Need to make a ReversiOthello Board game in JAVAThe board size ca.pdf
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Need to make a Reversi/Othello Board game in JAVA The board size can be N x N (so 4x4 is default, and it could be larger like 5x5, 6x6 etc. NEEDS TO BE ABLE TO WORK WITH ODD SIZE) Player 1 is going to be you and your going to be the black tiles, and the AI is going to be the white tiles. Black tiles will start the game, and then white will go after them, then back to black, repeat. The players must put a disc of their color on an empty square, adjacent to their opponent\'s disc. Any of the oppponents tiles in between the tile put down, and another of your tiles will cause them to flip to your color. The winner is decided when the board is completely filled or no viable moves are left, and whoever has the most pieces. This program is meant to be simple design (no GUI or big interface designs), broken into multiple classes (can be extension\'s off the class or abstract interface off each other), and the user will be entering the coordinates of where to put the pieces (so just using scanner method)?. The start of the game must always have 4 tiles put down in the center (so the center can change depending on the size of the board), and the gameplay would look something like this Again, coding done in JAVA is what I\'m looking for. Scenario in which the game ends early. JAVA code BW Success: Black move at C1, 0) BW Score: Black: 4, White: 1 Success: White move at C2, 0D Solution package Reversi_Othello_GameReversiOthello; import java.awt.*; import java.applet.*; public class Reversi_Othello_GameReversiOthello extends Applet implements Runnable { Thread runner; // declare a thread for this GameReversiOthello boolean black_shown = false; // flag to signal pause boolean show_em = false; final int BLACK = 1; // declare state of each square final int WHITE = 2; final int EMPTY = 0; final int OFFBOARD = -1; final static int GameReversiOthello[][] = new int[10][10]; //10x10 matrix of squares protected int Count_Black = 0; protected int Count_White = 0; Event evt; int x, y; public void start() // create a thread and start it { if (runner == null) { black_shown = false; runner = new Thread(this); runner.start(); } } public void stop() // stop the thread { if (runner != null) { runner.stop(); runner = null; black_shown = false; } } public synchronized void run() // initialize screen { setBackground(Color.green); for (int i = 0; i < 10; i++) // initialize off-board squares { GameReversiOthello[i][0] = OFFBOARD; GameReversiOthello[i][9] = OFFBOARD; GameReversiOthello[0][i] = OFFBOARD; GameReversiOthello[9][i] = OFFBOARD; } for (int i = 1; i < 9; i++) // initialize GameReversiOthello board to be empty { for (int j = 1; j < 9; j++) { GameReversiOthello[i][j] = EMPTY; } } GameReversiOthello[4][4] = WHITE; // except for initial set up GameReversiOthello[5][4] = BLACK; GameReversiOthello[4][5] = BLACK; GameReversiOthello[5][5] = WHITE; while (runner != null) // signal thread to wait after painting { // black and before white responds while (!black_shown) { try { w.
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![Need to make a Reversi/Othello Board game in JAVA
The board size can be N x N (so 4x4 is default, and it could be larger like 5x5, 6x6 etc. NEEDS
TO BE ABLE TO WORK WITH ODD SIZE)
Player 1 is going to be you and your going to be the black tiles, and the AI is going to be the
white tiles. Black tiles will start the game, and then white will go after them, then back to black,
repeat. The players must put a disc of their color on an empty square, adjacent to their
opponent's disc. Any of the oppponents tiles in between the tile put down, and another of your
tiles will cause them to flip to your color. The winner is decided when the board is completely
filled or no viable moves are left, and whoever has the most pieces.
This program is meant to be simple design (no GUI or big interface designs), broken into
multiple classes (can be extension's off the class or abstract interface off each other), and the
user will be entering the coordinates of where to put the pieces (so just using scanner method)?.
The start of the game must always have 4 tiles put down in the center (so the center can change
depending on the size of the board), and the gameplay would look something like this
Again, coding done in JAVA is what I'm looking for.
Scenario in which the game ends early.
JAVA code BW Success: Black move at C1, 0) BW Score: Black: 4, White: 1 Success: White
move at C2, 0D
Solution
package Reversi_Othello_GameReversiOthello;
import java.awt.*;
import java.applet.*;
public class Reversi_Othello_GameReversiOthello extends Applet implements Runnable {
Thread runner; // declare a thread for this GameReversiOthello
boolean black_shown = false; // flag to signal pause
boolean show_em = false;
final int BLACK = 1; // declare state of each square
final int WHITE = 2;
final int EMPTY = 0;
final int OFFBOARD = -1;
final static int GameReversiOthello[][] = new int[10][10]; //10x10 matrix of squares
protected int Count_Black = 0;
protected int Count_White = 0;](https://image.slidesharecdn.com/needtomakeareversiothelloboardgameinjavatheboardsizeca-230709103752-d62a8ea9/85/Need-to-make-a-ReversiOthello-Board-game-in-JAVAThe-board-size-ca-pdf-1-320.jpg)
![Event evt;
int x, y;
public void start() // create a thread and start it
{
if (runner == null) {
black_shown = false;
runner = new Thread(this);
runner.start();
}
}
public void stop() // stop the thread
{
if (runner != null) {
runner.stop();
runner = null;
black_shown = false;
}
}
public synchronized void run() // initialize screen
{
setBackground(Color.green);
for (int i = 0; i < 10; i++) // initialize off-board squares
{
GameReversiOthello[i][0] = OFFBOARD;
GameReversiOthello[i][9] = OFFBOARD;
GameReversiOthello[0][i] = OFFBOARD;
GameReversiOthello[9][i] = OFFBOARD;
}
for (int i = 1; i < 9; i++) // initialize GameReversiOthello board to be empty
{
for (int j = 1; j < 9; j++) {
GameReversiOthello[i][j] = EMPTY;
}
}
GameReversiOthello[4][4] = WHITE; // except for initial set up
GameReversiOthello[5][4] = BLACK;](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
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In Java using Eclipse, Im suppose to write a class that encapsulat.pdf
In Java using Eclipse, I\'m suppose to write a class that encapsulates a tic tac toe board using two
dimensional arrays. It should only involve the human player vs. the computer, and should
randomly select who should use \'X\' or \'O\' and whether the human player or the computer
should go first. Verify that all moves by the human player are to a valid space on the tic-tac-toe
board, and an incorrect choice should not halt or terminate the game. Below is my Java program
that is currently a work in progress. Can you help me remodify it? Thanks.
import java.util.Scanner;
public class LeavinesTicTacToe
{
public static Scanner sc = new Scanner(System.in);
public static void main(String[] args)
{
final int SIZE = 3;
char[][] board = new char[SIZE][SIZE]; // game board
resetBoard(board); // initialize the board (with \' \' for all cells)
// First, welcome message and display the board.
System.out.println(\"===== WELCOME TO THE TIC-TAC-TOE GAME!! =====\ \");
showBoard(board);
// Then ask the user which symbol (x or o) he/she wants to play.
System.out.print(\" Which symbol do you want to play, \\\"x\\\" or \\\"o\\\"? \");
char userSymbol = sc.next().toLowerCase().charAt(0);
char compSymbol = (userSymbol == \'x\') ? \'o\' : \'x\';
// Also ask whether or not the user wants to go first.
System.out.println();
System.out.print(\" Do you want to go first (y/n)? \");
char ans = sc.next().toLowerCase().charAt(0);
int turn; // 0 -- the user, 1 -- the computer
int remainCount = SIZE * SIZE; // empty cell count
// THE VERY FIRST MOVE.
if (ans == \'y\') {
turn = 0;
userPlay(board, userSymbol); // user puts his/her first tic
}
else {
turn = 1;
compPlay(board, compSymbol); // computer puts its first tic
}
// Show the board, and decrement the count of remaining cells.
showBoard(board);
remainCount--;
// Play the game until either one wins.
boolean done = false;
int winner = -1; // 0 -- the user, 1 -- the computer, -1 -- draw
while (!done && remainCount > 0) {
// If there is a winner at this time, set the winner and the done flag to true.
done = isGameWon(board, turn, userSymbol, compSymbol); // Did the turn won?
if (done)
winner = turn; // the one who made the last move won the game
else {
// No winner yet. Find the next turn and play.
turn = (turn + 1 ) % 2;
if (turn == 0)
userPlay(board, userSymbol);
else
compPlay(board, compSymbol);
// Show the board after one tic, and decrement the rem count.
showBoard(board);
remainCount--;
}
}
// Winner is found. Declare the winner.
if (winner == 0)
System.out.println(\"\ ** YOU WON. CONGRATULATIONS!! **\");
else if (winner == 1)
System.out.println(\"\ ** YOU LOST.. Maybe next time :) **\");
else
System.out.println(\"\ ** DRAW... **\");
}
public static void resetBoard(char[][] brd)
{
for (int i = 0; i < brd.length; i++)
for (int j = 0; j < brd[0].length; j++)
brd[i][j] = \' \';
}
public static void showBoard(char[][] brd)
{
int numRow = brd.length;
int numCol = brd[0].length;
System.out.println();
// First write the column he.
import java.awt.;import java.awt.event.;import javax.swing.;.pdf
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.util.ArrayList;
public class Checkers extends JPanel {
public static void main(String[] args) {
JFrame window = new JFrame(\"Checkers\");
Checkers content = new Checkers();
window.setContentPane(content);
window.pack();
Dimension screensize = Toolkit.getDefaultToolkit().getScreenSize();
window.setLocation( (screensize.width - window.getWidth())/2,
(screensize.height - window.getHeight())/2 );
window.setDefaultCloseOperation( JFrame.EXIT_ON_CLOSE );
window.setResizable(false);
window.setVisible(true);
}
private JButton newGameButton; // Button for starting a new game.
private JButton resignButton; // Button that a player can use to end
// the game by resigning.
private JLabel message; // Label for displaying messages to the user.
public Checkers() {
setLayout(null); // I will do the layout myself.
setPreferredSize( new Dimension(350,250) );
setBackground(new Color(0,150,0)); // Dark green background.
/* Create the components and add them to the applet. */
Board board = new Board(); // Note: The constructor for the
// board also creates the buttons
// and label.
add(board);
add(newGameButton);
add(resignButton);
add(message);
/* Set the position and size of each component by calling
its setBounds() method. */
board.setBounds(20,20,164,164); // Note: size MUST be 164-by-164 !
newGameButton.setBounds(210, 60, 120, 30);
resignButton.setBounds(210, 120, 120, 30);
message.setBounds(0, 200, 350, 30);
} // end constructor
private static class CheckersMove {
int fromRow, fromCol; // Position of piece to be moved.
int toRow, toCol; // Square it is to move to.
CheckersMove(int r1, int c1, int r2, int c2) {
// Constructor. Just set the values of the instance variables.
fromRow = r1;
fromCol = c1;
toRow = r2;
toCol = c2;
}
boolean isJump() {
// Test whether this move is a jump. It is assumed that
// the move is legal. In a jump, the piece moves two
// rows. (In a regular move, it only moves one row.)
return (fromRow - toRow == 2 || fromRow - toRow == -2);
}
} // end class CheckersMove.
private class Board extends JPanel implements ActionListener, MouseListener {
CheckersData board; // The data for the checkers board is kept here.
// This board is also responsible for generating
// lists of legal moves.
boolean gameInProgress; // Is a game currently in progress?
/* The next three variables are valid only when the game is in progress. */
int currentPlayer; // Whose turn is it now? The possible values
// are CheckersData.RED and CheckersData.BLACK.
int selectedRow, selectedCol; // If the current player has selected a piece to
// move, these give the row and column
// containing that piece. If no piece is
// yet selected, then selectedRow is -1.
CheckersMove[] legalMoves; // An array containing the legal moves for the
// current player.
Board() {
setBackground(Color.BLACK);
addMouseListener(this);
resignButton = new JButton(\"Resign\");
resignButton.addActionListener(this);
newGameBu.
This is a homework assignment that I have for my Java coding class. .pdf
This is a homework assignment that I have for my Java coding class. I have completed most of
the assignment, but I am having some issue. Could you find my problem and then take my code
and add the corrections to it and then display the complete code that works? I REPEAT CAN
YOU LOCATE WHY MY CODE ISN\'T WORKING AND THEN USE MY CODE AND ADD
THE CHANGES. I REPEAT CAN YOU LOCATE WHY MY CODE ISN\'T WORKING AND
THEN USE MY CODE AND ADD THE CHANGES!
I have asked this question 3 times and no one has done what I have requested. I don\'t want a
different solution to my problem. It doesn\'t take a lot of work to search chegg and then copy and
paste an answer from another question. I REPEAT CAN YOU LOCATE WHY MY CODE
ISN\'T WORKING AND THEN USE MY CODE AND ADD THE CHANGES!
Objective:
Write a game where you are an X trying to get an ice cream cone in a mine field
Before the game starts, a field of mines are created.
The board has to be first initialized
There mines occupy a tenth of the board (IE (BoardSize x BoardSize)/10 = the number of mines)
The mines are randomly placed on the board. If a space which is already occupied (either by the
player, the ice cream cone, or another mine) is selected then another space must be selected until
an empty space is found.
The player is placed at 0,0
The ice cream cone is placed at a random location on the board
At each turn, the player chooses to move in the X or Y direction by entering either -1, 0, or 1,
where
-1 is going one space in the negative direction
1 is going one space in the positive direction (remember positive for Y is down)
0 is staying still
9 quits the game
Anything other than these values should prompt the player that they have inputted an invalid
value and then not move in that direction (IE 0).
Before each turn the board is displayed indicating where the player (X) and the goal (^) are
located. Unoccupied spaces and mines are denoted by and underscore (_). Remember mines need
to be hidden so they are also underscores (_). The board is maximum 10 spaces long and wide.
Once the player reaches the ice cream cone the player wins
If the player lands on a space with a mine they are killed and the game is over
After the game is over, the player should be prompted whether or not they want to play again.
Example Dialog:
Welcome to Mine Walker. Get the ice cream cone and avoid the mines
X_________
__________
__________
__________
__________
__________
__________
__________
__________
_________^
Enter either a -1, 0, or 1 in the X or 9 to quit
1
Enter either a -1,0, or 1 in the Y
1
__________
_X________
__________
__________
__________
__________
__________
__________
__________
_________^
Enter either a -1, 0, or 1 in the X or 9 to quit
0
Enter either a -1,0, or 1 in the Y
1
__________
__________
_X________
__________
__________
__________
__________
__________
__________
_________^
Enter either a -1, 0, or 1 in the X or 9 to quit
-1
Enter either a -1,0, or 1 in the Y
1
Boom! Dead!
Would you like to play .
Hello!This is Java assignment applet.Can someone help me writing.pdf
Hello!
This is Java assignment applet.
Can someone help me writing a code how to exit the game when I press no in question( would
you like to play again?). Also if no one wins or draws i would like to pop up the question ( would
you like to play again?). I have the code below i would like someone to add it
Thanks in advance!
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.applet.*;
public class TicTacToe extends Applet implements ActionListener{
// Array to store buttons
JButton button[][] = new JButton[3][3];
boolean isNewGame =false;
// To switch player either X or O
boolean isZero = true; //first turn is always 0
// Setup size
// Set layout to grid
// Create buttons through loop
// Add buttons to layout
// Add listener
public void init(){
setSize(500, 500);
setLayout(new GridLayout(3,3));
// if it is not a new game
if(isNewGame==false) {
// Adding buttons to layout
//initialize the Grid and add ActionListener to each Button
for(int i = 0; i < 3; i++){
for(int j = 0; j < 3; j++){
// init jButton
button[i][j] = new JButton(\"\");
// Setup Font and Size here
button[i][j].setFont(new Font(\"Lucida Grande\", Font.PLAIN, 28));
// Add is a method from applet to add buttons in layout
add(button[i][j]);
// Listener
button[i][j].addActionListener(this);
}
}
}
else {
// If we need to restart the game, then we only set text to empty
// Back to black color
// add listener
for(int i = 0; i < 3; i++){
for(int j = 0; j < 3; j++){
button[i][j].setText(\"\");
button[i][j].setForeground(Color.BLACK);
button[i][j].removeActionListener(this);
button[i][j].addActionListener(this);
}
}
}
}
// Go all the buttons in arrsy
// Check the event with button in array
// if player O is true, set button text O. Otherwise. X
// Remove Listerner. Why? only once you can click
// Change player by isZero
// Check for winner
public void actionPerformed(ActionEvent event){
for(int i = 0; i < 3; i++)
for(int j = 0; j < 3; j++){
if((event.getSource() == button[i][j])){
if(isZero){
button[i][j].setText(\"O\");
}
else{
button[i][j].setText(\"X\");
}
button[i][j].removeActionListener(this); //you cannot click on one tile more than
once
isZero = !isZero;
checkForWinners(); //check if any winner after each move
}
}
}
public void checkForWinners(){
//3 horizontal lines
for(int i = 0; i < 3; i++){
if(button[i][0].getText().equals(button[i][1].getText())
&& button[i][1].getText().equals(button[i][2].getText())
&& !button[i][0].getText().equals(\"\")){
String player = button[i][0].getText();
button[i][0].setForeground(Color.RED);
button[i][1].setForeground(Color.RED);
button[i][2].setForeground(Color.RED);
int reply =JOptionPane.showConfirmDialog(null, player + \" wins!\"+\"\ Would like
to play again?\",\"Game over\",JOptionPane.YES_NO_OPTION);
if (reply == JOptionPane.YES_OPTION) {
isNewGame = true;
init();
return;
}
else {
System.exit(0);
return;
}
}
}
//3 vertical lines
for(int i = 0; i < 3; i++){
if(button[0][i].getText().equals(button[1][i].getText())
&& .
i have a code that runs, but it only lets the player to guess where .pdf
i have a code that runs, but it only lets the player to guess where the ships are(which is a one
player game with one board). is there a way some one can help turn this game into a player vs
computer game (with two boards one for player and one for computer) Please help me.
