The document describes the rules of Tic-Tac-Toe (OOXX) game. It is a 3x3 grid game where two players take turns marking spaces with "O" or "X" symbols. The first player to mark 3 of their symbols in a row (horizontal, vertical or diagonal) wins. If all 9 spaces are filled without a winner, the game ends in a draw. The document then provides code for a C# OOXX game program that implements these rules.

1. OOXX電 機 2 B
第 十 組
102103224 許嘉玳
102103244 李偉弘
102103245 許峻杰
102103251 游馭成

2. 井字遊戲(又稱OOXX)
 一個是圈(O)，一個是叉(X)，輪流在3x3的方格上點自己的
符號。
 最先以橫線、直線、斜線連成者，皆為獲勝的一方。
 當九格都填滿雙方平手。
 分出勝負才能按

3. namespace OOXX
{
public partial class MainWindow : Window
{
bool turn = true; // true = "X"; false = "O";
int turn_conut = 0; //被點擊按鈕計數
Image pic;
BitmapImage bit;
Record rec;
public MainWindow()
{
InitializeComponent();
}
private void Window_Loaded(object sender, RoutedEventArgs e)
{
againButton.IsEnabled = false;
rec = new Record();
}
private void button_Click(object sender, RoutedEventArgs e)
{
Button btn = (Button)sender;
if (turn)
{
loadImage(“X”); //讀取O.png或X.png圖檔
btn.Content = pic; //將圖檔賦予給Content
rec.ROW(btn.Name,‘X’); //堆入暫存器(一維陣列)
}
else
{
loadImage("O"); //讀取O.png或X.png圖檔
btn.Content = pic; //將圖檔賦予給Content
rec.ROW(btn.Name, 'O'); //堆入暫存器(一維陣列)
}
btn.IsEnabled = false;
turn_conut++;
check_Winner();
turn = !turn;
}
共
用
同
事
件
省
程
式
碼

4. private void button_MouseEnter(object sender, System.Windows.Input.MouseEventArgs e)
{
Button btn = (Button)sender;
if (btn.IsEnabled)
{
if (turn)
{
loadImage("X");
btn.Content = pic;
}
else
{
loadImage("O");
btn.Content = pic;
}
}
}
private void button_Leave(object sender, System.Windows.Input.MouseEventArgs e)
{
Button btn = (Button)sender;
if (btn.IsEnabled)
btn.Content = "";
}
private void loadImage(string i)
{
pic = new Image();
bit = new BitmapImage();
bit.BeginInit();
bit.UriSource = new Uri("Images/" + i.ToString() + ".png", UriKind.Relative);
bit.EndInit();
pic.Stretch = Stretch.Fill;
pic.Source = bit;
}

5. namespace OOXX
{
class Record
{
public char[] nineGrid=new char[9];
public void ROW(string Grid, char Both)//例如丟入Record.ROW(A1, 'O');
{
switch (Grid)
{
case "A1":
nineGrid[0] = Both;
break;
case "A2":
nineGrid[1] = Both;
break;
case "A3":
nineGrid[2] = Both;
break;
case "B1":
nineGrid[3] = Both;
break;
case "B2":
nineGrid[4] = Both;
break;
case "B3":
nineGrid[5] = Both;
break;
case "C1":
nineGrid[6] = Both;
break;
case "C2":
nineGrid[7] = Both;
break;
case "C3":
nineGrid[8] = Both;
break;
}
btn.Content = pic;此屬性已是圖檔
將圖檔ToString()轉成字串，不管是OX圖片
都是”System.Window.Contorl.Image”
還有其他疑難雜症…所以就想到…
土法煉鋼法
程式碼又長又臭~~

6. private void check_Winner()
{
bool born_Winner = false; //有贏家true 沒贏家false
//九宮格暫存器的水平連線判斷
if ((rec.nineGrid[0] == rec.nineGrid[1]) && (rec.nineGrid[1] == rec.nineGrid[2]) && (!A1.IsEnabled))
born_Winner = true;
else if ((rec.nineGrid[3] == rec.nineGrid[4]) && (rec.nineGrid[4] == rec.nineGrid[5]) && (!B1.IsEnabled))
born_Winner = true;
else if ((rec.nineGrid[6] == rec.nineGrid[7]) && (rec.nineGrid[7] == rec.nineGrid[8]) && (!C1.IsEnabled))
born_Winner = true;
//九宮格暫存器的垂直連線判斷
else if ((rec.nineGrid[0] == rec.nineGrid[3]) && (rec.nineGrid[3] == rec.nineGrid[6]) && (!A1.IsEnabled))
born_Winner = true;
else if ((rec.nineGrid[1] == rec.nineGrid[4]) && (rec.nineGrid[4] == rec.nineGrid[7]) && (!A2.IsEnabled))
born_Winner = true;
else if ((rec.nineGrid[2] == rec.nineGrid[5]) && (rec.nineGrid[5] == rec.nineGrid[8]) && (!A3.IsEnabled))
born_Winner = true;
//九宮格暫存器的橫向連線判斷
else if ((rec.nineGrid[0] == rec.nineGrid[4]) && (rec.nineGrid[4] == rec.nineGrid[8]) && (!A1.IsEnabled))
born_Winner = true;
else if ((rec.nineGrid[2] == rec.nineGrid[4]) && (rec.nineGrid[4] == rec.nineGrid[6]) && (!A3.IsEnabled))
born_Winner = true;

7. if (born_Winner)
{
if (turn) //true:"X" ; false:"O"
{
MessageBox.Show("贏家是【X】一方", "恭喜");
disable();
}
else
{
MessageBox.Show("贏家是【O】一方", "恭喜");
disable();
}
}
else if (turn_conut == 9)
{
MessageBox.Show("平手!!!", "Notice");
disable();
}
}
private void disable()
{
//參考http://blog.sina.com.cn/s/blog_87398e6701013j5y.html
foreach (UIElement element in gridUCContent.Children)//進行遍歷
{
if (element is Button)
{
element.IsEnabled = false;
againButton.IsEnabled = true;
}
}
}

8. private void againButton_Click(object sender, RoutedEventArgs e)
{
againButton.IsEnabled = false;
turn = true;
turn_conut = 0;
Array.Clear(rec.nineGrid, 0, 9); //九宮格暫存器歸零
A1.Content = ""; A2.Content = ""; A3.Content = "";
B1.Content = ""; B2.Content = ""; B3.Content = "";
C1.Content = ""; C2.Content = ""; C3.Content = "";
foreach (UIElement element in gridUCContent.Children)//進行遍歷
{
if (element is Button)
{
if(!(element == againButton))
element.IsEnabled = true;
}
}
}

9. 心得與反省
●以 純字串，判斷輸贏跟顯示太容易沒挑戰性
●採用 來顯示遇到許多困難，測試很久才解決
●太依賴VS C#寫好的物件，反而沒想到直接用C語言
時學的array、swith等
●有時小專案對各狀態逐一key上程式沒關係，
這樣才不會陷入思考的迴圈，除非你要寫演算法
●學到共同事件的用法