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Physical Chemistry 3
Lecture 2
Review of Mathematical Concepts
3D Vector โ€“ can be represented by specifying its
components ๐‘Ž๐‘– with respect to a set of three mutually
perpendicular unit vectors ๐‘’๐‘– as;
๐‘Ž = ๐‘’1๐‘Ž1 + ๐‘’2๐‘Ž2 + ๐‘’3๐‘Ž3 =
๐‘–=1
3
๐‘’๐‘–๐‘Ž๐‘–
the basis is not unique;
๐‘Ž = ๐œ€1๐‘Ž1 + ๐œ€2๐‘Ž2 + ๐œ€3๐‘Ž3 =
๐‘–=1
3
๐œ€๐‘–๐‘Ž๐‘–
๐‘’ =
1 0 0
0 1 0
0 0 1
๐œ€ =
0.354 0.612 0.707
โˆ’0.927 0.127 0.354
0.127 โˆ’0.78 0.612
Same vector under two basis
๐‘Ž1
๐‘Ž2
๐‘Ž3
=
โˆ’0.5
0.5
0.75
๐‘Ž1
๐‘Ž2
๐‘Ž3
=
โˆ’0.55
โˆ’0.83
0.28
0.28
Red
Blue
Green
-0.83
-0.55
What is a basis
๐‘’ =
1 0 0
0 1 0
0 0 1
๐‘’1 =
1
0
0
๐‘’2 =
0
1
0
๐‘’3 =
0
0
1
๐œ€ =
0.354 0.612 0.707
โˆ’0.927 0.127 0.354
0.127 โˆ’0.78 0.612
๐œ€1 =
0.354
โˆ’0.927
0.127
๐œ€2 =
0.612
0.12
โˆ’0.78
๐œ€3 =
0.707
0.354
0.612
๐‘Ž = ๐‘’1๐‘Ž1 + ๐‘’2๐‘Ž2 + ๐‘’3๐‘Ž3 =
๐‘–=1
3
๐‘’๐‘–๐‘Ž๐‘–
๐‘Ž =
1
0
0
โˆ’0.5 +
0
1
0
0.5 +
1
0
0
0.75 =
โˆ’0.5
0.5
0.75
๐‘Ž =
0.354
โˆ’0.927
0.127
โˆ’0.55 +
0.612
0.12
โˆ’0.78
โˆ’0.83 +
0.707
0.354
0.612
0.28
๐‘Ž =
โˆ’0.5
0.5
0.75
๐‘Ž = ๐‘’๐‘–|๐‘Ž๐‘–
0.354 0.612 0.707
โˆ’0.927 0.127 0.354
0.127 โˆ’0.78 0.612
๐‘‡
โˆ’0.55
โˆ’0.83
0.28
Properties of basis
๐‘’ ๐‘–|๐‘’ ๐‘— =
1 ๐‘–๐‘“ ๐‘– = ๐‘—
0 ๐‘œ๐‘กโ„Ž๐‘’๐‘Ÿ๐‘ค๐‘–๐‘ ๐‘’
0.354 โˆ’0.927 0.127
0.612
0.12
โˆ’0.78
= 0
๐‘’ =
1 0 0
0 1 0
0 0 1
๐œ€ =
0.354 0.612 0.707
โˆ’0.927 0.127 0.354
0.127 โˆ’0.78 0.612
0.354 โˆ’0.927 0.127
0.354
โˆ’0.927
0.127
= 1
๐‘Ž = ๐‘’1๐‘Ž1 + ๐‘’2๐‘Ž2 + ๐‘’3๐‘Ž3 =
๐‘–=1
3
๐‘’๐‘–๐‘Ž๐‘–
๐‘’๐‘—๐‘Ž = ๐‘Ž๐‘—
๐‘’ ๐‘–๐‘’ ๐‘— =
1 ๐‘–๐‘“ ๐‘– = ๐‘—
0 ๐‘œ๐‘กโ„Ž๐‘’๐‘Ÿ๐‘ค๐‘–๐‘ ๐‘’
๐‘’ 2๐‘Ž = ๐‘’ 2๐‘’1๐‘Ž1 + ๐‘’ 2๐‘’2๐‘Ž2 + ๐‘’ 2๐‘’3๐‘Ž3
๐‘’ 2๐‘Ž = 0 โˆ— ๐‘Ž1 + 1 โˆ— ๐‘Ž2 + 0 โˆ— ๐‘Ž3
๐‘’ 2๐‘Ž = ๐‘Ž2
Since
Properties of basis
Coordinate systems
Cartesian and Polar coordinate
Scalar Product of Two Vectors
๐‘Ž โˆ— ๐‘ = ๐‘Ž1๐‘1 + ๐‘Ž2๐‘2 + ๐‘Ž3๐‘3 =
๐‘–=1
3
๐‘Ž๐‘–๐‘๐‘–
๐‘Ž โˆ— ๐‘ =
๐‘– ๐‘—
๐‘’ ๐‘–๐‘’ ๐‘—๐‘Ž๐‘–๐‘๐‘–
๐‘’ ๐‘–|๐‘’ ๐‘— = ๐›ฟ๐‘–๐‘— =
1 ๐‘–๐‘“ ๐‘– = ๐‘—
0 ๐‘œ๐‘กโ„Ž๐‘’๐‘Ÿ๐‘ค๐‘–๐‘ ๐‘’
Orthonormal -mutually perpendicular and have unit length
๐‘–
๐‘’ ๐‘–๐‘’ ๐‘– = 1
What is an Operator?
