Im creating a skip list program for my Algorithms and Advanced Data.pdf
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I'm creating a skip list program for my Algorithms and Advanced Data Structure class. I was tasked with implementing a find & add method for the skiplist. Here is my program, I'm running into a segmentation fault when I add my second value into the skiplist. My first issue that I fixed was that I wasn't checking the first node in the list to see if it was nullptr, but that was not my only issue apparently. Add Method: void SkipList::add(const ElemType &el) { // Create a new node with the given element Node *newNode = new Node(el); // Get the height of the new node int newHeight = newNode->nodeHeight; // If the height of the new node is greater than the current list height, // update the list height. if (newHeight > listHeight) { listHeight = newHeight; } // Array to keep track of nodes to update Node *update[MAX_NUM_LISTS]; // Start from the top level Node *current = head[listHeight - 1]; // Initialize current correctly // If the list is empty, assign the first node to head if (head[0] == nullptr) { head[0] = newNode; } else { // Loop to traverse through list for (int i = listHeight - 1; i >= 0; i--) { // Move forward in the current level while (current->next[i] != nullptr && current->next[i]->elem < el) { current = current->next[i]; } // Store the node before which the new node should be inserted update[i] = current; } // Insert the new node at each level for (int i = 0; i < newHeight; i++) { newNode->next[i] = update[i]->next[i]; update[i]->next[i] = newNode; } } } Find Method: bool SkipList::find(const ElemType &el) const { // Start from the top level Node *current = head[listHeight - 1]; bool found = false; // Iterate through the levels of the skip list for (int i = listHeight - 1; i >= 0; i--) { // Move forward in the current level until reaching the end or finding a larger element while (current->next[i] != nullptr && current->next[i]->elem < el) { current = current->next[i]; } // Check if the current node's next node contains the target element if (current->next[i] != nullptr && current->next[i]->elem == el) { found = true; // Element found } } return found; // Element not found in the skip list } Main: int main() { ElemType inputs[] = {5, 7, 8, 10, 12, 17, 19, 22, 28, 31, 33, 35, 42, 51, 59}; SkipList list1; cout << "For list1 (same as in the slide 10 of Skip List1 Lecture Note):\n"; // for (int i=0; i(std::size(inputs)); i++) { cout << "add " << inputs[i] << endl; list1.add(inputs[i]); cout << "list1:\n" << list1 << endl; } if (list1.find(33)) cout << "33 is found!\n"; else cout << "33 is not found!!!!\n"; if (list1.find(70)) cout << "70 is found!\n"; else cout << "70 is not found!!!!\n"; if (list1.find(10)) cout << "10 is found!\n"; else cout << "10 is not found!!!!\n"; cout << "\n===================================\n"; cout << "For list2:\n"; ElemType inputs2[] = {19, 8, 17, 59, 12, 7, 5, 22, 28, 35, 33, 31, 42, 51, 10}; SkipList list2; for (int i = 0; i < static_cast(std::size(inputs2)); i++) { cout << "add " << inputs2[i] << endl.
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![I'm creating a skip list program for my Algorithms and Advanced Data Structure class. I was
tasked with implementing a find & add method for the skiplist. Here is my program, I'm running
into a segmentation fault when I add my second value into the skiplist. My first issue that I fixed
was that I wasn't checking the first node in the list to see if it was nullptr, but that was not my
only issue apparently.
Add Method:
void SkipList::add(const ElemType &el) {
// Create a new node with the given element
Node *newNode = new Node(el);
// Get the height of the new node
int newHeight = newNode->nodeHeight;
// If the height of the new node is greater than the current list height,
// update the list height.
if (newHeight > listHeight) {
listHeight = newHeight;
}
// Array to keep track of nodes to update
Node *update[MAX_NUM_LISTS];
// Start from the top level
Node *current = head[listHeight - 1]; // Initialize current correctly
// If the list is empty, assign the first node to head
if (head[0] == nullptr) {
head[0] = newNode;
} else {](https://image.slidesharecdn.com/imcreatingaskiplistprogramformyalgorithmsandadvanceddata-231007090351-0549e5f6/85/Im-creating-a-skip-list-program-for-my-Algorithms-and-Advanced-Data-pdf-1-320.jpg)
![// Loop to traverse through list
for (int i = listHeight - 1; i >= 0; i--) {
// Move forward in the current level
while (current->next[i] != nullptr && current->next[i]->elem < el) {
current = current->next[i];
}
// Store the node before which the new node should be inserted
update[i] = current;
}
// Insert the new node at each level
for (int i = 0; i < newHeight; i++) {
newNode->next[i] = update[i]->next[i];
update[i]->next[i] = newNode;
}
}
}
Find Method:
bool SkipList::find(const ElemType &el) const {
// Start from the top level
Node *current = head[listHeight - 1];
bool found = false;
// Iterate through the levels of the skip list
for (int i = listHeight - 1; i >= 0; i--) {
// Move forward in the current level until reaching the end or finding a larger element
while (current->next[i] != nullptr && current->next[i]->elem < el) {
current = current->next[i];
}](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
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The MyLinkedList class used in Listing 24.6 is a one-way directional .docx
The MyLinkedList class used in Listing 24.6 is a one-way directional .docx
please help me in C++Objective Create a singly linked list of num.pdf
please help me in C++
Objective: Create a singly linked list of numbers based upon user input.
Program logic: Ask for a number, add that number to the front of the list, print the list. Repeat
until they enter -1 for the number. .
Sample Input: 10, 15, 5, 2, 4, -1 Output: 4, 2, 5, 15, 10
Solution
#include
#include
using namespace std;
// It contains the value and the pointer to the next element in the list.
struct element {
int value;
struct element *next;
};
struct element *head = NULL;
// The list is stored in the object of this class.
class linkedlist {
public:
// To display list, we first see if head is NULL,
// If head is NULL it means the list is empty.
// Then we traverse along the list and display each item, until the next pointer is NULL.
void display() {
if(head == NULL){
cout << \"The list is empty\ \";
} else {
struct element *temp;
temp = head;
while(temp != NULL){
cout << temp->value << \" \" ;
temp = temp->next;
}
cout << \"\ \";
}
}
// To add an element to the list,create a newElement and store the value.
// If head is NULL, add the newElement to the head.
// To add an element at the starting of the list.
// The next pointer of the newElement must point to the old head.
// The new head must be pointed to the newElement.
void add(int a){
struct element *newElement;
newElement = (struct element *)malloc(sizeof(struct element));
newElement->value = a;
newElement->next = NULL;
if(head == NULL) {
head = newElement;
} else {
newElement->next = head;
head = newElement;
}
}
};
int main()
{
// Create an object of the class linkedlist.
linkedlist l = linkedlist();
int a;
do {
cout << \"Enter a number : \";
cin >> a;
if(a!=-1) { // If the number is -1 do not add it to the list.
l.add(a); // Add the number to the list.
}
l.display(); // Display the list.
} while(a!=-1); // Keep asking for a number until -1 is pressed.
return 0;
}.
1. 3 singly linked list insertion 2
1. 3 singly linked list insertion 2P. Subathra Kishore, KAMARAJ College of Engineering and Technology, Madurai
singly linked list insertion 2double Skiplist code below#include iostream#include vector.pdf
double Skiplist code below
#include
#include
#include
#include
#include
#include
#include "Node.h"
#ifndef SKIPLIST_H
#define SKIPLIST_H
using namespace std;
class SkipList{
public:
// Maximum number of levels allowed for this skip list
int MAXIMUM_ALLOWED_LEVELS;
// current maximum level amongst the inserted nodes
int level;
// the head node's next links are connected to the first node at every level
Node *head;
SkipList(int maxLevels){
MAXIMUM_ALLOWED_LEVELS = maxLevels;
// initially we have the bottom-most level only
level = 0;
// create the header node, value is irrelevant (as long as it doesn't match an inserted value -
NO REPEATS), number of next links is important (this node is connected to the first node at
every level)
head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVELS);
}
int RandomLevel(){
float probablity = (float)rand()/RAND_MAX; // flip a coin
int lvl = 0;
/*Olog(n) */while (probablity < 0.5 && lvl < MAXIMUM_ALLOWED_LEVELS){
lvl++; // landed heads so increase level by 1
probablity = (float)rand()/RAND_MAX; // flip a coin again
}
return lvl;
}
Node* CreateNode(int value, int level){
// create a new node with next links for every level that this node will be part of
// it will use these links to connect to the next node at each level
return new Node(value, level);
}
void InsertElement(int value)/*Olog(n) becuase all the functions in it are Olog(n) */{
/**
* THIS CODE HAS A BUG,
*
* ***********FIND THE BUG,
* *************EXPLAIN THE WHY THE BUG EXIST
* AND
* **********************SUGGEST A FIX *
*
*/
//w
Node *current = head; // start at head node at the toppest level
/*Olog(n)*/vector update(MAXIMUM_ALLOWED_LEVELS+1, nullptr); // this will hold
the nodes that need updating at every level after the insert takes place
/*BIG Olog(n)*/for (int i = level; i >= 0; i--){ //level is the current maximum level
// for level i, if value is to be inserted here then find out where (i.e. after which node)
/*O(1) constant */ while (current->next[i] != nullptr && current->next[i]->value <
value){ //the while loop is saying keep moving right until null or the current.value > value
current = current->next[i];
}
// found the node after which the value is to be placed at level i
update[i] = current;
}
//if
current = current->next[0]; // current moves bcoz we need to check if the value exists
if (current == nullptr || current->value != value){
/*Olog(n) */int ranLevel = RandomLevel(); // choose a random level upto where the new
node will be placed
if (ranLevel > level){
// if random level for current node is higher than the current maximum level for the
existing nodes then set updates for each level over current maximum to head (since there are no
nodes at these levels yet).
