Nucleophile is any negative ion or any neutral mo.pdf
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Nucleophile is any negative ion or any neutral molecule that has at least one unshared electron pair. Alkene act as a Nucleophile Halide ion act as a Nucleophile Sodium borohydride is the transfer of a hydride ion, from the metal to the carbonyl carbon. In this transfer the hydride ion acts as nucleophile. Solution Nucleophile is any negative ion or any neutral molecule that has at least one unshared electron pair. Alkene act as a Nucleophile Halide ion act as a Nucleophile Sodium borohydride is the transfer of a hydride ion, from the metal to the carbonyl carbon. In this transfer the hydride ion acts as nucleophile..
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C ) common in nature, but commonly used psychological measures rare.pdf
C ) common in nature, but commonly used psychological measures rarely yield normally
distributed scores
Solution
C ) common in nature, but commonly used psychological measures rarely yield normally
distributed scores.
Question evidence 1. Comparison of DNA sequences among single-ce.pdf
Question evidence 1. Comparison of DNA sequences among single-celled organisms
suggests that eukaryotes are more closely related to archaea than to bacteria. Bioinformatics 2.
The oldest known and most primitive bird is the 150-million-year old Archaeopteryx. Its remains
display feathered wings, but its skeleton is otherwise similar to the two-legged dinosaurs that
lived at that time. Fossil record 3. The skulls of humans and other primates have the same basic
layout of bones, even though the heads are drastically different sizes and shapes. comparative
anatomy. Comparative anatomy 4. Most of the animals found on the island of Madagascar are
found nowhere else, indicating they evolved from ancestral populations after Madagascar was
biogeography isolated from other continents. Biogeography 5. Remains of a 365 million year
old organi named Ichthyostega include features that suggest it me in water and on land,
indicating that a transitional species becween fish and land-dwelling amphibians. Fossil record
6. The amino acid sequence of human hemoglobin is more similar to the sequence of hemoglobin
from dogs than it is to the sequence from fish Bioinformatics 7. Fossils of some species of
reptile are found only in West Africa and Brazil, even though these locations are currently
separated by thousands of miles of Atlantic ocean. Biogeography
Solution
Question evidence 1. Comparison of DNA sequences among single-celled organisms
suggests that eukaryotes are more closely related to archaea than to bacteria. Bioinformatics 2.
The oldest known and most primitive bird is the 150-million-year old Archaeopteryx. Its remains
display feathered wings, but its skeleton is otherwise similar to the two-legged dinosaurs that
lived at that time. Fossil record 3. The skulls of humans and other primates have the same basic
layout of bones, even though the heads are drastically different sizes and shapes. comparative
anatomy. Comparative anatomy 4. Most of the animals found on the island of Madagascar are
found nowhere else, indicating they evolved from ancestral populations after Madagascar was
biogeography isolated from other continents. Biogeography 5. Remains of a 365 million year
old organi named Ichthyostega include features that suggest it me in water and on land,
indicating that a transitional species becween fish and land-dwelling amphibians. Fossil record
6. The amino acid sequence of human hemoglobin is more similar to the sequence of hemoglobin
from dogs than it is to the sequence from fish Bioinformatics 7. Fossils of some species of
reptile are found only in West Africa and Brazil, even though these locations are currently
separated by thousands of miles of Atlantic ocean. Biogeography.
The purpose of alchol (ethanol) is to dissolve io.pdf
The purpose of alchol (ethanol) is to dissolve iodine in it as iodine does not dissolve
in water.
Solution
The purpose of alchol (ethanol) is to dissolve iodine in it as iodine does not dissolve
in water..
The components may not separate properly, because.pdf
The components may not separate properly, because the solvent will overload
Solution
The components may not separate properly, because the solvent will overload.
The answer would be 5 because Dehydration in a .pdf
The answer would be 5 because: Dehydration in a secondary alcohol usually reacts
via E1 reactions. In E1 reactions, rearrangements occur if possible so although the product
assumed would be 1, a methyl shift occurs. One of the methyl groups from the tertiary carbon
shifts when the molecule is a carbocation, so that the carbocation becomes not a secondary but a
tertiary carbocation. Pictures would make it easier to visualize, but if you look up E1 reactions,
you will understand how rearrangements work.
Solution
The answer would be 5 because: Dehydration in a secondary alcohol usually reacts
via E1 reactions. In E1 reactions, rearrangements occur if possible so although the product
assumed would be 1, a methyl shift occurs. One of the methyl groups from the tertiary carbon
shifts when the molecule is a carbocation, so that the carbocation becomes not a secondary but a
tertiary carbocation. Pictures would make it easier to visualize, but if you look up E1 reactions,
you will understand how rearrangements work..