BattleShipGame.java
package battleship;
import java.util.ArrayList;
import java.util.Scanner;
public class BattleshipGame {
private Ocean ocean;
private boolean[][] availableSpot;
private Scanner sc;
public BattleshipGame() {
// define a new ocean and a new 2D array to store available coordinates
ocean = new Ocean();
availableSpot = new boolean[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++){
availableSpot[i][j] = true;
}
}
}
/**
* prints the game menu and info
* //param select
*/
public void print(int select){
String info;
switch (select) {
case 1: info = \"Welcome to the World of Battleship!\";
break;
case 2: info = \"Enter coordinates to fire: \";
break;
case 3: info = \"Shots fired: \"+ocean.getShotsFired()+\", Ships sunk:
\"+ocean.getShipsSunk();
break;
case 4: info = \"Congratulations! You win!\";
break;
case 99: info = \"Invalid input. Please re-enter:\";
break;
case 100: info = \"--------------------------------------------\";
break;
case 101: info = \"\ ============================================\";
break;
default: info = \"Error selection\";
break;
}
System.out.println(info);
}
/**
* check if the input is valid
* //param input
* //return boolean
*/
public boolean checkValidInput(String input){
ArrayList numList = new ArrayList();
for (int i=0;i<10;i++){
numList.add(\"\"+i);
}
String[] coordinates = input.split(\" \");
//returns false if there are not 2 strings
if (coordinates.length!=2){
return false;
}
//returns false if any of the strings is not a single digit number
for (String str: coordinates){
if (numList.contains(str)==false){
return false;
}
}
//returns false if the coordinates have already been shot at
int row = Integer.parseInt(coordinates[0]);
int column = Integer.parseInt(coordinates[1]);
if (this.availableSpot[row][column]==false){
return false;
}
return true;
}
/**
* get the coordinates to shoot at from the String input
* //param input
* //return int[] coordinates
*/
public int[] getCoordinates(String input){
int[] coordinates = new int[2];
String[] strList = input.split(\" \");
int row = Integer.parseInt(strList[0]);
int column = Integer.parseInt(strList[1]);
coordinates[0] = row;
coordinates[1] = column;
return coordinates;
}
/**
* play the battleship game
*/
public void play(){
print(101);
print(1);
ocean.placeAllShipsRandomly();
boolean isGameOver = ocean.isGameOver();
sc = new Scanner(System.in);
//print the ocean and start the game
ocean.print();
print(3);
while (!isGameOver){
print(2);
String input = sc.nextLine();
//check if input is valid
while (!checkValidInput(input)){
print(99);
input = sc.nextLine();
}
//get coordinates and fire
int[] coordinates = getCoordinates(input);
int row = coordinates[0];
int column = coord.
#include stdio.h #include string.h #include stdlib.h #in.pdf
#include
#include
#include
#include
#include \"game.h\"
#include \"aaball.h\"
#define CHECKERS_CELL_SIZE 40
#define CHECKERS_NUM_PIECES 4
#define CHECKERS_BOARD_WID 8
#define CHECKERS_BOARD_HEIT 8
#define CHECKERS_WK 1
#define CHECKERS_WP 2
#define CHECKERS_BK 3
#define CHECKERS_BP 4
#define CHECKERS_ISKING(x) (x == 1 || x == 3)
#define CHECKERS_ISPAWN(x) (x == 2 || x == 4)
#define CHECKERS_ISWHITE(x) (x >= 1 && x <= 2)
#define CHECKERS_ISBLACK(x) (x >= 3 && x <= 4)
char checkers_colors[] =
{200, 200, 200,
220,220,255};
int checkers_init_pos[] =
{
0 , 4 , 0 , 4 , 0 , 4 , 0 , 4 ,
4 , 0 , 4 , 0 , 4 , 0 , 4 , 0 ,
0 , 4 , 0 , 4 , 0 , 4 , 0 , 4 ,
0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 ,
0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 ,
2 , 0 , 2 , 0 , 2 , 0 , 2 , 0 ,
0 , 2 , 0 , 2 , 0 , 2 , 0 , 2 ,
2 , 0 , 2 , 0 , 2 , 0 , 2 , 0 ,
};
static int checkers_max_moves = 200;
void checkers_init ();
int checkers_getmove (Pos *, int, int, GtkboardEventType, Player, byte **, int **);
ResultType checkers_who_won (Pos *, Player, char **);
byte *checkers_movegen (Pos *);
ResultType checkers_eval (Pos *, Player, float *);
char ** checkers_get_pixmap (int idx, int color);
void checkers_reset_uistate ();
Game Checkers =
{ CHECKERS_CELL_SIZE, CHECKERS_BOARD_WID,
CHECKERS_BOARD_HEIT,
CHECKERS_NUM_PIECES,
checkers_colors, checkers_init_pos, NULL, \"Checkers\",
checkers_init};
void checkers_init ()
{
game_getmove = checkers_getmove;
game_movegen = checkers_movegen;
game_who_won = checkers_who_won;
game_eval = checkers_eval;
game_get_pixmap = checkers_get_pixmap;
game_reset_uistate = checkers_reset_uistate;
game_file_label = FILERANK_LABEL_TYPE_ALPHA;
game_rank_label = FILERANK_LABEL_TYPE_NUM | FILERANK_LABEL_DESC;
game_allow_flip = TRUE;
game_doc_about =
\"Checkers\ \"
\"Two player game\ \"
\"Status: Partially implemented (currently unplayable)\ \"
\"URL: \"GAME_DEFAULT_URL(\"checkers\");
}
ResultType checkers_who_won (Pos *pos, Player player, char **commp)
{
static char comment[32];
char *who_str [2] = { \"white won\", \"black won\"};
int found_w = 0, found_b = 0;
int i;
for (i=0; iboard[i])) found_w = 1;
else if (CHECKERS_ISBLACK (pos->board[i])) found_b = 1;
if (!found_b)
{
strncpy (comment, who_str[0], 31);
*commp = comment;
return RESULT_WHITE;
}
if (!found_w)
{
strncpy (comment, who_str[1], 31);
*commp = comment;
return RESULT_BLACK;
}
return RESULT_NOTYET;
}
byte * checkers_movegen (Pos *pos)
{
int i, j, diffx, diffy;
byte movbuf [256];
byte *movlist, *mp = movbuf;
byte *board = pos->board;
Player player = pos->player;
for (i=0; iboard [j * board_wid + i])
{
case CHECKERS_WK: sum += (5 - fabs ((i-3.5) * (j-3.5)) / 10); break;
case CHECKERS_WP: sum += (1 + j / 10.0); break;
case CHECKERS_BK: sum -= (5 - fabs ((i-3.5) * (j-3.5)) / 10); break;
case CHECKERS_BP: sum -= (1 + (board_heit - 1 - j) / 10.0); break;
}
}
*eval = sum;
return RESULT_NOTYET;
}
static int oldx = -1, oldy = -1;
void checkers_reset_uistate ()
{
oldx = -1, oldy = -1;
}
int checkers_getmove (Pos *pos, int x, int y, Gtkboa.
Include
This document contains code for a Tic-Tac-Toe game written in C++ using the Allegro library. It includes functions to initialize the game board, place markers for X and O turns, check for a winner after each turn, and allow player movement and input using keyboard arrows and enter. The main game loop handles drawing the board, player input, placing markers, checking for a winner, and continues until the player presses escape to quit.
tetris
This document contains code for a Tetris game implementation. It includes functions for:
- Drawing the game grid and pieces
- Detecting collisions and removing full rows
- Tracking the score, level, and current/next pieces
- Handling game events like pausing, restarting, and detecting a game over state
The core game logic involves randomly generating and moving falling pieces, removing full rows to increase the score, and checking for collisions to end the game.
Recommended
In Java using Eclipse, Im suppose to write a class that encapsulat.pdf
In Java using Eclipse, I\'m suppose to write a class that encapsulates a tic tac toe board using two
dimensional arrays. It should only involve the human player vs. the computer, and should
randomly select who should use \'X\' or \'O\' and whether the human player or the computer
should go first. Verify that all moves by the human player are to a valid space on the tic-tac-toe
board, and an incorrect choice should not halt or terminate the game. Below is my Java program
that is currently a work in progress. Can you help me remodify it? Thanks.
import java.util.Scanner;
public class LeavinesTicTacToe
{
public static Scanner sc = new Scanner(System.in);
public static void main(String[] args)
{
final int SIZE = 3;
char[][] board = new char[SIZE][SIZE]; // game board
resetBoard(board); // initialize the board (with \' \' for all cells)
// First, welcome message and display the board.
System.out.println(\"===== WELCOME TO THE TIC-TAC-TOE GAME!! =====\ \");
showBoard(board);
// Then ask the user which symbol (x or o) he/she wants to play.
System.out.print(\" Which symbol do you want to play, \\\"x\\\" or \\\"o\\\"? \");
char userSymbol = sc.next().toLowerCase().charAt(0);
char compSymbol = (userSymbol == \'x\') ? \'o\' : \'x\';
// Also ask whether or not the user wants to go first.
System.out.println();
System.out.print(\" Do you want to go first (y/n)? \");
char ans = sc.next().toLowerCase().charAt(0);
int turn; // 0 -- the user, 1 -- the computer
int remainCount = SIZE * SIZE; // empty cell count
// THE VERY FIRST MOVE.
if (ans == \'y\') {
turn = 0;
userPlay(board, userSymbol); // user puts his/her first tic
}
else {
turn = 1;
compPlay(board, compSymbol); // computer puts its first tic
}
// Show the board, and decrement the count of remaining cells.
showBoard(board);
remainCount--;
// Play the game until either one wins.
boolean done = false;
int winner = -1; // 0 -- the user, 1 -- the computer, -1 -- draw
while (!done && remainCount > 0) {
// If there is a winner at this time, set the winner and the done flag to true.
done = isGameWon(board, turn, userSymbol, compSymbol); // Did the turn won?
if (done)
winner = turn; // the one who made the last move won the game
else {
// No winner yet. Find the next turn and play.
turn = (turn + 1 ) % 2;
if (turn == 0)
userPlay(board, userSymbol);
else
compPlay(board, compSymbol);
// Show the board after one tic, and decrement the rem count.
showBoard(board);
remainCount--;
}
}
// Winner is found. Declare the winner.
if (winner == 0)
System.out.println(\"\ ** YOU WON. CONGRATULATIONS!! **\");
else if (winner == 1)
System.out.println(\"\ ** YOU LOST.. Maybe next time :) **\");
else
System.out.println(\"\ ** DRAW... **\");
}
public static void resetBoard(char[][] brd)
{
for (int i = 0; i < brd.length; i++)
for (int j = 0; j < brd[0].length; j++)
brd[i][j] = \' \';
}
public static void showBoard(char[][] brd)
{
int numRow = brd.length;
int numCol = brd[0].length;
System.out.println();
// First write the column he.
import java.awt.;import java.awt.event.;import javax.swing.;.pdf
import java.awt.*;
import java.awt.event.*;
import javax.swing.*;
import java.util.ArrayList;
public class Checkers extends JPanel {
public static void main(String[] args) {
JFrame window = new JFrame(\"Checkers\");
Checkers content = new Checkers();
window.setContentPane(content);
window.pack();
Dimension screensize = Toolkit.getDefaultToolkit().getScreenSize();
window.setLocation( (screensize.width - window.getWidth())/2,
(screensize.height - window.getHeight())/2 );
window.setDefaultCloseOperation( JFrame.EXIT_ON_CLOSE );
window.setResizable(false);
window.setVisible(true);
}
private JButton newGameButton; // Button for starting a new game.
private JButton resignButton; // Button that a player can use to end
// the game by resigning.
private JLabel message; // Label for displaying messages to the user.
public Checkers() {
setLayout(null); // I will do the layout myself.
setPreferredSize( new Dimension(350,250) );
setBackground(new Color(0,150,0)); // Dark green background.
/* Create the components and add them to the applet. */
Board board = new Board(); // Note: The constructor for the
// board also creates the buttons
// and label.
add(board);
add(newGameButton);
add(resignButton);
add(message);
/* Set the position and size of each component by calling
its setBounds() method. */
board.setBounds(20,20,164,164); // Note: size MUST be 164-by-164 !
newGameButton.setBounds(210, 60, 120, 30);
resignButton.setBounds(210, 120, 120, 30);
message.setBounds(0, 200, 350, 30);
} // end constructor
private static class CheckersMove {
int fromRow, fromCol; // Position of piece to be moved.
int toRow, toCol; // Square it is to move to.
CheckersMove(int r1, int c1, int r2, int c2) {
// Constructor. Just set the values of the instance variables.
fromRow = r1;
fromCol = c1;
toRow = r2;
toCol = c2;
}
boolean isJump() {
// Test whether this move is a jump. It is assumed that
// the move is legal. In a jump, the piece moves two
// rows. (In a regular move, it only moves one row.)
return (fromRow - toRow == 2 || fromRow - toRow == -2);
}
} // end class CheckersMove.
private class Board extends JPanel implements ActionListener, MouseListener {
CheckersData board; // The data for the checkers board is kept here.
// This board is also responsible for generating
// lists of legal moves.
boolean gameInProgress; // Is a game currently in progress?
/* The next three variables are valid only when the game is in progress. */
int currentPlayer; // Whose turn is it now? The possible values
// are CheckersData.RED and CheckersData.BLACK.
int selectedRow, selectedCol; // If the current player has selected a piece to
// move, these give the row and column
// containing that piece. If no piece is
// yet selected, then selectedRow is -1.
CheckersMove[] legalMoves; // An array containing the legal moves for the
// current player.
Board() {
setBackground(Color.BLACK);
addMouseListener(this);
resignButton = new JButton(\"Resign\");
resignButton.addActionListener(this);
newGameBu.
This is a homework assignment that I have for my Java coding class. .pdf
This is a homework assignment that I have for my Java coding class. I have completed most of
the assignment, but I am having some issue. Could you find my problem and then take my code
and add the corrections to it and then display the complete code that works? I REPEAT CAN
YOU LOCATE WHY MY CODE ISN\'T WORKING AND THEN USE MY CODE AND ADD
THE CHANGES. I REPEAT CAN YOU LOCATE WHY MY CODE ISN\'T WORKING AND
THEN USE MY CODE AND ADD THE CHANGES!
I have asked this question 3 times and no one has done what I have requested. I don\'t want a
different solution to my problem. It doesn\'t take a lot of work to search chegg and then copy and
paste an answer from another question. I REPEAT CAN YOU LOCATE WHY MY CODE
ISN\'T WORKING AND THEN USE MY CODE AND ADD THE CHANGES!
Objective:
Write a game where you are an X trying to get an ice cream cone in a mine field
Before the game starts, a field of mines are created.
The board has to be first initialized
There mines occupy a tenth of the board (IE (BoardSize x BoardSize)/10 = the number of mines)
The mines are randomly placed on the board. If a space which is already occupied (either by the
player, the ice cream cone, or another mine) is selected then another space must be selected until
an empty space is found.
The player is placed at 0,0
The ice cream cone is placed at a random location on the board
At each turn, the player chooses to move in the X or Y direction by entering either -1, 0, or 1,
where
-1 is going one space in the negative direction
1 is going one space in the positive direction (remember positive for Y is down)
0 is staying still
9 quits the game
Anything other than these values should prompt the player that they have inputted an invalid
value and then not move in that direction (IE 0).
Before each turn the board is displayed indicating where the player (X) and the goal (^) are
located. Unoccupied spaces and mines are denoted by and underscore (_). Remember mines need
to be hidden so they are also underscores (_). The board is maximum 10 spaces long and wide.
Once the player reaches the ice cream cone the player wins
If the player lands on a space with a mine they are killed and the game is over
After the game is over, the player should be prompted whether or not they want to play again.
Example Dialog:
Welcome to Mine Walker. Get the ice cream cone and avoid the mines
X_________
__________
__________
__________
__________
__________
__________
__________
__________
_________^
Enter either a -1, 0, or 1 in the X or 9 to quit
1
Enter either a -1,0, or 1 in the Y
1
__________
_X________
__________
__________
__________
__________
__________
__________
__________
_________^
Enter either a -1, 0, or 1 in the X or 9 to quit
0
Enter either a -1,0, or 1 in the Y
1
__________
__________
_X________
__________
__________
__________
__________
__________
__________
_________^
Enter either a -1, 0, or 1 in the X or 9 to quit
-1
Enter either a -1,0, or 1 in the Y
1
Boom! Dead!
Would you like to play .
Hello!This is Java assignment applet.Can someone help me writing.pdf
Hello!
This is Java assignment applet.
Can someone help me writing a code how to exit the game when I press no in question( would
you like to play again?). Also if no one wins or draws i would like to pop up the question ( would
you like to play again?). I have the code below i would like someone to add it
Thanks in advance!
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.applet.*;
public class TicTacToe extends Applet implements ActionListener{
// Array to store buttons
JButton button[][] = new JButton[3][3];
boolean isNewGame =false;
// To switch player either X or O
boolean isZero = true; //first turn is always 0
// Setup size
// Set layout to grid
// Create buttons through loop
// Add buttons to layout
// Add listener
public void init(){
setSize(500, 500);
setLayout(new GridLayout(3,3));
// if it is not a new game
if(isNewGame==false) {
// Adding buttons to layout
//initialize the Grid and add ActionListener to each Button
for(int i = 0; i < 3; i++){
for(int j = 0; j < 3; j++){
// init jButton
button[i][j] = new JButton(\"\");
// Setup Font and Size here
button[i][j].setFont(new Font(\"Lucida Grande\", Font.PLAIN, 28));
// Add is a method from applet to add buttons in layout
add(button[i][j]);
// Listener
button[i][j].addActionListener(this);
}
}
}
else {
// If we need to restart the game, then we only set text to empty
// Back to black color
// add listener
for(int i = 0; i < 3; i++){
for(int j = 0; j < 3; j++){
button[i][j].setText(\"\");
button[i][j].setForeground(Color.BLACK);
button[i][j].removeActionListener(this);
button[i][j].addActionListener(this);
}
}
}
}
// Go all the buttons in arrsy
// Check the event with button in array
// if player O is true, set button text O. Otherwise. X
// Remove Listerner. Why? only once you can click
// Change player by isZero
// Check for winner
public void actionPerformed(ActionEvent event){
for(int i = 0; i < 3; i++)
for(int j = 0; j < 3; j++){
if((event.getSource() == button[i][j])){
if(isZero){
button[i][j].setText(\"O\");
}
else{
button[i][j].setText(\"X\");
}
button[i][j].removeActionListener(this); //you cannot click on one tile more than
once
isZero = !isZero;
checkForWinners(); //check if any winner after each move
}
}
}
public void checkForWinners(){
//3 horizontal lines
for(int i = 0; i < 3; i++){
if(button[i][0].getText().equals(button[i][1].getText())
&& button[i][1].getText().equals(button[i][2].getText())
&& !button[i][0].getText().equals(\"\")){
String player = button[i][0].getText();
button[i][0].setForeground(Color.RED);
button[i][1].setForeground(Color.RED);
button[i][2].setForeground(Color.RED);
int reply =JOptionPane.showConfirmDialog(null, player + \" wins!\"+\"\ Would like
to play again?\",\"Game over\",JOptionPane.YES_NO_OPTION);
if (reply == JOptionPane.YES_OPTION) {
isNewGame = true;
init();
return;
}
else {
System.exit(0);
return;
}
}
}
//3 vertical lines
for(int i = 0; i < 3; i++){
if(button[0][i].getText().equals(button[1][i].getText())
&& .
i have a code that runs, but it only lets the player to guess where .pdf
i have a code that runs, but it only lets the player to guess where the ships are(which is a one
player game with one board). is there a way some one can help turn this game into a player vs
computer game (with two boards one for player and one for computer) Please help me.
