Starware now needs to raise a second round of capital, and it has
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$1.00
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24%
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Solve using java and using this Singly linked list class:
public class SLL {
private class SLLNode {
private T info;
private SLLNode next;
public SLLNode() {
this(null,null);
}
public SLLNode(T el) {
this(el,null);
}
public SLLNode(T el, SLLNode ptr) {
info = el; next = ptr;
}
}
protected SLLNode head, tail;
public SLL() {
head = tail = null;
}
public boolean isEmpty() {
return head == null;
}
public void addToHead(T el) {
head = new SLLNode(el,head);
if (tail == null)
tail = head;
}
public void addToTail(T el) {
if (!isEmpty()) {
tail.next = new SLLNode(el);
tail = tail.next;
}
else head = tail = new SLLNode(el);
}
public T deleteFromHead() { // delete the head and return its info;
if (isEmpty())
return null;
T el = head.info;
if (head == tail) // if only one node on the list;
head = tail = null;
else head = head.next;
return el;
}
public T deleteFromTail() { // delete the tail and return its info;
if (isEmpty())
return null;
T el = tail.info;
if (head == tail) // if only one node in the list;
head = tail = null;
else { // if more than one node in the list,
SLLNode tmp; // find the predecessor of tail;
for (tmp = head; tmp.next != tail; tmp = tmp.next);
tail = tmp; // the predecessor of tail becomes tail;
tail.next = null;
}
return el;
}
public void delete(T el) { // delete the node with an element el;
if (!isEmpty())
if (head == tail && el.equals(head.info)) // if only one
head = tail = null; // node on the list;
else if (el.equals(head.info)) // if more than one node on the list;
head = head.next; // and el is in the head node;
else { // if more than one node in the list
SLLNode pred, tmp;// and el is in a nonhead node;
for (pred = head, tmp = head.next;
tmp != null && !tmp.info.equals(el);
pred = pred.next, tmp = tmp.next);
if (tmp != null) { // if el was found;
pred.next = tmp.next;
if (tmp == tail) // if el is in the last node;
tail = pred;
}
}
}
@Override
public String toString() {
if(head == null)
return "[ ]";
String str = "[ ";
SLLNode tmp = head;
while(tmp != null){
str += tmp.info + " ";
tmp = tmp.next;
}
return str+"]";
}
public boolean contains(T el) {
if(head == null)
return false;
SLLNode tmp = head;
while(tmp != null){
if(tmp.info.equals(el))
return true;
tmp = tmp.next;
}
return false;
}
public int size(){
if(head == null)
return 0;
int count = 0;
SLLNode p = head;
while(p != null) {
count++;
p = p.next;
}
return count;
}
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Use the singly linked list class introduced in the lab to implement integers of unlimited size.
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mutations like these are not exposed to natural selection. Instead, these neutral @ changes evolve
by a random process called genetic drift As we will discuss elsewhere, the neutral theory of
molecular evolution predicts that neutral changes in DNA should accumulate in populations at a
rate equal to the mutation rate If the mutation rate stays reasonably constant, and if generation
times remain similar, then the number of neutral molecular differences between two taxa should
be proportional to the age of their most recent common ancestor By counting distinct neutral
mutations observed in two species and multiplying by a calibration rate representing how
frequently neutral changes occur per million years, researchers can estimate when the species
diverged. Although the possibility of dating events from estimates of genetic divergence is
tantalizing, there are several important caveats. For example, it is critical to realize that the
mutation rate to neutral alleles will vary from gene to gene and lineage to lineage, and even from
base to base. For reasons explained in another chapter, silent site changes in the third positions of
codons are more likely to be neutral with respect to fitness, and thus to accumulate at a clocklike
rate, than replacement changes that occur at the first and second positions in codons. And if
allele frequencies change rapidly due to strong selection at a particular gene, it is unlikely that
the mutations involved are accumulating in a clocklike fashion. Finally rates of change calibrated
for a particular gene and lineage are unlikely to work for other groups, which may have different
generation times and selection histories (Martin et al. 1992; Martin and Palumbi 1993; Hillis et
al. 1996). Even if clocklike change occurs in a particular gene and lineage, how can the rate be
determined? Investigators have to rely on the fossil or geological records. The idea is to measure
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Solve using java and using this Singly linked list class:
public class SLL {
private class SLLNode {
private T info;
private SLLNode next;
public SLLNode() {
this(null,null);
}
public SLLNode(T el) {
this(el,null);
}
public SLLNode(T el, SLLNode ptr) {
info = el; next = ptr;
}
}
protected SLLNode head, tail;