Moles of acid (HNO2) = Vol conc = 0.52 = 1 mol.pdf
Moles of acid (HNO2) = Vol * conc = 0.5*2 = 1 mole Moles of salt = 140 / MM =
2 moles pH = pKa + log (salt / acid) = - log (Ka) + log (salt/acid) = - log (5*10^-4) + log (2/1)
= 3.602
Solution
Moles of acid (HNO2) = Vol * conc = 0.5*2 = 1 mole Moles of salt = 140 / MM =
2 moles pH = pKa + log (salt / acid) = - log (Ka) + log (salt/acid) = - log (5*10^-4) + log (2/1)
= 3.602.
it is a salt formed by KOH and HCl it is a neutra.pdf
it is a salt formed by KOH and HCl it is a neutral salt since both are strong
Solution
it is a salt formed by KOH and HCl it is a neutral salt since both are strong.
Recommended
C ) common in nature, but commonly used psychological measures rare.pdf
C ) common in nature, but commonly used psychological measures rarely yield normally
distributed scores
Solution
C ) common in nature, but commonly used psychological measures rarely yield normally
distributed scores.
Question evidence 1. Comparison of DNA sequences among single-ce.pdf
Question evidence 1. Comparison of DNA sequences among single-celled organisms
suggests that eukaryotes are more closely related to archaea than to bacteria. Bioinformatics 2.
The oldest known and most primitive bird is the 150-million-year old Archaeopteryx. Its remains
display feathered wings, but its skeleton is otherwise similar to the two-legged dinosaurs that
lived at that time. Fossil record 3. The skulls of humans and other primates have the same basic
layout of bones, even though the heads are drastically different sizes and shapes. comparative
anatomy. Comparative anatomy 4. Most of the animals found on the island of Madagascar are
found nowhere else, indicating they evolved from ancestral populations after Madagascar was
biogeography isolated from other continents. Biogeography 5. Remains of a 365 million year
old organi named Ichthyostega include features that suggest it me in water and on land,
indicating that a transitional species becween fish and land-dwelling amphibians. Fossil record
6. The amino acid sequence of human hemoglobin is more similar to the sequence of hemoglobin
from dogs than it is to the sequence from fish Bioinformatics 7. Fossils of some species of
reptile are found only in West Africa and Brazil, even though these locations are currently
separated by thousands of miles of Atlantic ocean. Biogeography
Solution
Question evidence 1. Comparison of DNA sequences among single-celled organisms
suggests that eukaryotes are more closely related to archaea than to bacteria. Bioinformatics 2.
The oldest known and most primitive bird is the 150-million-year old Archaeopteryx. Its remains
display feathered wings, but its skeleton is otherwise similar to the two-legged dinosaurs that
lived at that time. Fossil record 3. The skulls of humans and other primates have the same basic
layout of bones, even though the heads are drastically different sizes and shapes. comparative
anatomy. Comparative anatomy 4. Most of the animals found on the island of Madagascar are
found nowhere else, indicating they evolved from ancestral populations after Madagascar was
biogeography isolated from other continents. Biogeography 5. Remains of a 365 million year
old organi named Ichthyostega include features that suggest it me in water and on land,
indicating that a transitional species becween fish and land-dwelling amphibians. Fossil record
6. The amino acid sequence of human hemoglobin is more similar to the sequence of hemoglobin
from dogs than it is to the sequence from fish Bioinformatics 7. Fossils of some species of
reptile are found only in West Africa and Brazil, even though these locations are currently
separated by thousands of miles of Atlantic ocean. Biogeography.
The purpose of alchol (ethanol) is to dissolve io.pdf
The purpose of alchol (ethanol) is to dissolve iodine in it as iodine does not dissolve
in water.
Solution
The purpose of alchol (ethanol) is to dissolve iodine in it as iodine does not dissolve
in water..
The components may not separate properly, because.pdf
The components may not separate properly, because the solvent will overload
Solution
The components may not separate properly, because the solvent will overload.
The answer would be 5 because Dehydration in a .pdf
The answer would be 5 because: Dehydration in a secondary alcohol usually reacts
via E1 reactions. In E1 reactions, rearrangements occur if possible so although the product
assumed would be 1, a methyl shift occurs. One of the methyl groups from the tertiary carbon
shifts when the molecule is a carbocation, so that the carbocation becomes not a secondary but a
tertiary carbocation. Pictures would make it easier to visualize, but if you look up E1 reactions,
you will understand how rearrangements work.
Solution
The answer would be 5 because: Dehydration in a secondary alcohol usually reacts
via E1 reactions. In E1 reactions, rearrangements occur if possible so although the product
assumed would be 1, a methyl shift occurs. One of the methyl groups from the tertiary carbon
shifts when the molecule is a carbocation, so that the carbocation becomes not a secondary but a
tertiary carbocation. Pictures would make it easier to visualize, but if you look up E1 reactions,
you will understand how rearrangements work..