BattleShipGame.java
package battleship;
import java.util.ArrayList;
import java.util.Scanner;
public class BattleshipGame {
private Ocean ocean;
private boolean[][] availableSpot;
private Scanner sc;
public BattleshipGame() {
// define a new ocean and a new 2D array to store available coordinates
ocean = new Ocean();
availableSpot = new boolean[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++){
availableSpot[i][j] = true;
}
}
}
/**
* prints the game menu and info
* //param select
*/
public void print(int select){
String info;
switch (select) {
case 1: info = \"Welcome to the World of Battleship!\";
break;
case 2: info = \"Enter coordinates to fire: \";
break;
case 3: info = \"Shots fired: \"+ocean.getShotsFired()+\", Ships sunk:
\"+ocean.getShipsSunk();
break;
case 4: info = \"Congratulations! You win!\";
break;
case 99: info = \"Invalid input. Please re-enter:\";
break;
case 100: info = \"--------------------------------------------\";
break;
case 101: info = \"\ ============================================\";
break;
default: info = \"Error selection\";
break;
}
System.out.println(info);
}
/**
* check if the input is valid
* //param input
* //return boolean
*/
public boolean checkValidInput(String input){
ArrayList numList = new ArrayList();
for (int i=0;i<10;i++){
numList.add(\"\"+i);
}
String[] coordinates = input.split(\" \");
//returns false if there are not 2 strings
if (coordinates.length!=2){
return false;
}
//returns false if any of the strings is not a single digit number
for (String str: coordinates){
if (numList.contains(str)==false){
return false;
}
}
//returns false if the coordinates have already been shot at
int row = Integer.parseInt(coordinates[0]);
int column = Integer.parseInt(coordinates[1]);
if (this.availableSpot[row][column]==false){
return false;
}
return true;
}
/**
* get the coordinates to shoot at from the String input
* //param input
* //return int[] coordinates
*/
public int[] getCoordinates(String input){
int[] coordinates = new int[2];
String[] strList = input.split(\" \");
int row = Integer.parseInt(strList[0]);
int column = Integer.parseInt(strList[1]);
coordinates[0] = row;
coordinates[1] = column;
return coordinates;
}
/**
* play the battleship game
*/
public void play(){
print(101);
print(1);
ocean.placeAllShipsRandomly();
boolean isGameOver = ocean.isGameOver();
sc = new Scanner(System.in);
//print the ocean and start the game
ocean.print();
print(3);
while (!isGameOver){
print(2);
String input = sc.nextLine();
//check if input is valid
while (!checkValidInput(input)){
print(99);
input = sc.nextLine();
}
//get coordinates and fire
int[] coordinates = getCoordinates(input);
int row = coordinates[0];
int column = coord.
#include stdio.h #include string.h #include stdlib.h #in.pdf
#include
#include
#include
#include
#include \"game.h\"
#include \"aaball.h\"
#define CHECKERS_CELL_SIZE 40
#define CHECKERS_NUM_PIECES 4
#define CHECKERS_BOARD_WID 8
#define CHECKERS_BOARD_HEIT 8
#define CHECKERS_WK 1
#define CHECKERS_WP 2
#define CHECKERS_BK 3
#define CHECKERS_BP 4
#define CHECKERS_ISKING(x) (x == 1 || x == 3)
#define CHECKERS_ISPAWN(x) (x == 2 || x == 4)
#define CHECKERS_ISWHITE(x) (x >= 1 && x <= 2)
#define CHECKERS_ISBLACK(x) (x >= 3 && x <= 4)
char checkers_colors[] =
{200, 200, 200,
220,220,255};
int checkers_init_pos[] =
{
0 , 4 , 0 , 4 , 0 , 4 , 0 , 4 ,
4 , 0 , 4 , 0 , 4 , 0 , 4 , 0 ,
0 , 4 , 0 , 4 , 0 , 4 , 0 , 4 ,
0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 ,
0 , 0 , 0 , 0 , 0 , 0 , 0 , 0 ,
2 , 0 , 2 , 0 , 2 , 0 , 2 , 0 ,
0 , 2 , 0 , 2 , 0 , 2 , 0 , 2 ,
2 , 0 , 2 , 0 , 2 , 0 , 2 , 0 ,
};
static int checkers_max_moves = 200;
void checkers_init ();
int checkers_getmove (Pos *, int, int, GtkboardEventType, Player, byte **, int **);
ResultType checkers_who_won (Pos *, Player, char **);
byte *checkers_movegen (Pos *);
ResultType checkers_eval (Pos *, Player, float *);
char ** checkers_get_pixmap (int idx, int color);
void checkers_reset_uistate ();
Game Checkers =
{ CHECKERS_CELL_SIZE, CHECKERS_BOARD_WID,
CHECKERS_BOARD_HEIT,
CHECKERS_NUM_PIECES,
checkers_colors, checkers_init_pos, NULL, \"Checkers\",
checkers_init};
void checkers_init ()
{
game_getmove = checkers_getmove;
game_movegen = checkers_movegen;
game_who_won = checkers_who_won;
game_eval = checkers_eval;
game_get_pixmap = checkers_get_pixmap;
game_reset_uistate = checkers_reset_uistate;
game_file_label = FILERANK_LABEL_TYPE_ALPHA;
game_rank_label = FILERANK_LABEL_TYPE_NUM | FILERANK_LABEL_DESC;
game_allow_flip = TRUE;
game_doc_about =
\"Checkers\ \"
\"Two player game\ \"
\"Status: Partially implemented (currently unplayable)\ \"
\"URL: \"GAME_DEFAULT_URL(\"checkers\");
}
ResultType checkers_who_won (Pos *pos, Player player, char **commp)
{
static char comment[32];
char *who_str [2] = { \"white won\", \"black won\"};
int found_w = 0, found_b = 0;
int i;
for (i=0; iboard[i])) found_w = 1;
else if (CHECKERS_ISBLACK (pos->board[i])) found_b = 1;
if (!found_b)
{
strncpy (comment, who_str[0], 31);
*commp = comment;
return RESULT_WHITE;
}
if (!found_w)
{
strncpy (comment, who_str[1], 31);
*commp = comment;
return RESULT_BLACK;
}
return RESULT_NOTYET;
}
byte * checkers_movegen (Pos *pos)
{
int i, j, diffx, diffy;
byte movbuf [256];
byte *movlist, *mp = movbuf;
byte *board = pos->board;
Player player = pos->player;
for (i=0; iboard [j * board_wid + i])
{
case CHECKERS_WK: sum += (5 - fabs ((i-3.5) * (j-3.5)) / 10); break;
case CHECKERS_WP: sum += (1 + j / 10.0); break;
case CHECKERS_BK: sum -= (5 - fabs ((i-3.5) * (j-3.5)) / 10); break;
case CHECKERS_BP: sum -= (1 + (board_heit - 1 - j) / 10.0); break;
}
}
*eval = sum;
return RESULT_NOTYET;
}
static int oldx = -1, oldy = -1;
void checkers_reset_uistate ()
{
oldx = -1, oldy = -1;
}
int checkers_getmove (Pos *pos, int x, int y, Gtkboa.
Include
This document contains code for a Tic-Tac-Toe game written in C++ using the Allegro library. It includes functions to initialize the game board, place markers for X and O turns, check for a winner after each turn, and allow player movement and input using keyboard arrows and enter. The main game loop handles drawing the board, player input, placing markers, checking for a winner, and continues until the player presses escape to quit.
tetris
This document contains code for a Tetris game implementation. It includes functions for:
- Drawing the game grid and pieces
- Detecting collisions and removing full rows
- Tracking the score, level, and current/next pieces
- Handling game events like pausing, restarting, and detecting a game over state
The core game logic involves randomly generating and moving falling pieces, removing full rows to increase the score, and checking for collisions to end the game.
The following code, is a one player battleship game in JAVA. Im tryi.pdf
The following code, is a one player battleship game in JAVA. Im trying to Enhance the game to
be a two player game (were a player plays aggainst a computer opponent). With TWO boards
displayed side by side. The player and the computer must take turns selecting the coordinates on
their own boards. (the ships cannot be placed adjacent to each other).
BattleShipGame.java
package battleship;
import java.util.ArrayList;
import java.util.Scanner;
public class BattleshipGame {
private Ocean ocean;
private boolean[][] availableSpot;
private Scanner sc;
public BattleshipGame() {
// define a new ocean and a new 2D array to store available coordinates
ocean = new Ocean();
availableSpot = new boolean[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++){
availableSpot[i][j] = true;
}
}
}
/**
* prints the game menu and info
* //param select
*/
public void print(int select){
String info;
switch (select) {
case 1: info = \"Welcome to the World of Battleship!\";
break;
case 2: info = \"Enter coordinates to fire: \";
break;
case 3: info = \"Shots fired: \"+ocean.getShotsFired()+\", Ships sunk:
\"+ocean.getShipsSunk();
break;
case 4: info = \"Congratulations! You win!\";
break;
case 99: info = \"Invalid input. Please re-enter:\";
break;
case 100: info = \"--------------------------------------------\";
break;
case 101: info = \"\ ============================================\";
break;
default: info = \"Error selection\";
break;
}
System.out.println(info);
}
/**
* check if the input is valid
* //param input
* //return boolean
*/
public boolean checkValidInput(String input){
ArrayList numList = new ArrayList();
for (int i=0;i<10;i++){
numList.add(\"\"+i);
}
String[] coordinates = input.split(\" \");
//returns false if there are not 2 strings
if (coordinates.length!=2){
return false;
}
//returns false if any of the strings is not a single digit number
for (String str: coordinates){
if (numList.contains(str)==false){
return false;
}
}
//returns false if the coordinates have already been shot at
int row = Integer.parseInt(coordinates[0]);
int column = Integer.parseInt(coordinates[1]);
if (this.availableSpot[row][column]==false){
return false;
}
return true;
}
/**
* get the coordinates to shoot at from the String input
* //param input
* //return int[] coordinates
*/
public int[] getCoordinates(String input){
int[] coordinates = new int[2];
String[] strList = input.split(\" \");
int row = Integer.parseInt(strList[0]);
int column = Integer.parseInt(strList[1]);
coordinates[0] = row;
coordinates[1] = column;
return coordinates;
}
/**
* play the battleship game
*/
public void play(){
print(101);
print(1);
ocean.placeAllShipsRandomly();
boolean isGameOver = ocean.isGameOver();
sc = new Scanner(System.in);
//print the ocean and start the game
ocean.print();
print(3);
while (!isGameOver){
print(2);
String input = sc.nextLine();
//check if input is valid
while (!checkValidInput(input)){
print(99);
input = sc.nextLine();
}
//get coordinates and fire
int[] coord.
C++ Programming (Please help me!! Thank you!!)Problem A Win SimU.pdf
C++ Programming: (Please help me!! Thank you!!)
Problem A: Win SimUniversity (20 points) Currently there is not way to “win” the game.
Modify the SimUniversity.cpp file to have a “hours until graduation” variable that starts at 48
(you may change this number for testing, but ensure you the code you submit has it at 48). In
addition to the normal output, give the time left to graduate as shown in the example below.
When you have graduated, end the game and tell them they have won. If you are expected to
graduate right when you would normally lose the game, you should graduate anyways and win
the game (see 2nd example). Please ensure you follow the sample output exactly
This is my program named SimUniversity.cpp to modify (you copy and paste to C++ to modify)
This is an example that I should get
Example 1 (user input is bold, board is not displayed because it is too big... do not change it):
Current stats are: Energy = 70, Entertainment = 70, Smartness = 70.
Current time: 8:00. You are at the Dorm. Do you want to (S)leep, do (H)omeowrk or (W)atch
some YouTube?
Do you want to (G)o to a different location?
g
Where do you want to travel to: (O, U, D)?
u
You go to University.
From your actions changed your stats by... Energy: -4, Entertainment: 0, Smartness: 0.
You have 47 hours left until graduation...
(Press enter to advance an hour)
Current stats are: Energy = 66, Entertainment = 70, Smartness = 70.
Current time: 9:00.
You are at the University. Do you want to (A)ttend class or (S)leep through lecture? Do you
want to (G)o to a different location?
a
You take copious notes and pay close attention to the material. From your actions changed your
stats by... Energy: - 4, Entertainment: - 8, Smartness: 3.
You have 46 hours left until graduation...
(Press enter to advance an hour)
... (skipping some time, this line is not actually output!) Current stats are: Energy = 67,
Entertainment = 50, Smartness = 73. Current time: 9:00.
You are at the Dorm.
Do you want to (S)leep, do (H)omeowrk or (W)atch some YouTube?
Do you want to (G)o to a different location?
h
You break out the books and pound through some problems. From your actions changed your
stats by... Energy: - 3, Entertainment: -20, Smartness: 3. You have 1 hours left until graduation...
(Press enter to advance an hour)
Current stats are: Energy = 64, Entertainment = 30, Smartness = 76.
Current time: 10:00.
You are at the Dorm.
Do you want to (S)leep, do (H)omeowrk or (W)atch some YouTube?
Do you want to (G)o to a different location?
w
OMG!! CATS!!!! From your actions changed your stats by... Energy: - 2, Entertainment: 20,
Smartness: - 1. You have 0 hours left until graduation...
You graduate from college.
(Press enter to advance an hour)
Solution
#include
#include
using namespace std;
class Room {
private:
// letters outline where the location is
char mapLetter;
// locations are rectangles....
int topLeftX;
int topLeftY;
int bottomRightX;
int bottomRightY;
// all good things have a name, right?
str.
NO PAPER ANSWERS. ALL ANSWER SUBMISSIONS SHOULD BE ABLE TO RUN WIT.pdf
The document describes a Java program to play a simplified single-player version of the Connect Four game. The program initializes an empty game board and allows a player to drop red disks into columns while the computer randomly drops yellow disks. It checks after each turn if either player has four disks in a row to win, and determines if it is a draw if the board is full without a win.
The main class of the tictoe game looks like.public class Main {.pdf
The main class of the tictoe game looks like.
public class Main {
public void play() {
TicTacToe game = new TicTacToe();
System.out.println(\"Welcome! Tic Tac Toe is a two player game.\");
System.out.print(\"Enter player one\'s name: \");
game.setPlayer1(game.getPrompt());
System.out.print(\"Enter player two\'s name: \");
game.setPlayer2(game.getPrompt());
boolean markerOk = false;
while (!markerOk) {
System.out.print(\"Select any letter as \" + game.getPlayer1() + \"\'s marker: \");
String marker = game.getPrompt();
if (marker.length() == 1 &&
Character.isLetter(marker.toCharArray()[0])) {
markerOk = true;
game.setMarker1(marker.toCharArray()[0]);
} else {
System.out.println(\"Invalid marker, try again\");
}
}
markerOk = false;
while (!markerOk) {
System.out.print(\"Select any letter as \" + game.getPlayer2() + \"\'s marker: \");
String marker = game.getPrompt();
if (marker.length() == 1 &&
Character.isLetter(marker.toCharArray()[0])) {
markerOk = true;
game.setMarker2(marker.toCharArray()[0]);
} else {
System.out.println(\"Invalid marker, try again\");
}
}
boolean continuePlaying = true;
while (continuePlaying) {
game.init();
System.out.println();
System.out.println(game.getRules());
System.out.println();
System.out.println(game.drawBoard());
System.out.println();
String player = null;
while (!game.winner() && game.getPlays() < 9) {
player = game.getCurrentPlayer() == 1 ? game.getPlayer1() : game.getPlayer2();
boolean validPick = false;
while (!validPick) {
System.out.print(\"It is \" + player + \"\'s turn. Pick a square: \");
String square = game.getPrompt();
if (square.length() == 1 && Character.isDigit(square.toCharArray()[0])) {
int pick = 0;
try {
pick = Integer.parseInt(square);
} catch (NumberFormatException e) {
//Do nothing here, it\'ll evaluate as an invalid pick on the next row.
}
validPick = game.placeMarker(pick);
}
if (!validPick) {
System.out.println(\"Square can not be selected. Retry\");
}
}
game.switchPlayers();
System.out.println();
System.out.println(game.drawBoard());
System.out.println();
}
if (game.winner()) {
System.out.println(\"Game Over - \" + player + \" WINS!!!\");
} else {
System.out.println(\"Game Over - Draw\");
}
System.out.println();
System.out.print(\"Play again? (Y/N): \");
String choice = game.getPrompt();
if (!choice.equalsIgnoreCase(\"Y\")) {
continuePlaying = false;
}
}
}
public static void main(String[] args) {
Main main = new Main();
main.play();
}
}
The TicTacToe class code will be like
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
/**
*
* author Iamavinashkotina
*/
public class TicTacToe {
private char[][] board = new char[3][3];
private String player1;
private String player2;
private int currentPlayer;
private char marker1;
private char marker2;
private int plays;
private BufferedReader reader =
new BufferedReader(new InputStreamReader(System.in));
protected void init() {
int counter = 0;
for (int i = 0; i < 3; i++) {
for (int i1 = 0; i1 < 3; i1++) {.
i have a runable code below that works with just guessing where the .pdf
i have a runable code below that works with just guessing where the ships are. i need help editing
this code to be able to have a player play against computer and taking turns playing battleship.
BattleShipGame.java
package battleship;
import java.util.ArrayList;
import java.util.Scanner;
public class BattleshipGame {
private Ocean ocean;
private boolean[][] availableSpot;
private Scanner sc;
public BattleshipGame() {
// define a new ocean and a new 2D array to store available coordinates
ocean = new Ocean();
availableSpot = new boolean[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++){
availableSpot[i][j] = true;
}
}
}
/**
* prints the game menu and info
* //param select
*/
public void print(int select){
String info;
switch (select) {
case 1: info = \"Welcome to the World of Battleship!\";
break;
case 2: info = \"Enter coordinates to fire: \";
break;
case 3: info = \"Shots fired: \"+ocean.getShotsFired()+\", Ships sunk:
\"+ocean.getShipsSunk();
break;
case 4: info = \"Congratulations! You win!\";
break;
case 99: info = \"Invalid input. Please re-enter:\";
break;
case 100: info = \"--------------------------------------------\";
break;
case 101: info = \"\ ============================================\";
break;
default: info = \"Error selection\";
break;
}
System.out.println(info);
}
/**
* check if the input is valid
* //param input
* //return boolean
*/
public boolean checkValidInput(String input){
ArrayList numList = new ArrayList();
for (int i=0;i<10;i++){
numList.add(\"\"+i);
}
String[] coordinates = input.split(\" \");
//returns false if there are not 2 strings
if (coordinates.length!=2){
return false;
}
//returns false if any of the strings is not a single digit number
for (String str: coordinates){
if (numList.contains(str)==false){
return false;
}
}
//returns false if the coordinates have already been shot at
int row = Integer.parseInt(coordinates[0]);
int column = Integer.parseInt(coordinates[1]);
if (this.availableSpot[row][column]==false){
return false;
}
return true;
}
/**
* get the coordinates to shoot at from the String input
* //param input
* //return int[] coordinates
*/
public int[] getCoordinates(String input){
int[] coordinates = new int[2];
String[] strList = input.split(\" \");
int row = Integer.parseInt(strList[0]);
int column = Integer.parseInt(strList[1]);
coordinates[0] = row;
coordinates[1] = column;
return coordinates;
}
/**
* play the battleship game
*/
public void play(){
print(101);
print(1);
ocean.placeAllShipsRandomly();
boolean isGameOver = ocean.isGameOver();
sc = new Scanner(System.in);
//print the ocean and start the game
ocean.print();
print(3);
while (!isGameOver){
print(2);
String input = sc.nextLine();
//check if input is valid
while (!checkValidInput(input)){
print(99);
input = sc.nextLine();
}
//get coordinates and fire
int[] coordinates = getCoordinates(input);
int row = coordinates[0];
int column = coordinates[1];
ocean.shootAt(row, column);
availableSpot[row][column] = false;
isGa.