Operator โ€“ a quantity that when acting on a vector ๐‘Ž
converts it into a vector ๐‘
๐’ช๐‘Ž = ๐‘
๐’ช ๐‘ฅ๐‘Ž + ๐‘ฆ๐‘ = ๐‘ฅ๐’ช๐‘Ž + ๐‘ฆ๐’ช๐‘
Linear Operator
Completely determined linear operator โ€“ its e ๐‘‚13 on every
possible vector is known
๐’ช๐‘’๐‘– =
๐‘—=1
3
๐‘’๐‘— ๐‘‚๐‘—๐‘–
๐‘‚ =
๐‘‚11 ๐‘‚12 ๐‘‚13
๐‘‚21 ๐‘‚22 ๐‘‚23
๐‘‚31 ๐‘‚32 ๐‘‚33
Matrix representation of ๐’ช in ๐‘’๐‘–
Permutation Operator
๐“Ÿ =
0 1 0
1 0 0
0 0 1
๐œ€1 =
0.354
โˆ’0.927
0.127
๐“Ÿ๐œ€1 =
0 1 0
1 0 0
0 0 1
0.354
โˆ’0.927
0.127
=
โˆ’0.927
0.354
0.127
๐“Ÿ๐œ€1 =
๐‘—=1
3
๐œ€๐‘—1 ๐‘ƒ๐‘—1
How to perform column permutations?
๐œ€2 =
0.612
0.12
โˆ’0.78
How to get P?
๐œ€ =
0.354 0.612 0.707
โˆ’0.927 0.127 0.354
0.127 โˆ’0.78 0.612
๐“Ÿ๐œ€ =
โˆ’0.927 0.127 0.354
0.354 0.612 0.707
0.127 โˆ’0.78 0.612
๐“Ÿ =
0 1 0
1 0 0
0 0 1
๐‘ƒ = ๐œ€ ๐“Ÿ ๐œ€ =
0.354 0.612 0.707
โˆ’0.927 0.127 0.354
0.127 โˆ’0.78 0.612
๐‘‡
๐“Ÿ๐œ€
๐‘ƒ =
โˆ’0.640 โˆ’0.621 โˆ’0.621
โˆ’0.621 0.764 โˆ’0.171
โˆ’0.452 โˆ’0.171 0.875
๐“Ÿ๐œ€๐‘– =
๐‘—=1
3
๐œ€๐‘— ๐‘ƒ๐‘—๐‘–
๐‘ƒ =
โˆ’0.640 โˆ’0.621 โˆ’0.621
โˆ’0.621 0.764 โˆ’0.171
โˆ’0.452 โˆ’0.171 0.875
๐“Ÿ =
0 1 0
1 0 0
0 0 1
๐œ€ =
0.354 0.612 0.707
โˆ’0.927 0.127 0.354
0.127 โˆ’0.78 0.612
๐“Ÿ๐œ€2 =
๐‘—=1
3
๐œ€๐‘— ๐‘ƒ๐‘—2
๐“Ÿ๐œ€2 =
0.127
0.612
โˆ’0.78
=
0.354
โˆ’0.927
0.127
โˆ’0.621 +
0.612
0.12
โˆ’0.78
0.764 +
0.707
0.354
0.612
โˆ’0.171
Rotation Operator
๐œ€ =
0.354 0.612 0.707
โˆ’0.927 0.127 0.354
0.127 โˆ’0.78 0.612
๐‘…๐‘ฅ๐‘ฆ =
0.707 0.000 0.707
โˆ’0.500 0.707 0.500
โˆ’0.5 โˆ’0.707 0.500
๐‘…๐‘ฅ๐‘ฆ๐œ€ =
0.340 โˆ’0.119 0.933
โˆ’0.769 โˆ’0.606 0.203
0.542 โˆ’0.786 โˆ’0.298
Matrix multiplication
๐“’ = ๐“๐“‘
๐“’๐‘’๐‘– =
๐‘—=1
3
๐‘’๐‘— ๐ถ๐‘—๐‘–
๐“๐“‘๐‘’๐‘– =
๐‘—=1
3
๐‘’๐‘— ๐ถ๐‘—๐‘–
๐“
๐‘—=1
3
๐‘’๐‘˜ ๐ต๐‘˜๐‘– =
๐‘—=1
3
๐‘’๐‘— ๐ถ๐‘—๐‘–
๐‘—=1
3
๐“๐‘’๐‘˜ ๐ต๐‘˜๐‘– =
๐‘—=1
3
๐‘’๐‘— ๐ถ๐‘—๐‘–
๐‘—=1
3
๐‘˜=1
3
๐‘’๐‘—๐ด๐‘—๐‘˜๐ต๐‘˜๐‘– =
๐‘—=1
3
๐‘’๐‘— ๐ถ๐‘—๐‘–
๐ถ๐‘—๐‘– =
๐‘˜=1
3
๐ด๐‘—๐‘˜๐ต๐‘˜๐‘–
Order of Matrix multiplication
๐“๐“‘ โ‰  ๐“‘๐“
Commutator of operators
Do not commute
๐ด, ๐ต = ๐ด๐ต โˆ’ ๐ต๐ด
Anti-commutator of operators
๐ด, ๐ต = ๐ด๐ต + ๐ต๐ด
Matrices : Definition
๐ด =
๐ด11 ๐ด12 โ‹ฏ ๐ด1๐‘€
๐ด21 ๐ด22 โ‹ฏ ๐ด2๐‘€
โ‹ฎ โ‹ฎ โ‹ฏ โ‹ฎ
๐ด๐‘1 ๐ด๐‘2 โ€ฆ ๐ด๐‘๐‘€
If N = M, matrix is square matrix