Moles of acid (HNO2) = Vol conc = 0.52 = 1 mol.pdf
Moles of acid (HNO2) = Vol * conc = 0.5*2 = 1 mole Moles of salt = 140 / MM =
2 moles pH = pKa + log (salt / acid) = - log (Ka) + log (salt/acid) = - log (5*10^-4) + log (2/1)
= 3.602
Solution
Moles of acid (HNO2) = Vol * conc = 0.5*2 = 1 mole Moles of salt = 140 / MM =
2 moles pH = pKa + log (salt / acid) = - log (Ka) + log (salt/acid) = - log (5*10^-4) + log (2/1)
= 3.602.
it is a salt formed by KOH and HCl it is a neutra.pdf
it is a salt formed by KOH and HCl it is a neutral salt since both are strong
Solution
it is a salt formed by KOH and HCl it is a neutral salt since both are strong.
Cultural competence refers to an ability to inter.pdf
Cultural competence refers to an ability to interact effectively with people of
different cultures and socio-economic backgrounds, particularly in the context of human
resources, non-profit organizations, and government agencies whose employees work with
persons from different cultural/ethnic backgrounds. Cultural competence comprises four
components: (a) Awareness of one\'s own cultural worldview, (b) Attitude towards cultural
differences, (c) Knowledge of different cultural practices and worldviews, and (d) Cross-cultural
skills. Developing cultural competence results in an ability to understand, communicate with,
and effectively interact with people across cultures.[1]
Solution
Cultural competence refers to an ability to interact effectively with people of
different cultures and socio-economic backgrounds, particularly in the context of human
resources, non-profit organizations, and government agencies whose employees work with
persons from different cultural/ethnic backgrounds. Cultural competence comprises four
components: (a) Awareness of one\'s own cultural worldview, (b) Attitude towards cultural
differences, (c) Knowledge of different cultural practices and worldviews, and (d) Cross-cultural
skills. Developing cultural competence results in an ability to understand, communicate with,
and effectively interact with people across cultures.[1].
Conformers can also be named as conformational is.pdf
Conformers can also be named as conformational isomers.The isomers used for the
conformational isomerism. Which can be defined as “ the form of stereoisomerism in which the
isomers can be interconverted by rotation of the single bonds”.
Solution
Conformers can also be named as conformational isomers.The isomers used for the
conformational isomerism. Which can be defined as “ the form of stereoisomerism in which the
isomers can be interconverted by rotation of the single bonds”..
benzene sulphonic acid - SO3H on benzene ring .pdf
benzene sulphonic acid - SO3H on benzene ring
Solution
benzene sulphonic acid - SO3H on benzene ring.
The HTML was developed by Tim Berners Lee, to create electronic docu.pdf
The HTML was developed by Tim Berners Lee, to create electronic documents. Theretains
information that has been entered through input devices. The JTextField component uses
SpringLayout to specify the location and size. BASIC is a programming language originally
developed by Microsoft. SABRE(Semi-automated Business Research Environment), developed
in the late 1950s, is still used in a considerable portion of today
Solution
The HTML was developed by Tim Berners Lee, to create electronic documents. Theretains
information that has been entered through input devices. The JTextField component uses
SpringLayout to specify the location and size. BASIC is a programming language originally
developed by Microsoft. SABRE(Semi-automated Business Research Environment), developed
in the late 1950s, is still used in a considerable portion of today.
The genotype of happy skipping smurf 2 – Hs hSSolutionThe ge.pdf
The genotype of happy skipping smurf 2 – Hs / hS
Solution
The genotype of happy skipping smurf 2 – Hs / hS.
ans D because NO2 has higher priority and should.pdf
ans :D because NO2 has higher priority and should be named following
alphabetical order so bromo comes first
Solution
ans :D because NO2 has higher priority and should be named following
alphabetical order so bromo comes first.
The objective of the above code is to define a phonebook entry in ja.pdf
The objective of the above code is to define a phonebook entry in java and test it .
It has 2 classes
- PhoneBookEntry
- PhoneBookEntryTest
The steps to achieve the objective are :
- create a class PhoneBookEntry
- identified attributes name and phone number
- declared the above attribites with private modifier to enable encapsulation and data hiding
capability.
- define parameterized constructor to initialize objects with instance variable values
- define getter and setter methods for the above instance variables to access and edit the instance
variable.
- define overidden toString() method to print the PhoneBookEntry object details like name and
phone number at the same time.
In the PhoneBookEntry class we have main() method to test the PhoneBookEntry class :
- create a ArrayList of type PhoneBookEntry class to store multiple phone book entries
- create a Scanner class object to be useful for taking command line input.
- using a for loop take input of name and phone number for 5 entries like
name=scan.nextLine();
phoneNo=scan.nextLong();
- create phonebookentry object at each iteration for 5 times by providing name phone number
details to the parameter ized constructor.
PhoneBookEntry pe =new PhoneBookEntry(name,phoneNo);
- add the object to the list of entries for 5 iterations
list.add(pe);
- finally print the 5 entries in the list using for each loop and toString() method
Solution
The objective of the above code is to define a phonebook entry in java and test it .
