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LESSON PLAN
Submitted by
Greeshma George
Three Quantities
If three quantities are in the
ratio 𝒂 ∶ 𝒃 ∶ 𝒄 , then there is a
quantity 𝒙 such that first is 𝒂𝒙
, second is 𝒃𝒙 and third is 𝒄𝒙
Problem 1
The sides of a triangle are in the
ratio 3:5:7 and its perimeter is 45
centimetres. What are the length
of the sides?
SOLUTION
Three sides are 3𝑥 , 5𝑥 𝑎𝑛𝑑 7𝑥
Perimeter = 45 centimetres
Then , 3𝑥 + 5𝑥 + 7𝑥 = 45
15𝑥 = 45
𝑥 = 45
15
𝑥 = 3
Then the sides are
3𝒙 = 3 × 3 = 9cm
5𝒙 = 5 × 3 = 15cm
7𝒙 = 7 × 3 = 21cm
Problem 2
The angles of a triangle are
in the ratio 1 : 3 : 5. How
much is each angle?
Solution
The first angle = 𝒙
The second angle = 𝟑𝒙
The third angle = 𝟓𝒙
Sum of angles of a triangle = 𝟏𝟖𝟎 𝟎
Then, x + 3x + 5x = 𝟏𝟖𝟎 𝟎
𝟗𝒙 = 𝟏𝟖𝟎 𝟎
𝒙 =
𝟏𝟖𝟎 𝟎
𝟗
= 𝟐𝟎 𝟎
First angle = 𝒙 = 𝟐𝟎 𝟎
Second angle = 𝟑𝒙
= 3 × 𝟐𝟎 𝟎
= 𝟔𝟎 𝟎
Third angle = 𝟓𝒙
= 5 × 𝟐𝟎 𝟎
= 𝟏𝟎𝟎 𝟎
Problem : 2
The outer angle of a triangle are
in the ratio 5 : 6 : 7 . What are
the angles?
Solution
The outer angles of a triangle are 5𝑥 , 6𝑥, 7𝑥
Sum of outer angles of a triangle are 3600
5𝑥 + 6𝑥 + 7𝑥 = 3600
18𝑥 = 3600
𝑥 =
3600
18
= 200
The angles of a triangle are in
the ratio 1 : 2 : 6. How much
is each angle?
The first angle = 𝑥
The second angle = 2𝑥
The third angle = 6𝑥
Sum of angles of a triangle = 1800
Then, x + 2x + 6x = 1800
9𝑥 = 1800
𝑥 =
1800
9
= 200
First angle = 𝒙 = 𝟐𝟎 𝟎
Second angle = 𝟐𝒙
= 2 × 𝟐𝟎 𝟎
= 𝟒𝟎 𝟎
Third angle = 𝟔𝒙
= 6 × 𝟐𝟎 𝟎 = 𝟏𝟐𝟎 𝟎
HOMEWORK
If the angles of a triangle are in
the ratio 2 : 3 : 4. What are the
angles?
ratio

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ratio

  • 2.
  • 3. Three Quantities If three quantities are in the ratio 𝒂 ∶ 𝒃 ∶ 𝒄 , then there is a quantity 𝒙 such that first is 𝒂𝒙 , second is 𝒃𝒙 and third is 𝒄𝒙
  • 4. Problem 1 The sides of a triangle are in the ratio 3:5:7 and its perimeter is 45 centimetres. What are the length of the sides?
  • 5. SOLUTION Three sides are 3𝑥 , 5𝑥 𝑎𝑛𝑑 7𝑥 Perimeter = 45 centimetres Then , 3𝑥 + 5𝑥 + 7𝑥 = 45 15𝑥 = 45 𝑥 = 45 15 𝑥 = 3
  • 6. Then the sides are 3𝒙 = 3 × 3 = 9cm 5𝒙 = 5 × 3 = 15cm 7𝒙 = 7 × 3 = 21cm
  • 7. Problem 2 The angles of a triangle are in the ratio 1 : 3 : 5. How much is each angle?
  • 8. Solution The first angle = 𝒙 The second angle = 𝟑𝒙 The third angle = 𝟓𝒙 Sum of angles of a triangle = 𝟏𝟖𝟎 𝟎 Then, x + 3x + 5x = 𝟏𝟖𝟎 𝟎 𝟗𝒙 = 𝟏𝟖𝟎 𝟎 𝒙 = 𝟏𝟖𝟎 𝟎 𝟗 = 𝟐𝟎 𝟎
  • 9. First angle = 𝒙 = 𝟐𝟎 𝟎 Second angle = 𝟑𝒙 = 3 × 𝟐𝟎 𝟎 = 𝟔𝟎 𝟎 Third angle = 𝟓𝒙 = 5 × 𝟐𝟎 𝟎 = 𝟏𝟎𝟎 𝟎
  • 10. Problem : 2 The outer angle of a triangle are in the ratio 5 : 6 : 7 . What are the angles?
  • 11. Solution The outer angles of a triangle are 5𝑥 , 6𝑥, 7𝑥 Sum of outer angles of a triangle are 3600 5𝑥 + 6𝑥 + 7𝑥 = 3600 18𝑥 = 3600 𝑥 = 3600 18 = 200
  • 12. The angles of a triangle are in the ratio 1 : 2 : 6. How much is each angle?
  • 13. The first angle = 𝑥 The second angle = 2𝑥 The third angle = 6𝑥 Sum of angles of a triangle = 1800 Then, x + 2x + 6x = 1800 9𝑥 = 1800 𝑥 = 1800 9 = 200
  • 14. First angle = 𝒙 = 𝟐𝟎 𝟎 Second angle = 𝟐𝒙 = 2 × 𝟐𝟎 𝟎 = 𝟒𝟎 𝟎 Third angle = 𝟔𝒙 = 6 × 𝟐𝟎 𝟎 = 𝟏𝟐𝟎 𝟎
  • 15. HOMEWORK If the angles of a triangle are in the ratio 2 : 3 : 4. What are the angles?