๐‘Ž =
๐‘Ž1
๐‘Ž2
โ‹ฎ
๐‘Ž๐‘
๐ด๐‘Ž = ๐‘ ๐‘๐‘– =
๐‘–=1
๐‘€
๐ด๐‘–๐‘—๐‘Ž๐‘—
Adjoint and Transpose
๐‘‚ =
๐‘‚11 ๐‘‚12 ๐‘‚13
๐‘‚21 ๐‘‚22 ๐‘‚23
๐‘‚31 ๐‘‚32 ๐‘‚33
๐‘‚๐‘‡
=
๐‘‚11 ๐‘‚21 ๐‘‚31
๐‘‚12 ๐‘‚22 ๐‘‚32
๐‘‚13 ๐‘‚23 ๐‘‚33
๐ด๐‘‡
๐‘–๐‘— = ๐ด๐‘—๐‘–
๐ดโ€ 
๐‘–๐‘—
๐‘‡
= ๐ดโˆ—
๐‘—๐‘–
Take complex conjugate of each
element and interchange the rows
interchange the rows
complex conjugate - the sign of the imaginary part of all its complex numbers have been changed
complex numbers
Complex numbers - extends the real numbers with a specific
element denoted i, called the imaginary unit.
๐‘– = โˆ’1 ๐‘–2
= โˆ’1
If a and b are real numbers, then ๐‘Ž + ๐‘๐‘– is a complex number
๐‘Ž + ๐‘๐‘–
The Complex Plane Basic operations
๐‘ง1 = ๐‘ฅ1 + ๐‘–๐‘ฆ1 ๐‘ง2 = ๐‘ฅ2 + ๐‘–๐‘ฆ2
๐‘ง1 + ๐‘ง2 = ๐‘ฅ1 + ๐‘ฅ1 + ๐‘– ๐‘ฆ1 + ๐‘ฆ2
๐‘ง1 โˆ’ ๐‘ง2 = ๐‘ฅ1 โˆ’ ๐‘ฅ1 + ๐‘– ๐‘ฆ1 โˆ’ ๐‘ฆ2
๐‘Ž๐‘ง1 = ๐‘Ž๐‘ฅ1 + ๐‘Ž๐‘–๐‘ฆ1
Definition in square Matrices
Diagonal matrix โ€“ all off diagonals are zero
Trace of matrix โ€“ sum of the diagonal elements
Unit matrix โ€“ Identity matrix, diagonal with 1 in diagonal
Inverse; ๐ดโˆ’1
๐ดโˆ’1
๐ด = ๐ด๐ดโˆ’1
= ๐ผ = 1
Unitary matrix
๐ดโˆ’1 = ๐ดโ€ 
Orthogonal matrix โ€“ real unitary matrix
Hermitian matrix โ€“ self adjoint ๐ด = ๐ดโ€ 
Symmetric matrix โ€“ real Hermitian matrix
Determinants
๐‘‘๐‘’๐‘ก ๐ด = ๐ด =
๐ด11 โ‹ฏ ๐ด1๐‘
โ‹ฎ โ‹ฎ โ‹ฎ
๐ด๐‘1 โ‹ฏ ๐ด๐‘๐‘
๐ด =
๐‘–=1
๐‘!
โˆ’1 ๐‘๐‘–
๐“Ÿ๐‘–๐ด11๐ด12 โ‹ฏ ๐ด๐‘๐‘
โˆ’1 0
๐ด11๐ด22๐ด33 + โˆ’1 1
๐ด12๐ด21๐ด33 +
โˆ’1 1
๐ด13๐ด22๐ด31 + โˆ’1 1
๐ด11๐ด23๐ด32
+ โˆ’1 2
๐ด13๐ด21๐ด32 + โˆ’1 2
๐ด12๐ด23๐ด31
๐ด11 ๐ด12 ๐ด13
๐ด21 ๐ด22 ๐ด23
๐ด31 ๐ด32 ๐ด33
=
N-dimensional vector spaces
๐‘’ |๐‘– ๐‘– = 1,2, โ€ฆ , ๐‘ |๐‘Ž =
๐‘–=1
๐‘
|๐‘– ๐‘Ž๐‘–
๐‘Ž =
๐‘Ž1
๐‘Ž2
โ‹ฎ
๐‘Ž๐‘
ket vectors
๐‘Žโ€  = ๐‘Ž1 ๐‘Ž2 โ‹ฏ ๐‘Ž๐‘
bra vectors
Braket notation
๐‘Ž||๐‘ = ๐‘Ž|๐‘ =
๐‘–=1
๐‘
๐‘Žโˆ—
๐‘–๐‘๐‘– = ๐‘Ž1 ๐‘Ž2 โ‹ฏ ๐‘Ž๐‘
๐‘1
๐‘2
โ‹ฎ
๐‘๐‘
๐‘Ž|๐‘Ž =
๐‘–=1
๐‘
๐‘Žโˆ—
๐‘–๐‘Ž๐‘– =
๐‘–=1
๐‘
๐‘Ž๐‘–
2
๐‘Ž =
๐‘Ž1
๐‘Ž2
โ‹ฎ
๐‘Ž๐‘
|๐‘Ž =
๐‘–=1
๐‘
|๐‘– ๐‘Ž๐‘–
๐‘Žโ€  = ๐‘Ž1 ๐‘Ž2 โ‹ฏ ๐‘Ž๐‘
๐‘Ž| =
๐‘–=1
๐‘
๐‘Ž๐‘–
โˆ— ๐‘–|
๐‘Ž|๐‘ =
๐‘–=1
๐‘
๐‘Ž๐‘–
โˆ— ๐‘–|
๐‘—=1
๐‘
|๐‘— ๐‘๐‘— =
๐‘–=1
๐‘
๐‘—=1
๐‘
๐‘Ž๐‘–
โˆ— ๐‘–|๐‘— ๐‘๐‘—
๐‘–|๐‘— = ๐›ฟ๐‘–๐‘—
How to determine components with respect to a basis?
