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pHYSICS EXAM HALF SHEET
1. DV = ½ g t2 + Vi t
a = ∆v/t Fnet = m a material = Hf, Hv
(T1/T2)2 = (r1/r2)3
Cu = 2.05E5, 5.07E6
Vf = at + Vi Ff = μ Fn Torbit = 2π√ r3/Gm
DH = VH t mercury = 1.15E4, 2.72E5
gold = 6.30E4, 1.64E6
D = vt Fnet = Fa + Ff w’d’2 = wd2
Tperiod = 2π √ (L/g) methnl = 1.09E5, 8.78E5
D = Vit + (½)at2 Fnet = Fa + w Fe = 2.66E5, 6.29E6
Fg = Gm1m2
g = V2 / r = ac
silver = 1.04E5, 2.36E6
2 2
V = Vi + 2aD Sinθ = Fparallel /w d2 Pb = 2.04E4, 8.64E5
v=√gr
f
-------------------- --- water = 3.34E5, 2.26E6
Cosθ = Fnormal /w g = (G mplanet)/ r2
W=Fd Fnet = m ac ------------- ----------
--------- -------------- F = (mplanet 4π2 r)/T2 CH20 = 4180 J/kg K
P = W/t = mv2 / r
PE = m g h CAl = 903 J/kg K
G= 6.67x10-11 Nm2/kg2
Wi = FE DE ac = 4π2 r / T2
Cbrass = 376 J/kg K
-------------- ---------
KE = ½ m v2
Wo = FR DR ------------- ---------- CC = 710 J/kg K
-------------- ---------
∆EA = -∆E B CCu = 385 J/kg K
MA = FR / FE F t = m ∆v = P
F1/A1 = F2/A2
Cglass = 664 J/kg K
∆EA = Q = m C ∆T
IMA = DE / DR F t = impulse
P=ρhg Cice = 2060 J/kg K
MACA(Tf-TiA)
eff = Wo / Wi m ∆v = momentum CFe = 450 J/kg K
Fbouyant = V g ρL
CPb = 130 J/kg K
= - MBCB(Tf-TiB)
= MA / IMA Pfa + Pfb = Pia + Pib
∆L = α Li ∆T Cmethanol = 2450 J/kg K
-------------------- --- Tf
-------------- --------- Csilver = 235 J/kg K
f’ = fs (v - vD)/ (v - vs) ∆V = β Vi ∆T
=[MACATiA+MBCBTiB]/ Csteam = 2020 J/kg K
v=fλ
DB = 10log(intensity/thresh) Wnet = Fg - Fb
Czinc = 388 J/kg K
[MACA + MBCB]
period (T) = 1/ f
Closed pipe = λ/4 ρ o = Pl Mo / Mo - Mol --------- --------------
---------------- -------
2:1 octave 4:3 fourth Qf = m Hf
Open pipe = λ/2 VSound = 343/1435 m/s Q = m C ∆T
Qv = m Hv
3:2 fifth 5:4 third
B= f1 – f2
Travis Langner