/*Olog(n)*/for (int i=level+1;i<=ranLevel;i++){
update[i] = head;
}
// also change the current maximum level for the existing nodes
level = ranLevel;
}
// create new node with next links for every level from ranLevel to zero
/*Olog(n) */Node* n = CreateNode(value, ranLevel);
// placi.
please i need help Im writing a program to test the merge sort alg.pdf
please i need help I\'m writing a program to test the merge sort algorithm for linked lists.
I need to Print the list before being sorted and the list after sorting the elements
here is my code only help in test program the four classes are ok except the test program.
TEST PROGRAM
import java.io.*;
import java.util.*;
public class Ch9_ProgExercise7 {
Scanner input = new Scanner(System.in);
public static void main(String[] args) throws IOException {
OrderedLinkedList list
= new OrderedLinkedList(); //Line 1
IntElement num = new IntElement(); //Line 2
// Prompt the user to enter some integers
System.out.println(\"Enter integers numbers \");
String temp = input.hasnextLine();
String[] split = temp.split(\" \");
for (int i = 0; i < split.length; i++) {
Integer a = Integer.parseInt(split[i]);
// insert the intgers into the list you created above
num.setNum(a);
list.insertNode(num);
}
System.out.println();
// Print the list before being sorted
// call the mergesort method
System.out.println();
// print the list after sorting the elements
}
}
ORDEREDLICKEDLIST CLASS
public class OrderedLinkedList extends LinkedListClass
{
//default constructor
public OrderedLinkedList()
{
super();
}
//copy constructor
public OrderedLinkedList(OrderedLinkedList otherList)
{
super(otherList);
}
public void linkedInsertionSort()
{
LinkedListNode lastInOrder;
LinkedListNode firstOutOfOrder;
LinkedListNode current;
LinkedListNode trailCurrent;
lastInOrder = first;
if(first == null)
System.out.println(\"Cannot sort an empty list\");
else
if(first.link == null)
System.out.println(\"The list is of length 1. \"
+ \"Already in order\");
else
while(lastInOrder.link != null)
{
firstOutOfOrder = lastInOrder.link;
if(firstOutOfOrder.info.compareTo(first.info) < 0)
{
lastInOrder.link = firstOutOfOrder.link;
firstOutOfOrder.link = first;
first = firstOutOfOrder;
}
else
{
trailCurrent = first;
current = first.link;
while(current.info.compareTo(firstOutOfOrder.info) < 0)
{
trailCurrent = current;
current = current.link;
}
if(current != firstOutOfOrder)
{
lastInOrder.link = firstOutOfOrder.link;
firstOutOfOrder.link = current;
trailCurrent.link = firstOutOfOrder;
}
else
lastInOrder = lastInOrder.link;
}
}
}//end linkedInsertionSort
//Method to determine whether searchItem is in
//the list.
//Postcondition: Returns true if searchItem is found
// in the list; otherwise, it returns
// false.
public boolean search(DataElement searchItem)
{
LinkedListNode current; //variable to traverse the list
boolean found;
current = first; //set current to point to the first
//node in the list
found = false; //set found to false
while(current != null && !found ) //search the list
if(current.info.compareTo(searchItem) >= 0)
found = true;
else
current = current.link; //make current point to
//the next node
if(found)
found = current.info.equals(searchItem);
return found;
}
//Method to insert insertItem in the list
//Postcondition: first points to the new list,
// newItem is inserted at the proper place
//.
The LinkedList1 class implements a Linked list. class.pdf
/**
The LinkedList1 class implements a Linked list.
*/
class LinkedList1
{
/**
The Node class stores a list element
and a reference to the next node.
*/
private class Node
{
String value;
Node next;
/**
Constructor.
@param val The element to store in the node.
@param n The reference to the successor node.
*/
Node(String val, Node n)
{
value = val;
next = n;
}
/**
Constructor.
@param val The element to store in the node.
*/
Node(String val)
{
// Call the other (sister) constructor.
this(val, null);
}
}
private Node first; // list head
private Node last; // last element in list
/**
Constructor.
*/
public LinkedList1()
{
first = null;
last = null;
}
/**
The isEmpty method checks to see
if the list is empty.
@return true if list is empty,
false otherwise.
*/
public boolean isEmpty()
{
return first == null;
}
/**
The size method returns the length of the list.
@return The number of elements in the list.
*/
public int size()
{
int count = 0;
Node p = first;
while (p != null)
{
// There is an element at p
count ++;
p = p.next;
}
return count;
}
/**
The add method adds an element to
the end of the list.
@param e The value to add to the
end of the list.
*/
public void add(String e)
{
if (isEmpty())
{
first = new Node(e);
last = first;
}
else
{
// Add to end of existing list
last.next = new Node(e);
last = last.next;
}
}
/**
The add method adds an element at a position.
@param e The element to add to the list.
@param index The position at which to add
the element.
@exception IndexOutOfBoundsException When
index is out of bounds.
*/
public void add(int index, String e)
{
if (index < 0 || index > size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
// Index is at least 0
if (index == 0)
{
// New element goes at beginning
first = new Node(e, first);
if (last == null)
last = first;
return;
}
// Set a reference pred to point to the node that
// will be the predecessor of the new node
Node pred = first;
for (int k = 1; k <= index - 1; k++)
{
pred = pred.next;
}
// Splice in a node containing the new element
pred.next = new Node(e, pred.next);
// Is there a new last element ?
if (pred.next.next == null)
last = pred.next;
}
/**
The toString method computes the string
representation of the list.
@return The string form of the list.
*/
public String toString()
{
StringBuilder strBuilder = new StringBuilder();
// Use p to walk down the linked list
Node p = first;
while (p != null)
{
strBuilder.append(p.value + \"\ \");
p = p.next;
}
return strBuilder.toString();
}
/**
The remove method removes the element at an index.
@param index The index of the element to remove.
@return The element removed.
@exception IndexOutOfBoundsException When index is
out of bounds.
*/
public String remove(int index)
{
if (index < 0 || index >= size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
String element; // The element to return
if (index == 0)
{
// Removal of first item in the list
element.
Implement the interface you wrote for Lab B (EntryWayListInterface)..pdf
Implement the interface you wrote for Lab B (EntryWayListInterface). As a reminder,
EntryWayListInterface allows the user to access to list elements only through the beginning and
end of the list.
Your implementation can use either an expandable array or linked nodes- it is your choice. You
can decide what instance variables are needed. You must implement every method from the
interface. Make sure to account for special conditions such as empty lists and singleton lists.
Note: your instance data variable should be either a) an array or b) one or more nodes. It should
not be an AList or LList object or an ArrayList object.
Your implementation must:
compile
contain these implemented methods:
insertHead
insertTail
deleteHead
deleteTail
display
contains
isEmpty
isFull
Also create a driver program to test your implementation. The driver program will operate from
the client perspective. Your driver program should:
display an empty list
add five entries to the list- some at the head and some at the tail
display the list
remove the first entry
remove the last entry
display the list
test to see if elements are in the list (test one element that is in the list and one that is not)
remove the last three elements in the list
try to remove an element from the empty list
Write a second class to implement EntryWayListInterface. Instead of using an array or linked
nodes, use either an AList or LList object as your instance data variable. In this way, you are
using an existing data type (AList or LList) to implement a new data type
(EntryWayListInterface). Inside the methods of this class, invoke methods on the AList or LList
object to accomplish the task.
