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![Math Model
A = area of square+area of circle
= x² + πr²
the length of wire is 4 feet
4 = 4x + 2πr
r=
premeter = 4x
circumference=2πr
π
)( x-12
Area = x² + πr²
22
]
)1(2
[
π
π
x
xA
]48)4[(
1 2
xxπ
π](https://image.slidesharecdn.com/lifeoptimizationproblems-160123162531/85/Life-optimization-problems-5-320.jpg)



This document discusses using optimization and math modeling to solve a life problem involving allocating a fixed amount of wire to maximize the total area of a square and circle. It presents a math problem where 4 feet of wire must be used to form both shapes. The math model defines the total area as the sum of the square area and circle area in terms of x and r, with the wire length constraint. Taking the derivative and setting it equal to 0 allows solving for the maximum total area.




![Math Model
A = area of square+area of circle
= x² + πr²
the length of wire is 4 feet
4 = 4x + 2πr
r=
premeter = 4x
circumference=2πr
π
)( x-12
Area = x² + πr²
22
]
)1(2
[
π
π
x
xA
]48)4[(
1 2
xxπ
π](https://image.slidesharecdn.com/lifeoptimizationproblems-160123162531/85/Life-optimization-problems-5-320.jpg)