The Ring programming language version 1.10 book - Part 71 of 212
The Gold Magic 800 is a puzzle game developed in Ring, RingAllegro and RingOpenGL. The goal is to move a box around levels to collect gold and open doors by placing the box on them, solving puzzles to progress through 44 levels. Players must plan their route, move directly to targets, consider future moves, avoid and learn from mistakes, and respect the cost to open the first door. The game teaches entrepreneurial thinking and skills like planning, efficiency, foresight, and patience. Screenshots show the level selection screen and an example level with the box and gold to collect.
TilePUzzle class Anderson, Franceschi public class TilePu.docx
The document contains code for a Tile Puzzle game implemented using Java classes. The TilePuzzle class represents the game logic and stores the game state including the grid size, tiles, and empty space location. The Game class sets up the GUI for the game using a GridLayout and JButtons to represent each tile. It links the GUI to the TilePuzzle class so user clicks are handled by trying to move tiles in the TilePuzzle. The NestedLayoutPractice driver class sets up a frame with options to set the grid size for a new game.
AI CHALLENGE ADMIN
This document contains the code for a Connect Four game. It defines constants, global variables, and functions for tracking the game state (board, current player), validating and executing moves, checking for wins, and handling I/O like drawing the board. The main function runs the game loop, continuously prompting for player moves until the board is full or a player wins. Special move types like clearing rows/columns are supported in addition to normal drops.
This is the Java code i have for a Battleship project i am working o.pdf
This is the Java code i have for a Battleship project i am working on, i am now wanting to
convert this to a fully graphical Gui interface, but i just cant seem to get anywhere with it, so if i
could get some help with this, i would apperciate it....(just a reminder its in JAVA)
public class BattleshipGame {
private Ocean ocean;
private boolean[][] availableSpot;
private Scanner sc;
public BattleshipGame() {
// define a new ocean and a new 2D array to store available coordinates
ocean = new Ocean();
availableSpot = new boolean[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++){
availableSpot[i][j] = true;
}
}
}
/**
* prints the game menu and info
* //param select
*/
public void print(int select){
String info;
switch (select) {
case 1: info = \"Welcome to the World of Battleship!\";
break;
case 2: info = \"Enter coordinates to fire: \";
break;
case 3: info = \"Shots fired: \"+ocean.getShotsFired()+\", Ships sunk:
\"+ocean.getShipsSunk();
break;
case 4: info = \"Congratulations! You win!\";
break;
case 99: info = \"Invalid input. Please re-enter:\";
break;
case 100: info = \"--------------------------------------------\";
break;
case 101: info = \"\ ============================================\";
break;
default: info = \"Error selection\";
break;
}
System.out.println(info);
}
/**
* check if the input is valid
* //param input
* //return boolean
*/
public boolean checkValidInput(String input){
ArrayList numList = new ArrayList();
for (int i=0;i<10;i++){
numList.add(\"\"+i);
}
String[] coordinates = input.split(\" \");
//returns false if there are not 2 strings
if (coordinates.length!=2){
return false;
}
//returns false if any of the strings is not a single digit number
for (String str: coordinates){
if (numList.contains(str)==false){
return false;
}
}
//returns false if the coordinates have already been shot at
int row = Integer.parseInt(coordinates[0]);
int column = Integer.parseInt(coordinates[1]);
if (this.availableSpot[row][column]==false){
return false;
}
return true;
}
/**
* get the coordinates to shoot at from the String input
* //param input
* //return int[] coordinates
*/
public int[] getCoordinates(String input){
int[] coordinates = new int[2];
String[] strList = input.split(\" \");
int row = Integer.parseInt(strList[0]);
int column = Integer.parseInt(strList[1]);
coordinates[0] = row;
coordinates[1] = column;
return coordinates;
}
/**
* play the battleship game
*/
public void play(){
print(101);
print(1);
ocean.placeAllShipsRandomly();
boolean isGameOver = ocean.isGameOver();
sc = new Scanner(System.in);
//print the ocean and start the game
ocean.print();
print(3);
while (!isGameOver){
print(2);
String input = sc.nextLine();
//check if input is valid
while (!checkValidInput(input)){
print(99);
input = sc.nextLine();
}
//get coordinates and fire
int[] coordinates = getCoordinates(input);
int row = coordinates[0];
int column = coordinates[1];
ocean.shootAt(row, column);
availableSpot[row][column] = false;
isGameOver = o.
This is for an homework assignment using Java code. Here is the home.pdf
This document discusses code for a Mine Walker game where the player moves around a board trying to reach an ice cream cone while avoiding mines. It provides the game rules and an example dialog. The code works but does not properly reset the board when the player chooses to play again. To fix this, the board initialization code needs to be moved to a separate function that can be called again when restarting.
efy-articles
The document describes a C++ program that implements a customer information system. The program allows users to add, list, modify, delete, search, and pack customer records stored in a .dat file. It features a main menu with these options. Selecting add, modify, or delete allows editing customer details like ID, name, address, phone number. Pack permanently removes deleted records to recover space. The source code and executable will be provided on next month's disc.
#include -stdio-h- #include -stdlib-h- #include -stdbool-h- #include - (1).docx
This code implements a tic-tac-toe game that can be played between two humans or a human and computer. It includes functions to create and print the game board, check for a draw, and check if a move resulted in a win. The main function handles parsing command line arguments, running the game loop, and cleaning up memory.
ObjectiveCreate a graphical game of minesweeper IN JAVA. The boar.pdf
Objective:
Create a graphical game of minesweeper IN JAVA. The board should consist of 10x10 buttons.
Of the 100 spaces there should be at least 20 randomly placed mines. If the button is clicked and
it is not a mine then it clears itself. If a space has been cleared then it should indicate how many
of its eight neighbors are mines. If a space is clicked and it is a mine then the game is over and
the player is asked if they want to play again. Finally, if all the non-mine spaces have been
clicked then the player is prompted that they won.
Solution
2 files need to be made.
First Game.Java which will have the gaming logic and User Interface and Main.Java which will
have have the main method and object of Game.java Number of rows and cols is customizable so
user can change that as and when needed.
import java.awt.*;
import java.awt.Dimension;
import javax.swing.*;
import java.awt.event.*;
import java.util.*;
public class Game extends JFrame implements ActionListener, ContainerListener {
int fw, fh, blockr, blockc, var1, var2, num_of_mine, detectedmine = 0, savedlevel = 1,
savedblockr, savedblockc, savednum_of_mine = 10;
int[] r = {-1, -1, -1, 0, 1, 1, 1, 0};
int[] c = {-1, 0, 1, 1, 1, 0, -1, -1};
JButton[][] blocks;
int[][] countmine;
int[][] colour;
ImageIcon[] ic = new ImageIcon[14];
JPanel panelb = new JPanel();
JPanel panelmt = new JPanel();
JTextField tf_mine, tf_time;
JButton reset = new JButton(\"\");
Random ranr = new Random();
Random ranc = new Random();
boolean check = true, starttime = false;
Point framelocation;
Stopwatch sw;
MouseHendeler mh;
Point p;
Game() {
super(\"Game\");
setLocation(400, 300);
setic();
setpanel(1, 0, 0, 0);
setmanue();
sw = new Stopwatch();
reset.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent ae) {
try {
sw.stop();
setpanel(savedlevel, savedblockr, savedblockc, savednum_of_mine);
} catch (Exception ex) {
setpanel(savedlevel, savedblockr, savedblockc, savednum_of_mine);
}
reset();
}
});
setDefaultCloseOperation(EXIT_ON_CLOSE);
show();
}
public void reset() {
check = true;
starttime = false;
for (int i = 0; i < blockr; i++) {
for (int j = 0; j < blockc; j++) {
colour[i][j] = \'w\';
}
}
}
public void setpanel(int level, int setr, int setc, int setm) {
if (level == 1) {
fw = 200;
fh = 300;
blockr = 10;
blockc = 10;
num_of_mine = 10;
} else if (level == 2) {
fw = 320;
fh = 416;
blockr = 16;
blockc = 16;
num_of_mine = 70;
} else if (level == 3) {
fw = 400;
fh = 520;
blockr = 20;
blockc = 20;
num_of_mine = 150;
} else if (level == 4) {
fw = (20 * setc);
fh = (24 * setr);
blockr = setr;
blockc = setc;
num_of_mine = setm;
}
savedblockr = blockr;
savedblockc = blockc;
savednum_of_mine = num_of_mine;
setSize(fw, fh);
setResizable(false);
detectedmine = num_of_mine;
p = this.getLocation();
blocks = new JButton[blockr][blockc];
countmine = new int[blockr][blockc];
colour = new int[blockr][blockc];
mh = new MouseHendeler();
getContentPane().removeAll();
panelb.removeAll();
tf_mine = new JTe.
Project 2
The document describes the rules and gameplay for a number board game where two players take turns selecting numbers to add to their score. Players can only move horizontally or vertically on the 8x8 board. The game ends when there are no remaining valid moves. Hard mode makes the computer opponent more intelligent by trying to predict player moves. The document also provides code snippets for game mechanics like handling invalid user input and returning to menus.
import java.util.Scanner;public class Main { public static in.pdf
import java.util.Scanner;
public class Main {
public static int gridArray1[][] = null;
public static int gridArray2[][] = null;
public static boolean playerTurn = true;
public static int count = 0;
public static void setGridDimensions(int x_max, int y_max) {
Main.gridArray1 = new int[x_max][y_max];
Main.gridArray2 = new int[x_max][y_max];
for (int i = 0; i < x_max; i++) {
for (int j = 0; j < y_max; j++) {
gridArray1[i][j] = -1;
gridArray2[i][j] = -1;
}
}
}
static void placeShip(int starting_x, int starting_y, int length, int direction) {
count++;
int ships[] = new int[10];
int battleshipArrayPositions1[] = new int[4];
int cruiserArrayPositions1[] = new int[3];
int submarineArrayPositions1[] = new int[3];
int destroyerArrayPositions1[] = new int[2];
int carrierArrayPositions2[] = new int[5];
int battleshipArrayPositions2[] = new int[4];
int cruiserArrayPositions2[] = new int[3];
int submarineArrayPositions2[] = new int[3];
int destroyerArrayPositions2[] = new int[2];
if (playerTurn) {
if (direction == 0) {
for (int i = starting_x; i < starting_x + length; i++) {
Main.gridArray1[i][starting_y] = 0;
}
} else {
for (int i = starting_y; i < starting_y + length; i++) {
Main.gridArray1[starting_x][i] = 0;
}
}
} else {
if (direction == 0) {
for (int i = starting_x; i < starting_x + length; i++) {
Main.gridArray2[i][starting_y] = 0;
}
} else {
for (int i = starting_y; i < starting_y + length; i++) {
Main.gridArray2[starting_x][i] = 0;
}
}
}
}
boolean isConflictingShipPlacement(int starting_x, int starting_y, int length, int direction) {
return false;
}
static int shoot(int x, int y) {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (Main.gridArray2[i][j] == 0) {
return 0;
}
}
}
} else {
}
return 0;
}
boolean hasBeenAttempted(int x, int y) {
return false;
}
static void displayGrid(boolean showShips) {
int count = 0;
System.out.print(\" 0 1 2 3 4 5 6 7 8 9\");
if (showShips) {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray1[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray1[i][j] == 0) {
System.out.print(\"@ \");
} else if (Main.gridArray1[i][j] == 1) {
System.out.print(\"+ \");
} else {
System.out.print(\"X \");
}
}
}
} else {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray2[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray2[i][j] == 0) {
System.out.print(\"@ \");
} else if (Main.gridArray2[i][j] == 1) {
System.out.print(\"+ \");
} else {
System.out.print(\"X \");
}
}
}
}
} else {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray1[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray1[i][j] == 0) {
System.out.print(\"- \");
} el.
Here is the code for youimport java.util.Scanner; import java.u.pdf
Here is the code for you:
import java.util.Scanner;
import java.util.Random;
public class TicTacToeGame {
static char[] [] board = new char[3][3];
static Scanner input=new Scanner(System.in);
//Object of Stats class to maintain statistics
static Stats stat = new Stats();
/**
* Prints the TicTacToe board
* @param arr: The board so far
*/
public static void printBoard(char [][] arr){
System.out.println();
for (int i=0; i<3; i++)
{
for (int j=0; j<3; j++)
{
System.out.print(arr[i][j]);
if(j!=2)
//Print the | for readable output
System.out.print(\" \" + \"|\" + \" \");
}
System.out.println();
if(i!=2) {
System.out.print(\"_ _ _ \"); // Print _ for readability
System.out.println();;
}
}
}
/**
* Clear the TicTacToe board before starting a new game
* @param arr: The board so far
*/
public static void clearBoard(char [][] arr){
for (int i=0; i<3; i++)
{
for (int j=0; j<3; j++)
{
arr[i][j]=\' \';
}
}
}
/** Determines if the player with the specified token wins
*
* @param symbol: Specifies whether the player is X or O
* @return true if player has won, false otherwise
*/
public static boolean isWon(char symbol) {
for (int i = 0; i < 3; i++) //horizontal
if (board[i][0] == symbol
&& board[i][1] == symbol
&& board[i][2] == symbol) {
return true;
}
//TODO!!! Also check for vertical and the two diagonals
for (int i = 0; i < 3; i++) //vertical
if (board[0][i] == symbol
&& board[1][i] == symbol
&& board[2][i] == symbol) {
return true;
}
//Leading diagonal
if (board[0][0] == symbol
&& board[1][1] == symbol
&& board[2][2] == symbol) {
return true;
}
//Trailing diagonal
if (board[0][2] == symbol
&& board[1][1] == symbol
&& board[2][0] == symbol) {
return true;
}
return false;
}
/** Determines if the cell is occupied
*
* @param row: Row of the cell to be checked
* @param col: Column of the cell to be checked
* @return true if the cell is occupied, false otherwise
*/
public static boolean isOccupied(int row, int col){
if (board[row][col]!=\' \') return false;
else return true;
}
/** Determines who starts the game
*/
public static int whoStarts(){
//TODO: Randomly chooses between 0 and 1 and returns the choice
return (int)(Math.random() + 0.5 );
}
/** takes care of the human\'s move
* 1. Prompt for a cell, then column
* 2. Puts a symbol (X or O) on the board
* 3. Prints the updated board
* 4. If a human wins: prints, updates stats and returns true
* 5. If not a win yet, returns false */
public static boolean humanTurn(char symbol){
//Prompt for a cell. User must enter
//row and column with a space in between.
System.out.print(\"\ \ Enter your move: (row column): \" );
int row = input.nextInt();
int col = input.nextInt();
//TODO!!! Mark user move in the board, print
//the board and check if user has won!
board[row][col] = symbol;
printBoard(board);
if(isWon(symbol))
return true;
return false;
}
/** takes care of the computer\'s move
* 1. Generates numbers until finds an empty cell
* 2. Puts a symbol (X or O) on the board
* 3. Prints the updated board
* 4. If a comp .
19012011102_Nayan Oza_Practical-7_AI.pdf
1. The document describes the steps to create a tic-tac-toe game using the minimax algorithm in Python. It includes defining classes for the game state and the tic-tac-toe game, and functions for evaluating the game state, determining valid moves and wins, and implementing the minimax algorithm.
2. The program allows two players to play tic-tac-toe against each other or against an AI opponent that uses minimax to select moves. It prints the game board and declares a winner or draw once the game is over.
3. The output shows a sample run of the tic-tac-toe game being played between a human and AI player.
The Ring programming language version 1.8 book - Part 66 of 202
This document contains Ring code for a 3D tic-tac-toe game. It includes classes for graphics handling, sound, a game background, individual game cubes, and displaying the game over screen. Methods are defined for loading resources, handling input, checking for game completion, and rotating the game cubes. The code provides a framework for rendering and updating a 3D tic-tac-toe game.
How does the mutation rate of speciation in the Dobzhansky- Muller m.pdf
How does the mutation rate of speciation in the Dobzhansky- Muller model? How does the
mutation rate affect the rate of speciation in the Dobzhansky Muller model? An increased
mutation rate results in a more rapid reproductive isolation between the two diverging
populations. O An increased mutation rate results in slower reproductive isolation between the
two diverging populations. The mutation rate is unrelated to the rate of evolution of reproductive
isolation.
Solution
ans- a increased mutation rate results in a more reproduction isolation between the two diverging
population.
an ancestral population splits into two parts the two lineage begins to diverge genetically which
are temporally isolated from each other.new alleles evolved at one locus of lineage and different
alleles evolved in another locus of the lineage..
Hello. I need help fixing this Java Code on Eclipse. Please fix part.pdf
Hello. I need help fixing this Java Code on Eclipse. Please fix parts indicated as \"//Fix\" or
\"//Fill-in\". The code given is the first image. Thank you! Sample outputs are given below along
with what the code is required to do. import java til. Random import java til. Scanner public class
GenCheeseShopv2 public static void intro (Stringt] names, double []prices int amounts Fill-in
public static void getAmount (Scanner input, String[] names, int[] amounts) public static void
itemizedList (String[] names, double Prices int[] amounts) Fill-i public static double
calcSubTotal (double prices, int amounts return 0; pub. lic static int discount (double subTotal
return 0; pub. lic static oid print Total (double subTotal int discount) Fill-in public static void mi
args final int MAXCH EESEE DO NOT CHANGE ANYTHING BELOW String[] names new
String CMAXCH EESE double[] prices new double EESE] int[] amounts new int
[MAXCHEESEJ Scanner input new Scanner (Syste intro names, prices, amounts get Amo unt
input, names, amounts double total calcSubTotal (prices, amounts if EESEE 0) System. out print
Display the itemized list? (1 for yes) int itemized input-nex if item 1) itemized List (names,
prices, amounts); System. out. println(); print Total(total, discount total));
Solution
import java.util.Random;
import java.util.Scanner;
public class GenCheeseShopv2 {
public static void intro(String[] names, double[] prices,int[] amounts){
System.out.println(\"We sell \"+names.length+\" kinds of cheese\");
for(int i=0;i0)
System.out.println(amounts[i]+\" lbs of \"+names[i]+\" @ \"+prices[i]+\" =
$\"+(amounts[i]*prices[i]));
}
}
public static double calcSubTotal( double[] prices,int[] amounts){
double subTotal=0;
for(int i=0;i100)
return 10;
else if(subTotal > 50)
return 25;
else
return 0;
}
public static void printTotal(double subTotal,int discount){
System.out.println(\"Sub Total : $\"+subTotal);
System.out.println(\"-Discount : $\"+discount);
System.out.println(\"Total : $\"+(subTotal-discount));
}
public static void main(String[] args){
final int MAXCHEESES=4;
String[] names = new String[MAXCHEESES];
double[] prices = new double[MAXCHEESES];
int[] amounts = new int[MAXCHEESES];
Scanner input = new Scanner(System.in);
intro(names, prices, amounts);
getAmount(input, names, amounts);
double total = calcSubTotal(prices, amounts);
if(MAXCHEESES>0){
System.out.println(\"Display the itemized list? (1 for yes)\");
int itemized = input.nextInt();
if(itemized==1){
itemizedList(names, prices, amounts);
}
}
System.out.println();
printTotal(total, discount(total));
}
}.
