Intravenous PyelogramReason for exam Fever of unknown originTec.pdf

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Intravenous Pyelogram Reason for exam: Fever of unknown origin Technical data: no-known allergies. 100 milliliter infusion through iv. No reaction noted. Intravenous Pyelogram: Following the intravenous injection of contrast material, several films were taken including anterior-posterior and oblique views showing that both kidneys are normal in size and configuration. The visualized course of the distal ureters are both normal. The bladder is well visualized on a delayed film and is within normal limits. There is a small amount of urinary residual on the post voiding film. Conclusion: Essentially normal intravenous pyelogram. Answer: Solution As the patient was suffering from fever of unknown origin. The possible cause of fever was assumed to be kidney infection (Acute pyelonephritis), urinary tract infection or bladder infection. So to have a clear idea the Intravenous Pyelogram was performed. It is an x-ray examination in which an injection of contrast material is used to evaluate the kidneys, urinary bladder and ureters. Since the reprts of intarvenous pyelogram was normal, the origin of fever is not the urinary system. Now the doctor can diagnose other organs to locate the origin of fever..

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Case Study University Hospital Discharge Summary Medical Record \# 12-34-56 Patient Names Willam Edison Admitted: 11/1/19 Discharged: 11/12/19 Chief Complaintt This 66 y.o. male was admitted for nausea, vomiting and anorexia of three days duration. The patient also complained of recent RUQ pain and pyrosis after heavy meals. This is the second hospital admission for this 66 y.0. male patient with a known history of chronic kidney disease, hypertension, osteoarthritis, asthma, gastroesophogeal reflux disease, PUD (with prior hemorrhage), and bilateral total knee replacement. Prior to admission, the patient had been drinking heavily as he had in the past and he had tremors prior to admission. He sleeps on two pillows and has dyspnea after climbing one flight of stairs. He denied recent colds, upper respiratory infections, hematemesis or diarrhea. The patient complained of some urinary frequency and urgency. There was a rash noted on the forearms, which the patient had been treating with Benadryl cream. Physical Examination: The patient was in some distress on examination. Examination of the head revealed pupils and eye movements to be within normal limits. The chest was clear and the heart rate was normal. The blood pressure was elevated at 200/120 . Temperature was slightly elevated at 100.6. Pulse was 72 and respirations vere 16. Examination of the abdomen revealed some distention with pain in the RUQ. The rectal examination revealed an enlarged prostate of two to three times the normal size. Occult blood was negative. The rest of the exam was within normal limits. Laboratory Studies: Admission blood tests revealed an elevated white blood cell count as well as an elevated serum bilirubin. Urinalysis showed albuminuria, the presence of bacteria, TNTC white cells and pus. Sonography and HIDA scan revealed cholelithiasis. PSA was 19.8. Impression: Cholelithiasis/cholecystitis. Enlarged prostate with elevated PSA, possible BPH, rule out tumor. Consider EGD due to history of GERD and PUD. Hospital Courser The patient was diagnosed with cholelithiasis/cholecystitis. The patient underwent laparoscopic cholecystectomy under general endotracheal anesthesia. Pathology revealed chronic cholecystitis and cholelithiasis. The patient tolerated the procedure well. On postop day 22 the patient developed nausea and vomiting which was likely due to a postoperative paralytic ileus. The patient was treated conservatively with a nasogastric tube to low concomitant suction. During the hospitalization, the patient also underwent transrectal vitrasound of the prostate with biopsy. Operative report revealed that the seminal vesicles were not dilated and the prostatic capsule was intact. Biopsy results were positive for adenocarcinoma of the prostate. Patient to be scheduled for TURP on another admission. The patient was treated with IV Levaquin for UT. The patient's ilens resolved and he was discharged on postop day 35 with plans for outpatient follow-up. The patient.

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Orchids are a type of flowering plant. How would biologists explain how a living orchid species lacking leaves evolved from an ancestral orchid species that had leaves? Solution A plant loses a feature means this feature is a kind of disadvantage in its environment. Meanwhile, what it gets from the lost feature can be got from its environment. A change in leaf morphology monopodial growth habit, and aeration complexes for gas exchange in photosynthetic roots seem to be the most important characters in making the evolutionary transition to leaflessness. The species no longer required broad leaves for transpiration . The leaves are not favourable for the survival of the plant species. In fact, having them makes it harder for the species to survive as energy is invested to keep them strong and alive. maybe it\'s a dark place, and hard for plants to do their photosynthesis, and the orchids can get carbon and water from the environment, for example, from soil, instead of leaves, from which orchids usually got carbon and water. may be only orchid species that lacked these leaves were able to sustain environmental changes at the time, so leaves were selected out of the population..