public SLL() {
head = tail = null;
}
public boolean isEmpty() {
return head == null;
}
public void addToHead(T el) {
head = new SLLNode(el,head);
if (tail == null)
tail = head;
}
public void addToTail(T el) {
if (!isEmpty()) {
tail.next = new SLLNode(el);
tail = tail.next;
}
else head = tail = new SLLNode(el);
}
public T deleteFromHead() { // delete the head and return its info;
if (isEmpty())
return null;
T el = head.info;
if (head == tail) // if only one node on the list;
head = tail = null;
else head = head.next;
return el;
}
public T deleteFromTail() { // delete the tail and return its info;
if (isEmpty())
return null;
T el = tail.info;
if (head == tail) // if only one node in the list;
head = tail = null;
else { // if more than one node in the list,
SLLNode tmp; // find the predecessor of tail;
for (tmp = head; tmp.next != tail; tmp = tmp.next);
tail = tmp; // the predecessor of tail becomes tail;
tail.next = null;
}
return el;
}
public void delete(T el) { // delete the node with an element el;
if (!isEmpty())
if (head == tail && el.equals(head.info)) // if only one
head = tail = null; // node on the list;
else if (el.equals(head.info)) // if more than one node on the list;
head = head.next; // and el is in the head node;
else { // if more than one node in the list
SLLNode pred, tmp;// and el is in a nonhead node;
for (pred = head, tmp = head.next;
tmp != null && !tmp.info.equals(el);
pred = pred.next, tmp = tmp.next);
if (tmp != null) { // if el was found;
pred.next = tmp.next;
if (tmp == tail) // if el is in the last node;
tail = pred;
}
}
}
@Override
public String toString() {
if(head == null)
return "[ ]";
String str = "[ ";
SLLNode tmp = head;
while(tmp != null){
str += tmp.info + " ";
tmp = tmp.next;
}
return str+"]";
}
public boolean contains(T el) {
if(head == null)
return false;
SLLNode tmp = head;
while(tmp != null){
if(tmp.info.equals(el))
return true;
tmp = tmp.next;
}
return false;
}
public int size(){
if(head == null)
return 0;
int count = 0;
SLLNode p = head;
while(p != null) {
count++;
p = p.next;
}
return count;
}
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Some evolutionary events can be dated from the fossil record But what options are available
when fossil data are missing? In at least some instances, it should be possible to address
questions about timing by analyzing molecular traits that change at a steady rate. This
hypothesis, called the molecular clock, @ originated with Emile Zuckerkandl and Linus Pauling
(1962). There are reasons to expect that some types of DNA sequences change in a clocklike
fashion. Many mutations change an individual's DNA but not its phenotype In most cases,
mutations like these are not exposed to natural selection. Instead, these neutral @ changes evolve
by a random process called genetic drift As we will discuss elsewhere, the neutral theory of
molecular evolution predicts that neutral changes in DNA should accumulate in populations at a
rate equal to the mutation rate If the mutation rate stays reasonably constant, and if generation
times remain similar, then the number of neutral molecular differences between two taxa should
be proportional to the age of their most recent common ancestor By counting distinct neutral
mutations observed in two species and multiplying by a calibration rate representing how
frequently neutral changes occur per million years, researchers can estimate when the species
diverged. Although the possibility of dating events from estimates of genetic divergence is
tantalizing, there are several important caveats. For example, it is critical to realize that the
mutation rate to neutral alleles will vary from gene to gene and lineage to lineage, and even from
base to base. For reasons explained in another chapter, silent site changes in the third positions of
codons are more likely to be neutral with respect to fitness, and thus to accumulate at a clocklike
rate, than replacement changes that occur at the first and second positions in codons. And if
allele frequencies change rapidly due to strong selection at a particular gene, it is unlikely that
the mutations involved are accumulating in a clocklike fashion. Finally rates of change calibrated
for a particular gene and lineage are unlikely to work for other groups, which may have different
generation times and selection histories (Martin et al. 1992; Martin and Palumbi 1993; Hillis et
al. 1996). Even if clocklike change occurs in a particular gene and lineage, how can the rate be
determined? Investigators have to rely on the fossil or geological records. The idea is to measure
the genetic distance between two taxa whose divergence date is known from fossil or geological
data and then to use this calibration to date the divergence times of groups that have no fossil
record. As an example of how researchers use molecular clocks to date events, consider work by
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sizes to a "reasonable" level (under 200, generally), Southeastern's dean, Holly Lutze, placed a
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mark with the correct trait.