Focus on Writing 4. Supporting a Point of View Do you think Social Se.pdf
Focus on Writing 4. Supporting a Point of View Do you think Social Security has encouraged
Americans to become too dependent on the state and federal governments for support in times of
need? Write a paragraph explaining your answer.
Solution
ANSWER:
In America, Social Security is the often used term for the federal Survivors, Old-Age, and
Disability Insurance (OASDI) program. Yes, I think social security has encouraged Americans to
become too dependent for their security solely on earnings from employment. The reasons are:
--Social Security, providing education or other assistance support, once considered to be the
responsibility of individuals, families, churches, neighbourhoods, and other civil society
institutions is rising thus reflecting that America is building a dependency culture , with ever-
more people relying on an ever-growing federal government to provide them benefits or cash.
--Industrialization caused the migration of people toward centres of work, therefore separating
children from the support provided by the wider family. Moreover, the development of
compulsory education prolonged the period during which kids were dependent on the parents.
--U.S. system developed enforced retirement and created too much dependency. Most retirees
rely on long-term care in assisted home health care providers or living facilities under Medicaid.
--Social Security has greatly encroached on the responsibility of people for giving their own
retirement funds, thus leaving millions of retirees dependent on working younger generations to
fund their retirement..
Decision-Making Across the Organization The board of trustees of a lo.pdf
Decision-Making Across the Organization The board of trustees of a local church is concerned
about the internal accounting controls for the offering collections made at weekly services. The
trustees ask you to serve on a three-person audit team with the internal auditor of a local college
and a CPA who has just joined the church. At a meeting of the audit team and the board of
trustees, you learn the following 1. The church\'s board of trustees has delegated responsibility
for the financial management and audit of the financial records to the finance committee. This
group prepares the annual budget and approves major disbursements. It is not involved in
collections or recordkeeping. No audit has been made in recent years because the same trusted
employee has kept church records and served as financial secretary for 15 years. The church does
not carry any fidelity insurance 2. The collection at the weekly service is taken by a team of
ushers who volunteer to serve one month. The ushers take the collection plates to a basement
office at the rear of the church. They hand their plates to the head usher and return to the church
service. After all plates have been turned in, the head usher counts the cash received. The head
usher then places the cash in the church safe along with a notation of the amount counted. The
head usher volunteers to serve for 3 months 3. The next morning, the financial secretary opens
the safe and recounts the collection. The secretary withholds $150-$200 in cash, depending on
the cash expenditures expected for the week, and deposits the remainder of the collections in the
bank. To facilitate the deposit, church members who contribute by check are asked to make their
checks payable to \"Cash.\" Each month, the financial secretary reconciles the bank statement
and submits a copy of the reconciliation to the board of trustees. The reconciliations have rarely
contained any bank errors and have never shown any errors per books. 4. Instructions With the
class divided into groups, answer the following. Indicate the weaknesses in internal accounting
control over the handling of collections. List the improvements in internal control procedures
that you plan to make at the next meeting of the audit team for (1) the ushers, (2) the head usher,
(3) the financial secretary, and (4) the finance committee What church policies should be
changed to improve internal control?
Solution
(a) The primary weakness in internal accounting control with regards to handling of collections
starts with the weakness that the church has not undertaken an audit in recent years. An audit
should have been done regardless of the trustworthiness of its employees and regardless of their
tenure at the church. Secondly the church does not have fidelity insurance and this can possibly
lead to a situation in which the church will not be able to negate its loss in case of any occurrence
of fraud.
Another weakness in internal control is with regards to passing of th.
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The following code, is a one player battleship game in JAVA. Im tryi.pdf
The following code, is a one player battleship game in JAVA. Im trying to Enhance the game to
be a two player game (were a player plays aggainst a computer opponent). With TWO boards
displayed side by side. The player and the computer must take turns selecting the coordinates on
their own boards. (the ships cannot be placed adjacent to each other).
BattleShipGame.java
package battleship;
import java.util.ArrayList;
import java.util.Scanner;
public class BattleshipGame {
private Ocean ocean;
private boolean[][] availableSpot;
private Scanner sc;
public BattleshipGame() {
// define a new ocean and a new 2D array to store available coordinates
ocean = new Ocean();
availableSpot = new boolean[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++){
availableSpot[i][j] = true;
}
}
}
/**
* prints the game menu and info
* //param select
*/
public void print(int select){
String info;
switch (select) {
case 1: info = \"Welcome to the World of Battleship!\";
break;
case 2: info = \"Enter coordinates to fire: \";
break;
case 3: info = \"Shots fired: \"+ocean.getShotsFired()+\", Ships sunk:
\"+ocean.getShipsSunk();
break;
case 4: info = \"Congratulations! You win!\";
break;
case 99: info = \"Invalid input. Please re-enter:\";
break;
case 100: info = \"--------------------------------------------\";
break;
case 101: info = \"\ ============================================\";
break;
default: info = \"Error selection\";
break;
}
System.out.println(info);
}
/**
* check if the input is valid
* //param input
* //return boolean
*/
public boolean checkValidInput(String input){
ArrayList numList = new ArrayList();
for (int i=0;i<10;i++){
numList.add(\"\"+i);
}
String[] coordinates = input.split(\" \");
//returns false if there are not 2 strings
if (coordinates.length!=2){
return false;
}
//returns false if any of the strings is not a single digit number
for (String str: coordinates){
if (numList.contains(str)==false){
return false;
}
}
//returns false if the coordinates have already been shot at
int row = Integer.parseInt(coordinates[0]);
int column = Integer.parseInt(coordinates[1]);
if (this.availableSpot[row][column]==false){
return false;
}
return true;
}
/**
* get the coordinates to shoot at from the String input
* //param input
* //return int[] coordinates
*/
public int[] getCoordinates(String input){
int[] coordinates = new int[2];
String[] strList = input.split(\" \");
int row = Integer.parseInt(strList[0]);
int column = Integer.parseInt(strList[1]);
coordinates[0] = row;
coordinates[1] = column;
return coordinates;
}
/**
* play the battleship game
*/
public void play(){
print(101);
print(1);
ocean.placeAllShipsRandomly();
boolean isGameOver = ocean.isGameOver();
sc = new Scanner(System.in);
//print the ocean and start the game
ocean.print();
print(3);
while (!isGameOver){
print(2);
String input = sc.nextLine();
//check if input is valid
while (!checkValidInput(input)){
print(99);
input = sc.nextLine();
}
//get coordinates and fire
int[] coord.
C++ Programming (Please help me!! Thank you!!)Problem A Win SimU.pdf
C++ Programming: (Please help me!! Thank you!!)
Problem A: Win SimUniversity (20 points) Currently there is not way to “win” the game.
Modify the SimUniversity.cpp file to have a “hours until graduation” variable that starts at 48
(you may change this number for testing, but ensure you the code you submit has it at 48). In
addition to the normal output, give the time left to graduate as shown in the example below.
When you have graduated, end the game and tell them they have won. If you are expected to
graduate right when you would normally lose the game, you should graduate anyways and win
the game (see 2nd example). Please ensure you follow the sample output exactly
This is my program named SimUniversity.cpp to modify (you copy and paste to C++ to modify)
This is an example that I should get
Example 1 (user input is bold, board is not displayed because it is too big... do not change it):
Current stats are: Energy = 70, Entertainment = 70, Smartness = 70.
Current time: 8:00. You are at the Dorm. Do you want to (S)leep, do (H)omeowrk or (W)atch
some YouTube?
Do you want to (G)o to a different location?
g
Where do you want to travel to: (O, U, D)?
u
You go to University.
From your actions changed your stats by... Energy: -4, Entertainment: 0, Smartness: 0.
You have 47 hours left until graduation...
(Press enter to advance an hour)
Current stats are: Energy = 66, Entertainment = 70, Smartness = 70.
Current time: 9:00.
You are at the University. Do you want to (A)ttend class or (S)leep through lecture? Do you
want to (G)o to a different location?
a
You take copious notes and pay close attention to the material. From your actions changed your
stats by... Energy: - 4, Entertainment: - 8, Smartness: 3.
You have 46 hours left until graduation...
(Press enter to advance an hour)
... (skipping some time, this line is not actually output!) Current stats are: Energy = 67,
Entertainment = 50, Smartness = 73. Current time: 9:00.
You are at the Dorm.
Do you want to (S)leep, do (H)omeowrk or (W)atch some YouTube?
Do you want to (G)o to a different location?
h
You break out the books and pound through some problems. From your actions changed your
stats by... Energy: - 3, Entertainment: -20, Smartness: 3. You have 1 hours left until graduation...
(Press enter to advance an hour)
Current stats are: Energy = 64, Entertainment = 30, Smartness = 76.
Current time: 10:00.
You are at the Dorm.
Do you want to (S)leep, do (H)omeowrk or (W)atch some YouTube?
Do you want to (G)o to a different location?
w
OMG!! CATS!!!! From your actions changed your stats by... Energy: - 2, Entertainment: 20,
Smartness: - 1. You have 0 hours left until graduation...
You graduate from college.
(Press enter to advance an hour)
Solution
#include
#include
using namespace std;
class Room {
private:
// letters outline where the location is
char mapLetter;
// locations are rectangles....
int topLeftX;
int topLeftY;
int bottomRightX;
int bottomRightY;
// all good things have a name, right?
str.
NO PAPER ANSWERS. ALL ANSWER SUBMISSIONS SHOULD BE ABLE TO RUN WIT.pdf
The document describes a Java program to play a simplified single-player version of the Connect Four game. The program initializes an empty game board and allows a player to drop red disks into columns while the computer randomly drops yellow disks. It checks after each turn if either player has four disks in a row to win, and determines if it is a draw if the board is full without a win.
The main class of the tictoe game looks like.public class Main {.pdf
The main class of the tictoe game looks like.
public class Main {
public void play() {
TicTacToe game = new TicTacToe();
System.out.println(\"Welcome! Tic Tac Toe is a two player game.\");
System.out.print(\"Enter player one\'s name: \");
game.setPlayer1(game.getPrompt());
System.out.print(\"Enter player two\'s name: \");
game.setPlayer2(game.getPrompt());
boolean markerOk = false;
while (!markerOk) {
System.out.print(\"Select any letter as \" + game.getPlayer1() + \"\'s marker: \");
String marker = game.getPrompt();
if (marker.length() == 1 &&
Character.isLetter(marker.toCharArray()[0])) {
markerOk = true;
game.setMarker1(marker.toCharArray()[0]);
} else {
System.out.println(\"Invalid marker, try again\");
}
}
markerOk = false;
while (!markerOk) {
System.out.print(\"Select any letter as \" + game.getPlayer2() + \"\'s marker: \");
String marker = game.getPrompt();
if (marker.length() == 1 &&
Character.isLetter(marker.toCharArray()[0])) {
markerOk = true;
game.setMarker2(marker.toCharArray()[0]);
} else {
System.out.println(\"Invalid marker, try again\");
}
}
boolean continuePlaying = true;
while (continuePlaying) {
game.init();
System.out.println();
System.out.println(game.getRules());
System.out.println();
System.out.println(game.drawBoard());
System.out.println();
String player = null;
while (!game.winner() && game.getPlays() < 9) {
player = game.getCurrentPlayer() == 1 ? game.getPlayer1() : game.getPlayer2();
boolean validPick = false;
while (!validPick) {
System.out.print(\"It is \" + player + \"\'s turn. Pick a square: \");
String square = game.getPrompt();
if (square.length() == 1 && Character.isDigit(square.toCharArray()[0])) {
int pick = 0;
try {
pick = Integer.parseInt(square);
} catch (NumberFormatException e) {
//Do nothing here, it\'ll evaluate as an invalid pick on the next row.
}
validPick = game.placeMarker(pick);
}
if (!validPick) {
System.out.println(\"Square can not be selected. Retry\");
}
}
game.switchPlayers();
System.out.println();
System.out.println(game.drawBoard());
System.out.println();
}
if (game.winner()) {
System.out.println(\"Game Over - \" + player + \" WINS!!!\");
} else {
System.out.println(\"Game Over - Draw\");
}
System.out.println();
System.out.print(\"Play again? (Y/N): \");
String choice = game.getPrompt();
if (!choice.equalsIgnoreCase(\"Y\")) {
continuePlaying = false;
}
}
}
public static void main(String[] args) {
Main main = new Main();
main.play();
}
}
The TicTacToe class code will be like
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
/**
*
* author Iamavinashkotina
*/
public class TicTacToe {
private char[][] board = new char[3][3];
private String player1;
private String player2;
private int currentPlayer;
private char marker1;
private char marker2;
private int plays;
private BufferedReader reader =
new BufferedReader(new InputStreamReader(System.in));
protected void init() {
int counter = 0;
for (int i = 0; i < 3; i++) {
for (int i1 = 0; i1 < 3; i1++) {.
i have a runable code below that works with just guessing where the .pdf
i have a runable code below that works with just guessing where the ships are. i need help editing
this code to be able to have a player play against computer and taking turns playing battleship.
BattleShipGame.java
package battleship;
import java.util.ArrayList;
import java.util.Scanner;
public class BattleshipGame {
private Ocean ocean;
private boolean[][] availableSpot;
private Scanner sc;
public BattleshipGame() {
// define a new ocean and a new 2D array to store available coordinates
ocean = new Ocean();
availableSpot = new boolean[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++){
availableSpot[i][j] = true;
}
}
}
/**
* prints the game menu and info
* //param select
*/
public void print(int select){
String info;
switch (select) {
case 1: info = \"Welcome to the World of Battleship!\";
break;
case 2: info = \"Enter coordinates to fire: \";
break;
case 3: info = \"Shots fired: \"+ocean.getShotsFired()+\", Ships sunk:
\"+ocean.getShipsSunk();
break;
case 4: info = \"Congratulations! You win!\";
break;
case 99: info = \"Invalid input. Please re-enter:\";
break;
case 100: info = \"--------------------------------------------\";
break;
case 101: info = \"\ ============================================\";
break;
default: info = \"Error selection\";
break;
}
System.out.println(info);
}
/**
* check if the input is valid
* //param input
* //return boolean
*/
public boolean checkValidInput(String input){
ArrayList numList = new ArrayList();
for (int i=0;i<10;i++){
numList.add(\"\"+i);
}
String[] coordinates = input.split(\" \");
//returns false if there are not 2 strings
if (coordinates.length!=2){
return false;
}
//returns false if any of the strings is not a single digit number
for (String str: coordinates){
if (numList.contains(str)==false){
return false;
}
}
//returns false if the coordinates have already been shot at
int row = Integer.parseInt(coordinates[0]);
int column = Integer.parseInt(coordinates[1]);
if (this.availableSpot[row][column]==false){
return false;
}
return true;
}
/**
* get the coordinates to shoot at from the String input
* //param input
* //return int[] coordinates
*/
public int[] getCoordinates(String input){
int[] coordinates = new int[2];
String[] strList = input.split(\" \");
int row = Integer.parseInt(strList[0]);
int column = Integer.parseInt(strList[1]);
coordinates[0] = row;
coordinates[1] = column;
return coordinates;
}
/**
* play the battleship game
*/
public void play(){
print(101);
print(1);
ocean.placeAllShipsRandomly();
boolean isGameOver = ocean.isGameOver();
sc = new Scanner(System.in);
//print the ocean and start the game
ocean.print();
print(3);
while (!isGameOver){
print(2);
String input = sc.nextLine();
//check if input is valid
while (!checkValidInput(input)){
print(99);
input = sc.nextLine();
}
//get coordinates and fire
int[] coordinates = getCoordinates(input);
int row = coordinates[0];
int column = coordinates[1];
ocean.shootAt(row, column);
availableSpot[row][column] = false;
isGa.
The Ring programming language version 1.10 book - Part 71 of 212
The Gold Magic 800 is a puzzle game developed in Ring, RingAllegro and RingOpenGL. The goal is to move a box around levels to collect gold and open doors by placing the box on them, solving puzzles to progress through 44 levels. Players must plan their route, move directly to targets, consider future moves, avoid and learn from mistakes, and respect the cost to open the first door. The game teaches entrepreneurial thinking and skills like planning, efficiency, foresight, and patience. Screenshots show the level selection screen and an example level with the box and gold to collect.
TilePUzzle class Anderson, Franceschi public class TilePu.docx
The document contains code for a Tile Puzzle game implemented using Java classes. The TilePuzzle class represents the game logic and stores the game state including the grid size, tiles, and empty space location. The Game class sets up the GUI for the game using a GridLayout and JButtons to represent each tile. It links the GUI to the TilePuzzle class so user clicks are handled by trying to move tiles in the TilePuzzle. The NestedLayoutPractice driver class sets up a frame with options to set the grid size for a new game.
AI CHALLENGE ADMIN
This document contains the code for a Connect Four game. It defines constants, global variables, and functions for tracking the game state (board, current player), validating and executing moves, checking for wins, and handling I/O like drawing the board. The main function runs the game loop, continuously prompting for player moves until the board is full or a player wins. Special move types like clearing rows/columns are supported in addition to normal drops.
This is the Java code i have for a Battleship project i am working o.pdf
This is the Java code i have for a Battleship project i am working on, i am now wanting to
convert this to a fully graphical Gui interface, but i just cant seem to get anywhere with it, so if i
could get some help with this, i would apperciate it....(just a reminder its in JAVA)
public class BattleshipGame {
private Ocean ocean;
private boolean[][] availableSpot;
private Scanner sc;
public BattleshipGame() {
// define a new ocean and a new 2D array to store available coordinates
ocean = new Ocean();
availableSpot = new boolean[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++){
availableSpot[i][j] = true;
}
}
}
/**
* prints the game menu and info
* //param select
*/
public void print(int select){
String info;
switch (select) {
case 1: info = \"Welcome to the World of Battleship!\";
break;
case 2: info = \"Enter coordinates to fire: \";
break;
case 3: info = \"Shots fired: \"+ocean.getShotsFired()+\", Ships sunk:
\"+ocean.getShipsSunk();
break;
case 4: info = \"Congratulations! You win!\";
break;
case 99: info = \"Invalid input. Please re-enter:\";
break;
case 100: info = \"--------------------------------------------\";
break;
case 101: info = \"\ ============================================\";
break;
default: info = \"Error selection\";
break;
}
System.out.println(info);
}
/**
* check if the input is valid
* //param input
* //return boolean
*/
public boolean checkValidInput(String input){
ArrayList numList = new ArrayList();
for (int i=0;i<10;i++){
numList.add(\"\"+i);
}
String[] coordinates = input.split(\" \");
//returns false if there are not 2 strings
if (coordinates.length!=2){
return false;
}
//returns false if any of the strings is not a single digit number
for (String str: coordinates){
if (numList.contains(str)==false){
return false;
}
}
//returns false if the coordinates have already been shot at
int row = Integer.parseInt(coordinates[0]);
int column = Integer.parseInt(coordinates[1]);
if (this.availableSpot[row][column]==false){
return false;
}
return true;
}
/**
* get the coordinates to shoot at from the String input
* //param input
* //return int[] coordinates
*/
public int[] getCoordinates(String input){
int[] coordinates = new int[2];
String[] strList = input.split(\" \");
int row = Integer.parseInt(strList[0]);
int column = Integer.parseInt(strList[1]);
coordinates[0] = row;
coordinates[1] = column;
return coordinates;
}
/**
* play the battleship game
*/
public void play(){
print(101);
print(1);
ocean.placeAllShipsRandomly();
boolean isGameOver = ocean.isGameOver();
sc = new Scanner(System.in);
//print the ocean and start the game
ocean.print();
print(3);
while (!isGameOver){
print(2);
String input = sc.nextLine();
//check if input is valid
while (!checkValidInput(input)){
print(99);
input = sc.nextLine();
}
//get coordinates and fire
int[] coordinates = getCoordinates(input);
int row = coordinates[0];
int column = coordinates[1];
ocean.shootAt(row, column);
availableSpot[row][column] = false;
isGameOver = o.