/** An interface for the ADT list.
Entries in a list have positions that begin with 1.
* Accesses only entries that are the head or tail of the list.
*/
public interface EntryWayInterface {
/** Adds a new entry to this list T.
* @param newEntry The object to be added as a new entry.
* @return True if the addition is successful, or false if not. */
public boolean insertHead(T newEntry);
/** Deletes a new entry to this list T.
* @param newEntry The object to be added as a new entry.
* @return True if the addition is successful, or false if not. */
public boolean insertTail(T newEntry);
/** Deletes the object that is at the head of list T.
* @return the object that has been deleted and returns
* null if no object was deleted.
*/
public T deleteHead();
/** Deletes the object that is at the tail of list T.
* @return the object that has been deleted or else return null
* if no object was deleted.
*/
public T deleteTail();
/** Displays the contents of the list T.
*/
public void display();
/** See whether this list T contains a given entry.
* @param anEntry The object that is the desired entry.
* @return the position of the entry that was found.
* else returns false if the object is not in the list.
*/
public int contains(T anEntry);
/** Sees whether this list is empty.
* @return True if the list is empty, or false.
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please help me in C++Objective Create a singly linked list of num.pdf
please help me in C++
Objective: Create a singly linked list of numbers based upon user input.
Program logic: Ask for a number, add that number to the front of the list, print the list. Repeat
until they enter -1 for the number. .
Sample Input: 10, 15, 5, 2, 4, -1 Output: 4, 2, 5, 15, 10
Solution
#include
#include
using namespace std;
// It contains the value and the pointer to the next element in the list.
struct element {
int value;
struct element *next;
};
struct element *head = NULL;
// The list is stored in the object of this class.
class linkedlist {
public:
// To display list, we first see if head is NULL,
// If head is NULL it means the list is empty.
// Then we traverse along the list and display each item, until the next pointer is NULL.
void display() {
if(head == NULL){
cout << \"The list is empty\ \";
} else {
struct element *temp;
temp = head;
while(temp != NULL){
cout << temp->value << \" \" ;
temp = temp->next;
}
cout << \"\ \";
}
}
// To add an element to the list,create a newElement and store the value.
// If head is NULL, add the newElement to the head.
// To add an element at the starting of the list.
// The next pointer of the newElement must point to the old head.
// The new head must be pointed to the newElement.
void add(int a){
struct element *newElement;
newElement = (struct element *)malloc(sizeof(struct element));
newElement->value = a;
newElement->next = NULL;
if(head == NULL) {
head = newElement;
} else {
newElement->next = head;
head = newElement;
}
}
};
int main()
{
// Create an object of the class linkedlist.
linkedlist l = linkedlist();
int a;
do {
cout << \"Enter a number : \";
cin >> a;
if(a!=-1) { // If the number is -1 do not add it to the list.
l.add(a); // Add the number to the list.
}
l.display(); // Display the list.
} while(a!=-1); // Keep asking for a number until -1 is pressed.
return 0;
}.
1. 3 singly linked list insertion 2
1. 3 singly linked list insertion 2P. Subathra Kishore, KAMARAJ College of Engineering and Technology, Madurai
singly linked list insertion 2double Skiplist code below#include iostream#include vector.pdf
double Skiplist code below
#include
#include
#include
#include
#include
#include
#include "Node.h"
#ifndef SKIPLIST_H
#define SKIPLIST_H
using namespace std;
class SkipList{
public:
// Maximum number of levels allowed for this skip list
int MAXIMUM_ALLOWED_LEVELS;
// current maximum level amongst the inserted nodes
int level;
// the head node's next links are connected to the first node at every level
Node *head;
SkipList(int maxLevels){
MAXIMUM_ALLOWED_LEVELS = maxLevels;
// initially we have the bottom-most level only
level = 0;
// create the header node, value is irrelevant (as long as it doesn't match an inserted value -
NO REPEATS), number of next links is important (this node is connected to the first node at
every level)
head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVELS);
}
int RandomLevel(){
float probablity = (float)rand()/RAND_MAX; // flip a coin
int lvl = 0;
/*Olog(n) */while (probablity < 0.5 && lvl < MAXIMUM_ALLOWED_LEVELS){
lvl++; // landed heads so increase level by 1
probablity = (float)rand()/RAND_MAX; // flip a coin again
}
return lvl;
}
Node* CreateNode(int value, int level){
// create a new node with next links for every level that this node will be part of
// it will use these links to connect to the next node at each level
return new Node(value, level);
}
void InsertElement(int value)/*Olog(n) becuase all the functions in it are Olog(n) */{
/**
* THIS CODE HAS A BUG,
*
* ***********FIND THE BUG,
* *************EXPLAIN THE WHY THE BUG EXIST
* AND
* **********************SUGGEST A FIX *
*
*/
//w
Node *current = head; // start at head node at the toppest level
/*Olog(n)*/vector update(MAXIMUM_ALLOWED_LEVELS+1, nullptr); // this will hold
the nodes that need updating at every level after the insert takes place
/*BIG Olog(n)*/for (int i = level; i >= 0; i--){ //level is the current maximum level
// for level i, if value is to be inserted here then find out where (i.e. after which node)
/*O(1) constant */ while (current->next[i] != nullptr && current->next[i]->value <
value){ //the while loop is saying keep moving right until null or the current.value > value
current = current->next[i];
}
// found the node after which the value is to be placed at level i
update[i] = current;
}
//if
current = current->next[0]; // current moves bcoz we need to check if the value exists
if (current == nullptr || current->value != value){
/*Olog(n) */int ranLevel = RandomLevel(); // choose a random level upto where the new
node will be placed
if (ranLevel > level){
// if random level for current node is higher than the current maximum level for the
existing nodes then set updates for each level over current maximum to head (since there are no
nodes at these levels yet).
/*Olog(n)*/for (int i=level+1;i<=ranLevel;i++){
update[i] = head;
}
// also change the current maximum level for the existing nodes
level = ranLevel;
}
// create new node with next links for every level from ranLevel to zero
/*Olog(n) */Node* n = CreateNode(value, ranLevel);
// placi.
please i need help Im writing a program to test the merge sort alg.pdf
please i need help I\'m writing a program to test the merge sort algorithm for linked lists.
I need to Print the list before being sorted and the list after sorting the elements
here is my code only help in test program the four classes are ok except the test program.
TEST PROGRAM
import java.io.*;
import java.util.*;
public class Ch9_ProgExercise7 {
Scanner input = new Scanner(System.in);
public static void main(String[] args) throws IOException {
OrderedLinkedList list
= new OrderedLinkedList(); //Line 1
IntElement num = new IntElement(); //Line 2
// Prompt the user to enter some integers
System.out.println(\"Enter integers numbers \");
String temp = input.hasnextLine();
String[] split = temp.split(\" \");
for (int i = 0; i < split.length; i++) {
Integer a = Integer.parseInt(split[i]);
// insert the intgers into the list you created above
num.setNum(a);
list.insertNode(num);
}
System.out.println();
// Print the list before being sorted
// call the mergesort method
System.out.println();
// print the list after sorting the elements
}
}
ORDEREDLICKEDLIST CLASS
public class OrderedLinkedList extends LinkedListClass
{
//default constructor
public OrderedLinkedList()
{
super();
}
//copy constructor
public OrderedLinkedList(OrderedLinkedList otherList)
{
super(otherList);
}
public void linkedInsertionSort()
{
LinkedListNode lastInOrder;
LinkedListNode firstOutOfOrder;
LinkedListNode current;
LinkedListNode trailCurrent;
lastInOrder = first;
if(first == null)
System.out.println(\"Cannot sort an empty list\");
else
if(first.link == null)
System.out.println(\"The list is of length 1. \"
+ \"Already in order\");
else
while(lastInOrder.link != null)
{
firstOutOfOrder = lastInOrder.link;
if(firstOutOfOrder.info.compareTo(first.info) < 0)
{
lastInOrder.link = firstOutOfOrder.link;
firstOutOfOrder.link = first;
first = firstOutOfOrder;
}
else
{
trailCurrent = first;
current = first.link;
while(current.info.compareTo(firstOutOfOrder.info) < 0)
{
trailCurrent = current;
current = current.link;
}
if(current != firstOutOfOrder)
{
lastInOrder.link = firstOutOfOrder.link;
firstOutOfOrder.link = current;
trailCurrent.link = firstOutOfOrder;
}
else
lastInOrder = lastInOrder.link;
}
}
}//end linkedInsertionSort
//Method to determine whether searchItem is in
//the list.