|๐‘Ž =
๐‘–=1
๐‘
|๐‘– ๐‘Ž๐‘–
๐‘Ž| =
๐‘–=1
๐‘
๐‘Ž๐‘–
โˆ— ๐‘–|
๐‘Ž|๐‘— =
๐‘–=1
๐‘
๐‘Ž๐‘–
โˆ—
๐‘–|๐‘— ๐‘—|๐‘Ž =
๐‘–=1
๐‘
๐‘—|๐‘– ๐‘Ž๐‘–
๐‘Ž|๐‘— = ๐‘Ž๐‘—
โˆ— ๐‘—|๐‘Ž = ๐‘Ž๐‘—
|๐‘Ž =
๐‘–=1
๐‘
|๐‘– ๐‘–|๐‘Ž
๐‘Ž| =
๐‘–=1
๐‘
๐‘Ž|๐‘– ๐‘–|
๐‘–=1
๐‘
|๐‘– ๐‘–| = 1
Completeness of the basis
0.354
โˆ’0.927
0.127
0.354 โˆ’0.927 0.127 +
0.612
0.127
โˆ’0.78
0.612 0.127 โˆ’0.78 +
0.707
0.354
0.612
0.707 0.354 0.612 =
1 0 0
0 1 0
0 0 1
|๐‘– =
0.354 0.612 0.707
โˆ’0.927 0.127 0.354
0.127 โˆ’0.78 0.612 ๐‘–=1
๐‘
|๐‘– ๐‘–| = 1
๐’ช|๐‘Ž = |๐‘
๐’ช|๐‘– =
๐‘—
๐‘
|๐‘— ๐‘‚๐‘—๐‘–
๐‘‚ is the matrix representation
of ๐’ช in the basis |๐‘–
๐‘˜|๐’ช|๐‘– =
๐‘—
๐‘
๐‘˜|๐‘— ๐‘‚๐‘—๐‘– = ๐‘‚๐‘˜๐‘–
Using completeness relation
๐’ช|๐‘– = 1๐’ช|๐‘– =
๐‘–=1
๐‘
|๐‘– ๐‘–| ๐’ช|๐‘–
๐‘— ๐’ช|๐‘– = ๐‘— ๐’ช|๐‘– = ๐‘‚๐‘—๐‘–
๐“’ = ๐“๐“‘
๐‘–|๐“’|๐‘— = ๐‘–|๐“๐“‘|๐‘—
๐‘–|๐“1๐“‘|๐‘—
๐‘–|๐“
๐‘˜=1
๐‘
|๐‘˜ ๐‘˜| ๐“‘|๐‘—
๐‘˜=1
๐‘
๐‘–|๐“|๐‘˜ ๐‘˜| ๐“‘|๐‘—
๐ถ๐‘–๐‘— =
๐‘˜=1
๐‘
๐ด๐‘–๐‘˜๐ต๐‘˜๐‘—
Hermitian operator โ€“ self adjoint
๐’ชโˆ—โ€  = ๐’ช
Change of basis
We can express any ket in the basis |ฮฑ as a linear
combination of the kets in basis |๐‘–
|ฮฑ = 1|ฮฑ |ฮฑ =
๐‘–=1
๐‘
|๐‘– ๐‘–|ฮฑ |ฮฑ =
๐‘–=1
๐‘
|๐‘– ๐‘ˆ๐‘–โˆ
๐‘–|ฮฑ = ๐‘ˆ Transformation matrix
๐‘–|ฮฑ = ๐‘ˆ
Properties of transformation matrix
๐‘ˆโ€ ๐‘ˆ = 1 ๐‘ˆ๐‘ˆโ€  = 1
๐™Š, ๐žจ, Matrix representation two operators in
basis |๐‘– and โˆ respectively
๐žจ = ๐‘ˆ๐™Š๐‘ˆโ€  ๐™Š = ๐‘ˆโ€ ๐žจU

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PhyChem3_vector_matrix_mechanics.pptx

  • 2. Review of Mathematical Concepts 3D Vector โ€“ can be represented by specifying its components ๐‘Ž๐‘– with respect to a set of three mutually perpendicular unit vectors ๐‘’๐‘– as; ๐‘Ž = ๐‘’1๐‘Ž1 + ๐‘’2๐‘Ž2 + ๐‘’3๐‘Ž3 = ๐‘–=1 3 ๐‘’๐‘–๐‘Ž๐‘– the basis is not unique; ๐‘Ž = ๐œ€1๐‘Ž1 + ๐œ€2๐‘Ž2 + ๐œ€3๐‘Ž3 = ๐‘–=1 3 ๐œ€๐‘–๐‘Ž๐‘–
  • 3. ๐‘’ = 1 0 0 0 1 0 0 0 1 ๐œ€ = 0.354 0.612 0.707 โˆ’0.927 0.127 0.354 0.127 โˆ’0.78 0.612 Same vector under two basis ๐‘Ž1 ๐‘Ž2 ๐‘Ž3 = โˆ’0.5 0.5 0.75 ๐‘Ž1 ๐‘Ž2 ๐‘Ž3 = โˆ’0.55 โˆ’0.83 0.28 0.28 Red Blue Green -0.83 -0.55