A
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
B
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
C
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
D
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
E
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
F
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
G
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
H
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development.
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Start Program like this:
// Chapter 7 Validate Password
import java.util.*;
public class ch7
{
public static void main(String[] args)
{
// Define variables
Scanner input = new Scanner(System.in);
String userPassword; // for input
int userPasswordLength;
int numUppercaseLetters = 0; // counter for uppercase
int numLowercaseLetters = 0; // counter for lowerase
int numNumbers = 0; // counter for digits
boolean passwordIsInvalid = true; // changes to false when password is valid
// continue looping as long as password is invalid
while(passwordIsInvalid)
{
System.out.print("Please enter password >> ");
userPassword = input.nextLine();
userPasswordLength = userPassword.length(); // get the length of the password
// loop thru the password character by character
for(int i = 0; i < userPasswordLength; i++)
{
char ch = userPassword.charAt(i); // get one character at a time
// is character uppercase?
if(Character.isUpperCase(ch))
numUppercaseLetters++; // add 1 to counter ixample of Program Run: Phe
password was invalid. It did not have enough of the following : uppercase letters, iust be at least
2 lowercase letters, must be at least 3 digits, must be at least 3 Please enter password >> coast
The password was invalid. It did not have enough of the following: uppercase letters, wust be at
least 2 Please enter password >> coast2 The password was invalid. It did not have enough of the
following: Please enter password cCoastz Valid password.
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communication- mannerisms, and common Aboriginal and/or Torres Strait Islander words.
Demonstrate cultural awareness of the Aboriginal and/or Torres Strait Islander local community
Please include Reference.
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2. El martes ____ (no/estar) en Polonia.
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8. Cunto tiempo _____ (l/estar) fuera?
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Step 1You need to run the JAVA programs in sections 3.3 and 3.5 for.pdf
Step 1:You need to run the JAVA programs in sections 3.3 and 3.5 for selection sort and
insertion sort. You need to attach the output results.
Step 2: You need to modify these two programs, save them, submit them, and add some
comments and explanations to them to sort the list elements from high to low value. The index
should be IndexHighest instead IndexSmallest.
Step3: Run the modified programs and print out the results and submit them.
In the end, you need the running results for original JAVA programs (selection and insertion sort
JAVA programs), the two modified programs to sort the values from high to low value for
selection and insertion sorts, and the results for the modified programs.
This program uses the selection sort algorithm to sort an array. The code has been modified to
also calculate how many item comparisons are done. You can try running the program with
different arrays to see how the total number of comparisons changes (or doesn't change).
CODE 3.3 ---
import java.util.Arrays;
public class SelectionSortDemo {
private static int selectionSort(int[] numbers) {
// A variable to hold the number of item comparisons
int comparisons = 0;
for (int i = 0; i < numbers.length - 1; i++) {
// Find index of smallest remaining element
int indexSmallest = i;
for (int j = i + 1; j < numbers.length; j++) {
comparisons++;
if (numbers[j] < numbers[indexSmallest]) {
indexSmallest = j;
}
}
// Swap numbers[i] and numbers[indexSmallest]
int temp = numbers[i];
numbers[i] = numbers[indexSmallest];
numbers[indexSmallest] = temp;
}
return comparisons;
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the selectionSort method
int comparisons = selectionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
System.out.println("Total comparisons: " + comparisons);
}
}
CODE 3.5 ---
import java.util.Arrays;
public class InsertionSortDemo {
private static void insertionSort(int[] numbers) {
for (int i = 1; i < numbers.length; i++) {
int j = i;
while (j > 0 && numbers[j] < numbers[j - 1]) {
// Swap numbers[j] and numbers [j - 1]
int temp = numbers[j];
numbers[j] = numbers[j - 1];
numbers[j - 1] = temp;
j--;
}
}
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the insertionSort method
insertionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
}
}.
step by step in detail on how to configure a firewall that blocks in.pdf
step by step in detail on how to configure a firewall that blocks incoming traffic to the server.
that is set up on a router..