//Postcondition: Returns true if searchItem is found
// in the list; otherwise, it returns
// false.
public boolean search(DataElement searchItem)
{
LinkedListNode current; //variable to traverse the list
boolean found;
current = first; //set current to point to the first
//node in the list
found = false; //set found to false
while(current != null && !found ) //search the list
if(current.info.compareTo(searchItem) >= 0)
found = true;
else
current = current.link; //make current point to
//the next node
if(found)
found = current.info.equals(searchItem);
return found;
}
//Method to insert insertItem in the list
//Postcondition: first points to the new list,
// newItem is inserted at the proper place
//.
The LinkedList1 class implements a Linked list. class.pdf
/**
The LinkedList1 class implements a Linked list.
*/
class LinkedList1
{
/**
The Node class stores a list element
and a reference to the next node.
*/
private class Node
{
String value;
Node next;
/**
Constructor.
@param val The element to store in the node.
@param n The reference to the successor node.
*/
Node(String val, Node n)
{
value = val;
next = n;
}
/**
Constructor.
@param val The element to store in the node.
*/
Node(String val)
{
// Call the other (sister) constructor.
this(val, null);
}
}
private Node first; // list head
private Node last; // last element in list
/**
Constructor.
*/
public LinkedList1()
{
first = null;
last = null;
}
/**
The isEmpty method checks to see
if the list is empty.
@return true if list is empty,
false otherwise.
*/
public boolean isEmpty()
{
return first == null;
}
/**
The size method returns the length of the list.
@return The number of elements in the list.
*/
public int size()
{
int count = 0;
Node p = first;
while (p != null)
{
// There is an element at p
count ++;
p = p.next;
}
return count;
}
/**
The add method adds an element to
the end of the list.
@param e The value to add to the
end of the list.
*/
public void add(String e)
{
if (isEmpty())
{
first = new Node(e);
last = first;
}
else
{
// Add to end of existing list
last.next = new Node(e);
last = last.next;
}
}
/**
The add method adds an element at a position.
@param e The element to add to the list.
@param index The position at which to add
the element.
@exception IndexOutOfBoundsException When
index is out of bounds.
*/
public void add(int index, String e)
{
if (index < 0 || index > size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
// Index is at least 0
if (index == 0)
{
// New element goes at beginning
first = new Node(e, first);
if (last == null)
last = first;
return;
}
// Set a reference pred to point to the node that
// will be the predecessor of the new node
Node pred = first;
for (int k = 1; k <= index - 1; k++)
{
pred = pred.next;
}
// Splice in a node containing the new element
pred.next = new Node(e, pred.next);
// Is there a new last element ?
if (pred.next.next == null)
last = pred.next;
}
/**
The toString method computes the string
representation of the list.
@return The string form of the list.
*/
public String toString()
{
StringBuilder strBuilder = new StringBuilder();
// Use p to walk down the linked list
Node p = first;
while (p != null)
{
strBuilder.append(p.value + \"\ \");
p = p.next;
}
return strBuilder.toString();
}
/**
The remove method removes the element at an index.
@param index The index of the element to remove.
@return The element removed.
@exception IndexOutOfBoundsException When index is
out of bounds.
*/
public String remove(int index)
{
if (index < 0 || index >= size())
{
String message = String.valueOf(index);
throw new IndexOutOfBoundsException(message);
}
String element; // The element to return
if (index == 0)
{
// Removal of first item in the list
element.
Implement the interface you wrote for Lab B (EntryWayListInterface)..pdf
Implement the interface you wrote for Lab B (EntryWayListInterface). As a reminder,
EntryWayListInterface allows the user to access to list elements only through the beginning and
end of the list.
Your implementation can use either an expandable array or linked nodes- it is your choice. You
can decide what instance variables are needed. You must implement every method from the
interface. Make sure to account for special conditions such as empty lists and singleton lists.
Note: your instance data variable should be either a) an array or b) one or more nodes. It should
not be an AList or LList object or an ArrayList object.
Your implementation must:
compile
contain these implemented methods:
insertHead
insertTail
deleteHead
deleteTail
display
contains
isEmpty
isFull
Also create a driver program to test your implementation. The driver program will operate from
the client perspective. Your driver program should:
display an empty list
add five entries to the list- some at the head and some at the tail
display the list
remove the first entry
remove the last entry
display the list
test to see if elements are in the list (test one element that is in the list and one that is not)
remove the last three elements in the list
try to remove an element from the empty list
Write a second class to implement EntryWayListInterface. Instead of using an array or linked
nodes, use either an AList or LList object as your instance data variable. In this way, you are
using an existing data type (AList or LList) to implement a new data type
(EntryWayListInterface). Inside the methods of this class, invoke methods on the AList or LList
object to accomplish the task.
/** An interface for the ADT list.
Entries in a list have positions that begin with 1.
* Accesses only entries that are the head or tail of the list.
*/
public interface EntryWayInterface {
/** Adds a new entry to this list T.
* @param newEntry The object to be added as a new entry.
* @return True if the addition is successful, or false if not. */
public boolean insertHead(T newEntry);
/** Deletes a new entry to this list T.
* @param newEntry The object to be added as a new entry.
* @return True if the addition is successful, or false if not. */
public boolean insertTail(T newEntry);
/** Deletes the object that is at the head of list T.
* @return the object that has been deleted and returns
* null if no object was deleted.
*/
public T deleteHead();
/** Deletes the object that is at the tail of list T.
* @return the object that has been deleted or else return null
* if no object was deleted.
*/
public T deleteTail();
/** Displays the contents of the list T.
*/
public void display();
/** See whether this list T contains a given entry.
* @param anEntry The object that is the desired entry.
* @return the position of the entry that was found.
* else returns false if the object is not in the list.
*/
public int contains(T anEntry);
/** Sees whether this list is empty.
* @return True if the list is empty, or false.
double linked list header file code#include iostream#include.pdf
double linked list header file code
#include
#include
#include
#include
#ifndef DOUBLYSKIPLIST_H
#define DOUBLYSKIPLIST_H
using namespace std;
class Node {
public:
int value;
int level;
vector next;
vector prev;
Node(int val, int lvl) : value(val), level(lvl) {
next.resize(lvl + 1, nullptr);
prev.resize(lvl + 1, nullptr);
}
};
class SkipList {
public:
int level;
Node* head;
Node* tail;
int MAXIMUM_ALLOWED_LEVELS;
SkipList(int maxLevels) : MAXIMUM_ALLOWED_LEVELS(maxLevels), level(0) {
head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVELS);
tail = new Node(INT_MAX, MAXIMUM_ALLOWED_LEVELS);
for (int i = 0; i <= MAXIMUM_ALLOWED_LEVELS; i++) {
head->next[i] = tail;
tail->prev[i] = head;
}
}
int RandomLevel() {
float probability = (float)rand() / RAND_MAX;
int lvl = 0;
while (probability < 0.5 && lvl < MAXIMUM_ALLOWED_LEVELS) {
lvl++;
probability = (float)rand() / RAND_MAX;
}
return lvl;
}
Node* CreateNode(int value, int level) {
return new Node(value, level);
}
void InsertElement(int value) {
Node* current = head;
vector update(MAXIMUM_ALLOWED_LEVELS + 1, nullptr);
for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {
current = current->next[i];
}
update[i] = current;
}
current = current->next[0];
if (current->value != value) {
int ranLevel = RandomLevel();
if (ranLevel > level) {
for (int i = level + 1; i <= ranLevel; i++) {
update[i] = head;
}
level = ranLevel;
}
Node* n = CreateNode(value, ranLevel);
for (int i = 0; i <= ranLevel; i++) {
n->next[i] = update[i]->next[i];
n->prev[i] = update[i];
update[i]->next[i]->prev[i] = n;
update[i]->next[i] = n;
}
}
}
void Delete(int value) {
if (!Search(value)) {
cout << value << " does not exist" << endl;
return;
}
Node* current = head;
vector update(MAXIMUM_ALLOWED_LEVELS + 1, nullptr);
for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {
current = current->next[i];
}
update[i] = current;
}
current = current->next[0];
for (int i = 0; i <= level; i++) {
if (update[i]->next[i] == current) {
update[i]->next[i] = current->next[i];
current->next[i]->prev[i] = update[i];
}
}
delete current;
}
bool Search(int value) {
Node* current = head;
for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {
current = current->next[i];
}
}
current = current->next[0];
return current->value == value;
}
void Show() {
for (int i = 0; i <= level; i++) {
Node* node = head->next[i];
cout << "Level " << i << ": ";
while (node != tail) {
cout << node->value << " -> ";
node = node->next[i];
}
cout << "Tail" << endl;
}
}
void ShowBackwards() {
Node* currTail = tail;
for (int i = 0; i <= level; i++) {
Node* node = currTail->prev[i];
cout << "Level " << i << ": ";
while (node != head) {
cout << node->value << " <- ";
node = node->prev[i];
}
cout << "Head" << endl;
}
}
};
#endif
Priority Queue header file code
#ifndef PRIORITYQ_H
#define PRIORITYQ_H
#include
#include
#include // for INT_MAX
#include // for rand()
#include
#include "doublySkiplist.h"
using namespace std;
class N.