It has 2 classes
- PhoneBookEntry
- PhoneBookEntryTest
The steps to achieve the objective are :
- create a class PhoneBookEntry
- identified attributes name and phone number
- declared the above attribites with private modifier to enable encapsulation and data hiding
capability.
- define parameterized constructor to initialize objects with instance variable values
- define getter and setter methods for the above instance variables to access and edit the instance
variable.
- define overidden toString() method to print the PhoneBookEntry object details like name and
phone number at the same time.
In the PhoneBookEntry class we have main() method to test the PhoneBookEntry class :
- create a ArrayList of type PhoneBookEntry class to store multiple phone book entries
- create a Scanner class object to be useful for taking command line input.
- using a for loop take input of name and phone number for 5 entries like
name=scan.nextLine();
phoneNo=scan.nextLong();
- create phonebookentry object at each iteration for 5 times by providing name phone number
details to the parameter ized constructor.
PhoneBookEntry pe =new PhoneBookEntry(name,phoneNo);
- add the object to the list of entries for 5 iterations
list.add(pe);
- finally print the 5 entries in the list using for each loop and toString() method.
A. He has a smaller radius than H because He has .pdf
A. He has a smaller radius than H because He has a larger effective nuclear charge
Hydrogen has one proton, helium has two. Hydrogen has one electron, helium has two, but IN
THE SAME ENERGY LEVEL (their average distance from the nucleus is the same). Since the
helium nucleus has increased positive charge, the helium electrons are drawn in toward the
nucleus (due to electrostatic attraction) than the single electron of hydrogen is to its nucleus.
(This is a side effect of imperfect electron shielding).
Solution
A. He has a smaller radius than H because He has a larger effective nuclear charge
Hydrogen has one proton, helium has two. Hydrogen has one electron, helium has two, but IN
THE SAME ENERGY LEVEL (their average distance from the nucleus is the same). Since the
helium nucleus has increased positive charge, the helium electrons are drawn in toward the
nucleus (due to electrostatic attraction) than the single electron of hydrogen is to its nucleus.
(This is a side effect of imperfect electron shielding)..
standard deviation = 0Solutionstandard deviation = 0.pdf
standard deviation = 0
Solution
standard deviation = 0.
A transducer is a device, usually electrical, ele.pdf
A transducer is a device, usually electrical, electronic, electro-mechanical,
electromagnetic, photonic, or photovoltaic that converts one type of energy to another for various
purposes including measurement or information transfer (for example, pressure sensors). In a
broader sense (for example in the Viable System Model) a transducer is sometimes defined as
any device that converts a signal from one form to another. A very common device is an audio
speaker, which converts electrical voltage variations representing music or speech, to mechanical
cone vibration. The speaker cone in turn vibrates air molecules creating acoustical energy
Solution
A transducer is a device, usually electrical, electronic, electro-mechanical,
electromagnetic, photonic, or photovoltaic that converts one type of energy to another for various
purposes including measurement or information transfer (for example, pressure sensors). In a
broader sense (for example in the Viable System Model) a transducer is sometimes defined as
any device that converts a signal from one form to another. A very common device is an audio
speaker, which converts electrical voltage variations representing music or speech, to mechanical
cone vibration. The speaker cone in turn vibrates air molecules creating acoustical energy.
PbI2 is not soluble. Li2SO4 and Fe(NO3)3 are soluble in water..pdf
PbI2 is not soluble.
Li2SO4 and Fe(NO3)3 are soluble in water.
Li2SO4 ---> Li+ and SO42-
Fe(NO3)3 ---> Fe3+ and NO3-
Solution
PbI2 is not soluble.
Li2SO4 and Fe(NO3)3 are soluble in water.
Li2SO4 ---> Li+ and SO42-
Fe(NO3)3 ---> Fe3+ and NO3-.
Process of determining CIDR notation in specific subnetClassless .pdf
Process of determining CIDR notation in specific subnet:
Classless inter domain routing(CIDR) is a method which is used to represent the specific subnet
in which it counts the number of network bits in the subnet mask.Inorder to communicate with
any device on the ethernet network directly you must know the IP address and the subnet mask.
The subnet mask which determines how an IP message set by IP host. Basically an IP address is
32 bit number which conveys two pieces of message that is network ID and host id in which
network Id indicates the Ip subnet address and host id whgich indicates a specific host address.
The network address will get by activating a bitwise AND comparison between the IP address
and the subnet mask there by we can determine the CIDR notation in specific subnet.
Solution
Process of determining CIDR notation in specific subnet:
Classless inter domain routing(CIDR) is a method which is used to represent the specific subnet
in which it counts the number of network bits in the subnet mask.Inorder to communicate with
any device on the ethernet network directly you must know the IP address and the subnet mask.
The subnet mask which determines how an IP message set by IP host. Basically an IP address is
32 bit number which conveys two pieces of message that is network ID and host id in which
network Id indicates the Ip subnet address and host id whgich indicates a specific host address.
