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NaOH ==== Na+ (aq) + OH-(aq) [OH-] = 0.25 M [H.pdf

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NaOH ====> Na+ (aq) + OH-(aq) [OH-] = 0.25 M [H+][OH-] = 1.0*10^-14 [H+] = (1.0*10^-14)/0.25 = 4.0*10^-14 pH = -log[H+] = -log(4.0*10^-14) = 13.397 = 13.40 pH+pOH=14 pOh = 14-pH = 14-13.40=0.6 Solution NaOH ====> Na+ (aq) + OH-(aq) [OH-] = 0.25 M [H+][OH-] = 1.0*10^-14 [H+] = (1.0*10^-14)/0.25 = 4.0*10^-14 pH = -log[H+] = -log(4.0*10^-14) = 13.397 = 13.40 pH+pOH=14 pOh = 14-pH = 14-13.40=0.6.

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NaOH ====> Na+ (aq) + OH-(aq) [OH-] = 0.25 M [H+][OH-] = 1.0*10^-14 [H+] = (1.0*10^-14)/0.25 = 4.0*10^-14 pH = -log[H+] = -log(4.0*10^-14) = 13.397 = 13.40 pH+pOH=14 pOh = 14-pH = 14-13.40=0.6 Solution NaOH ====> Na+ (aq) + OH-(aq) [OH-] = 0.25 M [H+][OH-] = 1.0*10^-14 [H+] = (1.0*10^-14)/0.25 = 4.0*10^-14 pH = -log[H+] = -log(4.0*10^-14) = 13.397 = 13.40 pH+pOH=14 pOh = 14-pH = 14-13.40=0.6

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NaOH ==== Na+ (aq) + OH-(aq) [OH-] = 0.25 M [H.pdf

  • 1. NaOH ====> Na+ (aq) + OH-(aq) [OH-] = 0.25 M [H+][OH-] = 1.0*10^-14 [H+] = (1.0*10^-14)/0.25 = 4.0*10^-14 pH = -log[H+] = -log(4.0*10^-14) = 13.397 = 13.40 pH+pOH=14 pOh = 14-pH = 14-13.40=0.6 Solution NaOH ====> Na+ (aq) + OH-(aq) [OH-] = 0.25 M [H+][OH-] = 1.0*10^-14 [H+] = (1.0*10^-14)/0.25 = 4.0*10^-14 pH = -log[H+] = -log(4.0*10^-14) = 13.397 = 13.40 pH+pOH=14 pOh = 14-pH = 14-13.40=0.6