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pH value increases as [H+] value decreases;
pH= -log([H+]) = -log(10-8) =8 ;
we know that,
[H20]=[H+][OH-]=[10-14]
applying -log on both sides,
pH + pOH =14
there fore,
1) when pH=5 , pOH=9
2)when pH=8 , pOH =6
Solution
pH value increases as [H+] value decreases;
pH= -log([H+]) = -log(10-8) =8 ;
we know that,
[H20]=[H+][OH-]=[10-14]
applying -log on both sides,
pH + pOH =14
there fore,
1) when pH=5 , pOH=9
2)when pH=8 , pOH =6

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pH value increases as [H+] value decreases; pH= -log([H+]) = -lo.pdf

  • 1. pH value increases as [H+] value decreases; pH= -log([H+]) = -log(10-8) =8 ; we know that, [H20]=[H+][OH-]=[10-14] applying -log on both sides, pH + pOH =14 there fore, 1) when pH=5 , pOH=9 2)when pH=8 , pOH =6 Solution pH value increases as [H+] value decreases; pH= -log([H+]) = -log(10-8) =8 ; we know that, [H20]=[H+][OH-]=[10-14] applying -log on both sides, pH + pOH =14 there fore, 1) when pH=5 , pOH=9 2)when pH=8 , pOH =6