Step 1 Implement the getSortedRunLength() methodImplement the get.pdf
Step 1: Implement the getSortedRunLength() method
Implement the getSortedRunLength() method in NaturalMergeSorter.java. Access
NaturalMergeSorter.java by clicking on the orange arrow next to NaturalMerge.java at the top of
the coding window.
getSortedRunLength() has three parameters:
array: a reference to an array of integers,
arrayLength: an integer for the array's length, and
startIndex: an integer for the run's starting index.
The method returns the number of array elements sorted in ascending order, starting at startIndex
and ending either at the end of the sorted run, or the end of the array, whichever comes first. The
method returns 0 if startIndex is out of bounds.
File NaturalMerge.java has several test cases for getSortedRunLength() that can be run by
clicking the "Run program" button. One test case also exists for naturalMergeSort(), but that can
be ignored until step two is completed.
The program's output does not affect grading.
Submit for grading to ensure that the getSortedRunLength() unit tests pass before proceeding.
Step 2: Implement the naturalMergeSort() method
Implement the naturalMergeSort() method in NaturalMergeSorter.java. naturalMergeSort() must:
Start at index i=0
Get the length of the first sorted run, starting at i
Return if the first run's length equals the array length
If the first run ends at the array's end, reassign i=0 and repeat step 2
Get the length of the second sorted run, starting immediately after the first
Merge the two runs with the provided merge() method
Reassign i with the first index after the second run, or 0 if the second run ends at the array's end
Go to step 2
NaturalMergeSorter.java
public class NaturalMergeSorter {
public static int getSortedRunLength(int[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
} else {
break;
}
}
return length;
}
public static int getSortedRunLength(double[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
} else {
break;
}
}
return length;
}
public static void naturalMergeSort(int[] array, int arrayLength) {
int i = 0;
while (i < arrayLength) {
int firstRunLength = getSortedRunLength(array, arrayLength, i);
if (firstRunLength == arrayLength) {
return;
}
int secondRunLength = getSortedRunLength(array, arrayLength, i + firstRunLength);
merge(array, i, i + firstRunLength - 1, i + firstRunLength + secondRunLength - 1);
if (i + firstRunLength + secondRunLength == arrayLength) {
i = 0;
} else {
i = i + firstRunLength + secondRunLength;
}
}
}
public static void naturalMergeSort(double[] array, int arrayLength) {
int i = 0;
while (i < arrayLength) {
int firstRunLength = getSortedRunLength(array, arrayLength, i);
if (firstRunLength == arrayLen.
STATs areA. Cytoplasmic transcription activators that are activat.pdf
STATs are:
A. Cytoplasmic transcription activators that are activated by dephosphorylation of an inactive
complex
B. Are activated by a tyrosine kinase complex that is found in the nucleus
C. Extracellular ligands that stimulate T-cell differentiation.
D. Are activated by a cytoplasmic tyrosine kinase complex that results in phosphorylation and
dimerization of the phosphorylated STATs that can now enter the nucleus.
Stats project question In a study conducted by Zogby Internati.pdf
Stats project question
In a study conducted by Zogby International for the Democrat and Chronicle, more than 700
New Yorkers were polled to determine whether the New York state government works,
Respondents surveyed were asked questions involving pay cuts for state legis-lators, restrictions
on lobbyists. term limits for legislators, and whether state citizens should be able to put matters
directly on the state ballot for a vote. The results regarding lines.
several proposed reforms had broad support, crossing all demographic and political New. York
was conducted. The part y athliation (Democrat, Independent, Republican) of Suppose that a
follow -up survey of 100 individuals who live in the western region of
each individual surveyed was recorded, as well as their responses to the following three
questions
I. Should legislative pay be cut for every day the state budget is late?
2. Should there be more restrictions on lobbyists?
Yes
No
Yes
.
No
Should there be term limits requiring that legislators serve a fixed number of years?