This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
In the class we extensively discussed a generic singly linked list i.pdf
In the class we extensively discussed a generic singly linked list implemented as a node class.
Implement a generic node class called DoublyNode in which each node contains an element of
type E and each node is linked not only forward to the next element in the list but also backward
to the previous element in the list. Your implementation should adapt and implement all the
methods of generic Node including the following methods:
Constructor for DoublyNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
Solution
import java.util.ListIterator;
import java.util.NoSuchElementException;
import java.util.Random;
public class DoublyNode {
private Node head;
private Node tail;
private int size;
public DoublyNode() {
size = 0;
}
private class Node {
E element;
Node getForeNode;
Node getBackNode;
public Node(E element, Node next, Node prev) {
this.element = element;
this.getForeNode = next;
this.getBackNode = prev;
}
}
public int listLength() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.getBackNode = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfter(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.getForeNode = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfterSpecifiedNode(E element, E tobeAddedAfter) {
Node prevTobeAddedAfter = listSearch(element);
Node afterNode = prevTobeAddedAfter.getForeNode;
Node tmpNode = new Node(element,prevTobeAddedAfter,afterNode);
tmpNode = prevTobeAddedAfter.getForeNode;
afterNode = tmpNode.getForeNode;
}
public void listCopy(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getForeNode;
}
}
public Node listSearch(E item){
System.out.println(\"Searching Item \"+item);
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
if(tmp.element == item) {
System.out.println(\"Item found \"+item);
return tmp;
}
tmp = tmp.getForeNode;
}
return null;
}
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getBackNode;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.getForeNode;
head.getBackNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeNodeAfter() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.getBackNode;
tail.getForeNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
}.
Write a function to merge two doubly linked lists. The input lists ha.pdf
Write a function to merge two doubly linked lists. The input lists have their elements in sorted
order, from lowest to highest. The output list should also be sorted from lowest to highest. Your
algorithm should run in linear time on the length of the output list. Provide an algorithm for your
function Implement and show some samples of your running function
Solution
The algorithm for LinkedList MergeSort is as follows.
The trick in this algorithm is to use a local list to store the value which is pointing to the actual
list to be returned as a result of the function
Step1: START
Step2: GET inputs of list1 and list2
Step3: INITIALIZE mergelist
STEP4: SET mylist = mergelist
Step5: WHILE list1 OR list2 is EMPTY
DO
IF (list1 AND list2) are NOT EMPTY
IF list1.value > list2.value
mylist.next = list2
ELSE
mylist.next = list1
ELSE IF list1 is EMPTY
mylist.next = list2
ELSE
mylist.next = list1
Step6: RETURN mergelist
Step7: STOP
Sample program for the same implemented in C++
//====================================================================
========
// Name : DoublyLinkedList.cpp
// Author : Kaju
// Version : 0.1
// Copyright : This is just an example code
// Description : MergeSort in C++, Ansi-style
//====================================================================
========
/*
* C++ Program to Implement Doubly Linked List
*/
#include
#include
#include
/*
* Node Declaration
*/
using namespace std;
// struct declaration for node which will hold the integer data with links to previous data and next
data
struct node
{
int data;
struct node *next;
struct node *prev;
};
/*
Class Declaration
*/
class DoublyLinkedList
{
private:
struct node *start; // collection of all the nodes
public:
void create(int value);
int peek();
int delete_head();
void display();
int count();
void mergeSort(DoublyLinkedList list1, DoublyLinkedList list2);
DoublyLinkedList()
{
start = NULL;
}
};
/*
* Add data into the list
*/
void DoublyLinkedList::create(int value)
{
struct node *s, *temp;
temp = new(struct node);
temp->data = value;
temp->next = NULL;
if (start == NULL)
{
temp->prev = NULL;
start = temp;
}
else
{
s = start;
while (s->next != NULL)
s = s->next;
s->next = temp;
temp->prev = s;
}
}
/*
* Deletion of the first element from the list
* store the first element in a temp node and then remove it from start.
*/
int DoublyLinkedList::delete_head()
{
struct node *tmp, *q;
int value;
tmp = start;
if(start->next!=NULL)
{
start = start->next;
start->prev = NULL;
}
else
start = NULL;
value = tmp->data;
free(tmp);
return value;
}
/*
* return the first element of Doubly Link List
*/
int DoublyLinkedList::peek()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
}
}
/*
* Display elements of Doubly Link List
*/
void DoublyLinkedList::display()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
q = q->next;
if(q != NULL)
{
cout<<\", \";
}
}
cout<<\"]\"<next;
cnt++;
}
return cnt;
}
/*
* MergeSort - takes two input lists and then based on the.
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Dividing a linked list into two sublists of almost equal sizesa. A.pdf
Dividing a linked list into two sublists of almost equal sizes
a. Add the operation divideMid to the class linkedListType as follows:
Consider the following statements:
unorderedLinkedList myList;
unorderedLinkedList subList;
Suppose myList points to the list with elements 34 65 27 89 12 (in this order). The statement:
myList.divideMid(subList); divides myList into two sublists: myList points to the list with the
elements 34 65 27,
and subList points to the sublist with the elements 89 12.
b. Write the definition of the function template to implement the operation divideMid. Also,
write a program to test your function. The header files linkedList.h and unorderedLinkedList.h
are supplied. Your test program should produce output similar to this:
Turn in:
linkedList.h with modifications
Your test program.
(C++)
Required code is below:
#ifndef H_UnorderedLinkedList
#define H_UnorderedLinkedList
#include \"linkedList.h\"
using namespace std;
template
class unorderedLinkedList: public linkedListType
{
public:
bool search(const Type& searchItem) const;
//Function to determine whether searchItem is in the list.
//Postcondition: Returns true if searchItem is in the
// list, otherwise the value false is
// returned.
void insertFirst(const Type& newItem);
//Function to insert newItem at the beginning of the list.
//Postcondition: first points to the new list, newItem is
// inserted at the beginning of the list,
// last points to the last node in the
// list, and count is incremented by 1.
void insertLast(const Type& newItem);
//Function to insert newItem at the end of the list.
//Postcondition: first points to the new list, newItem
// is inserted at the end of the list,
// last points to the last node in the
// list, and count is incremented by 1.
void deleteNode(const Type& deleteItem);
//Function to delete deleteItem from the list.
//Postcondition: If found, the node containing
// deleteItem is deleted from the list.
// first points to the first node, last
// points to the last node of the updated
// list, and count is decremented by 1.
};
template
bool unorderedLinkedList::
search(const Type& searchItem) const
{
nodeType *current; //pointer to traverse the list
bool found = false;
current = this->first; //set current to point to the first
//node in the list
while (current != NULL && !found) //search the list
if (current->info == searchItem) //searchItem is found
found = true;
else
current = current->link; //make current point to
//the next node
return found;
}//end search
template
void unorderedLinkedList::insertFirst(const Type& newItem)
{
nodeType *newNode; //pointer to create the new node
newNode = new nodeType; //create the new node
newNode->info = newItem; //store the new item in the node
newNode->link = this->first; //insert newNode before first
this->first = newNode; //make first point to the
//actual first node
this->count++; //increment count
if (this->last == NULL) //if the list was empty, newNode is also
//the last node in the list
this->l.
C++ problemPart 1 Recursive Print (40 pts)Please write the recu.pdf
C++ problem
Part 1: Recursive Print (40 pts)
Please write the recursive List reverse print function, whose iterative version we wrote in class.
Below are the function signatures for the functions you are going to need:
public:
/**Additional Operations*/
void print_reverse();
//Wrapper function that calls the reverse helper function to print a list in reverse
//prints nothing if the List is empty
private:
void reverse(Nodeptr node);
//Helper function for the public printReverse() function.
//Recursively prints the data in a List in reverse.
Why do we need the private helper function here?
Since we are going to be reversing our list node by node, in a recursive fashion, we want to pass
a one node at a time to our reverse function.
