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Loops
While statement
Description
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Requirements
Do this assignment using a While statement.
Test
For turning in the assignment, perform the following test run using the input shown.
(The user input is shown in bold)
Test Run
Enter data count
5
Enter a data value:
10
Enter a data value
50
Enter a data value
40
Enter a data value
20
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(Above, user input is shown in bold)
Submit
Copy the following in a file and submit the file:
Output of the test run
C/C++ Source code
Sample Code
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double sum;
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//input data count
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//Test
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//Update Setup
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Show all calculations (4 points)
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e) Lrs/Lrs and lRS/lRS
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a) L is in the middle
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c) S is in the middle
d) none of the above
e) the answers a, b, and c are possible
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b) 10 cM
c) 20 cM
d) 30 cM
e) 35 cM
iv) What is the distance between the R and S genes? Show all calculations. (2 points)
a) 10 cM
b) 14 cM
c) 20 cM
d) 30 cM
e) 35 cM
iv) What is the distance between the L and S genes? Show all calculations. (2 points)
a) 5 cM
b) 10 cM
c) 15 cM
d) 20 cM
e) 30 cM
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c) 0.4
d) 0.6
e) 0.8.
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In order to complete this problem set, it is helpful to refer to Chapters 1 through 4 in Stock and
Watson. This assignment is due at the beginning of class on Tuesday.
1. In EViews, estimate a linear regression equation using the El Paso vehicle registration and
population data from the problem set data workbook. Note that the dependent variable is the
number of registered vehicles and population is the explanatory variable. Be sure to interpret the
results you obtain.
El Paso
El Paso
County
County
Registered
Population
Vehicles, 1000s
1000s
Year
CARS
POP
1969
182.025
364.022
1970
181.883
360.462
1971
203.869
369.189
1972
212.266
378.364
1973
225.501
398.203
1974
235.533
411.532
1975
274.781
427.292
1976
262.130
440.333
1977
270.361
450.007
1978
282.738
460.611
1979
296.099
472.343
1980
309.533
483.711
1981
290.775
497.523
1982
298.800
511.892
1983
309.533
521.038
1984
328.549
529.668
1985
344.199
538.809
1986
341.486
549.592
1987
344.099
559.479
1988
351.540
568.804
1989
357.254
580.982
1990
356.312
595.350
1991
362.404
608.206
1992
341.702
619.138
1993
347.386
634.044
1994
366.326
646.181
1995
369.504
654.250
1996
396.920
656.482
1997
400.611
665.066
1998
429.326
671.250
1999
443.443
675.397
2000
445.849
681.729
2001
457.576
689.163
2002
477.725
696.446
2003
501.426
705.200
2004
505.459
717.652
2005
533.438
728.095
2006
562.591
744.795
2007
575.054
755.578
2008
567.693
769.930
2009
570.744
786.759
2010
589.193
803.548
2011
597.092
819.796
2012
615.285
832.118
2013
626.930
830.585
2014
641.825
833.370
2015
657.944
831.382
2016
660.861
834.112
2017
671.024
836.087
2018
670.643
835.590
2019
674.628
837.501
2020
670.804
865.984
2021
685.900
867.947
2. Use the regression output to test a null hypothesis that population has no effect on the number
of cars registered in El Paso County. Be sure to state the null and alternative hypotheses.
3. Also in EViews, plot a scatter diagram that includes registered vehicles on the vertical axis
and population on the horizontal axis. Briefly discuss any information that can be discerned from
the graph.
4. Answer Problem 3.5 on Page 90 of Stock and Watson.
5. As the data above indicate, population growth usually leads to more vehicle registrations.
Forecast the number of registered vehicles in El Paso if the population increases to 875 thousand.
When population increased in 2020, did El Paso County vehicle registrations also increase?
Based on real world conditions, explain why this may have occurred.
El Paso El Paso
County County
Registered Population
Vehicles,
1000s
1000s
Year CARS POP
1969 182.025 364.022
1970 181.883 360.462
1971 203.869 369.189
1972 212.266 378.364
1973 225.501 398.203
1974 235.533 411.532
1975 274.781 427.292
1976 262.130 440.333
1977 270.361 450.007
1978 282.738 460.611
1979 296.099 472.343
1980 309.533 483.711
1981 290.775 497.523
1982 298.800 511.892
1983 309.533 521.038
1984 328.549 529.668
1985 344.199 538.809
1986 341.486 549.592
1987 344.099 559.479
1988 351.540 568.804
1989 357.2.
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Have an understanding of Unicode and how encoding works
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In JAVA how do you encode and print each sentence in the file using a basic Caesar Cipher.