Yes
No
Managerial Report
1. Use descriptive statistic
irize the data from this study. What are your prelimi-
nary conclusions abor
adence of the response (Yes or No) and party affilia-
tion for each of the three
in the survey?
2. With regard to question 1, test for the independence of the response (Yes and No) and party
affiliation. Use a =
0.5
3. With regard to question 2, test for the independence of the response (Yes and No) and
party affiliation. Use a = 05
4. With regard to question 3, test for the independence of the response (Yes and No) and
party affiliation. Use a = 05.
5. Does it appear that there is broad support for change across all political lines? Explain..
Spotify es un servicio de transmisi�n de m�sica utilizado por m�s de.pdf
Spotify es un servicio de transmisin de msica utilizado por ms de 200 millones de usuarios en
todo el mundo. Spotify ofrece una versin gratuita que proporciona transmisin bsica e incluye
anuncios. Tambin ofrecen Spotify Premium por una tarifa mensual que brinda a los usuarios
audio de mayor calidad, descargas de canciones y sin anuncios.
Ofrecer msica como un servicio de suscripcin en lugar de algo que compras y posees es un
nuevo modelo para la industria de la msica, pero est creciendo rpidamente. Otros competidores
incluyen Apple Music y Pandora. Veamos algunos aspectos nicos de este modelo:
Dado que las tasas de regalas son ms bajas para la transmisin, artistas como Taylor Swift y
AC/DC inicialmente se negaron a ofrecer su msica en el servicio. Pero a medida que Spotify ha
crecido, los artistas ven cada vez ms el beneficio de que sus canciones se transmitan en el
servicio.
Los 100 millones de clientes que usan Spotify Premium pueden descargar canciones y
escucharlas en lnea. Sin embargo, si cancelan el servicio, esas descargas ya no estn disponibles.
Spotify ofrece planes familiares y para estudiantes con un precio para mltiples usuarios. El
precio de estos planes representa un descuento significativo en comparacin con tener varias
cuentas individuales.
Debido a que Spotify puede realizar un seguimiento de la msica que escucha, puede ofrecer
promociones especiales, como entradas de conciertos premium para los artistas que disfruta.
R. Si Spotify anunciara que puedes escuchar "cualquier cancin", pero descubriste que Taylor
Swift no estaba en el servicio, este sera un ejemplo de qu brecha en la calidad del servicio?
brecha 3
brecha 1
brecha 2
brecha 4
B. Suponga que un suscriptor de Spotify Premium descarg una lista de reproduccin en su telfono
pero nunca escuch las canciones. Luego cancelaron su suscripcin y se sintieron decepcionados al
descubrir que sus canciones ya no estaban disponibles en su telfono. El hecho de que el
consumidor solo pudiera escuchar esas canciones cuando estaba suscrito activamente al servicio
demuestra qu caracterstica distingue a los productos de los bienes.
Estrategia para colocar precios
Fiabilidad
caducidad
Heterogeneidad
C. Al ofrecer descuentos en los precios, crear conexiones sociales, ofrecer personalizacin y
ofrecer servicios de valor agregado, como asientos premium en eventos, Spotify est demostrando
qu nivel de marketing relacional para los servicios.
Nivel 4
Nivel 3
Nivel 1
Nivel 2.
State the degrees of freedom used in this test Write the formula .pdf
State the degrees of freedom used in this test?
Write the formula for the pooled variance and interpret it.
What is the formula for the test statistic? Unknown Variances, Assumed Equal
tcalc=n1sp2+n2sp2where(x1x2)sp2=n1+n22(n11)s12+(n21)s22 For critical value, use Student's
twith d.f. =n1+n22.
Short Answer Identify the 4 Main Animal Tissue Types (Connective, Ne.pdf
Short Answer: Identify the 4 Main Animal Tissue Types (Connective, Nervous, Epithelial,
Muscle) 4. Which type of tissue includes bones, blood and cushions and binds? 5. Which type of
tissue produces voluntary and involuntary movements by contracting? 6. Which type of tissue
lines internal surfaces and secretes mucus, enzymes, and hormones? 7. Which type of tissue
consists of neurons and receives and transmits chemical and electrical impulses?.