However, since our nodes are private, we cannot access them if we call the function inside of
main.
Add these function signatures to your List.h file along with your other function prototypes inside
the class definition.
Make sure that you place the reverse function inside the private portion of your List class
definition and the print_reverse function prototype to the public portion of your List class
definition.
Now, implement these two functions inside of List.h, under your section for additional
operations.
Important: Test each function carefully inside of your ListTest.cpp to make sure that it is
working properly.
Part 2: Adding an Index to Your List Nodes (20 pts)
Next, you will add the following functions to your List.h
/**Accessor Functions*/
int get_index();
//Indicates the index of the Node where the iterator is currently pointing
//Nodes are numbered from 1 to length of the list
//Pre: length != 0
//Pre: !off_end()
...
int List::get_index()
{
//Implement the function here
}
/**Manipulation Procedures*/
void scroll_to_index(int index);
//Moves the iterator to the node whose index is specified by the user
//Pre: length != 0
...
void scroll_to_index(int index)
{
//Implement function here
}
Part 3: Implementing Search as Part of Your List (40 pts)
Now, we are going to add two search functions to our List so that we can search for elements in
our List.
The first of these functions is going to be a simple linear search function.
You will need to add the following function prototype and function definition to your List.h:
/**Additional Operations*/
int linear_search(listitem item);
//Searchs the list, element by element, from the start of the List to the end of the List
//Returns the index of the element, if it is found in the List
//Returns -1 if the element is not in the List
//Pre: length != 0
...
int List::linear_search(listitem item)
{
//Implement the function here
}
You are also going to add a function to perform recursive binary search on your List.
You will need to add the following function prototype and function definition to your List.h:
int binary_search(int low, int high, listitem item);
//Recursively searchs the list by dividing the search space in half
//Returns the index of the element, if it is fo.
STAGE 2 The Methods 65 points Implement all the methods t.pdf
STAGE 2: The Methods (65 points) Implement all the methods that are marked as Left as
Exercise. The Driver program only works when you have done all the methods. I have added the
template of all the methods with a placeholder value as return types of the methods. For example,
return 0 if method returns an int value.
List of the methods left as exercise are as follows: /** Create a list from an array of objects */
@SuppressWarnings("unchecked") public MyLinkedList(E[] objects) /** Add a new element at the
specified index in this list in ascending order */ public void addInOrder(E e) /** Check to see if this
list contains element e */ public boolean contains(E e) /** Remove all the occurrences of the
element e * from this list. Return true if the element is * removed. */ public boolean removeAll(E e)
/** Remove the first occurrence of the element e * from this list. Return true if the element is *
removed. */ public boolean remove(E e) /** Return the element at the specified index */ public E
get(int index) /** Return the index of the head matching element in * this list. Return -1 if no match.
*/ public int indexOf(Object e) /** Return the index of the last matching element in * this list. Return
-1 if no match. */ public int lastIndexOf(E e) /** Replace the element at the specified position * in
this list with the specified element. */ public E set(int index, E e) /** Print this list using recursion */
public void printList() /** Returns an array containing all of the elements * in this collection; * the
runtime type of the returned array is that of * the specified array. */ public <E> E[] toArray(E[]
array) /** Split the original list in half. The original * list will continue to reference the * front half of
the original list and the method * returns a reference to a new list that stores the * back half of the
original list.
public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Incr.
Hi,I have added the methods and main class as per your requirement.pdf
Hi,
I have added the methods and main class as per your requirement. it is working fine now.
Highlighted the code changes.
MyLinkedListTest.java
public class MyLinkedListTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
MyLinkedList list = new MyLinkedList();
list.addFirst(\"AAAAA\");
list.add(\"1\");
list.add(\"2\");
list.add(\"3\");
list.addLast(\"ZZZZZ\");
System.out.println(\"Linked List Elements : \"+list.toString());
System.out.println(\"First element: \"+list.getFirst());
System.out.println(\"Second element: \"+list.getLast());
System.out.println(\"Removed First Element: \"+list.removeFirst());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed Last Element: \"+list.removeLast());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed all element: \");
list.removeAll();
System.out.println(\"Now Linked List Elements : \"+list.toString());
}
}
MyLinkedList.java
public class MyLinkedList extends MyAbstractList {
private Node head, tail;
/** Create a default list */
public MyLinkedList() {
}
/** Create a list from an array of objects */
public MyLinkedList(E[] objects) {
super(objects);
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return (E)head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return (E)tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node newNode = new Node(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node newNode = new Node(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
/** Add a new element at the specified index in this list
* The index of the head element is 0 */
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node temp = current.next;
current.next = new Node(e);
(current.next).next = temp;
size++;
}
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
Node temp = head;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return (E)temp.element;
}
}
/** Remove all elements from list */
public void removeAll() {
while(true) {
if (size == 0) {
break;
}
else {
Node temp = head;
head =.
Write a Java Class to Implement a Generic Linked ListYour list mus.pdf
Write a Java Class to Implement a Generic Linked List
Your list must be implemented as a singly-linked list of generic nodes, where each Node object
has two instance variables: an object of the “type variable” class, and a pointer to the next node
on the list.
Your class will contain separate methods to handle each of the operations read from a data file
(see II., below)
Your class will also override toString() to return the objects on the list in the order in which they
occur.
Write a Test Class for Your LinkedList Class
Your main method will read list operation instructions from a data file, until end-of-file and call
the appropriate LinkedList method to execute each one.
After each operation is executed, print out the operation and the updated list.
The data file to be used is on the class web site and the operations are:
APPEND X - Append object X to the end of the list
ADD N X - Insert object X as the new Nth element in the list, increasing the size of the list by 1
E.g. Suppose the list is:
head -> 1 -> 2 -> 3 -> 4->null
After ADD 3 7 it would be:
head -> 1 -> 2 -> 7 -> 3 -> 4->null
DELETE N – Remove the Nth object from the list
SWAP M N - Interchange the positions of the Mth and Nth
objects on the list
For credit, the two nodes must actually \"trade places\" in the list, and not merely swap their data
values
REVERSE - Reverse the order of the objects on the list
This must be done by reversing the order of the nodes themselves, rather than by swapping the
data stored
To get credit for your reverse() method, it must use either one of these 2 algorithms:
For each node on the list except the current “head”
node, delete the node and insert it as the new head
Use your swap() method
6. CLEAR – Clear the list (make it empty)
No credit will be given for programs that use any additional data structures – either from the Java
API or programmer defined -, other than your own LinkedList class
txt file:
Solution
//Java Program to Implement Singly Linked List
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
/* Class Node */
class Nodes
{
protected Object data;
protected Nodes next;
/* Constructor */
public Nodes()
{
next = null;
data = null;
}
/* Constructor */
public Nodes(Object d,Nodes n)
{
data = d;
next = n;
}
/* Function to set link to next Node */
public void setLink(Nodes n)
{
next = n;
}
/* Function to set data to current Node */
public void setData(Object d)
{
data = d;
}
/* Function to get link to next node */
public Nodes getLink()
{
return next;
}
/* Function to get data from current Node */
public Object getData()
{
return data;
}
}
/* Class linkedList */
class linkList
{
protected Nodes start;
protected Nodes end ;
public int size ;
/* Constructor */
public linkList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isEmpty()
{
return start == null;
}
/* Function to get size of list */
public int getSize()
{
return .
Given below is the completed implementation of MyLinkedList class. O.pdf
Given below is the completed implementation of MyLinkedList class. Other classes are not
modified and remain same as in question - MyList, MyAbstractList, TestMyLinkedList.
The output of TestMyLinkedList is shown below. Please don\'t forget to rate the answer if it
helped. Thank you very much.
