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Reabsorption of salt and water &
    Renal plasma clearance
Reabsorption of salt, water and glucose
The kidneys filter about 180 l per day,
but the urine excreted is about 1 – 2 l (1%)
Per day.

This means that 99% of the ultrafiltrate is
reabsorbed and 1% excreted.

The minimum volume of urine required
per day to eliminate the metabolic wastes
is 400 ml (obligatory water loss).

 Water reabsorption in the proximal
 tubules is by osmosis.
Salt and water reabsorption
Reabsorption of glucose


                     Glucose is easily filtered by the glumeruli
                     into the renal tubules.

                     375 mg/min is reabsorbed and the rest is
                     excreted (Glycosuria).

                     This occur in the proximal tubule by
                     secondary active transport which
                     transport glucose with sodium.
Reabsorption of salt and water
                      •   ~ 65 % of salt and water which were
                          filtered at the glomerulus are
                          reabsorbed back into blood in the
                          proximal tubule.

                      •   Another 20% of water is reabsorbed in
                          the descending loop of the Henle.
65% water
reabsorbed
                      •   The total 85% salt and water which are
                          reabsorbed occur constantly and are
   20% water              not under any hormonal regulations.
   reabsorbed
                      •   Still a large volume (~ 180 L x 15% = 27
                          L) is remained to be reabsorbed in the
                          rest of the nephron tubules (distal
                          convoluted tubules and collecting
                          ducts).
Counter current multiplier system


                                       Ascending limb of
               Descending limb of      loop of Henle       ~ 100 mOsm
               loop of Henle                               goes to distal
                                                           convoluted tubules
                                                           and collecting duct.


                                              < 300
         > 300                > 300 mOsm/L
                      > 300
              Water                  NaCl      NaCl



  Capillary
Water reabsorption in distal convoluted
      tubules and collecting duct


      Distal CT                              ADH

            100 mOsm
                   300            300


                   400            400

                         water   Collecting Duct
                   600
                                  600
                  NaCl
                                  800
                   800
Vasa recta and countercurrent exchange
The role of urea in the concentration of the urine
Plasma concentration and antidiuretic hormone ADH
The final products of the process


Composition of the plasma, glomerular filtrate, and the urine:

       Solute                 Plasma Filtrate Final urine % reclaimed

       Urea                      +       +        +         50%

       Glucose                   +       +        -         100%

       Amino acids               +       +        -         100%

      Total inorganic ions*      +       +        +         95.5%

       Protein                   +       +        -         -

      Organic toxins             +       +        ++        0%


* mainly Na+ and Cl-
Renal plasma clearance
Renal clearance of inulin
Renal clearance of Inulin
                        measurement of GFR
      •   Inulin is not produced by our cells and it is not metabolized. Also it is
          fully filtered and neither secreted nor reabsorbed.
      - Inulin clearance depends on GFR.
          Inulin filtered = inulin excrected

   Inulin Filtered = GFR (ml/min) x P (mg/ml)

Glomerular Filteration Rate            Plasma concentration of Inulin


    Inulin excreted = V (ml/min) x U (mg/ml)


   Rate of urine formation        Inulin concentration in urine

                       GFR x P = V x U
                                         V (ml/min) x U (mg/ml)
                    GFR (ml/min) =
                                               P (mg/ml)
Renal Plasma Clearance of Solutes
Clearance of a solute is the volume of plasma that is completely cleared
from that solute in one minute.


Clearance of inulin (ml/min) = GFR (ml/min)



                        V (ml/min) x U (mg/ml)
 Clearance (ml/min) =
                            P (mg/ml)



- A substance that is filtered and reabsorbed has
       clearance < GFR or inulin

- A substance that is filtered and secreted has
       clearance > GFR or inulin
Clearance of Urea

-Urea is filtered like inulin but also partially
reabsorbed.


-So how clearance of urea is compared to GFR?




UREA CLEARNCE (ml/min)               ?
                                     <       GFR (ml/min)
Clearance of Para-aminohippuric Acid (PAH)

PAH is filtered like inulin but in addition it is also
secreted.


-So how clearance of PAH is compared to GFR?



PAH (ml/min)         >
                     ?     GFR (ml/min)



PAH is used to measure renal plasma flow.
Renal control of electrolyte and
       acid-base balance
                   In the region of the late distal tubule
                   and the cortical collecting duct,
                   reabsorbtion of Na+ results in
                   secretion of K+ and H+.

                   In case of hyperacidity H+ is
                   secreted at the expense of K+
                   this is why hyperacidity is
                   associated with increase in
                   blood K+.

                   On the other hand hyperkalemia
                   results in secretion of K+ at the
                   expense of H+ causing hyperacidity
                   in the blood.

                   Reabsorption of Na+ and
                   secretion of K+ are regulated by
                   aldosterone.
Homeostasis of plasma Na+
Urine formation
                  Filtration is the process of flow
                  of water and dissolved solutes from
                  the blood plasma to the capsule.

                  Reabsorption is the back uptake of
                  water and NaCl, glucose, and amino
                  acids from the tubular fluid to the
                  blood.

                  Secretion is the addition of some
                  substances from the blood capillaries
                   directly into the tubules.

                  Excretion is the elimination of water
                  and some solutes in form of urine.
Kidney Disease
• Glomerulonephritis
•   It is the inflammation of the glomeruli, or small blood vessels in the
    kidneys. It may present with isolated hematuria and/or proteinuria
    (blood or protein in the urine).