This is for an homework assignment using Java code. Here is the home.pdf
This document discusses code for a Mine Walker game where the player moves around a board trying to reach an ice cream cone while avoiding mines. It provides the game rules and an example dialog. The code works but does not properly reset the board when the player chooses to play again. To fix this, the board initialization code needs to be moved to a separate function that can be called again when restarting.
efy-articles
The document describes a C++ program that implements a customer information system. The program allows users to add, list, modify, delete, search, and pack customer records stored in a .dat file. It features a main menu with these options. Selecting add, modify, or delete allows editing customer details like ID, name, address, phone number. Pack permanently removes deleted records to recover space. The source code and executable will be provided on next month's disc.
#include -stdio-h- #include -stdlib-h- #include -stdbool-h- #include - (1).docx
This code implements a tic-tac-toe game that can be played between two humans or a human and computer. It includes functions to create and print the game board, check for a draw, and check if a move resulted in a win. The main function handles parsing command line arguments, running the game loop, and cleaning up memory.
ObjectiveCreate a graphical game of minesweeper IN JAVA. The boar.pdf
Objective:
Create a graphical game of minesweeper IN JAVA. The board should consist of 10x10 buttons.
Of the 100 spaces there should be at least 20 randomly placed mines. If the button is clicked and
it is not a mine then it clears itself. If a space has been cleared then it should indicate how many
of its eight neighbors are mines. If a space is clicked and it is a mine then the game is over and
the player is asked if they want to play again. Finally, if all the non-mine spaces have been
clicked then the player is prompted that they won.
Solution
2 files need to be made.
First Game.Java which will have the gaming logic and User Interface and Main.Java which will
have have the main method and object of Game.java Number of rows and cols is customizable so
user can change that as and when needed.
import java.awt.*;
import java.awt.Dimension;
import javax.swing.*;
import java.awt.event.*;
import java.util.*;
public class Game extends JFrame implements ActionListener, ContainerListener {
int fw, fh, blockr, blockc, var1, var2, num_of_mine, detectedmine = 0, savedlevel = 1,
savedblockr, savedblockc, savednum_of_mine = 10;
int[] r = {-1, -1, -1, 0, 1, 1, 1, 0};
int[] c = {-1, 0, 1, 1, 1, 0, -1, -1};
JButton[][] blocks;
int[][] countmine;
int[][] colour;
ImageIcon[] ic = new ImageIcon[14];
JPanel panelb = new JPanel();
JPanel panelmt = new JPanel();
JTextField tf_mine, tf_time;
JButton reset = new JButton(\"\");
Random ranr = new Random();
Random ranc = new Random();
boolean check = true, starttime = false;
Point framelocation;
Stopwatch sw;
MouseHendeler mh;
Point p;
Game() {
super(\"Game\");
setLocation(400, 300);
setic();
setpanel(1, 0, 0, 0);
setmanue();
sw = new Stopwatch();
reset.addActionListener(new ActionListener() {
public void actionPerformed(ActionEvent ae) {
try {
sw.stop();
setpanel(savedlevel, savedblockr, savedblockc, savednum_of_mine);
} catch (Exception ex) {
setpanel(savedlevel, savedblockr, savedblockc, savednum_of_mine);
}
reset();
}
});
setDefaultCloseOperation(EXIT_ON_CLOSE);
show();
}
public void reset() {
check = true;
starttime = false;
for (int i = 0; i < blockr; i++) {
for (int j = 0; j < blockc; j++) {
colour[i][j] = \'w\';
}
}
}
public void setpanel(int level, int setr, int setc, int setm) {
if (level == 1) {
fw = 200;
fh = 300;
blockr = 10;
blockc = 10;
num_of_mine = 10;
} else if (level == 2) {
fw = 320;
fh = 416;
blockr = 16;
blockc = 16;
num_of_mine = 70;
} else if (level == 3) {
fw = 400;
fh = 520;
blockr = 20;
blockc = 20;
num_of_mine = 150;
} else if (level == 4) {
fw = (20 * setc);
fh = (24 * setr);
blockr = setr;
blockc = setc;
num_of_mine = setm;
}
savedblockr = blockr;
savedblockc = blockc;
savednum_of_mine = num_of_mine;
setSize(fw, fh);
setResizable(false);
detectedmine = num_of_mine;
p = this.getLocation();
blocks = new JButton[blockr][blockc];
countmine = new int[blockr][blockc];
colour = new int[blockr][blockc];
mh = new MouseHendeler();
getContentPane().removeAll();
panelb.removeAll();
tf_mine = new JTe.
Project 2
The document describes the rules and gameplay for a number board game where two players take turns selecting numbers to add to their score. Players can only move horizontally or vertically on the 8x8 board. The game ends when there are no remaining valid moves. Hard mode makes the computer opponent more intelligent by trying to predict player moves. The document also provides code snippets for game mechanics like handling invalid user input and returning to menus.
import java.util.Scanner;public class Main { public static in.pdf
import java.util.Scanner;
public class Main {
public static int gridArray1[][] = null;
public static int gridArray2[][] = null;
public static boolean playerTurn = true;
public static int count = 0;
public static void setGridDimensions(int x_max, int y_max) {
Main.gridArray1 = new int[x_max][y_max];
Main.gridArray2 = new int[x_max][y_max];
for (int i = 0; i < x_max; i++) {
for (int j = 0; j < y_max; j++) {
gridArray1[i][j] = -1;
gridArray2[i][j] = -1;
}
}
}
static void placeShip(int starting_x, int starting_y, int length, int direction) {
count++;
int ships[] = new int[10];
int battleshipArrayPositions1[] = new int[4];
int cruiserArrayPositions1[] = new int[3];
int submarineArrayPositions1[] = new int[3];
int destroyerArrayPositions1[] = new int[2];
int carrierArrayPositions2[] = new int[5];
int battleshipArrayPositions2[] = new int[4];
int cruiserArrayPositions2[] = new int[3];
int submarineArrayPositions2[] = new int[3];
int destroyerArrayPositions2[] = new int[2];
if (playerTurn) {
if (direction == 0) {
for (int i = starting_x; i < starting_x + length; i++) {
Main.gridArray1[i][starting_y] = 0;
}
} else {
for (int i = starting_y; i < starting_y + length; i++) {
Main.gridArray1[starting_x][i] = 0;
}
}
} else {
if (direction == 0) {
for (int i = starting_x; i < starting_x + length; i++) {
Main.gridArray2[i][starting_y] = 0;
}
} else {
for (int i = starting_y; i < starting_y + length; i++) {
Main.gridArray2[starting_x][i] = 0;
}
}
}
}
boolean isConflictingShipPlacement(int starting_x, int starting_y, int length, int direction) {
return false;
}
static int shoot(int x, int y) {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (Main.gridArray2[i][j] == 0) {
return 0;
}
}
}
} else {
}
return 0;
}
boolean hasBeenAttempted(int x, int y) {
return false;
}
static void displayGrid(boolean showShips) {
int count = 0;
System.out.print(\" 0 1 2 3 4 5 6 7 8 9\");
if (showShips) {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray1[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray1[i][j] == 0) {
System.out.print(\"@ \");
} else if (Main.gridArray1[i][j] == 1) {
System.out.print(\"+ \");
} else {
System.out.print(\"X \");
}
}
}
} else {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray2[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray2[i][j] == 0) {
System.out.print(\"@ \");
} else if (Main.gridArray2[i][j] == 1) {
System.out.print(\"+ \");
} else {
System.out.print(\"X \");
}
}
}
}
} else {
if (playerTurn) {
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (j % 10 == 0) {
System.out.print(\"\ \" + count + \" \");
count++;
}
if (Main.gridArray1[i][j] == -1) {
System.out.print(\"- \");
} else if (Main.gridArray1[i][j] == 0) {
System.out.print(\"- \");
} el.
Here is the code for youimport java.util.Scanner; import java.u.pdf
Here is the code for you:
import java.util.Scanner;
import java.util.Random;
public class TicTacToeGame {
static char[] [] board = new char[3][3];
static Scanner input=new Scanner(System.in);
//Object of Stats class to maintain statistics
static Stats stat = new Stats();
/**
* Prints the TicTacToe board
* @param arr: The board so far
*/
public static void printBoard(char [][] arr){
System.out.println();
for (int i=0; i<3; i++)
{
for (int j=0; j<3; j++)
{
System.out.print(arr[i][j]);
if(j!=2)
//Print the | for readable output
System.out.print(\" \" + \"|\" + \" \");
}
System.out.println();
if(i!=2) {
System.out.print(\"_ _ _ \"); // Print _ for readability
System.out.println();;
}
}
}
/**
* Clear the TicTacToe board before starting a new game
* @param arr: The board so far
*/
public static void clearBoard(char [][] arr){
for (int i=0; i<3; i++)
{
for (int j=0; j<3; j++)
{
arr[i][j]=\' \';
}
}
}
/** Determines if the player with the specified token wins
*
* @param symbol: Specifies whether the player is X or O
* @return true if player has won, false otherwise
*/
public static boolean isWon(char symbol) {
for (int i = 0; i < 3; i++) //horizontal
if (board[i][0] == symbol
&& board[i][1] == symbol
&& board[i][2] == symbol) {
return true;
}
//TODO!!! Also check for vertical and the two diagonals
for (int i = 0; i < 3; i++) //vertical
if (board[0][i] == symbol
&& board[1][i] == symbol
&& board[2][i] == symbol) {
return true;
}
//Leading diagonal
if (board[0][0] == symbol
&& board[1][1] == symbol
&& board[2][2] == symbol) {
return true;
}
//Trailing diagonal
if (board[0][2] == symbol
&& board[1][1] == symbol
&& board[2][0] == symbol) {
return true;
}
return false;
}
/** Determines if the cell is occupied
*
* @param row: Row of the cell to be checked
* @param col: Column of the cell to be checked
* @return true if the cell is occupied, false otherwise
*/
public static boolean isOccupied(int row, int col){
if (board[row][col]!=\' \') return false;
else return true;
}
/** Determines who starts the game
*/
public static int whoStarts(){
//TODO: Randomly chooses between 0 and 1 and returns the choice
return (int)(Math.random() + 0.5 );
}
/** takes care of the human\'s move
* 1. Prompt for a cell, then column
* 2. Puts a symbol (X or O) on the board
* 3. Prints the updated board
* 4. If a human wins: prints, updates stats and returns true
* 5. If not a win yet, returns false */
public static boolean humanTurn(char symbol){
//Prompt for a cell. User must enter
//row and column with a space in between.
System.out.print(\"\ \ Enter your move: (row column): \" );
int row = input.nextInt();
int col = input.nextInt();
//TODO!!! Mark user move in the board, print
//the board and check if user has won!
board[row][col] = symbol;
printBoard(board);
if(isWon(symbol))
return true;
return false;
}
/** takes care of the computer\'s move
* 1. Generates numbers until finds an empty cell
* 2. Puts a symbol (X or O) on the board
* 3. Prints the updated board
* 4. If a comp .
19012011102_Nayan Oza_Practical-7_AI.pdf
1. The document describes the steps to create a tic-tac-toe game using the minimax algorithm in Python. It includes defining classes for the game state and the tic-tac-toe game, and functions for evaluating the game state, determining valid moves and wins, and implementing the minimax algorithm.
2. The program allows two players to play tic-tac-toe against each other or against an AI opponent that uses minimax to select moves. It prints the game board and declares a winner or draw once the game is over.
3. The output shows a sample run of the tic-tac-toe game being played between a human and AI player.
The Ring programming language version 1.8 book - Part 66 of 202
This document contains Ring code for a 3D tic-tac-toe game. It includes classes for graphics handling, sound, a game background, individual game cubes, and displaying the game over screen. Methods are defined for loading resources, handling input, checking for game completion, and rotating the game cubes. The code provides a framework for rendering and updating a 3D tic-tac-toe game.
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C++ Programming (Please help me!! Thank you!!)Problem A Win SimU.pdf
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NO PAPER ANSWERS. ALL ANSWER SUBMISSIONS SHOULD BE ABLE TO RUN WIT.pdf
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The main class of the tictoe game looks like.public class Main {.pdf
The main class of the tictoe game looks like.public class Main {.pdf
i have a runable code below that works with just guessing where the .pdf
i have a runable code below that works with just guessing where the .pdf
The Ring programming language version 1.10 book - Part 71 of 212
The Ring programming language version 1.10 book - Part 71 of 212
TilePUzzle class Anderson, Franceschi public class TilePu.docx
TilePUzzle class Anderson, Franceschi public class TilePu.docx
This is the Java code i have for a Battleship project i am working o.pdf
This is the Java code i have for a Battleship project i am working o.pdf
This is for an homework assignment using Java code. Here is the home.pdf
This is for an homework assignment using Java code. Here is the home.pdf
#include -stdio-h- #include -stdlib-h- #include -stdbool-h- #include - (1).docx
#include -stdio-h- #include -stdlib-h- #include -stdbool-h- #include - (1).docx
ObjectiveCreate a graphical game of minesweeper IN JAVA. The boar.pdf
ObjectiveCreate a graphical game of minesweeper IN JAVA. The boar.pdf
import java.util.Scanner;public class Main { public static in.pdf
import java.util.Scanner;public class Main { public static in.pdf
Here is the code for youimport java.util.Scanner; import java.u.pdf
Here is the code for youimport java.util.Scanner; import java.u.pdf
The Ring programming language version 1.8 book - Part 66 of 202
The Ring programming language version 1.8 book - Part 66 of 202
More from flashfashioncasualwe
How does the mutation rate of speciation in the Dobzhansky- Muller m.pdf
How does the mutation rate of speciation in the Dobzhansky- Muller model? How does the
mutation rate affect the rate of speciation in the Dobzhansky Muller model? An increased
mutation rate results in a more rapid reproductive isolation between the two diverging
populations. O An increased mutation rate results in slower reproductive isolation between the
two diverging populations. The mutation rate is unrelated to the rate of evolution of reproductive
isolation.
Solution
ans- a increased mutation rate results in a more reproduction isolation between the two diverging
population.
an ancestral population splits into two parts the two lineage begins to diverge genetically which
are temporally isolated from each other.new alleles evolved at one locus of lineage and different
alleles evolved in another locus of the lineage..
Hello. I need help fixing this Java Code on Eclipse. Please fix part.pdf
Hello. I need help fixing this Java Code on Eclipse. Please fix parts indicated as \"//Fix\" or
\"//Fill-in\". The code given is the first image. Thank you! Sample outputs are given below along
with what the code is required to do. import java til. Random import java til. Scanner public class
GenCheeseShopv2 public static void intro (Stringt] names, double []prices int amounts Fill-in
public static void getAmount (Scanner input, String[] names, int[] amounts) public static void
itemizedList (String[] names, double Prices int[] amounts) Fill-i public static double
calcSubTotal (double prices, int amounts return 0; pub. lic static int discount (double subTotal
return 0; pub. lic static oid print Total (double subTotal int discount) Fill-in public static void mi
args final int MAXCH EESEE DO NOT CHANGE ANYTHING BELOW String[] names new
String CMAXCH EESE double[] prices new double EESE] int[] amounts new int
[MAXCHEESEJ Scanner input new Scanner (Syste intro names, prices, amounts get Amo unt
input, names, amounts double total calcSubTotal (prices, amounts if EESEE 0) System. out print
Display the itemized list? (1 for yes) int itemized input-nex if item 1) itemized List (names,
prices, amounts); System. out. println(); print Total(total, discount total));
Solution
import java.util.Random;
import java.util.Scanner;
public class GenCheeseShopv2 {
public static void intro(String[] names, double[] prices,int[] amounts){
System.out.println(\"We sell \"+names.length+\" kinds of cheese\");
for(int i=0;i0)
System.out.println(amounts[i]+\" lbs of \"+names[i]+\" @ \"+prices[i]+\" =
$\"+(amounts[i]*prices[i]));
}
}
public static double calcSubTotal( double[] prices,int[] amounts){
double subTotal=0;
for(int i=0;i100)
return 10;
else if(subTotal > 50)
return 25;
else
return 0;
}
public static void printTotal(double subTotal,int discount){
System.out.println(\"Sub Total : $\"+subTotal);
System.out.println(\"-Discount : $\"+discount);
System.out.println(\"Total : $\"+(subTotal-discount));
}
public static void main(String[] args){
final int MAXCHEESES=4;
String[] names = new String[MAXCHEESES];
double[] prices = new double[MAXCHEESES];
int[] amounts = new int[MAXCHEESES];
Scanner input = new Scanner(System.in);
intro(names, prices, amounts);
getAmount(input, names, amounts);
double total = calcSubTotal(prices, amounts);
if(MAXCHEESES>0){
System.out.println(\"Display the itemized list? (1 for yes)\");
int itemized = input.nextInt();
if(itemized==1){
itemizedList(names, prices, amounts);
}
}
System.out.println();
printTotal(total, discount(total));
}
}.
Focus on Writing 4. Supporting a Point of View Do you think Social Se.pdf
Focus on Writing 4. Supporting a Point of View Do you think Social Security has encouraged
Americans to become too dependent on the state and federal governments for support in times of
need? Write a paragraph explaining your answer.
Solution
ANSWER:
In America, Social Security is the often used term for the federal Survivors, Old-Age, and
Disability Insurance (OASDI) program. Yes, I think social security has encouraged Americans to
become too dependent for their security solely on earnings from employment. The reasons are:
--Social Security, providing education or other assistance support, once considered to be the
responsibility of individuals, families, churches, neighbourhoods, and other civil society
institutions is rising thus reflecting that America is building a dependency culture , with ever-
more people relying on an ever-growing federal government to provide them benefits or cash.
--Industrialization caused the migration of people toward centres of work, therefore separating
children from the support provided by the wider family. Moreover, the development of
compulsory education prolonged the period during which kids were dependent on the parents.
--U.S. system developed enforced retirement and created too much dependency. Most retirees
rely on long-term care in assisted home health care providers or living facilities under Medicaid.
