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1. Programming with 8085
2. Instruction set of 8085
Assembly Language,
Machine Language
Machine Dependent
Low Level Language
C, C++, JAVA
Machine Independent
High Level Language
Programming with 8085
Internal Structure of 8085
 A is Accumulator – used to perform
arithmetic and logical operations
 F is Flag register – not directly accessible
 B, C, D, E, H, L are general purpose
registers
 B-C, D-E, H-L can be used as 16-bit
register
 SP is Stack Pointer
 PC is Program Counter used by µP itself. It
stores the 16-bit address of the next
memory register to be executed
A Flag
B C
D E
H L
SP
PC
Flag Register
S Z AC P CY
= 1
NEGATIVE
= 0
POSITIVE
S = 1
RESULT IS
ZERO
= 0
RESULT IS
NOT ZERO
Z =1
EVEN NO. OF
1’S
=0
ODD NO. OF
1’S
P
= 1
CARRY
GENERATED BY
D3
= 0
OTHERWISE
AC = 1
CARRY
GENERATED
= 0
CARRY NOT
GENERATED
CY
D0
OPCODE: Operation to be performed
OPERAND: On which the operation to be
performed
OPCODE OPERAND
MOV A, B
Each instruction has two parts
Instruction Format
Number of registers required to store an instruction in
memory
HLT 76 1 Byte
MVI B, 37H 06 37 2 Byte
STA 3015H 32 15 30 3 Byte
Instruction Byte Size
T State: Time period of the system Clock. (1 / frequency)
Clock: A Clock is a square wave generator which is used to
synchronize various devices in the microprocessor and in the
system.
Instruction Cycle: Total time to execute a complete instruction
Machine Cycle: an instruction may be divided into several
parts like Opcode fetch, Memory read, Memory write etc.
Time to execute each part is known as Machine Cycle.
Instruction Timing
Memory Code
0000 H XX
---- --
---- --
3010 H 3E H
3011 H 35 H
---- --
---- --
FFFF H XX
MVI A, 35H
Steps:
Opcode Fetch (4 T-state)
Place the address 3010H in the address bus
Activate ALE signal
Activate Read signal
Copy Opcode 3E H in the data bus
Memory Read (3 T-state)
Place the address 3011H in the address bus
Activate ALE signal
Activate Read signal
Copy Data 35 H in the data bus
Timing Diagram
Memory Code
3010 H 3E H
3011 H 35 H
MVI A, 35 H
Timing
Diagram
Memory Code
0000 H XX
---- --
---- --
3010 H 21 H
3011 H 35 H
3012 H 20 H
---- --
FFFF H XX
LXI H 2035H
Steps:
Opcode Fetch (4 T-state)
 Place the address 3010H in the address bus
 Activate ALE signal
 Activate Read signal
 Copy Opcode 21 H in the data bus
Memory Read (3 T-state)
 Place the address 3011H in the address bus
 Activate ALE signal
 Activate Read signal
 Copy Data 35 H in the data bus
Memory Read (3 T-state)
 Place the address 3012H in the address bus
 Activate ALE signal
 Activate Read signal
 Copy Data 20 H in the data bus
Timing Diagram
8085 Instruction Set
The different ways in which a source operand / data is denoted
in an instruction are known as addressing modes.
