The document describes the rules and gameplay for a number board game where two players take turns selecting numbers to add to their score. Players can only move horizontally or vertically on the 8x8 board. The game ends when there are no remaining valid moves. Hard mode makes the computer opponent more intelligent by trying to predict player moves. The document also provides code snippets for game mechanics like handling invalid user input and returning to menus.

1. UMUT KIRAÇ

2.  Game board is 8*8 fields.
 There are numbers between -9 and 9 except 0.
 Player can only move the cursor horizontally.
 Computer/Player2 can only move the cursor vertically.
 Collected numbers are added to their scores.
 if there is no possible move no number in the row or
coloumn, the game is over.

5. EASY MODE
 COMPUTER CAN ONLY CHOOSE LARGEST
NUMBER IN THAT COLUMN.

6. HARD MODE
 IN THIS MODE, COMPUTER IS MORE
INTELLIGENT BECAUSE OF US.
 COMPUTER GUESS THAT YOU’LL CHOOSE
NUMBERS.

7.  IN THIS MODE YOU CAN PLAY AGAINST YOUR
FRIENDS.

8.  PLAYER AND COMPUTER MAY CHOOSE NULL
POINT.
move = Console.ReadKey(true);
if (move.Key == ConsoleKey.D1)
{
j = 0;
i = cursor_y - 1;
……………………………
if(satir[i,j]==-10)
Console.Write("--Null Point-- Enter A New Point!!");
}

10.  PLAYER MAY PRESS UNVALID KEY.
while (move.Key != ConsoleKey.NumPad1 & ……… &
move.Key != ConsoleKey.NumPad8)
{
Console.Write(" Unvalid Chosen Key!! ");
move = Console.ReadKey(true);
}

12.  RETURN IN NESTED MENU.
if (menu1 == 1)
{
Console.WriteLine("1.EASY ");
Console.WriteLine("2.HARD ");
Console.WriteLine("3.BACK TO MENU");
menu2 = Convert.ToInt32(Console.ReadLine());
}
Console.Clear();
}
while (menu1 == 3 | menu2 == 3 | menu == 2);

14.  if there is no possible move no number in the row or
coloumn, the game is over.
while(…….)
{
count = 0;
for (b = 0; b < 8; b++)
{
if (satir[cursor_y - 1, b] == -10)
count++;
}
if (count == 8)
break;
}

15.  COMPUTER CAN FINISH THE GAME IF IT WIN.
for (b = 0; b < 8; b++)
{
count = 0;
for (d = 0; d < 8; d++)
{
if (satir[b, d] == -10 & satir[b, j] != -10)
count++;
if (count == 7)
{
cursor_y = b + 1;
break;
}
}

16.  PROBLEMS ABOUT A.I
for (b = 0; b < 8; b++)
{
number1 = -20;
for (d = 0; d < 8; d++)
{
if ((number1 < satir[b, d]) & (satir[b, d] != -10) & (d != j))
{
number1 = satir[b, d];
e = b;
f = d;
}
}
if ((number2 < satir[b, j] - satir[e, f]) & (satir[b, j] != -10))
{
number2 = satir[b, j] - satir[e, f];
cursor_y = b + 1;
}
}

17. System.Threading.Thread.Sleep(1000);
Console.Beep();
Try and Catch code.
MAKE A MENU
CREATE AN ARTIFICIAL INTELLEGENCE

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