--Social Security has greatly encroached on the responsibility of people for giving their own
retirement funds, thus leaving millions of retirees dependent on working younger generations to
fund their retirement..
Decision-Making Across the Organization The board of trustees of a lo.pdf
Decision-Making Across the Organization The board of trustees of a local church is concerned
about the internal accounting controls for the offering collections made at weekly services. The
trustees ask you to serve on a three-person audit team with the internal auditor of a local college
and a CPA who has just joined the church. At a meeting of the audit team and the board of
trustees, you learn the following 1. The church\'s board of trustees has delegated responsibility
for the financial management and audit of the financial records to the finance committee. This
group prepares the annual budget and approves major disbursements. It is not involved in
collections or recordkeeping. No audit has been made in recent years because the same trusted
employee has kept church records and served as financial secretary for 15 years. The church does
not carry any fidelity insurance 2. The collection at the weekly service is taken by a team of
ushers who volunteer to serve one month. The ushers take the collection plates to a basement
office at the rear of the church. They hand their plates to the head usher and return to the church
service. After all plates have been turned in, the head usher counts the cash received. The head
usher then places the cash in the church safe along with a notation of the amount counted. The
head usher volunteers to serve for 3 months 3. The next morning, the financial secretary opens
the safe and recounts the collection. The secretary withholds $150-$200 in cash, depending on
the cash expenditures expected for the week, and deposits the remainder of the collections in the
bank. To facilitate the deposit, church members who contribute by check are asked to make their
checks payable to \"Cash.\" Each month, the financial secretary reconciles the bank statement
and submits a copy of the reconciliation to the board of trustees. The reconciliations have rarely
contained any bank errors and have never shown any errors per books. 4. Instructions With the
class divided into groups, answer the following. Indicate the weaknesses in internal accounting
control over the handling of collections. List the improvements in internal control procedures
that you plan to make at the next meeting of the audit team for (1) the ushers, (2) the head usher,
(3) the financial secretary, and (4) the finance committee What church policies should be
changed to improve internal control?
Solution
(a) The primary weakness in internal accounting control with regards to handling of collections
starts with the weakness that the church has not undertaken an audit in recent years. An audit
should have been done regardless of the trustworthiness of its employees and regardless of their
tenure at the church. Secondly the church does not have fidelity insurance and this can possibly
lead to a situation in which the church will not be able to negate its loss in case of any occurrence
of fraud.
Another weakness in internal control is with regards to passing of th.
Explain the experience of African-Americans in the South over the co.pdf
Explain the experience of African-Americans in the South over the course of the half-century
following the Civil War.
How did an interracial democracy in the South come to be a plausible goal for a time? Why was
this goal not realized?
Why did sharecropping become the dominant form of black labor by the end of Reconstruction
and why was the white South able to impose a “Jim Crow” style of segregation, even as it was
disfranchising the overwhelming majority of black men?
Solution
1.
Post civil war the African Americans faced a lot of troubles like : Destruction, hunger,
lawlessness and violence amongst others.
after the civil war many of the african americans came out out slavery and were refugees and
they did not kenw what to do next.But when they arrived home, they found a strange new world
waiting for them..
During a diversity management session, a manager suggests that stereo.pdf
During a diversity management session, a manager suggests that stereotypes are a necessary part
of working with others. \"I have to make assumptions about what\'s in the other person\'s head,
and stereotypes help me do that,\" she explains. \"It\'s better to rely on stereotypes than to enter a
working relationship with someone from another culture without any idea of what they believe
in!\" Discuss the merits of and problems with the manager\'s statement.
Solution
The manager statement highlights her viewpoint on the benefits of stereotypes in a diverse
working environment. Below are merits and problems of her statement -
Merits
1. Individuals from different cultures hold a viewpoint regarding one another through stereotypes
2. It becomes easy to initiate the communication among individuals by having a viewpoint rather
than having nothing
3. As individuals start interaction and communication with stereotypes in minds, they will be
careful in how to communicate with others without hurting their sentiments.
Problems
1. Stereotype is the most common opinion about a culture or group based on historical references
that are in the news. Hence, they will not provide a clear viewpoint on the individuals.
2. Stereotypes usually carry viewpoints that oversimplify an individual\'s personality and
character based on his/her culture or origin thus resulting in hurting the individual who might be
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3. It becomes difficult to change the opinion about an individual if viewed through stereotype..
Explain why a mycoplasma PCR kit might give a negative result when u.pdf
Explain why a mycoplasma PCR kit might give a negative result when used to test for
mycoplasma in a cell line containing mycoplasma
Solution
Mycoplasma is a prokaryotic organism that is a frequent and occult contaminant of cell cultures.
This organism can modify many aspects of cell physiology, rendering experiments that are
conducted with contaminated cells worthless. Because of their small size, Mycoplasma can pass
through filters used to prevent bacterial and fungal contamination and potentially spread to all
the cultures in a laboratory. It is essential that all new cell cultures entering a laboratory and all
cell banks are tested for presence of Mycoplasma. It is recommended that two techniques be
used, selected from a PCR-based methos, indirect staining and an agar and broth culture. These
three tests for detecting Mycoplasma take one day to 3-4 weeks and such tests should be an
obligatory component of quality control in every tissue culture laboratory.
Mycoplasma refers to any of over 200 species of tiny bacteria that invade cell cultures and may
even persist unrecognized for some time. They can come from sources as mundane as other cells
introduced to lab via media, sera or lab personnel. So, it is important to test your cell lines for
mycoplasma regularly. Consequences to your cells of mycoplasma infestation include changes in
growth rates, gene expression, morphology, metabolism and viability.
Even though most lab contamination can be blamed on as few as eight main culprit species, these
differ enough that no one test can find them all. And the little blighters are hardy – most
antibiotics used in cell culture are ineffective against mycoplasmas. For example, mycoplasmas
lack a cell wall, which is the key to penicillin’s success. Flawless cell culture technique is one of
the best preventive tools and testing to ascertain which cultures are clean and which cultures are
infected – so you can take quick and aggressive action before infestation spreads.
The M.hyorhinis strain is picked up by the PCR method of detection. This is the quickest but
also the least sensitive, mycoplasma assay. In this method, you perform PCR on samples of your
suspected cell cultures, using primers specific for mycoplasma DNA, usually mycoplasma’s 16S
rRNA genes. Running the PCR product on a gel shows presence of mycoplasma DNA by bands
of distinct sizes.
One major limitation of PCR is that prior information about target sequence is necessary in order
to generate the primers that will allow its selective amplification. This means that, typically, PCR
users must know precise sequences upstream of target region on each of the two single-stranded
templates in order to ensure that DNA polymerase properly binds to primer-template hybrids and
subsequently generates entire target region during DNA synthesis. Like all enzymes, DNA
polymerases are also prone to error, which in turn causes mutations in PCR fragments that are
generated. Specificity of PCR fragments can .
Describe the difference between the MOV instruction and the LEA instr.pdf
Describe the difference between the MOV instruction and the LEA instruction as used in these
two sample instructions. MOV D, V1 LEA DX, V1
Solution
Answer:
MOV D , V1 it moves the D to V1 and the instruction LEA DX V1 moves the address of the data
to V1 . There is no difference between MOV and LEA but LEA can be more powerful than
MOV if we need to calculate the address..
Explain how enzymes work, explaining the four major types of metabol.pdf
Explain how enzymes work, explaining the four major types of metabolic reactions enzymes
perform. Include: (Metabolism, catabolism, anabolism, substrate product, active site, induced fit,
competative and non competative inhibitors, allosteric regulation, cofactors and coenzymes,
hydrolysis and dehydration reactions, Redox Reactions, NADH, FADH2, phosphorylation,
exergonic/ endergonic reactions, ATP, isomerization reactions, feedback inhibition)
Solution
Enzymes are biological molecules (typically proteins) that significantly speed up the rate of
virtually all of the chemical reactions that take place within cells.
They are vital for life and serve a wide range of important functions in the body, such as aiding
in digestion and metabolism. Substrate binding[edit]
Enzymes must bind their substrates before they can catalyse any chemical reaction. Enzymes are
usually very specific as to what substrates they bind and then the chemical reaction catalysed.
Specificity is achieved by binding pockets with complementary shape, charge and
hydrophilic/hydrophobic characteristics to the substrates. Enzymes can therefore distinguish
between very similar substrate molecules to be chemoselective, regioselective and stereospecific.
Some of the enzymes showing the highest specificity and accuracy are involved in the copying
and expression of the genome. Some of these enzymes have \"proof-reading\" mechanisms.
Here, an enzyme such as DNA polymerase catalyzes a reaction in a first step and then checks
that the product is correct in a second step. This two-step process results in average error rates of
less than 1 error in 100 million reactions in high-fidelity mammalian polymerases.:5.3.1 Similar
proofreading mechanisms are also found in RNA polymerase, aminoacyl tRNA synthetases and
ribosomes.
Conversely, some enzymes display enzyme promiscuity, having broad specificity and acting on a
range of different physiologically relevant substrates. Many enzymes possess small side
activities which arose fortuitously (i.e. neutrally), which may be the starting point for the
evolutionary selection of a new function.
Enzyme changes shape by induced fit upon substrate binding to form enzyme-substrate complex.
Hexokinase has a large induced fit motion that closes over the substrates adenosine triphosphate
and xylose. Binding sites in blue, substrates in black and Mg2+ cofactor in yellow. (PDB: 2E2N,
2E2Q)
\"Lock and key\" model
To explain the observed specificity of enzymes, in 1894 Emil Fischer proposed that both the
enzyme and the substrate possess specific complementary geometric shapes that fit exactly into
one another.This is often referred to as \"the lock and key\" model:8.3.2 This early model
explains enzyme specificity, but fails to explain the stabilization of the transition state that
enzymes achieve.
Induced fit model
In 1958, Daniel Koshland suggested a modification to the lock and key model: since enzymes are
rather flexible structures, the active site is conti.
Develop an inventory management system for an electronics store. The .pdf
Develop an inventory management system for an electronics store. The inventory system should
have the following functionalities .BuildInventory: reada text file containing electronics products
information and store them in an array of pointers .Shownventory display all inventory items
.ShowDefectInventory: display inventory items that are defective Terminate: to save cument
inventory to a text file This lab assignment illustrates the following concepts: -Text file readings
and writings .Arrays of pointers and dynamic memory allocations with new and delete
Inheritance .C++ type casting: static cast Class Design You need at least three classes class
Inventory System: (minimum implementation specified below). This class stores Inyentoryltem
objects (which are in fact Inventory item base class pointers to derived Product objects and
member functions to manipulate those Product objects as shown below. .Private data members
Store Name Store ID ltem List (array of pointers to Inventory Item objects, max of 512) ltem
Count (tracking how many items are currently stored in the array) .Constructors (initialize all
pointers in the array to NULL in addition to what\'s described below .Default constructor: set
data members to 0 (for integers), 0.0 (for float/double), or NULL (for pointers) as appropriate.
Also invoke this function to initialize a seed for the random generator srand (time (NULL), (to
be used later by Product class to genearte random values for Product ID. See Code Helper
section at the end of the lab specs.) .Non-default constructor: taking a string for store name, an
integer for store ID. Call srand as shown above Destructor: de-allocate dynamic memory in the
amay off pointers (up to Item Count elements) .Public member functions: BuildInventory: read a
text file containing Product records (one Product per line), dynamically allocate Product objects
and store the objects in the array ItemList (an array of Inventoryltem pointers). It should also
update Item Count as needed Shownventory: display all Products in the inventory. Output must
be properly formatted and aligned (usingfield with and floating data with 2 digits after decimal
point). Note that if you invoke the Display function using the pointers from the array only Invent
tem (base objec) information will be displayed. Extra work is needed to properly display
Products (derived objects) information ntory: display only defective Products Terminate: iterate
thru the array of pointers to write Product objects in the array to a text file in the same format as
they were read in. You may use a different file name for wniting .mutator cessors for store name,
store id, and item count
Solution
/*
import com.incors.plaf.*;
import com.incors.plaf.kunststoff.*;
import com.incors.plaf.kunststoff.themes.*;
*/
public class MainForm extends JFrame implements WindowListener{
/************************ Variable declaration start **********************/
//The form container variable
JPanel Panel1;
JDeskto.
Describe one event from your daily life when you have changed your o.pdf
Describe one event from your daily life when you have changed your original attitude, and one
event when you could not change your original attitude. For the event when you changed your
original attitude, explain how you changed your attitude and what led to the change. For the
event when you could not change your original attitude, explain what did not work. Submission
Requirements: Submit your responses in a Microsoft Word document of the following
specifications:•Font: Arial; 12-Point •Line Spacing: Double •Length: 300–500 words Evaluation
Criteria:•Did you describe one event from your daily life when you have changed your original
attitude? •Did you describe one event from your daily life when you have not changed your
original attitude? •Did you explain how you changed your attitude and what led to the change?
•Did you explain what did not work when you could not change your original attitude? •Did you
provide your answers in complete sentences with few grammatical errors?
Solution
Instance where I changed my Attitude -
I don\'t believe in charity and philanthropy. I had this firm belief that money given to NGOs and
trusts in grants is mis-used. I always believed in commercial models and never realized that
texcept for a few most of development agencies are working for the welfare of people.
When I came acrossNanhi Kali NGO which works for girl child education I was sure that this is
another fraud NGOs which improperly utilizes the money earned in grant. But when I visited the
centre and saw the real impact on ground then my eyes remained wide open. They were doing
awesome work and even there financial statements were also showing this. This instance
changed my attitude towards NGOs.
What made me Change -
The critical factor which made me change my attitude is my interaction with foundation and
meeting with a few girls who really got benefits from the activities of NGO. The interaction
helped me understand their model in a better way. When I analyzed their financials I realized
that manpower is working at half the salaries and highly motivated and focused towards the
cause. This all made me change my attitude.
Instance Where my attitude remained same -
Based on the learnings from my experiences in past I believed that people in politics are not
good at heart. Politicians should ideally be social worker and should have a motive of public
welfare but noboday remember their promises once elected. I always had this image of politicans
in mind. A lot of people tried to convince me that new breed of politicans are good and not
greedy but I remained and still firm on my attitude that all politicans are not good people.
Reasons behind my attitude -
This attitude had been built over a period of time. There is no substantial argument against my
attitude which can make me think. This is why I still beleive that none of the politician is good
person..
All answers must be in your own wordsProvide a good, understandabl.pdf
All answers must be in your own words
Provide a good, understandable definition of the following 40, using your own words (do not
simply copy words from the book).
Retaliation Blood feud
Vendetta Civil death
Inquisition Corporal punishment
Brank Criminology
Mamertine Prison Sanctuary
Bridewell Jail fever
Age of Enlightenment Classical School of Criminology
Workhouse Gaols
Banishment Transportation
Hulks Penitentiary
Pennsylvania System Outside cell
Inside cell Eastern Penitentiary
Auburn System Cell block
Congregate system System of silence
Lockstep formation Prison stripes
Treadmill Solitary confinement
Indeterminate sentence Irish system
Reformatory Industrial prison
Alcatraz Lock psychosis
Convict bogey Ombudsman
Ticket of Leave
Solution
Retaliation – In the event of attack by the enemy, do the fierce counter attack from our side.
Blood feud – It is lengthy fighting in the families going on for the generations. It involves killing
of various members of the families. Vendetta – Person whose relative has been killed seeks
revenge from the murderer. Civil death – It is the loss of the civil rights which is the result of act
of government in the some of conviction of civil people. Inquisition – Out of curiosity asking
many question on the related topic. Corporal punishment – It is the type of punishment which
involves physical pain. It involves mutilation, flogging branding etc. Brank – It is the birdcage-
like instrument put on prisonr’s head with sharp plates that would cut tongues and mouths once
involved in the gossips Criminology – This is the branch of science which involves study of
crime and criminals. Mamertine Prison – In the early age in the Rome confinement are under the
main sewers where survival is very difficult even for few days.. Sanctuary – It means taking
shelter or refuge from the danger or pursuit. Bridewell – It is called for city jail or reform center
or jail for pity offender. Jail fever – It is the former name to the typhus. It is commonly occurred
in the jail so got he name from its origin. Age of Enlightenment – European politics, philosophy,
science and communications were radically reoriented during beginning of the 18th century and
then throughout of the 18th century. This period is known as Age of Enlightenment. Classical
School of Criminology – It is the body of thought which understands the nature of crime and
suggests the best form of punishment to the crime. Looking at the severity of the punishment in
the early 18th century philosopher come up with this type of thoughts. Workhouse – It is the
place where unemployed people who can not support themselves were given shelter and
employment. Gaols – It the synonym to the jail. It is the place of confinement to the criminals.
Banishment – As an act of punishment offender are sent away from the designated place or
country known as banishment. Transportation – It is the act of movement of goods or people
from one place to another place. Hulks – It is an old ship whi.
C programming tweak needed for a specific program.This is the comp.pdf
C programming tweak needed for a specific program.
This is the complete program up and running. except for one modification that my teacher is
requiring but it is confusing me.
The program needs to allocate disjoint memory and use that.
right now im allocating a continous block of memory on the heap but I need it to do disjoing
memory instead.
// Purpose: Program will allow a reseller to save their sales and calculate their profits.
// Also able to view highest profitable items and remove any sales they no longer want in their
sales inventory.
#define _CRT_SECURE_NO_WARNINGS
#include
#include
#include
#define PAUSE system(\"pause\")
#define CLS system(\"cls\");
//#define FLUSH fflush(stdin);
//////////////// SRUCTS BELOW //////////////////////////
typedef struct
{
char itemName[40];
float purchasePrice;
float soldPrice;
float shippingPrice;
float ebayFee;
float payPalFee;
float profit;
}SALES;
////////// FUNCTION PROTOTYPE BELOW /////////////
void addSale(SALES *Inventory, int *InventoryCounter);
void displayMenu(int *InventoryCounter);
void displayProfit(int *InventoryCounter, SALES *Inventory);
void displaySales(int *InventoryCounter, SALES *Inventory);
int getChoice(int *InventoryCounter);
void searchSale(SALES* Inventory, int InventoryCounter);
void sortProfits(SALES* Inventory, int InventoryCounter);
void removeSale(SALES* Inventory, int *InventoryCounter);
main() {
int SIZE;
int userChoice;
int InventoryCounter = 0;
//printf(\"*********************\ \");
//printf(\"* Welcome Reseller! *\ \");
//printf(\"*********************\ \");
printf(\"Enter the size of todays inventory:\");
scanf(\"%i\", &SIZE);
SALES *Inventory;
Inventory = calloc(SIZE, sizeof(SALES));//Using dynamic memory to allocate space on the
heap
do {
userChoice = getChoice(&InventoryCounter);
switch (userChoice) {
case 1:// Add a Sale
if (InventoryCounter == SIZE) // statement checks so we dont exceed the size of the
inventory user wants to enter.
