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1 of 9
Summer vacation is
over…
PRACTICE QUIZ
1-1 & 1-2
2) What is the domain and range for each?
5
9
)
( 

 x
x
f  
)
9
,
5
(
),
2
,
1
(
),
2
,
0
(
),
3
,
1
(
)
( 




x
f
Equations are
“continuous”
Coordinates are
“discrete”
1) Which example below is discrete, and
which is continuous?
Linear equations are infinite,
so domain & range are both
(-∞, +∞)
D= { -1, 0, 5 }
R = { -9, -3, 2 }
3) Why is the example on
the right NOT considered
to be a function?
There is a
duplicate
coordinate in
the domain!
4) Which of the following graphs pass the
vertical line test? (and is therefore a function)
Nowhere does it hit it
more than once! So,
YES, it’s a function!
Oops, hits it twice.
NOT a function!
Here’s the only spot in
question, but the open
circle means…no, it
does not hit it twice.
So, YES, it is a
function!
Use the function: f(x) = 3x3 – 2x + 8 to find…
5) f(5) 6) f(-2) 7) f(2n)
f(5) = 3(5)3 – 2(5) + 8
= 3(125) – 10 + 8
= 375 – 10 + 8
= 373
f(5) = 373
f(5) = 3(-2)3 – 2(-2) + 8
= 3(-8) + 4 + 8
= -24 + 4 + 8
= -12
f(-2) = -12
f(5) = 3(2n)3 – 2(2n) + 8
= 3(8n3) – 4n + 8
= 24n3 – 4n + 8
f(2n) = 24n3 – 4n + 8
8) Change to “standard form” (Ax + By = C)
y
x 3
7
2 
 Don’t want
the “x”-term
to be
negative, so…
x
y 7
3
2 

Is that the
best order?
Well, no…
2
3
7 
 y
x
But that is!
9) Change to standard form:
2
5
2
10
3 y
x


I) common denominators ---->
10
5
10
4
10
3 y
x


II) lose the denominators ----> y
x 5
4
3 

III) move the 4 and 5y ----> 3𝑥 − 5𝑦 = −4
10) Find the x & y-intercepts for: y
x 5
10
3 

x-int
3x – 10 = 5(0)
3x – 10 = 0
3x = 10
x = 10/3
y-int
3(0) – 10 = 5y
-10 = 5y
-2 = y
Or, the cover-up
method (same thing)
11) Find me some linear equations
11
2


x
y
11
2


x
y
11
2

 y
x
11
2 
 x
y
11
2 
 x
y
11
6
5

 y
x
11

x
Good luck
on your
first Algebra
2 quiz!

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PPquiz 1-1 to 1-2.pptx

  • 2. 2) What is the domain and range for each? 5 9 ) (    x x f   ) 9 , 5 ( ), 2 , 1 ( ), 2 , 0 ( ), 3 , 1 ( ) (      x f Equations are “continuous” Coordinates are “discrete” 1) Which example below is discrete, and which is continuous? Linear equations are infinite, so domain & range are both (-∞, +∞) D= { -1, 0, 5 } R = { -9, -3, 2 } 3) Why is the example on the right NOT considered to be a function? There is a duplicate coordinate in the domain!
  • 3. 4) Which of the following graphs pass the vertical line test? (and is therefore a function) Nowhere does it hit it more than once! So, YES, it’s a function! Oops, hits it twice. NOT a function! Here’s the only spot in question, but the open circle means…no, it does not hit it twice. So, YES, it is a function!
  • 4. Use the function: f(x) = 3x3 – 2x + 8 to find… 5) f(5) 6) f(-2) 7) f(2n) f(5) = 3(5)3 – 2(5) + 8 = 3(125) – 10 + 8 = 375 – 10 + 8 = 373 f(5) = 373 f(5) = 3(-2)3 – 2(-2) + 8 = 3(-8) + 4 + 8 = -24 + 4 + 8 = -12 f(-2) = -12 f(5) = 3(2n)3 – 2(2n) + 8 = 3(8n3) – 4n + 8 = 24n3 – 4n + 8 f(2n) = 24n3 – 4n + 8
  • 5. 8) Change to “standard form” (Ax + By = C) y x 3 7 2   Don’t want the “x”-term to be negative, so… x y 7 3 2   Is that the best order? Well, no… 2 3 7   y x But that is!
  • 6. 9) Change to standard form: 2 5 2 10 3 y x   I) common denominators ----> 10 5 10 4 10 3 y x   II) lose the denominators ----> y x 5 4 3   III) move the 4 and 5y ----> 3𝑥 − 5𝑦 = −4
  • 7. 10) Find the x & y-intercepts for: y x 5 10 3   x-int 3x – 10 = 5(0) 3x – 10 = 0 3x = 10 x = 10/3 y-int 3(0) – 10 = 5y -10 = 5y -2 = y Or, the cover-up method (same thing)
  • 8. 11) Find me some linear equations 11 2   x y 11 2   x y 11 2   y x 11 2   x y 11 2   x y 11 6 5   y x 11  x
  • 9. Good luck on your first Algebra 2 quiz!