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Problem 5:                                              Read problem and answer following questions
  A regular pentagon of 30 mm sides is resting            1. Surface inclined to which plane? -------      HP
  on HP on one of it’s sides while it’s opposite          2. Assumption for initial position? ------ // to HP
  vertex (corner) is 30 mm above HP.                      3. So which view will show True shape? --- TV
  Draw projections when side in HP is 300                 4. Which side will be vertical? --------any side.
  inclined to VP.                                            Hence begin with TV,draw pentagon below
  SURFACE INCLINATION INDIRECTLY GIVEN
                                                             X-Y line, taking one side vertical.
     SIDE INCLINATION DIRECTLY GIVEN:

                    ONLY CHANGE is
   the manner in which surface inclination is described:
  One side on Hp & it’s opposite corner 30 mm above Hp.                             d’                     d’1
Hence redraw 1st Fv as a 2nd Fv making above arrangement.
          Keep a’b’ on xy & d’ 30 mm above xy.
                                                                             c’e’                                    e’1
                                                                30                            c’1
                                     b’ a’         c’e’    d’
                                 X                                                                                            Y
                                                                     b’ a’                          300    b’1      a’1
                                                   e                          e1
                                                                                                               b1
                                     a                               a1

                                                                                              c1                         a1
                                                             d                           d1

                                     b                               b1
                                                                                                          d1        e1
                                                    c                          c1

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  • 1. Problem 5: Read problem and answer following questions A regular pentagon of 30 mm sides is resting 1. Surface inclined to which plane? ------- HP on HP on one of it’s sides while it’s opposite 2. Assumption for initial position? ------ // to HP vertex (corner) is 30 mm above HP. 3. So which view will show True shape? --- TV Draw projections when side in HP is 300 4. Which side will be vertical? --------any side. inclined to VP. Hence begin with TV,draw pentagon below SURFACE INCLINATION INDIRECTLY GIVEN X-Y line, taking one side vertical. SIDE INCLINATION DIRECTLY GIVEN: ONLY CHANGE is the manner in which surface inclination is described: One side on Hp & it’s opposite corner 30 mm above Hp. d’ d’1 Hence redraw 1st Fv as a 2nd Fv making above arrangement. Keep a’b’ on xy & d’ 30 mm above xy. c’e’ e’1 30 c’1 b’ a’ c’e’ d’ X Y b’ a’ 300 b’1 a’1 e e1 b1 a a1 c1 a1 d d1 b b1 d1 e1 c c1