 Register Addressing
 Data stored in a register and that register is specified in the instruction
 Immediate Addressing
 Data itself is specified in the instruction
 Direct Addressing
 Data stored in memory and that address is specified in the instruction
 Register Indirect Addressing
 Specified register contains the address of the data
 Implicit Addressing
 No data is specified in the instruction
Addressing Mode
1. Data Transfer Operation
2. Arithmetic Operation
3. Logical Operation
4. Branching & machine Control Operation
Types of Instruction
• MOV Rd, Rs
Rd Rs
Example:
MOV A,B
MOV C,H
MOV D,C
Addressing Mode: Register
Instruction Size: 1 Byte
Rd: Destination Register
Rs; Source Register
• MVI Rd, <8-Bit data>
Rd
Example:
MVI A, 54H
MVI C, 61H
MVI D, 8CH
<8-Bit data>
Addressing Mode: Immediate
Instruction Size: 2 Bytes
• LXI Rp, <16-Bit data>
Rp
Example:
LXI H,5004H
LXI B,6021H
LXI D,840CH
<16-Bit data>
Addressing Mode: Immediate
Instruction Size: 3 Bytes
Rp: Register Pair
• MVI M, <8 bit data>
• MOV R, M
• MOV M, R
R
MEMORYµP
XX XX
H L
XXXXH
R: Register
M; Memory Register
• Data transfer between microprocessor and a memory register
• Address of the memory register is stored in H-L register pair
Addressing Mode: Immediate / Reg. Indirect
Instruction Size: 2 Bytes / 1 Bytes
D
Example:
LXI H,2004H
MOV D, M
MEMORYµP
20 04
42
H L
42H
MEMORY
39H
42H
72H
2003H
2004H
2005H
• LDA <16 Bit Address>
• STA <16 Bit Address>
ACC
MemoryµP
ACC
MemoryµP
Addressing Mode: Direct
Instruction Size: 3 Bytes
1600H 2500H
LDA 1600H
STA 2500H
Timing Diagram of ‘STA’ instruction
STA 526A H
Memory Code
41FFH 32H
4200H 6AH
4201H 52H
• STAX B
• STAX D
• LDAX B
• LDAX D
ACC
Memory
µP
ACC
Memory
µP
B C B C
Addressing Mode: Register Indirect
Instruction Size: 1 Bytes
• SHLD <16 Bit Address>
• LHLD <16 Bit Address>
Memory
µP
Memory
µP
1660H 2080H
H L H L
1661H 2081H
Addressing Mode: Direct
Instruction Size: 3 Bytes
SHLD 2080H
LHLD 1660H
• XCHG
µP µP
pq rs ab cd
H L H L
Addressing Mode: Register
Instruction Size: 1 Bytes
Exchange the contents of H-L with D-E register pair
ab cd
D E
pq rs
D E
• ADD R
• ADD M
• ADI <8-BIT Data>
Acc R Acc
Acc MEMORY
(Address from H-L)
Acc
Acc 8-Bit Data Acc
ADDITION
• ADC R
• ADC M
• ACI <8-BIT Data>
Acc R Acc
Acc MEMORY
(Address from H-L)
Acc
Acc 8-Bit Data Acc
CY
CY
CY
ADDITION with CARRY
• SUB R
• SUB M
• SUI <8-BIT Data>
Acc R Acc
Acc MEMORY
(Address from H-L)
Acc
Acc 8-Bit Data Acc
SUBTRACTION
• SBB R
• SBB M
• SBI <8-BIT Data>
Acc R Acc
Acc MEMORY
(Address from H-L)
Acc
Acc 8-Bit Data Acc
CY
CY
CY
SUBTRACTION with BORROW
• DAD Rp
H RpL H L
 LXI H,1800H
 LXI B,1200H
 DAD B
 HLT
H
0018
L B
XXXX
C
H
0018
L B
0012
C
H
002A
L B
0012
C
16 Bit Addition
• INR R
• DCR R
• INX Rp
• DCX Rp
R R
R R
Rp Rp
Rp Rp
Increment & Decrement
• DAA
Decimal Adjust Accumulator
The DAA instruction is provided to correct the problem associated with BCD
(Binary Coded Decimal) addition
After an Addition instruction
1. If the lower nibble (4 bits) is greater than 9, or if AC=1, add 0110 (6) to the
lower 4 bits
2. If the upper nibble is greater than 9, or if CY=1, add 0110 (6) to the upper
4 bits
Example
MVI A, 29H A = 29 H HEX BCD
29 0010 1001
+ 18 + 0001 1000
41 0100 0001 AC=1
+ 6 + 0110
47 0100 0111
ADI 18H
A = 29H + 18H = 41H
Aux. Carry = 1
DAA A = 41H + 06H = 47H
BCD Operation
The binary representation of the digits 0 to 9 is called BCD (Binary Coded Decimal)
Digit BCD
0 0000
1 0001
2 0010
3 0011
4 0100
5 0101
6 0110
7 0111
8 1000
9 1001
Unpacked BCD
In unpacked BCD, the lower 4 bits of the number represent the
BCD number, and the rest of the bits are 0
Ex. 9 = 0000 1001
5 = 0000 0101
Packed BCD
In packed BCD, a single byte has two BCD number in it, one in
the lower 4 bits, and one in the upper 4 bits
Ex. 59 = 0101 1001 (not 0011 1011)
Problem Associated with BCD Addition
To correct this problem, the programmer must add 6 (0110) to the low digit:
3FH + 06H = 45H.