SHORT ANSWER. Write the word or phrase that best completes each state.pdf
SHORT ANSWER. Write the word or phrase that best completes each statement or answers the
question. 50) Examine the picture to answer the following questions and identify the labeled
structures. B: C: D: E: Is the neuron pictured a sensory, association or motor neuron? What is its
function? F: Is the neuron multipolar or unipolar? Explain your answer..
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Subject Management Information System Please complete the four qu.pdf
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Solve the following balance and income sheet for this specialty hosp.pdf
Solve the following balance and income sheet for this specialty hospital. Please show how the
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Su clase se ha ofrecido como voluntaria para trabajar por el Referndum 13 en la boleta electoral
de noviembre, que exige matrcula y libros gratuitos para todos los cursos universitarios, excepto
Administracin de operaciones. El apoyo para el referndum incluye el montaje de carteles de
10,000 yardas (carteles de papel resistentes al agua preimpresos para ser pegados y grapados a
una estaca de madera) un sbado de otoo. Construya un diagrama de flujo y un diagrama de
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Su compaa de TI es responsable de crear programas de virus de software. Usted es responsable
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mark with the correct trait.
A
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
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[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
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[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
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[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
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Amoeba Diploblasty Deuterostome development Crab Sea Star
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F
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
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Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development
H
[ Choose ] Bacteria Multicellularity Ability to photosynthesize
Amoeba Diploblasty Deuterostome development Crab Sea Star
Archaea Membrane-bound nucleus Protostome development.
study of tension, compression, and shear and compare those three dir.pdf
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environment?.
Start Program like this Chapter 7 Validate Password import.pdf
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// Chapter 7 Validate Password
import java.util.*;
public class ch7
{
public static void main(String[] args)
{
// Define variables
Scanner input = new Scanner(System.in);
String userPassword; // for input
int userPasswordLength;
int numUppercaseLetters = 0; // counter for uppercase
int numLowercaseLetters = 0; // counter for lowerase
int numNumbers = 0; // counter for digits
boolean passwordIsInvalid = true; // changes to false when password is valid
// continue looping as long as password is invalid
while(passwordIsInvalid)
{
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userPassword = input.nextLine();
userPasswordLength = userPassword.length(); // get the length of the password
// loop thru the password character by character
for(int i = 0; i < userPasswordLength; i++)
{
char ch = userPassword.charAt(i); // get one character at a time
// is character uppercase?
if(Character.isUpperCase(ch))
numUppercaseLetters++; // add 1 to counter ixample of Program Run: Phe
password was invalid. It did not have enough of the following : uppercase letters, iust be at least
2 lowercase letters, must be at least 3 digits, must be at least 3 Please enter password >> coast
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Students may research the local Aboriginal andor Torres Strait Isla.pdf
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Stevie es un hombre ocupado. El viaja mucho. Usa las palabras entre .pdf
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2. El martes ____ (no/estar) en Polonia.
3. No sabe dnde _____ (estar) el mircoles.
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Step 1You need to run the JAVA programs in sections 3.3 and 3.5 for.pdf
Step 1:You need to run the JAVA programs in sections 3.3 and 3.5 for selection sort and
insertion sort. You need to attach the output results.
Step 2: You need to modify these two programs, save them, submit them, and add some
comments and explanations to them to sort the list elements from high to low value. The index
should be IndexHighest instead IndexSmallest.
Step3: Run the modified programs and print out the results and submit them.
In the end, you need the running results for original JAVA programs (selection and insertion sort
JAVA programs), the two modified programs to sort the values from high to low value for
selection and insertion sorts, and the results for the modified programs.
This program uses the selection sort algorithm to sort an array. The code has been modified to
also calculate how many item comparisons are done. You can try running the program with
different arrays to see how the total number of comparisons changes (or doesn't change).
