The document describes solving a system of equations to find the values of a, b, and c in the equations F(x)=ax^2+bx+c and F(x+3)=3x^2+7x+4. It is determined that a=3, b=-11, and c=10. When added together, a+b+c equals 2.
On Triplet of Positive Integers Such That the Sum of Any Two of Them is a Per...inventionjournals
In this article we discussed determination of distinct positive integers a, b, c such that a + b, a + c, b + c are perfect squares. We can determine infinitely many such triplets. There are such four tuples and from them eliminating any one number we obtain triplets with the specific property. We can also obtain infinitely many such triplets from a single triplet.
Theta θ(g,x) and pi π(g,x) polynomials of hexagonal trapezoid system tb,aijcsa
A counting polynomial, called Omega Ω(G,x), was proposed by Diudea. It is defined on the ground of
“opposite edge strips” ops. Theta Θ(G,x) and Pi Π(G,x) polynomials can also be calculated by ops
counting. In this paper we compute these counting polynomials for a family of Benzenoid graphs that called
Hexagonal trapezoid system Tb,a.
On Triplet of Positive Integers Such That the Sum of Any Two of Them is a Per...inventionjournals
In this article we discussed determination of distinct positive integers a, b, c such that a + b, a + c, b + c are perfect squares. We can determine infinitely many such triplets. There are such four tuples and from them eliminating any one number we obtain triplets with the specific property. We can also obtain infinitely many such triplets from a single triplet.
Theta θ(g,x) and pi π(g,x) polynomials of hexagonal trapezoid system tb,aijcsa
A counting polynomial, called Omega Ω(G,x), was proposed by Diudea. It is defined on the ground of
“opposite edge strips” ops. Theta Θ(G,x) and Pi Π(G,x) polynomials can also be calculated by ops
counting. In this paper we compute these counting polynomials for a family of Benzenoid graphs that called
Hexagonal trapezoid system Tb,a.
IT'S A PRESENTATION ON QUADRATIC EQUATION PART 1, CLASS 10, CHAPTER 4, IT STARTS WITH THE SHAPE PARABOLA AND IT'S DAY TO DAY LIFE EXAMPLES, AS WE PROCEED FURTHER WE SOLVE SOME EXPRESSIONS, WE COVERT IT INTO QUADRATIC EQUATIONS. AFTERWARDS, WE LEARN HOW TO FORM STANDARD QUADRATIC EQUATIONS WITH EXAMPLES (WORD PROBLEMS).
Mathematical Operations Reasoning QuestionsSandip Kar
Solved examples of verbal reasoning questions and answers on “Mathematical Operations” with explanation with detailed answer description, explanation. Suitable for various competitive exams like Bank PO, IBPS, LIC, Railways and SBI Clerk.
2. Suppose that F(x+3)= 3x2+7x+4 and
F(x)= ax2+bx+c. What is a+b+c?
First, you take the equation F(x)= ax2+bx+c and substitute (x+3) for
x.
F(x)= ax2+bx+c
F(x+3)= a(x+3)2 + b(x+3) + c
F(x+3)= a(x2+6x+9) + bx + 3b + c
F(x+3)= ax2 + 6ax + 9a + bx + 3b + c
F(x+3)= ax2 + (6a+b)x + 9a + 3b + c
3. In the equation F(x+3)= 3x2+7x+4,
3 is the a term, 7 is the b term, and 4 is the c term. In
the equation
F(x+3)= ax2 + (6a+b)x + 9a + 3b + c,
a is the a term, (6a+b) is the b term, and 9a is the c
term.
If you set the terms equal to each other, you get
a=3, 7= 6a+b, and 4= 9a + 3b + c.
Now you have a system of two variables with
7= 6a+b and 4= 9a + 3b + c.
4. Solve:
7= 6a + b
4= 9a + 3b + c
7= 6a + b 4= 9a + 3b + c
7= 6(3)+ b 4= 9(3) + 3(-11) + c
7= 18 + b 4= 27 - 33 + c
-11= b 4= -6 + c
10= c
a+b+c=
3-11+10=2
a+b+c=2