BCD addition
17
+ 28
45 (0100 0101)
HEX addition
17
+ 28
3F (0011 1111)
General rule: After addition
1. If the first digit is greater than 9, or if there is a carry generation in first digit
place, add 06H to the result
2. If the second digit is greater than 9, or if there is a carry generation in second
digit place, add 60H to the result
• ANA R
• ANA M
• ANI <8-BIT Data>
Acc R/M/DATA Acc
• ORA R
• ORA M
• ORI <8-BIT Data> Acc R/M/DATA Acc
• XRA R
• XRA M
• XRI <8-BIT Data> Acc R/M/DATA Acc
AND Operation
OR Operation
XOR Operation
Rotate Operation
• RLC (Rotate Accumulator Left)
• RAL (Rotate Accumulator Left Through Carry)
1 0 1 0 1 1 0 0 0 1 0 1 1 0 0 1
X 1
RLC
CY CY
1 0 1 0 1 1 0 0 0 1 0 1 1 0 0 X
X 1
RAL
CY
CY
Rotate Operation
• RRC (Rotate Accumulator Right)
• RAR (Rotate Accumulator Right Through Carry)
1 0 1 0 1 1 0 0 0 1 0 1 0 1 1 0
X 0
RRC
CY CY
0
RAR
CY
1 0 1 0 1 1 0 0
X
CY
X 1 0 1 0 1 1 0
Compare
• CMP R
• CMP M
• CPI <8-Bit Number>
Acc R/M/8-Bit No.
1 0
CY Z
0 0
CY Z
0 1
CY Z
When Result
is —ve
When Result
is +ve
When Result
is Zero
Complement
• CMA
1’s complement of the content of the Accumulator
• CMC
Complement of the content of the Carry bit
Jump Instruction
2000H Instruction 1
2001H Instruction 2
2002H .
2003H .
2004H JMP 200AH
2005H
2006H
2007H .
2008H .
2009H .
200AH .
200BH .
200CH .
200DH .
200EH .
Conditional Jump
• JP <16-Bit Address> jump when s = 0
• JM <16-Bit Address> jump when s = 1
• JZ <16-Bit Address> jump when z = 1
• JNZ <16-Bit Address> jump when z = 0
• JPE <16-Bit Address> jump when P = 1
• JPO <16-Bit Address> jump when P = 0
• JC <16-Bit Address> jump when CY = 1
• JNC <16-Bit Address> jump when CY = 0
Some Special Instructions
• PCHL
Content of H-L pair are transferred to the program counter
• NOP
No operation. Content of the program counter is
incremented by 1
• HLT
Microprocessor stops program execution until an interrupt

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Microprocessor Part 3

  • 1. 1. Programming with 8085 2. Instruction set of 8085
  • 2. Assembly Language, Machine Language Machine Dependent Low Level Language C, C++, JAVA Machine Independent High Level Language Programming with 8085
  • 4.  A is Accumulator – used to perform arithmetic and logical operations  F is Flag register – not directly accessible  B, C, D, E, H, L are general purpose registers  B-C, D-E, H-L can be used as 16-bit register  SP is Stack Pointer  PC is Program Counter used by µP itself. It stores the 16-bit address of the next memory register to be executed A Flag B C D E H L SP PC
  • 5. Flag Register S Z AC P CY = 1 NEGATIVE = 0 POSITIVE S = 1 RESULT IS ZERO = 0 RESULT IS NOT ZERO Z =1 EVEN NO. OF 1’S =0 ODD NO. OF 1’S P = 1 CARRY GENERATED BY D3 = 0 OTHERWISE AC = 1 CARRY GENERATED = 0 CARRY NOT GENERATED CY D0
  • 6. OPCODE: Operation to be performed OPERAND: On which the operation to be performed OPCODE OPERAND MOV A, B Each instruction has two parts Instruction Format
  • 7. Number of registers required to store an instruction in memory HLT 76 1 Byte MVI B, 37H 06 37 2 Byte STA 3015H 32 15 30 3 Byte Instruction Byte Size
  • 8. T State: Time period of the system Clock. (1 / frequency) Clock: A Clock is a square wave generator which is used to synchronize various devices in the microprocessor and in the system. Instruction Cycle: Total time to execute a complete instruction Machine Cycle: an instruction may be divided into several parts like Opcode fetch, Memory read, Memory write etc. Time to execute each part is known as Machine Cycle. Instruction Timing
  • 9. Memory Code 0000 H XX ---- -- ---- -- 3010 H 3E H 3011 H 35 H ---- -- ---- -- FFFF H XX MVI A, 35H Steps: Opcode Fetch (4 T-state) Place the address 3010H in the address bus Activate ALE signal Activate Read signal Copy Opcode 3E H in the data bus Memory Read (3 T-state) Place the address 3011H in the address bus Activate ALE signal Activate Read signal Copy Data 35 H in the data bus Timing Diagram
  • 10. Memory Code 3010 H 3E H 3011 H 35 H MVI A, 35 H Timing Diagram
  • 11. Memory Code 0000 H XX ---- -- ---- -- 3010 H 21 H 3011 H 35 H 3012 H 20 H ---- -- FFFF H XX LXI H 2035H Steps: Opcode Fetch (4 T-state)  Place the address 3010H in the address bus  Activate ALE signal  Activate Read signal  Copy Opcode 21 H in the data bus Memory Read (3 T-state)  Place the address 3011H in the address bus  Activate ALE signal  Activate Read signal  Copy Data 35 H in the data bus Memory Read (3 T-state)  Place the address 3012H in the address bus  Activate ALE signal  Activate Read signal  Copy Data 20 H in the data bus Timing Diagram
  • 12.