CODE 3.3 ---
import java.util.Arrays;
public class SelectionSortDemo {
private static int selectionSort(int[] numbers) {
// A variable to hold the number of item comparisons
int comparisons = 0;
for (int i = 0; i < numbers.length - 1; i++) {
// Find index of smallest remaining element
int indexSmallest = i;
for (int j = i + 1; j < numbers.length; j++) {
comparisons++;
if (numbers[j] < numbers[indexSmallest]) {
indexSmallest = j;
}
}
// Swap numbers[i] and numbers[indexSmallest]
int temp = numbers[i];
numbers[i] = numbers[indexSmallest];
numbers[indexSmallest] = temp;
}
return comparisons;
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the selectionSort method
int comparisons = selectionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
System.out.println("Total comparisons: " + comparisons);
}
}
CODE 3.5 ---
import java.util.Arrays;
public class InsertionSortDemo {
private static void insertionSort(int[] numbers) {
for (int i = 1; i < numbers.length; i++) {
int j = i;
while (j > 0 && numbers[j] < numbers[j - 1]) {
// Swap numbers[j] and numbers [j - 1]
int temp = numbers[j];
numbers[j] = numbers[j - 1];
numbers[j - 1] = temp;
j--;
}
}
}
public static void main(String[] args) {
// Create an array of numbers to sort
int[] numbers = { 10, 2, 78, 4, 45, 32, 7, 11 };
// Display the contents of the array
System.out.println("UNSORTED: " + Arrays.toString(numbers));
// Call the insertionSort method
insertionSort(numbers);
// Display the sorted contents of the array
System.out.println("SORTED: " + Arrays.toString(numbers));
}
}.
step by step in detail on how to configure a firewall that blocks in.pdf
step by step in detail on how to configure a firewall that blocks incoming traffic to the server.
that is set up on a router..
Step 1 Implement the getSortedRunLength() methodImplement the get.pdf
Step 1: Implement the getSortedRunLength() method
Implement the getSortedRunLength() method in NaturalMergeSorter.java. Access
NaturalMergeSorter.java by clicking on the orange arrow next to NaturalMerge.java at the top of
the coding window.
getSortedRunLength() has three parameters:
array: a reference to an array of integers,
arrayLength: an integer for the array's length, and
startIndex: an integer for the run's starting index.
The method returns the number of array elements sorted in ascending order, starting at startIndex
and ending either at the end of the sorted run, or the end of the array, whichever comes first. The
method returns 0 if startIndex is out of bounds.
File NaturalMerge.java has several test cases for getSortedRunLength() that can be run by
clicking the "Run program" button. One test case also exists for naturalMergeSort(), but that can
be ignored until step two is completed.
The program's output does not affect grading.
Submit for grading to ensure that the getSortedRunLength() unit tests pass before proceeding.
Step 2: Implement the naturalMergeSort() method
Implement the naturalMergeSort() method in NaturalMergeSorter.java. naturalMergeSort() must:
Start at index i=0
Get the length of the first sorted run, starting at i
Return if the first run's length equals the array length
If the first run ends at the array's end, reassign i=0 and repeat step 2
Get the length of the second sorted run, starting immediately after the first
Merge the two runs with the provided merge() method
Reassign i with the first index after the second run, or 0 if the second run ends at the array's end
Go to step 2
NaturalMergeSorter.java
public class NaturalMergeSorter {
public static int getSortedRunLength(int[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
} else {
break;
}
}
return length;
}
public static int getSortedRunLength(double[] array, int arrayLength, int startIndex) {
if (startIndex < 0 || startIndex >= arrayLength) {
return 0;
}
int length = 1;
for (int i = startIndex + 1; i < arrayLength; i++) {
if (array[i] >= array[i - 1]) {
length++;
} else {
break;
}
}
return length;
}
public static void naturalMergeSort(int[] array, int arrayLength) {
int i = 0;
while (i < arrayLength) {
int firstRunLength = getSortedRunLength(array, arrayLength, i);
if (firstRunLength == arrayLength) {
return;
}
int secondRunLength = getSortedRunLength(array, arrayLength, i + firstRunLength);
merge(array, i, i + firstRunLength - 1, i + firstRunLength + secondRunLength - 1);
if (i + firstRunLength + secondRunLength == arrayLength) {
i = 0;
} else {
i = i + firstRunLength + secondRunLength;
}
}
}
public static void naturalMergeSort(double[] array, int arrayLength) {
int i = 0;
while (i < arrayLength) {
int firstRunLength = getSortedRunLength(array, arrayLength, i);
if (firstRunLength == arrayLen.