The network address will get by activating a bitwise AND comparison between the IP address
and the subnet mask there by we can determine the CIDR notation in specific subnet..
Please find the answer to the above problem as follows- Program.pdf
Please find the answer to the above problem as follows:-
/* Program to insert in a sorted list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
void sortedDelete(struct node** head_ref, int number)
{
struct node *temp = *head_ref;
struct node *prev = NULL;
if(*head_ref != NULL && (*head_ref)->data == number){
*head_ref = (*head_ref)->next;
return;
}
while(temp != NULL)
{
if(temp->data == number){
prev->next = temp->next;
free(temp);
return;
}
prev = temp;
temp = temp->next;
}
}
/* function to insert a new_node in a list. Note that this
* function expects a pointer to head_ref as this can modify the
* head of the input linked list (similar to push())*/
void sortedInsert(struct node** head_ref, struct node* new_node)
{
struct node* current;
/* Special case for the head end */
if (*head_ref == NULL || (*head_ref)->data >= new_node->data)
{
if(*head_ref != NULL&&(*head_ref)->data==new_node->data){
return;
}
new_node->next = *head_ref;
*head_ref = new_node;
}
else
{
/* Locate the node before the point of insertion */
current = *head_ref;
while (current->next!=NULL &&
current->next->data < new_node->data)
{
current = current->next;
}
if(current->next!=NULL && current->next->data == new_node->data){
return;
}
new_node->next = current->next;
current->next = new_node;
}
}
/* BELOW FUNCTIONS ARE JUST UTILITY TO TEST sortedInsert */
/* A utility function to create a new node */
struct node *newNode(int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
new_node->next = NULL;
return new_node;
}
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
if(temp == NULL)
printf(\"\ \");
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
/* Drier program to test count function*/
int main(int argc, char *argv[])
{
/* Start with the empty list */
struct node* head = NULL;
struct node *new_node;
FILE *fp;
fp = fopen(argv[1], \"r+\");
if(!fp){
printf(\"error\");
return 1;
}
char op = \' \';
int number = 0;
while(fscanf(fp, \"%c\\t%d\ \", &op, &number)!=EOF){
if(op==\'i\'){
new_node = newNode(number);
sortedInsert(&head, new_node);
}else if(op==\'d\'){
sortedDelete(&head, number);
}else{
printf(\"error\");
return;
}
}
printList(head);
printf(\"\ \");
return 0;
}
Solution
Please find the answer to the above problem as follows:-
/* Program to insert in a sorted list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
void sortedDelete(struct node** head_ref, int number)
{
struct node *temp = *head_ref;
struct node *prev = NULL;
if(*head_ref != NULL && (*head_ref)->data == number){
*head_ref = (*head_ref)->next;
return;
}
while(temp != NULL)
{
if(temp->data == number){
prev->next = temp->next;
free(temp);
return;
}
prev = temp;
temp = temp->next;
}
}
/* function to insert a new_node in a list. Note that this
* function expects a point.
option D is correct.Solutionoption D is correct..pdf
option D is correct.
Solution
option D is correct..
Mass of helium = moles x molar mass= 3.06 x 4.00= 12.24 g= 0.0.pdf
Mass of helium = moles x molar mass
= 3.06 x 4.00
= 12.24 g
= 0.01224 kg 0.0122 kg
Solution
Mass of helium = moles x molar mass
= 3.06 x 4.00
= 12.24 g
= 0.01224 kg 0.0122 kg.
HNO3 on dissolving in water dissosiates asHNO3 --- H+ + NO3-S.pdf
HNO3 on dissolving in water dissosiates as
HNO3 ---> H+ + NO3-
Solution
HNO3 on dissolving in water dissosiates as
HNO3 ---> H+ + NO3-.
If a Plant has a mutation and jhas lost function of C gene, the expr.pdf
If a Plant has a mutation and jhas lost function of C gene, the expression of C gene functions in
the whorls giving rise to sepals and petals.So the Answer is C. only Petals and Sepals.
Solution
If a Plant has a mutation and jhas lost function of C gene, the expression of C gene functions in
the whorls giving rise to sepals and petals.So the Answer is C. only Petals and Sepals..
Increased acidity increases the H3O ions. When calciumphosphate .pdf
Increased acidity increases the H3O ions. When calciumphosphate dissolves it produces PO4^3-,
a base. The H3O ionsneutralize the OH- ions formed by the PO4^3 so the reaction isdriven to the
right to make up for it.
Solution
Increased acidity increases the H3O ions. When calciumphosphate dissolves it produces PO4^3-,
a base. The H3O ionsneutralize the OH- ions formed by the PO4^3 so the reaction isdriven to the
right to make up for it..
The approach at University of Liverpool.pptx
How libraries can support authors with open access requirements for UKRI funded books
Wednesday 22 May 2024, 14:00-15:00.