  • 14. The different ways in which a source operand / data is denoted in an instruction are known as addressing modes.  Register Addressing  Data stored in a register and that register is specified in the instruction  Immediate Addressing  Data itself is specified in the instruction  Direct Addressing  Data stored in memory and that address is specified in the instruction  Register Indirect Addressing  Specified register contains the address of the data  Implicit Addressing  No data is specified in the instruction Addressing Mode
  • 15. 1. Data Transfer Operation 2. Arithmetic Operation 3. Logical Operation 4. Branching & machine Control Operation Types of Instruction
  • 16. • MOV Rd, Rs Rd Rs Example: MOV A,B MOV C,H MOV D,C Addressing Mode: Register Instruction Size: 1 Byte Rd: Destination Register Rs; Source Register
  • 17. • MVI Rd, <8-Bit data> Rd Example: MVI A, 54H MVI C, 61H MVI D, 8CH <8-Bit data> Addressing Mode: Immediate Instruction Size: 2 Bytes
  • 18. • LXI Rp, <16-Bit data> Rp Example: LXI H,5004H LXI B,6021H LXI D,840CH <16-Bit data> Addressing Mode: Immediate Instruction Size: 3 Bytes Rp: Register Pair
  • 19. • MVI M, <8 bit data> • MOV R, M • MOV M, R R MEMORYµP XX XX H L XXXXH R: Register M; Memory Register • Data transfer between microprocessor and a memory register • Address of the memory register is stored in H-L register pair Addressing Mode: Immediate / Reg. Indirect Instruction Size: 2 Bytes / 1 Bytes
  • 20. D Example: LXI H,2004H MOV D, M MEMORYµP 20 04 42 H L 42H MEMORY 39H 42H 72H 2003H 2004H 2005H
  • 21. • LDA <16 Bit Address> • STA <16 Bit Address> ACC MemoryµP ACC MemoryµP Addressing Mode: Direct Instruction Size: 3 Bytes 1600H 2500H LDA 1600H STA 2500H
  • 22. Timing Diagram of ‘STA’ instruction STA 526A H Memory Code 41FFH 32H 4200H 6AH 4201H 52H
  • 23. • STAX B • STAX D • LDAX B • LDAX D ACC Memory µP ACC Memory µP B C B C Addressing Mode: Register Indirect Instruction Size: 1 Bytes
  • 24. • SHLD <16 Bit Address> • LHLD <16 Bit Address> Memory µP Memory µP 1660H 2080H H L H L 1661H 2081H Addressing Mode: Direct Instruction Size: 3 Bytes SHLD 2080H LHLD 1660H
  • 25. • XCHG µP µP pq rs ab cd H L H L Addressing Mode: Register Instruction Size: 1 Bytes Exchange the contents of H-L with D-E register pair ab cd D E pq rs D E
  • 26. • ADD R • ADD M • ADI <8-BIT Data> Acc R Acc Acc MEMORY (Address from H-L) Acc Acc 8-Bit Data Acc ADDITION
  • 27. • ADC R • ADC M • ACI <8-BIT Data> Acc R Acc Acc MEMORY (Address from H-L) Acc Acc 8-Bit Data Acc CY CY CY ADDITION with CARRY
  • 28. • SUB R • SUB M • SUI <8-BIT Data> Acc R Acc Acc MEMORY (Address from H-L) Acc Acc 8-Bit Data Acc SUBTRACTION
  • 29. • SBB R • SBB M • SBI <8-BIT Data> Acc R Acc Acc MEMORY (Address from H-L) Acc Acc 8-Bit Data Acc CY CY CY SUBTRACTION with BORROW
  • 30. • DAD Rp H RpL H L  LXI H,1800H  LXI B,1200H  DAD B  HLT H 0018 L B XXXX C H 0018 L B 0012 C H 002A L B 0012 C 16 Bit Addition
  • 31. • INR R • DCR R • INX Rp • DCX Rp R R R R Rp Rp Rp Rp Increment & Decrement