STATs areA. Cytoplasmic transcription activators that are activat.pdf
STATs are:
A. Cytoplasmic transcription activators that are activated by dephosphorylation of an inactive
complex
B. Are activated by a tyrosine kinase complex that is found in the nucleus
C. Extracellular ligands that stimulate T-cell differentiation.
D. Are activated by a cytoplasmic tyrosine kinase complex that results in phosphorylation and
dimerization of the phosphorylated STATs that can now enter the nucleus.
Stats project question In a study conducted by Zogby Internati.pdf
Stats project question
In a study conducted by Zogby International for the Democrat and Chronicle, more than 700
New Yorkers were polled to determine whether the New York state government works,
Respondents surveyed were asked questions involving pay cuts for state legis-lators, restrictions
on lobbyists. term limits for legislators, and whether state citizens should be able to put matters
directly on the state ballot for a vote. The results regarding lines.
several proposed reforms had broad support, crossing all demographic and political New. York
was conducted. The part y athliation (Democrat, Independent, Republican) of Suppose that a
follow -up survey of 100 individuals who live in the western region of
each individual surveyed was recorded, as well as their responses to the following three
questions
I. Should legislative pay be cut for every day the state budget is late?
2. Should there be more restrictions on lobbyists?
Yes
No
Yes
.
No
Should there be term limits requiring that legislators serve a fixed number of years?
Yes
No
Managerial Report
1. Use descriptive statistic
irize the data from this study. What are your prelimi-
nary conclusions abor
adence of the response (Yes or No) and party affilia-
tion for each of the three
in the survey?
2. With regard to question 1, test for the independence of the response (Yes and No) and party
affiliation. Use a =
0.5
3. With regard to question 2, test for the independence of the response (Yes and No) and
party affiliation. Use a = 05
4. With regard to question 3, test for the independence of the response (Yes and No) and
party affiliation. Use a = 05.
5. Does it appear that there is broad support for change across all political lines? Explain..
Spotify es un servicio de transmisi�n de m�sica utilizado por m�s de.pdf
Spotify es un servicio de transmisin de msica utilizado por ms de 200 millones de usuarios en
todo el mundo. Spotify ofrece una versin gratuita que proporciona transmisin bsica e incluye
anuncios. Tambin ofrecen Spotify Premium por una tarifa mensual que brinda a los usuarios
audio de mayor calidad, descargas de canciones y sin anuncios.
Ofrecer msica como un servicio de suscripcin en lugar de algo que compras y posees es un
nuevo modelo para la industria de la msica, pero est creciendo rpidamente. Otros competidores
incluyen Apple Music y Pandora. Veamos algunos aspectos nicos de este modelo:
Dado que las tasas de regalas son ms bajas para la transmisin, artistas como Taylor Swift y
AC/DC inicialmente se negaron a ofrecer su msica en el servicio. Pero a medida que Spotify ha
crecido, los artistas ven cada vez ms el beneficio de que sus canciones se transmitan en el
servicio.
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escucharlas en lnea. Sin embargo, si cancelan el servicio, esas descargas ya no estn disponibles.
Spotify ofrece planes familiares y para estudiantes con un precio para mltiples usuarios. El
precio de estos planes representa un descuento significativo en comparacin con tener varias
cuentas individuales.
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promociones especiales, como entradas de conciertos premium para los artistas que disfruta.
R. Si Spotify anunciara que puedes escuchar "cualquier cancin", pero descubriste que Taylor
Swift no estaba en el servicio, este sera un ejemplo de qu brecha en la calidad del servicio?
brecha 3
brecha 1
brecha 2
brecha 4
B. Suponga que un suscriptor de Spotify Premium descarg una lista de reproduccin en su telfono
pero nunca escuch las canciones. Luego cancelaron su suscripcin y se sintieron decepcionados al
descubrir que sus canciones ya no estaban disponibles en su telfono. El hecho de que el
consumidor solo pudiera escuchar esas canciones cuando estaba suscrito activamente al servicio
demuestra qu caracterstica distingue a los productos de los bienes.
Estrategia para colocar precios
Fiabilidad
caducidad
Heterogeneidad
C. Al ofrecer descuentos en los precios, crear conexiones sociales, ofrecer personalizacin y
ofrecer servicios de valor agregado, como asientos premium en eventos, Spotify est demostrando
qu nivel de marketing relacional para los servicios.
Nivel 4
Nivel 3
Nivel 1
Nivel 2.
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