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- For example if we encoded the character 'A' with a shift of 5 it would become the character 'F'
- For example if we encoded the character 'X' with a shift of 5 it would become the character ']'
- Spaces should be printed but not encoded
- Use the method caesarCipher
Write each encoded sentence to a new text file called encoded.txt
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and each line will correspond to a single sentence.)
Sample Output:
Ex: If input is:
anexample.txt
the output is:
Please enter the name of the file:
It tw it sty1 ymjwj nx st yw~&
Qnkj nx f qtsl qjxxts ns mzrnqny~3
Ex: If input is:
anexample2.txt
the output is:
Please enter the name of the file:
Mjqqt Qnq~1 ~tz itnsl |jqqD
N,r knsj&&&&&
Qnkj nx tzwx yt gj xujsy1 sty yt gj xf{ji3
\j mf{j mtuj3333 Wjgjqqntsx fwj gznqy ts mtuj3333
N kfnqji r~ |f~ yt xzhhjxx3
Ex: If the input is:
WrongFileName
the output is:
File does not exist
.
In Jan 2022 an environmental factor that may to trigger MS was identif.pdf
In Jan 2022 an environmental factor that may to trigger MS was identified as exposure to
pesticides the diversity of the microbiome infection by Covid -19 all of these answers infection
by the Epstein Barr virus For an action potential (AP) train, the frequency and duration of the AP
train depend primarily on all of these answers the length of the axon and whether it's in the CNS
or PNS the magnitude and duration of summed graded potentials at the initial segment the
activation of voltage gated Na + and K + channels in the dendrites, cell body and axon the
diameter of the axon and whether it is myelinated The frequency and duration of the APs in an
AP train are affected by the number and duration of excitatory and inhibitory synaptic inputs
(summed synaptic potentials) all of these answers the resting membrane potential and how
excitable the neuron is the branching of dendrites and their distance from the cell soma the
density and characteristics of the voltage gated Na + and K + channels at the initial segment
Single action potentials are limited because they all of these answers propagate along the axon in
only one direction often decay along the axon before reaching the presynaptic terminus are often
too rapid/transient to initiate synaptic transmission in the presynaptic terminus can't provide
information pout exactly how much activity occurred in the neuron that produced them.
In JAVA Encode and print each sentence in the file using a basic Caesa.pdf
In JAVA
Encode and print each sentence in the file using a basic Caesar Cipher.
- Encode the characters by shifting their Unicode value by 5
- For example if we encoded the character 'A' with a shift of 5 it would become the character 'F'
- For example if we encoded the character 'X' with a shift of 5 it would become the character ']'
- Spaces should be printed but not encoded
- Use the method caesarCipher
Write each encoded sentence to a new text file called encoded.txt
- If a IOException is thrown catch the exception and alert the user of the error
- Use the method encodedFile
(The main method cannot be set to throw any exceptions. The text file will contain multiple lines
and each line will correspond to a single sentence.)
Sample Output:
Ex: If input is:
anexample.txt
the output is:
Please enter the name of the file:
It tw it sty1 ymjwj nx st yw~&
Qnkj nx f qtsl qjxxts ns mzrnqny~3
Ex: If input is:
anexample2.txt
the output is:
Please enter the name of the file:
Mjqqt Qnq~1 ~tz itnsl |jqqD
N,r knsj&&&&&
Qnkj nx tzwx yt gj xujsy1 sty yt gj xf{ji3
\j mf{j mtuj3333 Wjgjqqntsx fwj gznqy ts mtuj3333
N kfnqji r~ |f~ yt xzhhjxx3
Ex: If the input is:
WrongFileName
the output is:
File does not exist
.
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptxMohd Adib Abd Muin, Senior Lecturer at Universiti Utara Malaysia
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IN C++ PLEASE Topics Loops While statement Description Write.pdf
IN C++ PLEASE
Topics
Loops
While statement
Description
Write a program that will compute the sum of one or more data values entered by the user. First,
the program will ask the user to provide the data count. Then it will ask the user data count times
to enter a data value. It will then display the sum of data values entered by the user. See the Test
section below for test data.
Requirements
Do this assignment using a While statement.
Test
For turning in the assignment, perform the following test run using the input shown.
(The user input is shown in bold)
Test Run
Enter data count
5
Enter a data value:
10
Enter a data value
50
Enter a data value
40
Enter a data value
20
Enter a data value
30
Sum: 150
(Above, user input is shown in bold)
Submit
Copy the following in a file and submit the file:
Output of the test run
C/C++ Source code
Sample Code
//variable declarations
//The variable below contains the running sum.