  • 32. • DAA Decimal Adjust Accumulator The DAA instruction is provided to correct the problem associated with BCD (Binary Coded Decimal) addition After an Addition instruction 1. If the lower nibble (4 bits) is greater than 9, or if AC=1, add 0110 (6) to the lower 4 bits 2. If the upper nibble is greater than 9, or if CY=1, add 0110 (6) to the upper 4 bits Example MVI A, 29H A = 29 H HEX BCD 29 0010 1001 + 18 + 0001 1000 41 0100 0001 AC=1 + 6 + 0110 47 0100 0111 ADI 18H A = 29H + 18H = 41H Aux. Carry = 1 DAA A = 41H + 06H = 47H
  • 33. BCD Operation The binary representation of the digits 0 to 9 is called BCD (Binary Coded Decimal) Digit BCD 0 0000 1 0001 2 0010 3 0011 4 0100 5 0101 6 0110 7 0111 8 1000 9 1001 Unpacked BCD In unpacked BCD, the lower 4 bits of the number represent the BCD number, and the rest of the bits are 0 Ex. 9 = 0000 1001 5 = 0000 0101 Packed BCD In packed BCD, a single byte has two BCD number in it, one in the lower 4 bits, and one in the upper 4 bits Ex. 59 = 0101 1001 (not 0011 1011)
  • 34. Problem Associated with BCD Addition To correct this problem, the programmer must add 6 (0110) to the low digit: 3FH + 06H = 45H. BCD addition 17 + 28 45 (0100 0101) HEX addition 17 + 28 3F (0011 1111) General rule: After addition 1. If the first digit is greater than 9, or if there is a carry generation in first digit place, add 06H to the result 2. If the second digit is greater than 9, or if there is a carry generation in second digit place, add 60H to the result
  • 35. • ANA R • ANA M • ANI <8-BIT Data> Acc R/M/DATA Acc • ORA R • ORA M • ORI <8-BIT Data> Acc R/M/DATA Acc • XRA R • XRA M • XRI <8-BIT Data> Acc R/M/DATA Acc AND Operation OR Operation XOR Operation
  • 36. Rotate Operation • RLC (Rotate Accumulator Left) • RAL (Rotate Accumulator Left Through Carry) 1 0 1 0 1 1 0 0 0 1 0 1 1 0 0 1 X 1 RLC CY CY 1 0 1 0 1 1 0 0 0 1 0 1 1 0 0 X X 1 RAL CY CY
  • 37. Rotate Operation • RRC (Rotate Accumulator Right) • RAR (Rotate Accumulator Right Through Carry) 1 0 1 0 1 1 0 0 0 1 0 1 0 1 1 0 X 0 RRC CY CY 0 RAR CY 1 0 1 0 1 1 0 0 X CY X 1 0 1 0 1 1 0
  • 38. Compare • CMP R • CMP M • CPI <8-Bit Number> Acc R/M/8-Bit No. 1 0 CY Z 0 0 CY Z 0 1 CY Z When Result is —ve When Result is +ve When Result is Zero
  • 39. Complement • CMA 1’s complement of the content of the Accumulator • CMC Complement of the content of the Carry bit
  • 40. Jump Instruction 2000H Instruction 1 2001H Instruction 2 2002H . 2003H . 2004H JMP 200AH 2005H 2006H 2007H . 2008H . 2009H . 200AH . 200BH . 200CH . 200DH . 200EH .
  • 41. Conditional Jump • JP <16-Bit Address> jump when s = 0 • JM <16-Bit Address> jump when s = 1 • JZ <16-Bit Address> jump when z = 1 • JNZ <16-Bit Address> jump when z = 0 • JPE <16-Bit Address> jump when P = 1 • JPO <16-Bit Address> jump when P = 0 • JC <16-Bit Address> jump when CY = 1 • JNC <16-Bit Address> jump when CY = 0
  • 42. Some Special Instructions • PCHL Content of H-L pair are transferred to the program counter • NOP No operation. Content of the program counter is incremented by 1 • HLT Microprocessor stops program execution until an interrupt