When a current passes through a silver nitrate solution, 3.24g of silver is deposited on the cathode. This corresponds to 0.003 moles of electrons. For the same quantity of charge, 0.0015 moles or 0.953g of copper would deposit at the anode, and 0.001 moles or 0.027g of aluminum would deposit at the cathode. When a 0.125A current passes through a 0.8 mol/dm3 copper(II) sulfate solution for 30 minutes, 0.0743g of copper will deposit at the cathode.