{
printf(\"You Have Reached Max Inventory \ \");
PAUSE;
}
else {
addSale(&(Inventory[InventoryCounter]), &InventoryCounter);
}
break;
case 2: // Display all sales records
displaySales(&InventoryCounter, Inventory);
PAUSE;
break;
case 3: // Display all profits
sortProfits(Inventory, InventoryCounter);
displayProfit(&InventoryCounter, Inventory);
PAUSE;
break;
case 4: // Display Inventory
searchSale(Inventory, InventoryCounter);
break;
case 5:// remove a sale
removeSale(Inventory, &InventoryCounter);
break;
case 6: // Quit
break;
default:
printf(\"Please choose a valid option\ \");
PAUSE;
break;
}// end of switch
} while (userChoice != 6);
free(Inventory);
} // End of main
//////////////////////////////////////////// FUNCTIONS BELOW //////////////////////////////////////////////////
void addSale(SALES *Inventory, int *InventoryCounter)// Function that adds sale and
calculates the fees in the background.
{
float payPalFee = 0; // variable to store the paypal fee from 1 sale
float ebayFee = 0; // variable to store ebay fee for 1 sale.
Add to BST.java a method height() that computes the height of the tr.pdf
Add to BST.java a method height() that computes the height of the tree. Develop two
implementations: a recursive method (which takes linear time and space proportional to the
height), and method like size() that adds a field to each node in the tree (and takes linear space
and constant time per query)
Solution
Answer:
/*BST.java a method height() that computes the height of the tree. Developing two
implementations: a recursive method, and method like size() that adds a field to each node in the
tree **/
public class SplayBST, Value> {
private Node root; // root of the BST
// BST helper node data type
private class Node {
private Key key; // key
private Value value; // associated data
private Node left, right; // left and right subtrees
public Node(Key key, Value value) {
this.key = key;
this.value = value;
}
}
public boolean contains(Key key) {
return get(key) != null;
}
// return value associated with the given key
// if no such value, return null
public Value get(Key key) {
root = splay(root, key);
int cmp = key.compareTo(root.key);
if (cmp == 0) return root.value;
else return null;
}
/*
* Splay tree insertion.
**/
public void put(Key key, Value value) {
// splay key to root
if (root == null) {
root = new Node(key, value);
return;
}
root = splay(root, key);
int cmp = key.compareTo(root.key);
// Insert new node at root
if (cmp < 0) {
Node n = new Node(key, value);
n.left = root.left;
n.right = root;
root.left = null;
root = n;
}
// Insert new node at root
else if (cmp > 0) {
Node n = new Node(key, value);
n.right = root.right;
n.left = root;
root.right = null;
root = n;
}
// It was a duplicate key. Simply replace the value
else {
root.value = value;
}
}
/*
* Splay tree deletion.
**/
/*
*This splays the key, then does a slightly modified Hibbard deletion on the root (if it is the node
to be deleted, if it is not, the key was not in the tree).
*The modification is that rather than swapping the root (call it node A) with its successor, it\'s
successor (call it Node B) is moved to the root position
*by splaying for the deletion key in A\'s right subtree. Finally, A\'s right child is made the new
root\'s right child.
*/
public void remove(Key key) {
if (root == null) return; // empty tree
root = splay(root, key);
int cmp = key.compareTo(root.key);
if (cmp == 0) {
if (root.left == null) {
root = root.right;
}
else {
Node x = root.right;
root = root.left;
splay(root, key);
root.right = x;
}
}
// else: it wasn\'t in the tree to remove
}
/*
* Splay tree function.
**/
// splay key in the tree rooted at Node h. If a node with that key exists,
// it is splayed to the root of the tree. If it does not, the last node
// along the search path for the key is splayed to the root.
private Node splay(Node h, Key key) {
if (h == null) return null;
int cmp1 = key.compareTo(h.key);
if (cmp1 < 0) {
// key not in tree, so we\'re done
if (h.left == null) {
return h;
}
int cmp2 = key.compareTo(h.left.key);
if (cmp2 < 0) {
h.left.left = splay(h.left.left, key);
h = rot.
Write an awareness objective for a newly formed adolescent chemical .pdf
Write an awareness objective for a newly formed adolescent chemical dependency program
whose target market consists of judeges and social workers who refer to the facility. How would
this objective change for the trial level of the hierarchy of effects?
Solution
Answer:
The objectives are:
1. To create primary level awareness to the people who uses this service frequently and also
those who refer our facility,
2. To find out the ways to help people in different situations and making an sustainable
ecosystem.
This objective (twin objectives) would become altered in case of implementation of them in real
situation..
which of these prokaryotes are most likely to be found in the immedi.pdf
which of these prokaryotes are most likely to be found in the immediate vicinity of active deep-
sea vents?
a) cynobacteria
b)archaea
c)aerobically respiring bacteria
d)bacteria adapted to being embedded in ice
Solution
The answer is Archaea
as they are the thermophilic anaerobes which do not depend on oxygen for survival..
2. Why is only one end point observed for citric acid even though it .pdf
Citric acid is a triprotic acid but only shows one endpoint in titration. This is because citric acid has three similar dissociation constants, so the buffering effects of the first and second dissociations prevent a fast rise in pH, resulting in only one observable endpoint instead of two or three.
10. Benefits and costs of International Trade Search for a newspap.pdf
10. Benefits and costs of International Trade : Search for a newspaper article from any English
newspaper that discusses the advantages or disadvantages of international trade. Copy and paste
the weblink into this Forum and discuss one or two main points of the article. Please give
detailed answer with examples and elaborations.
Solution
The web is a awesome invention. Since of its introduction into schooling and its availability to
just about any individual, the world will mainly never be the identical.
Persons of all a while can go surfing 24/7 looking for something they want. The elderly woman
who\'s unable to drive can log onto the web and shop for groceries, fill a prescription or even
chat together with her grandchildren via web cam.
Collectors now not have got to scour flea markets and yard revenue on weekends to find coveted
gadgets so as to add to their collections all they need to do is go browsing to Ebay and publish a
bid. Something can be purchased on line now. Garb, jewellery, furniture...Even take-out.
As a instructor i\'ve discovered the web to be extremely valuable in planning classes. The web
has a plethora of websites created in particular for lecturers to share suggestions, change
information, and share records (thanks enotes!). Probably young people stand to gain the most
from making use of the web. Additionally to being in a position to express themselves and show
creativity on websites like MySpace and Twitter, they can also use the web for school tasks and
homework.
Still, for every pro, there is a con. I feel that scholars regularly count too much in the internet.
They do not look to have an understanding of that simply considering the fact that some thing is
on Google, that does not make it a riskless supply. I are not able to depend the number of
occasions a scholar has became in an essay that includes unsuitable data from web sites which
were created with the aid of any person who is not an authority on the topic.
Chat rooms have emerge as the brand new playground for sexual predators. The web gives them
the anonymity they have got to entice unsuspecting youngsters into inappropriate conversations
and in some circumstances meeting up with them. There are laws that preserve predators far
from parks and schools, however none retaining them off the web.
With out suitable supervision, kids can accidentally go online to pornographic web pages. Even
adults can fall prey to identity theft and stolen passwords if they don\'t seem to be careful about
the matters they are downloading onto their laptop.
Advantages and drawbacks of web use amongst kids and adults can be considered from quite a
lot of angles - objectively, or subjectively. If a individual is in favor of science, then he/she
would find extra advantages than negative aspects for its use. However, if a man or woman
believes in guide work and that technology could one day be used to replace human work, then
the he/she may just view web use to be more damaging than .
Why does the pattern in a shift register shift only one bit position.pdf
Why does the pattern in a shift register shift only one bit position each time it is clocked?
please no hand written answers
Solution
Beacuse if we move all bits at a time there will be no buffers to store the bits temporarily and
then shift the data to next position for each bit.
Hence , first Least significant bit(LSB) is moved out the the others follow for each step upto the
MSB most significant bit is moved by one bit position..
Use the Internet to identify three network firewalls, and create a t.pdf
Use the Internet to identify three network firewalls, and create a table that compares their
features. Note if they are rule-based or settings-based, perform stateless or stateful packet
filtering, what additional features they include (IDS, content filtering, and so on), their costs, and
so on.
Solution
Below is the table :
Firewall Capability
Packet Filters
Application-layer Gateways
Stateful Inspection
Communication Information
Partial
Partial
Yes
Communication-derived State
No
Partial
Yes
Application-derived State
No
Yes
Yes
Information Manipulation
Partial
Yes
Yes
If you take packet filters, for example, historically they are implemented on routers, are filters on
user defined content, such as IP addresses. packet filters examine a packet at the network layer
and are application independent, which allows them to deliver good performance and
scaleability. However, they are the least secure type of firewall, especially when filtering
services such as FTP.
As with application gateways, he security is improved by examining all application layers,
bringing context information into the decision process. However, they do this by breaking the
client/server model. Every client/server communication requires two connections: one from the
client to the firewall and one from the firewall to the server. In addition, each proxy requires a
different application process, or daemon, making scaleability and support for new applications a
problem.
The Stateful Inspection introduced by Check Point overcomes the limitations of the previous two
approaches by providing full application-layer awareness without breaking the client/server
model. With Stateful Inspection, the packet is intercepted at the network layer. It extracts state-
related information required for the security decision from all application layers and maintains
this information in dynamic state tables for evaluating subsequent connection attempts. This
provides a solution which is highly secure and offers maximum performance, scaleability, and
extensibility.
Firewall Capability
Packet Filters
Application-layer Gateways
Stateful Inspection
Communication Information
Partial
Partial
Yes
Communication-derived State
No
Partial
Yes
Application-derived State
No
Yes
Yes
Information Manipulation
Partial
Yes
Yes.
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- 1. Need to make a Reversi/Othello Board game in JAVA The board size can be N x N (so 4x4 is default, and it could be larger like 5x5, 6x6 etc. NEEDS TO BE ABLE TO WORK WITH ODD SIZE) Player 1 is going to be you and your going to be the black tiles, and the AI is going to be the white tiles. Black tiles will start the game, and then white will go after them, then back to black, repeat. The players must put a disc of their color on an empty square, adjacent to their opponent's disc. Any of the oppponents tiles in between the tile put down, and another of your tiles will cause them to flip to your color. The winner is decided when the board is completely filled or no viable moves are left, and whoever has the most pieces. This program is meant to be simple design (no GUI or big interface designs), broken into multiple classes (can be extension's off the class or abstract interface off each other), and the user will be entering the coordinates of where to put the pieces (so just using scanner method)?. The start of the game must always have 4 tiles put down in the center (so the center can change depending on the size of the board), and the gameplay would look something like this Again, coding done in JAVA is what I'm looking for. Scenario in which the game ends early. JAVA code BW Success: Black move at C1, 0) BW Score: Black: 4, White: 1 Success: White move at C2, 0D Solution package Reversi_Othello_GameReversiOthello; import java.awt.*; import java.applet.*; public class Reversi_Othello_GameReversiOthello extends Applet implements Runnable { Thread runner; // declare a thread for this GameReversiOthello boolean black_shown = false; // flag to signal pause boolean show_em = false; final int BLACK = 1; // declare state of each square final int WHITE = 2; final int EMPTY = 0; final int OFFBOARD = -1; final static int GameReversiOthello[][] = new int[10][10]; //10x10 matrix of squares protected int Count_Black = 0; protected int Count_White = 0;
- 2. Event evt; int x, y; public void start() // create a thread and start it { if (runner == null) { black_shown = false; runner = new Thread(this); runner.start(); } } public void stop() // stop the thread { if (runner != null) { runner.stop(); runner = null; black_shown = false; } } public synchronized void run() // initialize screen { setBackground(Color.green); for (int i = 0; i < 10; i++) // initialize off-board squares { GameReversiOthello[i][0] = OFFBOARD; GameReversiOthello[i][9] = OFFBOARD; GameReversiOthello[0][i] = OFFBOARD; GameReversiOthello[9][i] = OFFBOARD; } for (int i = 1; i < 9; i++) // initialize GameReversiOthello board to be empty { for (int j = 1; j < 9; j++) { GameReversiOthello[i][j] = EMPTY; } } GameReversiOthello[4][4] = WHITE; // except for initial set up GameReversiOthello[5][4] = BLACK;
- 3. GameReversiOthello[4][5] = BLACK; GameReversiOthello[5][5] = WHITE; while (runner != null) // signal thread to wait after painting { // black and before white responds while (!black_shown) { try { wait(); } catch (InterruptedException e) { } black_shown = false; showStatus("You Move is Awesome!! Keep Going"); pause(1000); whiteResponds(); } } } // BLACK clicked on a square - update screen public synchronized boolean mouseUp(Event evt, int x, int y) { Dimension d = size(); // find out which square was clicked int c = (x * 8) / d.width + 1; // column int r = (y * 8) / d.height + 1; // row boolean black_done; // true if black cannot move anywhere if (MoveLegal(r, c, BLACK, WHITE, true)) { GameReversiOthello[r][c] = BLACK; // set that square to black repaint(); black_shown = true; notify(); } else { showStatus("Not a legal move"); } black_done = true; // check if black can move anywhere for (int i = 1; i < 9; i++) { for (int j = 1; j < 9; j++) { if (MoveLegal(i, j, BLACK, WHITE, false)) { black_done = false; }
- 4. } } if (black_done) // black cannot move - white finishes up { for (int i = 1; i < 65; i++) { whiteResponds(); } } return true; } // computer responds with a move public void whiteResponds() { boolean found; // true if a legal square is found int i, j; // indices for loops found = false; if (MoveLegal(1, 1, WHITE, BLACK, true)) // first check corners { GameReversiOthello[1][1] = WHITE; found = true; } if ((!found) && (MoveLegal(8, 8, WHITE, BLACK, true))) { GameReversiOthello[8][8] = WHITE; found = true; } if ((!found) && (MoveLegal(1, 8, WHITE, BLACK, true))) { GameReversiOthello[1][8] = WHITE; found = true; } if ((!found) && (MoveLegal(8, 1, WHITE, BLACK, true))) { GameReversiOthello[8][1] = WHITE; found = true; } i = 3; // check center squares while ((!found) && (i < 7)) { j = 3; while ((!found) && (j < 7)) {
- 5. if (MoveLegal(i, j, WHITE, BLACK, true)) { GameReversiOthello[i][j] = WHITE; found = true; } j++; } i++; } i = 3; while ((!found) && (i < 7)) // then check edges except for those { // surrounding a corner if (MoveLegal(1, i, WHITE, BLACK, true)) { GameReversiOthello[1][i] = WHITE; found = true; } if ((!found) && (MoveLegal(8, i, WHITE, BLACK, true))) { GameReversiOthello[8][i] = WHITE; found = true; } if ((!found) && (MoveLegal(i, 1, WHITE, BLACK, true))) { GameReversiOthello[i][1] = WHITE; found = true; } if ((!found) && (MoveLegal(i, 8, WHITE, BLACK, true))) { GameReversiOthello[i][8] = WHITE; found = true; } i++; } i = 3; while ((!found) && (i < 7)) // next check inner edges { if (MoveLegal(2, i, WHITE, BLACK, true)) { GameReversiOthello[2][i] = WHITE; found = true; }
- 6. if ((!found) && (MoveLegal(7, i, WHITE, BLACK, true))) { GameReversiOthello[7][i] = WHITE; found = true; } if ((!found) && (MoveLegal(i, 2, WHITE, BLACK, true))) { GameReversiOthello[i][2] = WHITE; found = true; } if ((!found) && (MoveLegal(i, 7, WHITE, BLACK, true))) { GameReversiOthello[i][7] = WHITE; found = true; } i++; } i = 1; // finally squares surrounding a corner while ((!found) && (i < 9)) { j = 1; while ((!found) && (j < 9)) { if (MoveLegal(i, j, WHITE, BLACK, true)) { found = true; GameReversiOthello[i][j] = WHITE; } j++; } i++; } repaint(); } // decide if the move is legal public boolean MoveLegal(int r, int c, int color, int othercolor, boolean flip) { int i, j; // position on board boolean legal; // true if legal move int stepcount; // counts the stepping // across the board legal = false;
- 7. if (GameReversiOthello[r][c] == EMPTY) // square clicked must be empty { for (int xdir = -1; xdir < 2; xdir++) { for (int ydir = -1; ydir < 2; ydir++) { stepcount = 0; do { stepcount++; i = r + stepcount * xdir; // so many steps along x-axis j = c + stepcount * ydir; // so many steps along y-axis } while ((i > 0) && (i < 9) && (j > 0) && (j < 9) && (GameReversiOthello[i][j] == othercolor)); if ((i > 0) && (i < 9) && (j > 0) && (j < 9) && (stepcount > 1) && // You must move more than one step for legal move (GameReversiOthello[i][j] == color)) { legal = true; if (flip) { for (int k = 1; k < stepcount; k++) { GameReversiOthello[r + xdir * k][c + ydir * k] = color; } } } } } } if (legal == true) { return true; } else { return false; } } void pause(int time) // time delay { try { runner.sleep(time); } catch (InterruptedException e) {
- 8. } } // paint the screen with the right configuartion public void paint(Graphics g) { Dimension d = size(); g.setColor(Color.black); int xoff = d.width / 8; int yoff = d.height / 8; Count_Black = 0; // initialize counts to 0 Count_White = 0; boolean done; // true if GameReversiOthello is over for (int i = 1; i <= 8; i++) // draw the lines { g.drawLine(i * xoff, 0, i * xoff, d.height); g.drawLine(0, i * yoff, d.width, i * yoff); } for (int i = 1; i < 9; i++) // scan board for black discs { for (int j = 1; j < 9; j++) { if (GameReversiOthello[i][j] == BLACK) // draw BLACK discs { g.fillOval((j * yoff + 3) - yoff, (i * xoff + 3) - xoff, 33, 33); Count_Black++; } } } g.setColor(Color.white); for (int i = 1; i < 9; i++) // scan board for white discs { for (int j = 1; j < 9; j++) { if (GameReversiOthello[i][j] == WHITE) // draw WHITE discs { g.fillOval((j * yoff + 3) - yoff, (i * xoff + 3) - xoff, 33, 33); Count_White++; } }
- 9. } g.setColor(Color.red); done = true; for (int i = 1; i < 9; i++) { for (int j = 1; j < 9; j++) { if ((MoveLegal(i, j, BLACK, WHITE, false)) || (MoveLegal(i, j, WHITE, BLACK, false))) { done = false; } } } if (done == true) { if (Count_White > Count_Black) { g.drawString("Game won By White with " + Count_White + " discs.", 10, 20); } else if (Count_Black > Count_White) { g.drawString("Game won By Black " + Count_Black + " discs.", 10, 20); } else { g.drawString("Tied GameReversiOthello", 10, 20); } } else { if (Count_White > Count_Black) { g.drawString("White is winning with " + Count_White + " discs", 10, 20); } else if (Count_Black > Count_White) { g.drawString("Black is winning with " + Count_Black + " discs", 10, 20); } else { g.drawString("Currently the game is Tie", 10, 20); } } if (show_em == true) { for (int i = 1; i < 9; i++) { for (int j = 1; j < 9; j++) { if (MoveLegal(i, j, BLACK, WHITE, false)) { g.fillOval((j * yoff + 15) - yoff, (i * xoff + 15) - xoff, 5, 5); } } }
- 10. } } public void Action() { if (show_em == false) { show_em = true; repaint(); } else { show_em = false; repaint(); } } }