Since the MyList is not completely pasted in the question ... giving the complete class file below
MyList.java
public interface MyList> extends java.lang.Iterable
{
// Add a new element at the end of this list
public void add (E e);
// Add a new element at specified index in this list
public void add (int index, E e);
// Return true if this list contains the element
public boolean contains (E e);
// Return the element at the specified index
public E get (int index);
// Return the index of the first matching element
// Return -1 if no match.
public int indexOf (E e);
// Return the index of the last matching element
// Return -1 if no match.
public int lastIndexOf (E e);
E remove(int index);
void clear();
E set(int index, E e);
}
MyLinkedList.java
public class MyLinkedList> extends MyAbstractList
implements Comparable>
{
private Node head, tail; // head and tail pointers
// Create a default list
public MyLinkedList()
{
}
public int size()
{
return size;
}
// Need this for implementing Comparable
public int compareTo (MyLinkedList e)
{
return(size() - e.size());
}
// Create a list from an array of objects
public MyLinkedList (E[] objects)
{
super(objects); // Passes the array up to abstract parent
}
// Return the head element in the list
public E getFirst()
{
if (size == 0)
{
return null;
}
else
{
return head.element;
}
}
// Return the last element in the list
public E getLast()
{
if (size == 0)
{
return null;
}
else
{
return tail.element;
}
}
// Add an element to the beginning of the list
public void addFirst (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // new node is only node
{
tail = head;
}
}
// Add an element to the end of the list
public void addLast (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
if (tail == null)
{
head = tail = newNode; // new node is only node
}
else
{
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
// Remove the head node and
// return the object from the removed node
public E removeFirst()
{
if (size == 0)
{
return null;
}
else
{
Node temp = head;
head = head.next;
size--;
if (head == null)
{
tail = null;
}
return temp.element;
}
}
// Remove the last node and return the object from it
public E removeLast()
{
if (size == 0)
{
return null;
}
else if (size == 1)
{
Node temp = head;
head = tail = null;
size = 0;
return temp.element;
}
else
{
Node current = head;
for (int i = 0; i < size - 2; i++)
{
current = current.next;
}
Node temp = tail;
tai.
Using the provided table interface table.h and the sample linked lis.pdf
Using the provided table interface table.h and the sample linked list code linkedList.c, complete
an implementation of the Table ADT. Make sure that you apply the concepts of design by
contract (DbC) to your implementation.
Once you have fully implemented the table, create a main.c file that implements a testing
framework for your table.
Your table implementation must ensure that values inserted are unique, and internally sorted
within a linked list.
table.h
linkedList.c
Solution
khsdg
#include
#include
typedef enum BOOL { false, true } bool;
// Linked list node definition
typedef struct Node node;
struct Node
{
int number;
node *next;
};
static node *top = NULL;
// used to track where we are for the list traversal methods
static node *traverseNode = NULL;
// \"destroy\" will deallocate all nodes in a linked list object
// and will set \"top\" to NULL.
void destroy()
{
node *curr = top;
node *temp = NULL;
while ( curr != NULL )
{
// flip order to see it blow up...
temp = curr;
curr = curr->next;
free( temp );
}
top = NULL;
}
// \"build\" will create an ordered linked list consisting
// of the first \"size\" even integers.
void build( int size )
{
node *newNode = NULL;
int i = 0;
// make sure we don\'t have a list yet
destroy();
for ( i=size ; i>0 ; i-- )
{
newNode = malloc( sizeof( node ) );
newNode->number = i*2;
newNode->next = top;
top = newNode;
}
}
// starts a list traversal by getting the data at top.
// returns false if top == NULL.
bool firstNode( int *item )
{
bool result = false;
if ( top )
{
*item = top->number;
traverseNode = top->next;
result = true;
}
return result;
}
// gets the data at the current traversal node and increments the traversal.
// returns false if we\'re at the end of the list.
bool nextNode( int *item )
{
bool result = false;
if ( traverseNode )
{
*item = traverseNode->number;
traverseNode = traverseNode->next;
result = true;
}
return result;
}
// \"print\" will output an object\'s entire linked list
// to the standard output device -- one \"number\" per line.
void print()
{
int value;
if ( firstNode( &value ) )
{
do
{
printf( \"%d\ \", value );
} while ( nextNode( &value ) );
}
}
int main( int argc, char *argv[] )
{
build( 10 );
print();
destroy();
build( 5 );
build( 20 );
print();
destroy();
return 0;
}.
C Homework Help
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To complete the task, you need to fill in the missing code. I’ve inc.pdf
To complete the task, you need to fill in the missing code. I’ve included code to create an
Iterator. An Iterator is an object that iterates over another object – in this case, a circular linked
list. You can use the .next() method to advance the Iterator to the next item (the first time you
call it, the iterator will travel to node at index 0). Using iterator’s .remove() removes the node the
iterator is currently at. Say that we had a CircularLinkedList that looked like this: A ==> B ==>
C ==> D ==> E ==> Calling .next() three times will advance the iterator to index 2. Calling
.remove() once will remove the node at index 2. A ==> B ==> D ==> E ==> Calling .remove()
once more will remove the node now at index 2. A ==> B ==> E ==> The Iterator methods
handle wrapping around the CircularLinkedList. Be sure to create the iterator using l.iterator()
and after you’ve added all the nodes to the list, where l is your CircularLinkedList
Solution
import java.util.Iterator;
class CircularLinkedList implements Iterable {
// Your variables
// You can include a reference to a tail if you want
Node head;
int size; // BE SURE TO KEEP TRACK OF THE SIZE
// implement this constructor
public CircularLinkedList() {
head=null;
}
// writing helper functions for add and remove, like the book did can help
// but remember, the last element\'s next node will be the head!
// attach a node to the end of the list
// Be sure to handle the adding to an empty list
// always returns true
public boolean add(E e) {
Node newNode=new Node(e);
if(size==0){
head=newNode;
}
else{
Node last=getNode(size-1);
last.next=newNode;
}
newNode.next=head; //last element node is set to head
size++;
return true;
}
// need to handle
// out of bounds
// empty list
// adding to front
// adding to middle
// adding to \"end\"
// REMEMBER TO INCREMENT THE SIZE
public boolean add(int index, E e){
if(index>size) return false;
Node tmp=new Node(e);
if(index==0){
tmp.next=head;
Node last=getNode(size-1);
head=tmp;
last.next=head;
}
else {
Node curr=getNode(index-1);
tmp.next=curr.next;
curr.next=tmp;
}
size++;
return true;
}
// I highly recommend using this helper method
// Return Node found at the specified index
// be sure to handle out of bounds cases
private Node getNode(int index ) {
Node prev=head;
for(int i=0;isize) {
e=null;
}
else if(index==0){
e = head.getElement();
Node last=getNode(size-1);
head=head.next;
last.next=head;
size--;
}
else{
Node prev=getNode(index-1);
Node curr=getNode(index);
e=curr.getElement();
prev.next=curr.next;
size--;
}
return e;
}
// Turns your list into a string
// Useful for debugging
public String toString(){
Node current = head;
StringBuilder result = new StringBuilder();
if(size == 0){
return \"\";
}
if(size == 1) {
return head.getElement().toString();
}
else{
do{
result.append(current.getElement());
result.append(\" ==> \");
current = current.next;
} while(current != head);
}
return result.toString();
}
public Iterator iterator() {
return new ListIterator();
}
/.
Node file code below#ifndef NODE_H#define NODE_H#include .pdf
Node file code below
#ifndef NODE_H
#define NODE_H
#include
using namespace std;
// the node
class Node{
public:
int value;
// Array of pointers to the next nodes (which may be located at various levels)
// next[i] is the next link for level i
// the size of this vector determines the number of levels that the current node is part of
vector next;
vector prev; // previous links for each level the node is part of
Node(int val, int level){
value = val;
next = vector(level+1, nullptr); // initialize array of pointers to nulls
prev = vector(level+1, nullptr); // initialize array of pointers to nulls
};
};
#endif
SKIPLIST.H FILE CODE BELOW
#include
#include
#include
#include
#include
#include
#include "Node.h"
#ifndef SKIPLIST_H
#define SKIPLIST_H
using namespace std;
class SkipList{
public:
// Maximum allowed level index
int MAXIMUM_ALLOWED_LEVEL_INDEX;
// current maximum level amongst the inserted nodes
int currentHighestLevelIndex;
// the head node's next links are connected to the first node at every level
Node *head;
Node* tail; // last node at every level
SkipList(int maxLevels){
MAXIMUM_ALLOWED_LEVEL_INDEX = maxLevels;
// initially we have the bottom-most level only
currentHighestLevelIndex = 0;
// create the header node, value is irrelevant (as long as it doesn't match an inserted value -
NO REPEATS), number of next links is important (initially this node is the first node at every
level)
head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVEL_INDEX);
tail = new Node(INT_MAX, MAXIMUM_ALLOWED_LEVEL_INDEX); // last nodes at
each level
// connect head to tail at every level
for(int i = 0; i <= MAXIMUM_ALLOWED_LEVEL_INDEX; i++){
head->next[i] = tail; // head's prev is null
tail->prev[i] = head; // tail's next is null
}
}
int RandomLevel(){
float probablity = (float)rand()/RAND_MAX; // flip a coin
int lvl = 0;
while (probablity < 0.5 && lvl < MAXIMUM_ALLOWED_LEVEL_INDEX){
lvl++; // landed heads so increase level by 1
probablity = (float)rand()/RAND_MAX; // flip a coin again
}
return lvl;
}
Node* CreateNode(int value, int level){
// create a new node with next links for every level that this node will be part of
// it will use these links to connect to the next node at each level
return new Node(value, level);
}
void InsertElement(int value){
Node *current = head; // start at head node
vector update(MAXIMUM_ALLOWED_LEVEL_INDEX+1, nullptr); // this will hold the
nodes that need updating at every level after the insert takes place
for (int i = currentHighestLevelIndex; i >= 0; i--){ // start at the highest level and move
down so that more nodes may be skipped
// for level i, if value is to be inserted here then find out where (i.e. after which node)
while (current->next[i] != nullptr && current->next[i]->value < value){
current = current->next[i];
}
// found the node after which the value is to be placed at level i
update[i] = current;
// move down a level, if possible
}
// at level 0, where current is pointing to by the end of the preceding loop, move over.