  • 4. What is a basis ๐‘’ = 1 0 0 0 1 0 0 0 1 ๐‘’1 = 1 0 0 ๐‘’2 = 0 1 0 ๐‘’3 = 0 0 1 ๐œ€ = 0.354 0.612 0.707 โˆ’0.927 0.127 0.354 0.127 โˆ’0.78 0.612 ๐œ€1 = 0.354 โˆ’0.927 0.127 ๐œ€2 = 0.612 0.12 โˆ’0.78 ๐œ€3 = 0.707 0.354 0.612
  • 5. ๐‘Ž = ๐‘’1๐‘Ž1 + ๐‘’2๐‘Ž2 + ๐‘’3๐‘Ž3 = ๐‘–=1 3 ๐‘’๐‘–๐‘Ž๐‘– ๐‘Ž = 1 0 0 โˆ’0.5 + 0 1 0 0.5 + 1 0 0 0.75 = โˆ’0.5 0.5 0.75 ๐‘Ž = 0.354 โˆ’0.927 0.127 โˆ’0.55 + 0.612 0.12 โˆ’0.78 โˆ’0.83 + 0.707 0.354 0.612 0.28 ๐‘Ž = โˆ’0.5 0.5 0.75 ๐‘Ž = ๐‘’๐‘–|๐‘Ž๐‘– 0.354 0.612 0.707 โˆ’0.927 0.127 0.354 0.127 โˆ’0.78 0.612 ๐‘‡ โˆ’0.55 โˆ’0.83 0.28
  • 6. Properties of basis ๐‘’ ๐‘–|๐‘’ ๐‘— = 1 ๐‘–๐‘“ ๐‘– = ๐‘— 0 ๐‘œ๐‘กโ„Ž๐‘’๐‘Ÿ๐‘ค๐‘–๐‘ ๐‘’ 0.354 โˆ’0.927 0.127 0.612 0.12 โˆ’0.78 = 0 ๐‘’ = 1 0 0 0 1 0 0 0 1 ๐œ€ = 0.354 0.612 0.707 โˆ’0.927 0.127 0.354 0.127 โˆ’0.78 0.612 0.354 โˆ’0.927 0.127 0.354 โˆ’0.927 0.127 = 1
  • 7. ๐‘Ž = ๐‘’1๐‘Ž1 + ๐‘’2๐‘Ž2 + ๐‘’3๐‘Ž3 = ๐‘–=1 3 ๐‘’๐‘–๐‘Ž๐‘– ๐‘’๐‘—๐‘Ž = ๐‘Ž๐‘— ๐‘’ ๐‘–๐‘’ ๐‘— = 1 ๐‘–๐‘“ ๐‘– = ๐‘— 0 ๐‘œ๐‘กโ„Ž๐‘’๐‘Ÿ๐‘ค๐‘–๐‘ ๐‘’ ๐‘’ 2๐‘Ž = ๐‘’ 2๐‘’1๐‘Ž1 + ๐‘’ 2๐‘’2๐‘Ž2 + ๐‘’ 2๐‘’3๐‘Ž3 ๐‘’ 2๐‘Ž = 0 โˆ— ๐‘Ž1 + 1 โˆ— ๐‘Ž2 + 0 โˆ— ๐‘Ž3 ๐‘’ 2๐‘Ž = ๐‘Ž2 Since Properties of basis
  • 9. Scalar Product of Two Vectors ๐‘Ž โˆ— ๐‘ = ๐‘Ž1๐‘1 + ๐‘Ž2๐‘2 + ๐‘Ž3๐‘3 = ๐‘–=1 3 ๐‘Ž๐‘–๐‘๐‘– ๐‘Ž โˆ— ๐‘ = ๐‘– ๐‘— ๐‘’ ๐‘–๐‘’ ๐‘—๐‘Ž๐‘–๐‘๐‘– ๐‘’ ๐‘–|๐‘’ ๐‘— = ๐›ฟ๐‘–๐‘— = 1 ๐‘–๐‘“ ๐‘– = ๐‘— 0 ๐‘œ๐‘กโ„Ž๐‘’๐‘Ÿ๐‘ค๐‘–๐‘ ๐‘’ Orthonormal -mutually perpendicular and have unit length ๐‘– ๐‘’ ๐‘–๐‘’ ๐‘– = 1
  • 10. What is an Operator? Operator โ€“ a quantity that when acting on a vector ๐‘Ž converts it into a vector ๐‘ ๐’ช๐‘Ž = ๐‘ ๐’ช ๐‘ฅ๐‘Ž + ๐‘ฆ๐‘ = ๐‘ฅ๐’ช๐‘Ž + ๐‘ฆ๐’ช๐‘ Linear Operator Completely determined linear operator โ€“ its e ๐‘‚13 on every possible vector is known ๐’ช๐‘’๐‘– = ๐‘—=1 3 ๐‘’๐‘— ๐‘‚๐‘—๐‘– ๐‘‚ = ๐‘‚11 ๐‘‚12 ๐‘‚13 ๐‘‚21 ๐‘‚22 ๐‘‚23 ๐‘‚31 ๐‘‚32 ๐‘‚33 Matrix representation of ๐’ช in ๐‘’๐‘–
  • 11. Permutation Operator ๐“Ÿ = 0 1 0 1 0 0 0 0 1 ๐œ€1 = 0.354 โˆ’0.927 0.127 ๐“Ÿ๐œ€1 = 0 1 0 1 0 0 0 0 1 0.354 โˆ’0.927 0.127 = โˆ’0.927 0.354 0.127 ๐“Ÿ๐œ€1 = ๐‘—=1 3 ๐œ€๐‘—1 ๐‘ƒ๐‘—1 How to perform column permutations? ๐œ€2 = 0.612 0.12 โˆ’0.78 How to get P?