//It contains the sum of all the values entered by the user so far.
double sum;
//The variable below contains user input.
//It contains the most recent value entered by the user
double num;
//The variable below contains the data count.
//It contains the number of values the user is going to enter.
//It contains the number of times the While loop should loop (go around).
int dataCount;
//The variable below contains the loop count.
//It contains the number of times the While loop have looped (gone around) so far.
int count;
//input data count
cout << "Enter data count" << endl;
cin >> dataCount;
//initialize sum
sum = 0;
//Initial Setup
count = 0;
//Test
while (count < dataCount)
{
//input a number
cout << "Enter a data value" << endl;
cin >> num;
//add num to sum (add a code line below)
//Update Setup
count = count + 1;
}
//display sum (add a code line below)
.
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Main function that calls all supporting functions in the order than they are to appear
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in python Define a function named swap_values that takes four integer.pdf
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alphabet. The encoded letter can be found in one of two ways, either a parallel list look up (ex.
letter to encode = ' B ', location = 1 , encoded letter location = 1 , which is a ' Y '), or a calculated
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call the encrypt_letter method, otherwise ignore the character. Build the encryption string using
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message) - convert the message to upper case letters, then loop through the message string one
character at a time. Build the decryption string using the decrypted letters in a manner similar to
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alphabet to find its location. Use that location to calculate the position of the encrypted letter in
the manner described above, then return the encrypted letter. 5.__decrypt_letter(self, letter) -
look up the letter in the alphabet to find its location. Use that location to calculate the position of
the decrypted letter in the manner described above, then return the decrypted letter.
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where the encrypted message is found by looking up each letter and finding the corresponding
letter in a shifted alphabet (ex. letter to encode = ' B ', location = 1 , shift value = 3 , location +
shift value = 1 + 3 = 4 , encoded letter location = 4 , which is an ' E '). If the shift value causes
the encoded letter to be past the end of the alphabet, then it should wrap around to the beginning
(ex. letter to encode = ' X ', location = 23 , shift value = 3 , location + shift value = 23 + 3 = 26 ,
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the encrypted letters and ignored characters, and then return it (ie. leave all spaces. punctuation,
and numbers the same, only letters in the string will be encrypted). 3. decrypt_message(self,
message) - convert the message to upper case letters, then loop through the message string one
character at a time. Build the decryption string using the decrypted letters in a manner similar to
the encrypt_message method above. 4. _encrypt_letter(self, letter) - look up the letter in the
alphabet to find its location. Use that location to calculate the position of the encrypted letter in
the manner described above, then retum the encrypted letter. 5. _decrypt_letter(self, letter)-look
up the letter in the alphabet to find its location. Use that location to calculate the position of the
decrypted letter in the manner described above, then return the decrypted letter. CasesarCipher
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encrypted message is found by looking up each letter and finding the corresponding letter in a
shifted alphabet (ex. letter to encode = ' B ", location = 1 , shift value = 3 , location + shift value
= 1 + 3 = 4 , encoded letter location = 4 , which is an + E ). . If the shift value causes the encoded
letter to be past the end of the alphabet, then it should wrap around to the beginning (ex. letter to
encode = ' X ', location = 23 , shift value = 3 , location + shift value = 23 + 3 = 26 , encoded
letter location = 26 , which is larger than 25 , subtract the total number of letters in the alphabet
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In order to perform a one-way ANOVA test, there are three basic assumptions to be fulfilled:
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2. All samples are randomly selected and independent.
3. The populations are assumed to have equal standard deviations (or variances).
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In one species of the plant coding for color- shape and amount of wate.pdf
In one species of the plant coding for color, shape and amount of water in the fruit are on the
same chromosome. The gene responsible for the color of the fruit has two alleles (R = red,
r=green), the gene responsible for the shape of the fruit also has two alleles (L =long, l=round),
and the gene responsible for the amount of water in the fruit also has two alleles (S dry, s=juicy).
The alleles represented by capital letters are dominant over the alleles represented by small
letters.