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Cultural competence refers to an ability to inter.pdf
Cultural competence refers to an ability to interact effectively with people of
different cultures and socio-economic backgrounds, particularly in the context of human
resources, non-profit organizations, and government agencies whose employees work with
persons from different cultural/ethnic backgrounds. Cultural competence comprises four
components: (a) Awareness of one\'s own cultural worldview, (b) Attitude towards cultural
differences, (c) Knowledge of different cultural practices and worldviews, and (d) Cross-cultural
skills. Developing cultural competence results in an ability to understand, communicate with,
and effectively interact with people across cultures.[1]
Solution
Cultural competence refers to an ability to interact effectively with people of
different cultures and socio-economic backgrounds, particularly in the context of human
resources, non-profit organizations, and government agencies whose employees work with
persons from different cultural/ethnic backgrounds. Cultural competence comprises four
components: (a) Awareness of one\'s own cultural worldview, (b) Attitude towards cultural
differences, (c) Knowledge of different cultural practices and worldviews, and (d) Cross-cultural
skills. Developing cultural competence results in an ability to understand, communicate with,
and effectively interact with people across cultures.[1].
Conformers can also be named as conformational is.pdf
Conformers can also be named as conformational isomers.The isomers used for the
conformational isomerism. Which can be defined as “ the form of stereoisomerism in which the
isomers can be interconverted by rotation of the single bonds”.
Solution
Conformers can also be named as conformational isomers.The isomers used for the
conformational isomerism. Which can be defined as “ the form of stereoisomerism in which the
isomers can be interconverted by rotation of the single bonds”..
benzene sulphonic acid - SO3H on benzene ring .pdf
benzene sulphonic acid - SO3H on benzene ring
Solution
benzene sulphonic acid - SO3H on benzene ring.
The HTML was developed by Tim Berners Lee, to create electronic docu.pdf
The HTML was developed by Tim Berners Lee, to create electronic documents. Theretains
information that has been entered through input devices. The JTextField component uses
SpringLayout to specify the location and size. BASIC is a programming language originally
developed by Microsoft. SABRE(Semi-automated Business Research Environment), developed
in the late 1950s, is still used in a considerable portion of today
Solution
The HTML was developed by Tim Berners Lee, to create electronic documents. Theretains
information that has been entered through input devices. The JTextField component uses
SpringLayout to specify the location and size. BASIC is a programming language originally
developed by Microsoft. SABRE(Semi-automated Business Research Environment), developed
in the late 1950s, is still used in a considerable portion of today.
The genotype of happy skipping smurf 2 – Hs hSSolutionThe ge.pdf
The genotype of happy skipping smurf 2 – Hs / hS
Solution
The genotype of happy skipping smurf 2 – Hs / hS.
ans D because NO2 has higher priority and should.pdf
ans :D because NO2 has higher priority and should be named following
alphabetical order so bromo comes first
Solution
ans :D because NO2 has higher priority and should be named following
alphabetical order so bromo comes first.
The objective of the above code is to define a phonebook entry in ja.pdf
The objective of the above code is to define a phonebook entry in java and test it .
It has 2 classes
- PhoneBookEntry
- PhoneBookEntryTest
The steps to achieve the objective are :
- create a class PhoneBookEntry
- identified attributes name and phone number
- declared the above attribites with private modifier to enable encapsulation and data hiding
capability.
- define parameterized constructor to initialize objects with instance variable values
- define getter and setter methods for the above instance variables to access and edit the instance
variable.
- define overidden toString() method to print the PhoneBookEntry object details like name and
phone number at the same time.
In the PhoneBookEntry class we have main() method to test the PhoneBookEntry class :
- create a ArrayList of type PhoneBookEntry class to store multiple phone book entries
- create a Scanner class object to be useful for taking command line input.
- using a for loop take input of name and phone number for 5 entries like
name=scan.nextLine();
phoneNo=scan.nextLong();
- create phonebookentry object at each iteration for 5 times by providing name phone number
details to the parameter ized constructor.
PhoneBookEntry pe =new PhoneBookEntry(name,phoneNo);
- add the object to the list of entries for 5 iterations
list.add(pe);
- finally print the 5 entries in the list using for each loop and toString() method
Solution
The objective of the above code is to define a phonebook entry in java and test it .
It has 2 classes
- PhoneBookEntry
- PhoneBookEntryTest
The steps to achieve the objective are :
- create a class PhoneBookEntry
- identified attributes name and phone number
- declared the above attribites with private modifier to enable encapsulation and data hiding
capability.
- define parameterized constructor to initialize objects with instance variable values
- define getter and setter methods for the above instance variables to access and edit the instance
variable.
- define overidden toString() method to print the PhoneBookEntry object details like name and
phone number at the same time.
In the PhoneBookEntry class we have main() method to test the PhoneBookEntry class :
- create a ArrayList of type PhoneBookEntry class to store multiple phone book entries
- create a Scanner class object to be useful for taking command line input.
