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Let E and F be two events for which one knows that the probability that atleast one of them occurs is 3/4. What is the probability that neither E nor F occurs? Solution P(A or B) = P(A) + P(B) - P(A & B) = .21+.34-.05 = .5 P(neither A nor B) = 1 - P(A or B) = .5.

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Let E and F be two events for which one knows that the probability that atleast one of them occurs is 3/4. What is the probability that neither E nor F occurs? Solution P(A or B) = P(A) + P(B) - P(A & B) = .21+.34-.05 = .5 P(neither A nor B) = 1 - P(A or B) = .5

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