Crossing a pure line plant with red, long, dry flowers with a pure line plant with green, round,
juicy fruits results in an F1 plant with rough, long, dry fruits. The F1 individuals are crossed with
a pure line plant having green, round and juicy fruits and an F2 is obtained composed of:
22 green, long, juicy fruits
22 red, round, dry fruits
181 red, long, dry fruits
2 green, round, dry fruits
50 green, long, dry fruits
175 green, round, juicy fruits
44 red, round, juicy fruits
4 red, long, juicy fruits
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Show all calculations (4 points)
a) LRS/LRS and lrs/lrs
b) LRS/lrs and LRS/lrs
c) L/L, R/R, s/s and l/l, r/r, S/S
d) L/L, R/R, s/s and l/l, r/r, s/s
e) Lrs/Lrs and lRS/lRS
ii) Which of these three genes (L, R, or S) is in the medium? Explain (2 points)
a) L is in the middle
b) R is in the middle
c) S is in the middle
d) none of the above
e) the answers a, b, and c are possible
iii) What is the distance between the genes R and L? Show all calculations. (2 points)
a) 8.8 cM
b) 10 cM
c) 20 cM
d) 30 cM
e) 35 cM
iv) What is the distance between the R and S genes? Show all calculations. (2 points)
a) 10 cM
b) 14 cM
c) 20 cM
d) 30 cM
e) 35 cM
iv) What is the distance between the L and S genes? Show all calculations. (2 points)
a) 5 cM
b) 10 cM
c) 15 cM
d) 20 cM
e) 30 cM
v) What is the coincidence coefficient? Show all calculations (2 points)
a) 0
b) 0.2
c) 0.4
d) 0.6
e) 0.8.
In order to complete this problem set- it is helpful to refer to Chapt.pdf
In order to complete this problem set, it is helpful to refer to Chapters 1 through 4 in Stock and
Watson. This assignment is due at the beginning of class on Tuesday.
1. In EViews, estimate a linear regression equation using the El Paso vehicle registration and
population data from the problem set data workbook. Note that the dependent variable is the
number of registered vehicles and population is the explanatory variable. Be sure to interpret the
results you obtain.
El Paso
El Paso
County
County
Registered
Population
Vehicles, 1000s
1000s
Year
CARS
POP
1969
182.025
364.022
1970
181.883
360.462
1971
203.869
369.189
1972
212.266
378.364
1973
225.501
398.203
1974
235.533
411.532
1975
274.781
427.292
1976
262.130
440.333
1977
270.361
450.007
1978
282.738
460.611
1979
296.099
472.343
1980
309.533
483.711
1981
290.775
497.523
1982
298.800
511.892
1983
309.533
521.038
1984
328.549
529.668
1985
344.199
538.809
1986
341.486
549.592
1987
344.099
559.479
1988
351.540
568.804
1989
357.254
580.982
1990
356.312
595.350
1991
362.404
608.206
1992
341.702
619.138
1993
347.386
634.044
1994
366.326
646.181
1995
369.504
654.250
1996
396.920
656.482
1997
400.611
665.066
1998
429.326
671.250
1999
443.443
675.397
2000
445.849
681.729
2001
457.576
689.163
2002
477.725
696.446
2003
501.426
705.200
2004
505.459
717.652
2005
533.438
728.095
2006
562.591
744.795
2007
575.054
755.578
2008
567.693
769.930
2009
570.744
786.759
2010
589.193
803.548
2011
597.092
819.796
2012
615.285
832.118
2013
626.930
830.585
2014
641.825
833.370
2015
657.944
831.382
2016
660.861
834.112
2017
671.024
836.087
2018
670.643
835.590
2019
674.628
837.501
2020
670.804
865.984
2021
685.900
867.947
2. Use the regression output to test a null hypothesis that population has no effect on the number
of cars registered in El Paso County. Be sure to state the null and alternative hypotheses.
3. Also in EViews, plot a scatter diagram that includes registered vehicles on the vertical axis
and population on the horizontal axis. Briefly discuss any information that can be discerned from
the graph.
4. Answer Problem 3.5 on Page 90 of Stock and Watson.
5. As the data above indicate, population growth usually leads to more vehicle registrations.
Forecast the number of registered vehicles in El Paso if the population increases to 875 thousand.
When population increased in 2020, did El Paso County vehicle registrations also increase?
Based on real world conditions, explain why this may have occurred.
El Paso El Paso
County County
Registered Population
Vehicles,
1000s
1000s
Year CARS POP
1969 182.025 364.022
1970 181.883 360.462
1971 203.869 369.189
1972 212.266 378.364
1973 225.501 398.203
1974 235.533 411.532
1975 274.781 427.292
1976 262.130 440.333
1977 270.361 450.007
1978 282.738 460.611
1979 296.099 472.343
1980 309.533 483.711
1981 290.775 497.523
1982 298.800 511.892
1983 309.533 521.038
1984 328.549 529.668
1985 344.199 538.809
1986 341.486 549.592
1987 344.099 559.479
1988 351.540 568.804
1989 357.2.
In least weasels- some individuals undergo a seasonal color molt (fur.pdf
In least weasels, some individuals undergo a seasonal color molt (fur change) from summer
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There are two alleles governing fur color: D , L . There are 130 DD individuals, 48 DL
individuals, and 60 LL individuals. Is this population evolving at this locus? Select one: a. Yes b.