- using a for loop take input of name and phone number for 5 entries like
name=scan.nextLine();
phoneNo=scan.nextLong();
- create phonebookentry object at each iteration for 5 times by providing name phone number
details to the parameter ized constructor.
PhoneBookEntry pe =new PhoneBookEntry(name,phoneNo);
- add the object to the list of entries for 5 iterations
list.add(pe);
- finally print the 5 entries in the list using for each loop and toString() method.
A. He has a smaller radius than H because He has .pdf
A. He has a smaller radius than H because He has a larger effective nuclear charge
Hydrogen has one proton, helium has two. Hydrogen has one electron, helium has two, but IN
THE SAME ENERGY LEVEL (their average distance from the nucleus is the same). Since the
helium nucleus has increased positive charge, the helium electrons are drawn in toward the
nucleus (due to electrostatic attraction) than the single electron of hydrogen is to its nucleus.
(This is a side effect of imperfect electron shielding).
Solution
A. He has a smaller radius than H because He has a larger effective nuclear charge
Hydrogen has one proton, helium has two. Hydrogen has one electron, helium has two, but IN
THE SAME ENERGY LEVEL (their average distance from the nucleus is the same). Since the
helium nucleus has increased positive charge, the helium electrons are drawn in toward the
nucleus (due to electrostatic attraction) than the single electron of hydrogen is to its nucleus.
(This is a side effect of imperfect electron shielding)..
standard deviation = 0Solutionstandard deviation = 0.pdf
standard deviation = 0
Solution
standard deviation = 0.
A transducer is a device, usually electrical, ele.pdf
A transducer is a device, usually electrical, electronic, electro-mechanical,
electromagnetic, photonic, or photovoltaic that converts one type of energy to another for various
purposes including measurement or information transfer (for example, pressure sensors). In a
broader sense (for example in the Viable System Model) a transducer is sometimes defined as
any device that converts a signal from one form to another. A very common device is an audio
speaker, which converts electrical voltage variations representing music or speech, to mechanical
cone vibration. The speaker cone in turn vibrates air molecules creating acoustical energy
Solution
A transducer is a device, usually electrical, electronic, electro-mechanical,
electromagnetic, photonic, or photovoltaic that converts one type of energy to another for various
purposes including measurement or information transfer (for example, pressure sensors). In a
broader sense (for example in the Viable System Model) a transducer is sometimes defined as
any device that converts a signal from one form to another. A very common device is an audio
speaker, which converts electrical voltage variations representing music or speech, to mechanical
cone vibration. The speaker cone in turn vibrates air molecules creating acoustical energy.
PbI2 is not soluble. Li2SO4 and Fe(NO3)3 are soluble in water..pdf
PbI2 is not soluble.
Li2SO4 and Fe(NO3)3 are soluble in water.
Li2SO4 ---> Li+ and SO42-
Fe(NO3)3 ---> Fe3+ and NO3-
Solution
PbI2 is not soluble.
Li2SO4 and Fe(NO3)3 are soluble in water.
Li2SO4 ---> Li+ and SO42-
Fe(NO3)3 ---> Fe3+ and NO3-.
Process of determining CIDR notation in specific subnetClassless .pdf
Process of determining CIDR notation in specific subnet:
Classless inter domain routing(CIDR) is a method which is used to represent the specific subnet
in which it counts the number of network bits in the subnet mask.Inorder to communicate with
any device on the ethernet network directly you must know the IP address and the subnet mask.
The subnet mask which determines how an IP message set by IP host. Basically an IP address is
32 bit number which conveys two pieces of message that is network ID and host id in which
network Id indicates the Ip subnet address and host id whgich indicates a specific host address.
The network address will get by activating a bitwise AND comparison between the IP address
and the subnet mask there by we can determine the CIDR notation in specific subnet.
Solution
Process of determining CIDR notation in specific subnet:
Classless inter domain routing(CIDR) is a method which is used to represent the specific subnet
in which it counts the number of network bits in the subnet mask.Inorder to communicate with
any device on the ethernet network directly you must know the IP address and the subnet mask.
The subnet mask which determines how an IP message set by IP host. Basically an IP address is
32 bit number which conveys two pieces of message that is network ID and host id in which
network Id indicates the Ip subnet address and host id whgich indicates a specific host address.
The network address will get by activating a bitwise AND comparison between the IP address
and the subnet mask there by we can determine the CIDR notation in specific subnet..
