Pb3O4 decomposes into lead (II) oxide (PbO) and lead (IV) oxide (Pb2O3) with the decomposition reaction shown. The mole ratio of lead (II) to lead (IV) in this decomposition is 1:1 according to the balanced equation Pb3O4 --> PbO + Pb2O3.
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Pb3O4 -- PbO + Pb2O3 hence the mole ratio of le.pdf
1. Pb3O4 --> PbO + Pb2O3 hence the mole ratio of lead (II) to lead (IV) = 1:1
Solution
Pb3O4 --> PbO + Pb2O3 hence the mole ratio of lead (II) to lead (IV) = 1:1