  • 12. ๐œ€ = 0.354 0.612 0.707 โˆ’0.927 0.127 0.354 0.127 โˆ’0.78 0.612 ๐“Ÿ๐œ€ = โˆ’0.927 0.127 0.354 0.354 0.612 0.707 0.127 โˆ’0.78 0.612 ๐“Ÿ = 0 1 0 1 0 0 0 0 1 ๐‘ƒ = ๐œ€ ๐“Ÿ ๐œ€ = 0.354 0.612 0.707 โˆ’0.927 0.127 0.354 0.127 โˆ’0.78 0.612 ๐‘‡ ๐“Ÿ๐œ€ ๐‘ƒ = โˆ’0.640 โˆ’0.621 โˆ’0.621 โˆ’0.621 0.764 โˆ’0.171 โˆ’0.452 โˆ’0.171 0.875
  • 13. ๐“Ÿ๐œ€๐‘– = ๐‘—=1 3 ๐œ€๐‘— ๐‘ƒ๐‘—๐‘– ๐‘ƒ = โˆ’0.640 โˆ’0.621 โˆ’0.621 โˆ’0.621 0.764 โˆ’0.171 โˆ’0.452 โˆ’0.171 0.875 ๐“Ÿ = 0 1 0 1 0 0 0 0 1 ๐œ€ = 0.354 0.612 0.707 โˆ’0.927 0.127 0.354 0.127 โˆ’0.78 0.612 ๐“Ÿ๐œ€2 = ๐‘—=1 3 ๐œ€๐‘— ๐‘ƒ๐‘—2 ๐“Ÿ๐œ€2 = 0.127 0.612 โˆ’0.78 = 0.354 โˆ’0.927 0.127 โˆ’0.621 + 0.612 0.12 โˆ’0.78 0.764 + 0.707 0.354 0.612 โˆ’0.171
  • 15. ๐œ€ = 0.354 0.612 0.707 โˆ’0.927 0.127 0.354 0.127 โˆ’0.78 0.612 ๐‘…๐‘ฅ๐‘ฆ = 0.707 0.000 0.707 โˆ’0.500 0.707 0.500 โˆ’0.5 โˆ’0.707 0.500 ๐‘…๐‘ฅ๐‘ฆ๐œ€ = 0.340 โˆ’0.119 0.933 โˆ’0.769 โˆ’0.606 0.203 0.542 โˆ’0.786 โˆ’0.298
  • 16.