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Need the mutiple choice answered Solution 1. A small software update designed to address an urgent or specific problem is called a: A. Hotfix. 2. In a UNIX operating system, which run-level describes single user mode? D. 1. 3. TCP wrappers do what? A. Help secure the system by restricting network connections. 4. File permissions under UNIX consist of what three types? B. Read, write, and execute. 5. The combination of hardware and software running on most routers, switches, and network devices is called: D. Firmware. 6. The mechanism that allows for centralized management and configuration of computers and remote users in an Active Directory environment is called: B. Group policies. 7. Under Windows Vista, the User Account Control function: D. Allows users to operate the system without requiring administrative privileges. 8. What feature in Windows Server 2008 controls access to network resources based on a client computer\'s identity and compliance with corporate governance policy? B. Network Access Protection 9. Microsoft\'s way of bundling updates, fixes, and new functions into a large, self-installing package is called a(n): A. Service pack 10. Applying the latest patches is important for maintaining the security of: B. Operating systems and applications.

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MaT: Identify the letter of the choice that best matches the phrase or definition. WiMax infrastructure mode legacy systems distributed systems amendment 80.11n gate way router scalability roaming broadband wireless communications protocols for metropolitan area networks. \"compared to mainframe architecture, these increase concerns about data security and integrity because many individual clients require access to perform processing.\" another term for a version of a wireless standard intended to improve bandwidth, range, and security\" standard that uses MIMO technology to boost performance. \"a device that connects network segments, determines the most efficient data path, and guides the flow of data\" another name for the wireless configuration in which a central wireless devise is used to serve all wireless clients. process that automatically allows a wireless client to associate with a stronger access point \"the connection between a network topology and a larger, dissimilar network.\" \"when considering physical design, a systems analyst must determine hoe a new application will communicate with these.\" \"especially important in implementing systems that are volume- related, such as transaction processing systems.\" Solution WiMax: (C) Another term for a version of a wireless standard intended to improve bandwidth, range, and security. Infrastructure mode: (F) Another name for the wireless configuration in which a central wireless device is used to serve all wireless clients. Legacy System: (A) Broadband wireless communications protocols for metropolitan area networks. Distributed Systems: (B) Compared to mainframe architecture, these increase concerns about data security and integrity because many individual clients require access to perform processing. Amendment: (I) When considering physical design, a systems analystmust determine how a new application will communicate with these. 802.11n: (D) Standard that uses MIMO technology to boost performance. Gateway: (H) The connection between a network topology and a larger, dissimilar network. Router: (E) A device that connects network segments, determinse the most efficient data path, and guides the flow of data. Scalability: (J) Especially important in implementing systems that are volume-related, such as transaction processing systems. Roaming: (G) Process that automatically allows a wireless client to associate with a stronger access point..

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A concave mirror forms an image on a screen that is twice as large as the object. Both the object and the screen are then moved to produce an image on the screen that is three times the size of the object. If the screen is moved 75 cm in the process, how far is the object moved? What is the focal length of the mirror? Solution magnification: m = hi / ho = di/do hi = size of the image ho = size of the object but, hi = 2* ho, so m = 2*ho / h o = 2, Then di= 2*do mirror formula: 1/ f = 1/do + 1/di 1/f = 1/do + 1/2do 1/f = 3/2do new magnification is m \' = 3, so distance moved by the screen is s = 75 cm new image distance: di \' = di +s do\' =do-s\' then, m \' = di\'/do\' = di +s /do-s\', therefore, 3(do-s\') = di +s new focal length: 1/ f = 1/do \' + 1/di\' 1/f = 1/ do-s\' + 1/3(do-s\') solve the above equations, we get, s\' = do /9 thus, do =112.5 cm, hence, s\'= 112.5cm /9 =12.5 cm therefore, the focal length: f = 3/2do = 75 cm.

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