• Acute Renal Failure
•   Acute: Sudden onset. Rapid reduction in urine output-usually
    reversible.
•   This may be due to infection, drugs, traumatic injury, major surgery,
    nephrotoxic poisons.
•   Emergency dialysis may be needed until the situation resolves and the
    kidneys begin functioning again.

• Chronic Renal Insufficiency (CRI)
•   Slow distruction of the filtering capacity of the kidney.
•   It is irreversible.
•   75% of function can be lost before it is noticeable.

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lecture 14 dr fawzy

  • 1. Reabsorption of salt and water & Renal plasma clearance
  • 2. Reabsorption of salt, water and glucose The kidneys filter about 180 l per day, but the urine excreted is about 1 – 2 l (1%) Per day. This means that 99% of the ultrafiltrate is reabsorbed and 1% excreted. The minimum volume of urine required per day to eliminate the metabolic wastes is 400 ml (obligatory water loss). Water reabsorption in the proximal tubules is by osmosis.
  • 3. Salt and water reabsorption
  • 4. Reabsorption of glucose Glucose is easily filtered by the glumeruli into the renal tubules. 375 mg/min is reabsorbed and the rest is excreted (Glycosuria). This occur in the proximal tubule by secondary active transport which transport glucose with sodium.
  • 5. Reabsorption of salt and water • ~ 65 % of salt and water which were filtered at the glomerulus are reabsorbed back into blood in the proximal tubule. • Another 20% of water is reabsorbed in the descending loop of the Henle. 65% water reabsorbed • The total 85% salt and water which are reabsorbed occur constantly and are 20% water not under any hormonal regulations. reabsorbed • Still a large volume (~ 180 L x 15% = 27 L) is remained to be reabsorbed in the rest of the nephron tubules (distal convoluted tubules and collecting ducts).
  • 6. Counter current multiplier system Ascending limb of Descending limb of loop of Henle ~ 100 mOsm loop of Henle goes to distal convoluted tubules and collecting duct. < 300 > 300 > 300 mOsm/L > 300 Water NaCl NaCl Capillary
  • 7. Water reabsorption in distal convoluted tubules and collecting duct Distal CT ADH 100 mOsm 300 300 400 400 water Collecting Duct 600 600 NaCl 800 800
  • 8. Vasa recta and countercurrent exchange
  • 9. The role of urea in the concentration of the urine
  • 10. Plasma concentration and antidiuretic hormone ADH
  • 11. The final products of the process Composition of the plasma, glomerular filtrate, and the urine: Solute Plasma Filtrate Final urine % reclaimed Urea + + + 50% Glucose + + - 100% Amino acids + + - 100% Total inorganic ions* + + + 95.5% Protein + + - - Organic toxins + + ++ 0% * mainly Na+ and Cl-
  • 12. Renal plasma clearance Renal clearance of inulin
  • 13. Renal clearance of Inulin measurement of GFR • Inulin is not produced by our cells and it is not metabolized. Also it is fully filtered and neither secreted nor reabsorbed. - Inulin clearance depends on GFR. Inulin filtered = inulin excrected Inulin Filtered = GFR (ml/min) x P (mg/ml) Glomerular Filteration Rate Plasma concentration of Inulin Inulin excreted = V (ml/min) x U (mg/ml) Rate of urine formation Inulin concentration in urine GFR x P = V x U V (ml/min) x U (mg/ml) GFR (ml/min) = P (mg/ml)
  • 14. Renal Plasma Clearance of Solutes Clearance of a solute is the volume of plasma that is completely cleared from that solute in one minute. Clearance of inulin (ml/min) = GFR (ml/min) V (ml/min) x U (mg/ml) Clearance (ml/min) = P (mg/ml) - A substance that is filtered and reabsorbed has clearance < GFR or inulin - A substance that is filtered and secreted has clearance > GFR or inulin
  • 15. Clearance of Urea -Urea is filtered like inulin but also partially reabsorbed. -So how clearance of urea is compared to GFR? UREA CLEARNCE (ml/min) ? < GFR (ml/min)
  • 16. Clearance of Para-aminohippuric Acid (PAH) PAH is filtered like inulin but in addition it is also secreted. -So how clearance of PAH is compared to GFR? PAH (ml/min) > ? GFR (ml/min) PAH is used to measure renal plasma flow.
  • 17. Renal control of electrolyte and acid-base balance In the region of the late distal tubule and the cortical collecting duct, reabsorbtion of Na+ results in secretion of K+ and H+. In case of hyperacidity H+ is secreted at the expense of K+ this is why hyperacidity is associated with increase in blood K+. On the other hand hyperkalemia results in secretion of K+ at the expense of H+ causing hyperacidity in the blood. Reabsorption of Na+ and secretion of K+ are regulated by aldosterone.
  • 19. Urine formation Filtration is the process of flow of water and dissolved solutes from the blood plasma to the capsule. Reabsorption is the back uptake of water and NaCl, glucose, and amino acids from the tubular fluid to the blood. Secretion is the addition of some substances from the blood capillaries directly into the tubules. Excretion is the elimination of water and some solutes in form of urine.
  • 20. Kidney Disease • Glomerulonephritis • It is the inflammation of the glomeruli, or small blood vessels in the kidneys. It may present with isolated hematuria and/or proteinuria (blood or protein in the urine). • Acute Renal Failure • Acute: Sudden onset. Rapid reduction in urine output-usually reversible. • This may be due to infection, drugs, traumatic injury, major surgery, nephrotoxic poisons. • Emergency dialysis may be needed until the situation resolves and the kidneys begin functioning again. • Chronic Renal Insufficiency (CRI) • Slow distruction of the filtering capacity of the kidney. • It is irreversible. • 75% of function can be lost before it is noticeable.