  • 17. Matrix multiplication ๐“’ = ๐“๐“‘ ๐“’๐‘’๐‘– = ๐‘—=1 3 ๐‘’๐‘— ๐ถ๐‘—๐‘– ๐“๐“‘๐‘’๐‘– = ๐‘—=1 3 ๐‘’๐‘— ๐ถ๐‘—๐‘– ๐“ ๐‘—=1 3 ๐‘’๐‘˜ ๐ต๐‘˜๐‘– = ๐‘—=1 3 ๐‘’๐‘— ๐ถ๐‘—๐‘– ๐‘—=1 3 ๐“๐‘’๐‘˜ ๐ต๐‘˜๐‘– = ๐‘—=1 3 ๐‘’๐‘— ๐ถ๐‘—๐‘– ๐‘—=1 3 ๐‘˜=1 3 ๐‘’๐‘—๐ด๐‘—๐‘˜๐ต๐‘˜๐‘– = ๐‘—=1 3 ๐‘’๐‘— ๐ถ๐‘—๐‘– ๐ถ๐‘—๐‘– = ๐‘˜=1 3 ๐ด๐‘—๐‘˜๐ต๐‘˜๐‘–
  • 18. Order of Matrix multiplication ๐“๐“‘ โ‰  ๐“‘๐“ Commutator of operators Do not commute ๐ด, ๐ต = ๐ด๐ต โˆ’ ๐ต๐ด Anti-commutator of operators ๐ด, ๐ต = ๐ด๐ต + ๐ต๐ด
  • 19. Matrices : Definition ๐ด = ๐ด11 ๐ด12 โ‹ฏ ๐ด1๐‘€ ๐ด21 ๐ด22 โ‹ฏ ๐ด2๐‘€ โ‹ฎ โ‹ฎ โ‹ฏ โ‹ฎ ๐ด๐‘1 ๐ด๐‘2 โ€ฆ ๐ด๐‘๐‘€ If N = M, matrix is square matrix ๐‘Ž = ๐‘Ž1 ๐‘Ž2 โ‹ฎ ๐‘Ž๐‘ ๐ด๐‘Ž = ๐‘ ๐‘๐‘– = ๐‘–=1 ๐‘€ ๐ด๐‘–๐‘—๐‘Ž๐‘—
  • 20. Adjoint and Transpose ๐‘‚ = ๐‘‚11 ๐‘‚12 ๐‘‚13 ๐‘‚21 ๐‘‚22 ๐‘‚23 ๐‘‚31 ๐‘‚32 ๐‘‚33 ๐‘‚๐‘‡ = ๐‘‚11 ๐‘‚21 ๐‘‚31 ๐‘‚12 ๐‘‚22 ๐‘‚32 ๐‘‚13 ๐‘‚23 ๐‘‚33 ๐ด๐‘‡ ๐‘–๐‘— = ๐ด๐‘—๐‘– ๐ดโ€  ๐‘–๐‘— ๐‘‡ = ๐ดโˆ— ๐‘—๐‘– Take complex conjugate of each element and interchange the rows interchange the rows complex conjugate - the sign of the imaginary part of all its complex numbers have been changed
  • 21. complex numbers Complex numbers - extends the real numbers with a specific element denoted i, called the imaginary unit. ๐‘– = โˆ’1 ๐‘–2 = โˆ’1 If a and b are real numbers, then ๐‘Ž + ๐‘๐‘– is a complex number ๐‘Ž + ๐‘๐‘– The Complex Plane Basic operations ๐‘ง1 = ๐‘ฅ1 + ๐‘–๐‘ฆ1 ๐‘ง2 = ๐‘ฅ2 + ๐‘–๐‘ฆ2 ๐‘ง1 + ๐‘ง2 = ๐‘ฅ1 + ๐‘ฅ1 + ๐‘– ๐‘ฆ1 + ๐‘ฆ2 ๐‘ง1 โˆ’ ๐‘ง2 = ๐‘ฅ1 โˆ’ ๐‘ฅ1 + ๐‘– ๐‘ฆ1 โˆ’ ๐‘ฆ2 ๐‘Ž๐‘ง1 = ๐‘Ž๐‘ฅ1 + ๐‘Ž๐‘–๐‘ฆ1
  • 22. Definition in square Matrices Diagonal matrix โ€“ all off diagonals are zero Trace of matrix โ€“ sum of the diagonal elements Unit matrix โ€“ Identity matrix, diagonal with 1 in diagonal Inverse; ๐ดโˆ’1 ๐ดโˆ’1 ๐ด = ๐ด๐ดโˆ’1 = ๐ผ = 1 Unitary matrix ๐ดโˆ’1 = ๐ดโ€  Orthogonal matrix โ€“ real unitary matrix
  • 23. Hermitian matrix โ€“ self adjoint ๐ด = ๐ดโ€  Symmetric matrix โ€“ real Hermitian matrix Determinants ๐‘‘๐‘’๐‘ก ๐ด = ๐ด = ๐ด11 โ‹ฏ ๐ด1๐‘ โ‹ฎ โ‹ฎ โ‹ฎ ๐ด๐‘1 โ‹ฏ ๐ด๐‘๐‘ ๐ด = ๐‘–=1 ๐‘! โˆ’1 ๐‘๐‘– ๐“Ÿ๐‘–๐ด11๐ด12 โ‹ฏ ๐ด๐‘๐‘ โˆ’1 0 ๐ด11๐ด22๐ด33 + โˆ’1 1 ๐ด12๐ด21๐ด33 + โˆ’1 1 ๐ด13๐ด22๐ด31 + โˆ’1 1 ๐ด11๐ด23๐ด32 + โˆ’1 2 ๐ด13๐ด21๐ด32 + โˆ’1 2 ๐ด12๐ด23๐ด31 ๐ด11 ๐ด12 ๐ด13 ๐ด21 ๐ด22 ๐ด23 ๐ด31 ๐ด32 ๐ด33 =