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in java please show multiple examples of each or in one code preferabl.pdf
in java please show multiple examples of each or in one code preferably, with comments
explaining. Studying for test :) just need examples. Thanks! This is on input and output files and
try and catch mainly.
Know how to read and write files line by line
Know how to create a try catch
Know how to create an ArrayList and add items
Know how to find the most frequent item in a list
Have an understanding of Unicode and how encoding works
o Have a basic understanding of how to implement a Caesar Cipher using Unicode.
In JAVA how do you encode and print each sentence in the file using a.pdf
In JAVA how do you encode and print each sentence in the file using a basic Caesar Cipher.
- Encode the characters by shifting their Unicode value by 5
- For example if we encoded the character 'A' with a shift of 5 it would become the character 'F'
- For example if we encoded the character 'X' with a shift of 5 it would become the character ']'
- Spaces should be printed but not encoded
- Use the method caesarCipher
Write each encoded sentence to a new text file called encoded.txt
- If a IOException is thrown catch the exception and alert the user of the error
- Use the method encodedFile
(The main method cannot be set to throw any exceptions. The text file will contain multiple lines
and each line will correspond to a single sentence.)
Sample Output:
Ex: If input is:
anexample.txt
the output is:
Please enter the name of the file:
It tw it sty1 ymjwj nx st yw~&
Qnkj nx f qtsl qjxxts ns mzrnqny~3
Ex: If input is:
anexample2.txt
the output is:
Please enter the name of the file:
Mjqqt Qnq~1 ~tz itnsl |jqqD
N,r knsj&&&&&
Qnkj nx tzwx yt gj xujsy1 sty yt gj xf{ji3
\j mf{j mtuj3333 Wjgjqqntsx fwj gznqy ts mtuj3333
N kfnqji r~ |f~ yt xzhhjxx3
Ex: If the input is:
WrongFileName
the output is:
File does not exist
.
In Jan 2022 an environmental factor that may to trigger MS was identif.pdf
In Jan 2022 an environmental factor that may to trigger MS was identified as exposure to
pesticides the diversity of the microbiome infection by Covid -19 all of these answers infection
by the Epstein Barr virus For an action potential (AP) train, the frequency and duration of the AP
train depend primarily on all of these answers the length of the axon and whether it's in the CNS
or PNS the magnitude and duration of summed graded potentials at the initial segment the
activation of voltage gated Na + and K + channels in the dendrites, cell body and axon the
diameter of the axon and whether it is myelinated The frequency and duration of the APs in an
AP train are affected by the number and duration of excitatory and inhibitory synaptic inputs
(summed synaptic potentials) all of these answers the resting membrane potential and how
excitable the neuron is the branching of dendrites and their distance from the cell soma the
density and characteristics of the voltage gated Na + and K + channels at the initial segment
Single action potentials are limited because they all of these answers propagate along the axon in
only one direction often decay along the axon before reaching the presynaptic terminus are often
too rapid/transient to initiate synaptic transmission in the presynaptic terminus can't provide
information pout exactly how much activity occurred in the neuron that produced them.
In JAVA Encode and print each sentence in the file using a basic Caesa.pdf
In JAVA
Encode and print each sentence in the file using a basic Caesar Cipher.
- Encode the characters by shifting their Unicode value by 5
- For example if we encoded the character 'A' with a shift of 5 it would become the character 'F'
- For example if we encoded the character 'X' with a shift of 5 it would become the character ']'
- Spaces should be printed but not encoded
- Use the method caesarCipher
Write each encoded sentence to a new text file called encoded.txt
- If a IOException is thrown catch the exception and alert the user of the error
- Use the method encodedFile
(The main method cannot be set to throw any exceptions. The text file will contain multiple lines
and each line will correspond to a single sentence.)
Sample Output:
Ex: If input is:
anexample.txt
the output is:
Please enter the name of the file:
It tw it sty1 ymjwj nx st yw~&
Qnkj nx f qtsl qjxxts ns mzrnqny~3
Ex: If input is:
anexample2.txt
the output is:
Please enter the name of the file:
Mjqqt Qnq~1 ~tz itnsl |jqqD
N,r knsj&&&&&
Qnkj nx tzwx yt gj xujsy1 sty yt gj xf{ji3
\j mf{j mtuj3333 Wjgjqqntsx fwj gznqy ts mtuj3333
N kfnqji r~ |f~ yt xzhhjxx3
Ex: If the input is:
WrongFileName
the output is:
File does not exist
.
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