SO4: Matter
waves
What youwill
learn
1. Properties of matter
waves
2. Davisson and
Germer
experiment
3. Heisenberg’s
What you already
know
1. Light as an EM wave
2. Photon theory of light
3. Electron emission
4. Photoelectric effect
5. Radiation pressure
2.
𝑃
=
=
𝐹
𝐼
𝐴
𝑐
For completeabsorption in normal incidence
Absorption coefficient 𝑎 = 1 , Reflection coefficient
(𝑟 = 0)
For complete absorption in oblique incidence
Absorption coefficient 𝑎 = 1 , Reflection coefficient
(𝑟 = 0)
�
�
𝐹 cos 𝜃
𝐼
𝑃 =
�
�
2
= cos
𝜃
3.
For partialreflection in normal
incidence
0 < 𝑎 < 1, 0 < 𝑟 < 1 𝑎 + 𝑟
= 1
𝑃
=
𝐹
𝐼
𝐴
𝑐
= (1
+ 𝑟)
𝑃
=
2
𝐼
�
�
For complete reflection in normal
incidence
Reflection coefficient (𝑟 = 1)
a
b
c
d
3.2 ×
10−6 𝑁
1.6×
10−6 𝑁
4.3 ×
10−8 𝑁
2 ×
10−8 𝑁
A beam of white light is incident normally on a plane surface absorbing 70% of the light
and reflecting the rest. If the incident beam carries 10 𝑊 of power
, find the force
exerted by it on the surface.
6.
Force exerted byit on the surface is
given by,
�
�
�
�
Radiation falling
perpendicularly
= (1
+ 𝑟)
⇒ =
𝐹 𝐼
𝐴 𝑐
𝐹
10
𝐴
𝐴𝑐
1 +
0.3
⇒ 𝐹
=
1
3
3 ×
108
= 4.3 ×
10−8 𝑁
Solutio
n
Hence, option (𝑐) is the correct
answer
.
Give
n:
𝑎 = 0.7
𝑎 + 𝑟 = 1 ⇒ 𝑟 =
0.3
⇒ 𝐼
=
Power delivered by the incident beam =
10 𝑊 = 𝐼𝐴
10
�
�
7.
In 1924, theFrench physicist Louis Victor de-Broglie put forward the bold hypothesis that
moving particles of matter should display wave like properties under suitable conditions.
The waves associated with moving particles are called Matter waves or de-Broglie waves.
The wavelength associated with a moving particle is known as de-Broglie wavelength.
ℎ
ℎ
𝜆 = =
𝑝
𝑚𝑣
𝑝
2
2
𝑚
𝐾. 𝐸. = ⇒ 𝑝
=
2𝑚
𝐾. 𝐸.
𝜆
=
ℎ
2𝑚
𝐾. 𝐸.
Where, p =
Momentum
8.
𝜆
=
ℎ
When charge 𝑞accelerated through a potential difference 𝑉
from rest.
Work done, 𝑊 = 𝐾. 𝐸. = 𝑞𝑉
2𝑚
𝑞𝑉
de-Broglie
𝜆
=
ℎ
2𝑚
𝑞𝑉
𝜆
=
12.2
7 �
�
Å
𝜆
=
ℎ
2𝑚
𝑞𝑉
=
6.62
×10−34
2 × 9.1× 10−31×1.6 ×
10−19 𝑉
⇒
Mass of an
electron,
Charge on an
electron,
9.
An electron isaccelerated from rest through a potential difference of 𝑉 volt. If the
de-Broglie
wavelength of the electron is 1.227 × 10−2 𝑛𝑚, the potential difference is….
a
b
c
d
10
𝑉
102
𝑉
103
𝑉
104
𝑉
10.
de-Broglie wavelength, 𝜆= 1.227 × 10−2 𝑛𝑚 =
0.1227 𝐴
𝜆
=
ℎ
2𝑚𝑒
𝑉
�
�
12.27
=
𝐴
⇒ 𝑉
=
12.2
7
0.122
7
=
100
Solutio
n
Give
n:
The de-Broglie wavelength of an electron is
given by
⇒ 𝑉 = 104 𝑉
Hence, option (𝑑) is the correct
answer
.
11.
a
b
c
d
The de-Broglie wavelengthof a neutron in thermal equilibrium with heavy water at a
temperature
𝑇 (𝑘𝑒𝑙𝑣𝑖𝑛) and mass 𝑚, is ….
ℎ
3𝑚𝑘
𝑇
2
ℎ
3𝑚𝑘
𝑇
2
ℎ
𝑚𝑘
𝑇
ℎ
𝑚𝑘
𝑇
12.
Solutio
n
The average K.E.of gas molecules is
given by,
Wher
e,
𝐽Τ
𝐾
𝑓 = Degree of freedom
𝑘 = Boltzmann constant = 1.38 ×
10−23
𝑇 = Temperature in absolute scale
For neutron, degree of
freedom, 𝑓 = 3
∴ K.E. of
neutron,
3
2
𝐾. 𝐸. =
𝑘𝑇
de-Broglie wavelength is given
by, 𝜆 =
ℎ
2𝑚
𝐾. 𝐸.
Substituting the value of K.E.,
we get,
𝜆
=
ℎ
3𝑚𝑘
𝑇
Hence, option (𝑎) is the correct
13.
Mass: 9.1 ×
10−31𝑘𝑔
Speed: 3 × 106
𝑚/𝑠
Mass: 138 𝑔
Speed: 30 𝑚/𝑠
ℎ 6.63 × 10−34
𝜆 = =
𝑚𝑣 0.138 ×
30
ℎ 6.63 × 10−34
𝜆 = =
𝑚𝑣
9.1 ×
10−31
× 3 ×
108
𝜆 = 1.6 × 10−34 𝑚
For macroscopic objects wave
characteristics can not be
𝜆 = 2.42 × 10−9 𝑚
For microscopic particles
wave
Matter waves are related to moving particles and independent of the
charge of particle. The phase velocity of matter waves can be greater than
the speed of light.
The wave and particle nature of moving bodies are mutually exclusive i.e.,
they can never be observed at the
same time.
Matter wave represents the probability of finding a particle in space.
In ordinary situation, de-Broglie wavelength is very small and wave nature
of matter can be ignored.
14.
Itis not possibleto measure both theposition and momentum of a particle at the same time
exactly. Uncertainty principle exists because everything in universe behaves both as particle and
wave at the same time.
Δ
𝑥 PARTICL
E
Δ𝑦
A particle exist in
single place at any
instant in time.
�
�
�
�
A wave doesn’t exist at a single place,
good
probability of finding in lots of different
places.
We can measure its wavelength and
thus its momentum.
15.
ℎ
𝑝 = 𝑝=
𝑚𝑣
𝜆
A fast-moving object has lots of momentum, which corresponds to very short
wavelength. A heavy object has lots of momentum, which again means a very
short wavelength.
This is the reason why we don’t notice the wave nature of everyday objects.
16.
WAV
E
Momentum can be
measured,but it
has no definite position.
PARTICL
E
Position can be measured, but it is
difficult to
measure momentum accurately.
If Δ𝑥 is uncertainty in specification of position and Δ𝑝 is uncertainty in specification of
momentum, then
Δ𝑥 x Δ𝑝
≥ ℎ
4
𝜋
Means if the position is measured very accurately then the momentum will have a lot of
uncertainty and vice versa.