  • 24. N-dimensional vector spaces ๐‘’ |๐‘– ๐‘– = 1,2, โ€ฆ , ๐‘ |๐‘Ž = ๐‘–=1 ๐‘ |๐‘– ๐‘Ž๐‘– ๐‘Ž = ๐‘Ž1 ๐‘Ž2 โ‹ฎ ๐‘Ž๐‘ ket vectors ๐‘Žโ€  = ๐‘Ž1 ๐‘Ž2 โ‹ฏ ๐‘Ž๐‘ bra vectors Braket notation ๐‘Ž||๐‘ = ๐‘Ž|๐‘ = ๐‘–=1 ๐‘ ๐‘Žโˆ— ๐‘–๐‘๐‘– = ๐‘Ž1 ๐‘Ž2 โ‹ฏ ๐‘Ž๐‘ ๐‘1 ๐‘2 โ‹ฎ ๐‘๐‘ ๐‘Ž|๐‘Ž = ๐‘–=1 ๐‘ ๐‘Žโˆ— ๐‘–๐‘Ž๐‘– = ๐‘–=1 ๐‘ ๐‘Ž๐‘– 2
  • 25. ๐‘Ž = ๐‘Ž1 ๐‘Ž2 โ‹ฎ ๐‘Ž๐‘ |๐‘Ž = ๐‘–=1 ๐‘ |๐‘– ๐‘Ž๐‘– ๐‘Žโ€  = ๐‘Ž1 ๐‘Ž2 โ‹ฏ ๐‘Ž๐‘ ๐‘Ž| = ๐‘–=1 ๐‘ ๐‘Ž๐‘– โˆ— ๐‘–| ๐‘Ž|๐‘ = ๐‘–=1 ๐‘ ๐‘Ž๐‘– โˆ— ๐‘–| ๐‘—=1 ๐‘ |๐‘— ๐‘๐‘— = ๐‘–=1 ๐‘ ๐‘—=1 ๐‘ ๐‘Ž๐‘– โˆ— ๐‘–|๐‘— ๐‘๐‘— ๐‘–|๐‘— = ๐›ฟ๐‘–๐‘—
  • 26. How to determine components with respect to a basis? |๐‘Ž = ๐‘–=1 ๐‘ |๐‘– ๐‘Ž๐‘– ๐‘Ž| = ๐‘–=1 ๐‘ ๐‘Ž๐‘– โˆ— ๐‘–| ๐‘Ž|๐‘— = ๐‘–=1 ๐‘ ๐‘Ž๐‘– โˆ— ๐‘–|๐‘— ๐‘—|๐‘Ž = ๐‘–=1 ๐‘ ๐‘—|๐‘– ๐‘Ž๐‘– ๐‘Ž|๐‘— = ๐‘Ž๐‘— โˆ— ๐‘—|๐‘Ž = ๐‘Ž๐‘— |๐‘Ž = ๐‘–=1 ๐‘ |๐‘– ๐‘–|๐‘Ž ๐‘Ž| = ๐‘–=1 ๐‘ ๐‘Ž|๐‘– ๐‘–| ๐‘–=1 ๐‘ |๐‘– ๐‘–| = 1 Completeness of the basis
  • 27. 0.354 โˆ’0.927 0.127 0.354 โˆ’0.927 0.127 + 0.612 0.127 โˆ’0.78 0.612 0.127 โˆ’0.78 + 0.707 0.354 0.612 0.707 0.354 0.612 = 1 0 0 0 1 0 0 0 1 |๐‘– = 0.354 0.612 0.707 โˆ’0.927 0.127 0.354 0.127 โˆ’0.78 0.612 ๐‘–=1 ๐‘ |๐‘– ๐‘–| = 1
  • 28. ๐’ช|๐‘Ž = |๐‘ ๐’ช|๐‘– = ๐‘— ๐‘ |๐‘— ๐‘‚๐‘—๐‘– ๐‘‚ is the matrix representation of ๐’ช in the basis |๐‘– ๐‘˜|๐’ช|๐‘– = ๐‘— ๐‘ ๐‘˜|๐‘— ๐‘‚๐‘—๐‘– = ๐‘‚๐‘˜๐‘– Using completeness relation ๐’ช|๐‘– = 1๐’ช|๐‘– = ๐‘–=1 ๐‘ |๐‘– ๐‘–| ๐’ช|๐‘– ๐‘— ๐’ช|๐‘– = ๐‘— ๐’ช|๐‘– = ๐‘‚๐‘—๐‘– ๐“’ = ๐“๐“‘ ๐‘–|๐“’|๐‘— = ๐‘–|๐“๐“‘|๐‘— ๐‘–|๐“1๐“‘|๐‘— ๐‘–|๐“ ๐‘˜=1 ๐‘ |๐‘˜ ๐‘˜| ๐“‘|๐‘— ๐‘˜=1 ๐‘ ๐‘–|๐“|๐‘˜ ๐‘˜| ๐“‘|๐‘— ๐ถ๐‘–๐‘— = ๐‘˜=1 ๐‘ ๐ด๐‘–๐‘˜๐ต๐‘˜๐‘—
  • 29. Hermitian operator โ€“ self adjoint ๐’ชโˆ—โ€  = ๐’ช Change of basis We can express any ket in the basis |ฮฑ as a linear combination of the kets in basis |๐‘– |ฮฑ = 1|ฮฑ |ฮฑ = ๐‘–=1 ๐‘ |๐‘– ๐‘–|ฮฑ |ฮฑ = ๐‘–=1 ๐‘ |๐‘– ๐‘ˆ๐‘–โˆ ๐‘–|ฮฑ = ๐‘ˆ Transformation matrix
  • 30. ๐‘–|ฮฑ = ๐‘ˆ Properties of transformation matrix ๐‘ˆโ€ ๐‘ˆ = 1 ๐‘ˆ๐‘ˆโ€  = 1 ๐™Š, ๐žจ, Matrix representation two operators in basis |๐‘– and โˆ respectively ๐žจ = ๐‘ˆ๐™Š๐‘ˆโ€  ๐™Š = ๐‘ˆโ€ ๐žจU