Please find the answer to the above problem as follows- Program.pdf
Please find the answer to the above problem as follows:-
/* Program to insert in a sorted list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
void sortedDelete(struct node** head_ref, int number)
{
struct node *temp = *head_ref;
struct node *prev = NULL;
if(*head_ref != NULL && (*head_ref)->data == number){
*head_ref = (*head_ref)->next;
return;
}
while(temp != NULL)
{
if(temp->data == number){
prev->next = temp->next;
free(temp);
return;
}
prev = temp;
temp = temp->next;
}
}
/* function to insert a new_node in a list. Note that this
* function expects a pointer to head_ref as this can modify the
* head of the input linked list (similar to push())*/
void sortedInsert(struct node** head_ref, struct node* new_node)
{
struct node* current;
/* Special case for the head end */
if (*head_ref == NULL || (*head_ref)->data >= new_node->data)
{
if(*head_ref != NULL&&(*head_ref)->data==new_node->data){
return;
}
new_node->next = *head_ref;
*head_ref = new_node;
}
else
{
/* Locate the node before the point of insertion */
current = *head_ref;
while (current->next!=NULL &&
current->next->data < new_node->data)
{
current = current->next;
}
if(current->next!=NULL && current->next->data == new_node->data){
return;
}
new_node->next = current->next;
current->next = new_node;
}
}
/* BELOW FUNCTIONS ARE JUST UTILITY TO TEST sortedInsert */
/* A utility function to create a new node */
struct node *newNode(int new_data)
{
/* allocate node */
struct node* new_node =
(struct node*) malloc(sizeof(struct node));
/* put in the data */
new_node->data = new_data;
new_node->next = NULL;
return new_node;
}
/* Function to print linked list */
void printList(struct node *head)
{
struct node *temp = head;
if(temp == NULL)
printf(\"\ \");
while(temp != NULL)
{
printf(\"%d \", temp->data);
temp = temp->next;
}
}
/* Drier program to test count function*/
int main(int argc, char *argv[])
{
/* Start with the empty list */
struct node* head = NULL;
struct node *new_node;
FILE *fp;
fp = fopen(argv[1], \"r+\");
if(!fp){
printf(\"error\");
return 1;
}
char op = \' \';
int number = 0;
while(fscanf(fp, \"%c\\t%d\ \", &op, &number)!=EOF){
if(op==\'i\'){
new_node = newNode(number);
sortedInsert(&head, new_node);
}else if(op==\'d\'){
sortedDelete(&head, number);
}else{
printf(\"error\");
return;
}
}
printList(head);
printf(\"\ \");
return 0;
}
Solution
Please find the answer to the above problem as follows:-
/* Program to insert in a sorted list */
#include
#include
/* Link list node */
struct node
{
int data;
struct node* next;
};
void sortedDelete(struct node** head_ref, int number)
{
struct node *temp = *head_ref;
struct node *prev = NULL;
if(*head_ref != NULL && (*head_ref)->data == number){
*head_ref = (*head_ref)->next;
return;
}
while(temp != NULL)
{
if(temp->data == number){
prev->next = temp->next;
free(temp);
return;
}
prev = temp;
temp = temp->next;
}
}
/* function to insert a new_node in a list. Note that this
* function expects a point.
option D is correct.Solutionoption D is correct..pdf
option D is correct.
Solution
option D is correct..
Mass of helium = moles x molar mass= 3.06 x 4.00= 12.24 g= 0.0.pdf
Mass of helium = moles x molar mass
= 3.06 x 4.00
= 12.24 g
= 0.01224 kg 0.0122 kg
Solution
Mass of helium = moles x molar mass
= 3.06 x 4.00
= 12.24 g
= 0.01224 kg 0.0122 kg.
HNO3 on dissolving in water dissosiates asHNO3 --- H+ + NO3-S.pdf
HNO3 on dissolving in water dissosiates as
HNO3 ---> H+ + NO3-
Solution
HNO3 on dissolving in water dissosiates as
HNO3 ---> H+ + NO3-.
If a Plant has a mutation and jhas lost function of C gene, the expr.pdf
If a Plant has a mutation and jhas lost function of C gene, the expression of C gene functions in
the whorls giving rise to sepals and petals.So the Answer is C. only Petals and Sepals.
Solution
If a Plant has a mutation and jhas lost function of C gene, the expression of C gene functions in
the whorls giving rise to sepals and petals.So the Answer is C. only Petals and Sepals..
Increased acidity increases the H3O ions. When calciumphosphate .pdf
Increased acidity increases the H3O ions. When calciumphosphate dissolves it produces PO4^3-,
a base. The H3O ionsneutralize the OH- ions formed by the PO4^3 so the reaction isdriven to the
right to make up for it.
Solution
Increased acidity increases the H3O ions. When calciumphosphate dissolves it produces PO4^3-,
a base. The H3O ionsneutralize the OH- ions formed by the PO4^3 so the reaction isdriven to the
right to make up for it..
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ans D because NO2 has higher priority and should.pdf
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The objective of the above code is to define a phonebook entry in ja.pdf
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A. He has a smaller radius than H because He has .pdf
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standard deviation = 0Solutionstandard deviation = 0.pdf
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A transducer is a device, usually electrical, ele.pdf
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Please find the answer to the above problem as follows- Program.pdf
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