Projection of planes 008
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A 30 mm regular pentagon rests on a horizontal plane (HP) with one side on the HP and the opposite vertex 30 mm above the HP. To draw the projections: 1) Draw the top view (TV) with any side of the pentagon vertical. 2) Draw the front view (FV) below the TV, making one side of the pentagon 30 mm above the HP to represent the given positioning. 3) The side inclination is directly given as 300, while the surface inclination is indirectly given by the positioning description.
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- 1. Problem 5: Read problem and answer following questions A regular pentagon of 30 mm sides is resting 1. Surface inclined to which plane? ------- HP on HP on one of it’s sides while it’s opposite 2. Assumption for initial position? ------ // to HP vertex (corner) is 30 mm above HP. 3. So which view will show True shape? --- TV Draw projections when side in HP is 300 4. Which side will be vertical? --------any side. inclined to VP. Hence begin with TV,draw pentagon below SURFACE INCLINATION INDIRECTLY GIVEN X-Y line, taking one side vertical. SIDE INCLINATION DIRECTLY GIVEN: ONLY CHANGE is the manner in which surface inclination is described: One side on Hp & it’s opposite corner 30 mm above Hp. d’ d’1 Hence redraw 1st Fv as a 2nd Fv making above arrangement. Keep a’b’ on xy & d’ 30 mm above xy. c’e’ e’1 30 c’1 b’ a’ c’e’ d’ X Y b’ a’ 300 b’1 a’1 e e1 b1 a a1 c1 a1 d d1 b b1 d1 e1 c c1