Here is selection filepublic class Selection { public static in.pdf
Here is selection file:
public class Selection { public static int select(int[] array, int n, int k)
{ return select(array, 0, n - 1, k); }
private static int select(int[] array, int left, int right, int k) { // complete this function } }
here is MedianOfMedians file:
public class MedianOfMedians { private static void insertionSort(int[] arr, int left, int right)
{ for (int i = left + 1; i <= right; i++) {
int j = i, temp = arr[j];
while (j > left && temp < arr[j - 1])
{ arr[j] = arr[j - 1];
j--; }
arr[j] = temp;
}
}
public static int select(int[] array, int n, int k) { return select(array, 0, n - 1, k); }
private static int select(int[] array, int left, int right, int k) { // complete this function
} }
here is Partition file needed to code this correctly
public class Partition {
static Random rand = new Random(System.currentTimeMillis());
protected static void swap(int[] array, int x, int y) { int temp = array[x];
array[x] = array[y];
array[y] = temp; }
public static int generateRandomPivot(int[] array, int left, int right)
{ return left + rand.nextInt(right - left + 1); }
public static int generateMedianOf3Pivot(int[] array, int left, int right) {
int mid = left + (right - left) / 2;
if (array[left] > array[mid]) swap(array, left, mid);
if (array[left] > array[right]) swap(array, left, right);
if (array[mid] > array[right]) swap(array, mid, right); return mid; }
public static int[] partition(int[] array, int left, int right, int pivotIndex) { // complete this
function } } 1.2 Part 2: Selection Algorithms In the second part, you are going to implement the
Selection algorithm for finding the kth smallest number in an array. For the pivot, you are going
to use a random one. Your task is to implement the following: - Quick-Selection Algorithm (File:
Selection) Implement select(int [] array, int left, int right, int k). For pivot generation, call the
function generateRandomPivot(int [] array, int left, int right). Since partition returns two indexes,
you must the appropriate quick-select algorithm from the notes that utilizes both the indexes. -
Median of Medians Algorithm (File: MedianOfMedians) Implement select(int [] array, int left,
int right, int k). Since partition returns two indexes, you must modify the median of medians
quick-select algorithm from the notes to utilize both the indexes - this modification is simple
(essentially copy and paste the final recursive part) if you have completed the randomized quick-
select.
- Partition Algorithm (File: Partition) Implement partition(int [] array, int left, int right, int
pivotIndex) using the partition method in notes that returns two indexes lower PartitionIndex and
upper PartitionIndex. Your code must satisfy all the criteria of a partition - linear time and in-
place. Additionally, it must scan the array no more than once. Otherwise, no credits will be
given..
Help me with these multiple-choice questions. Please dont use chat .pdf
Help me with these multiple-choice questions. Please don't use chat GPT. 8) Which of the
following are properties of relations? A) Each attribute has the same name. B) No two rows in a
relation are identical. C) There are multivalued attributes in a relation. D) All columns are
numeric. 9) The entity integrity rule states that: A) no primary key attribute can be null. B)
referential integrity must be maintained across all entities. C) each entity must have a primary
key. D) a primary key must have only one attribute. 10) The states that no primary key attribute
may be null. A) referential integrity constraint B) entity integrity rule C) partial specialization
rule D) range domain rule
11) An Internal schema describes the A) high-level description of the whole database B) views
of different user groups C) physical storage structures of the database D) none of the above 12)
A data manipulation language is used for A) specifying how primary and candidate keys should
be created B) specifying database retrievals and updates C) specifying database conceptual
schemas D) specifying user views and storage structures E) none of the above 13) In
Client/Server architecture, the middle tier is used to A) run application programs and storing
business rules B) implement graphical user interfaces of a web application C) access data from
the databases D) none of the above.
More Related Content
Similar to Im creating a skip list program for my Algorithms and Advanced Data.pdf
double linked list header file code#include iostream#include.pdf
double linked list header file code
#include
#include
#include
#include
#ifndef DOUBLYSKIPLIST_H
#define DOUBLYSKIPLIST_H
using namespace std;
class Node {
public:
int value;
int level;
vector next;
vector prev;
Node(int val, int lvl) : value(val), level(lvl) {
next.resize(lvl + 1, nullptr);
prev.resize(lvl + 1, nullptr);
}
};
class SkipList {
public:
int level;
Node* head;
Node* tail;
int MAXIMUM_ALLOWED_LEVELS;
SkipList(int maxLevels) : MAXIMUM_ALLOWED_LEVELS(maxLevels), level(0) {
head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVELS);
tail = new Node(INT_MAX, MAXIMUM_ALLOWED_LEVELS);
for (int i = 0; i <= MAXIMUM_ALLOWED_LEVELS; i++) {
head->next[i] = tail;
tail->prev[i] = head;
}
}
int RandomLevel() {
float probability = (float)rand() / RAND_MAX;
int lvl = 0;
while (probability < 0.5 && lvl < MAXIMUM_ALLOWED_LEVELS) {
lvl++;
probability = (float)rand() / RAND_MAX;
}
return lvl;
}
Node* CreateNode(int value, int level) {
return new Node(value, level);
}
void InsertElement(int value) {
Node* current = head;
vector update(MAXIMUM_ALLOWED_LEVELS + 1, nullptr);
for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {
current = current->next[i];
}
update[i] = current;
}
current = current->next[0];
if (current->value != value) {
int ranLevel = RandomLevel();
if (ranLevel > level) {
for (int i = level + 1; i <= ranLevel; i++) {
update[i] = head;
}
level = ranLevel;
}
Node* n = CreateNode(value, ranLevel);
for (int i = 0; i <= ranLevel; i++) {
n->next[i] = update[i]->next[i];
n->prev[i] = update[i];
update[i]->next[i]->prev[i] = n;
update[i]->next[i] = n;
}
}
}
void Delete(int value) {
if (!Search(value)) {
cout << value << " does not exist" << endl;
return;
}
Node* current = head;
vector update(MAXIMUM_ALLOWED_LEVELS + 1, nullptr);
for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {
current = current->next[i];
}
update[i] = current;
}
current = current->next[0];
for (int i = 0; i <= level; i++) {
if (update[i]->next[i] == current) {
update[i]->next[i] = current->next[i];
current->next[i]->prev[i] = update[i];
}
}
delete current;
}
bool Search(int value) {
Node* current = head;
for (int i = level; i >= 0; i--) {
while (current->next[i]->value < value) {
current = current->next[i];
}
}
current = current->next[0];
return current->value == value;
}
void Show() {
for (int i = 0; i <= level; i++) {
Node* node = head->next[i];
cout << "Level " << i << ": ";
while (node != tail) {
cout << node->value << " -> ";
node = node->next[i];
}
cout << "Tail" << endl;
}
}
void ShowBackwards() {
Node* currTail = tail;
for (int i = 0; i <= level; i++) {
Node* node = currTail->prev[i];
cout << "Level " << i << ": ";
while (node != head) {
cout << node->value << " <- ";
node = node->prev[i];
}
cout << "Head" << endl;
}
}
};
#endif
Priority Queue header file code
#ifndef PRIORITYQ_H
#define PRIORITYQ_H
#include
#include
#include // for INT_MAX
#include // for rand()
#include
#include "doublySkiplist.h"
using namespace std;
class N.
This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a sequential
non contiguous and dynamic datastructure called LinkedList. A linked list object is
a container consisting of connected ListNode objects. As before, we are not going
to use pre-fabricated classes from the c++ library, but construct the LinkedList
ADT from scratch.
The first step is construction and testing of the ListNode class. A ListNode object
contains a data field and a pointer to the next ListNode object (note the recursive
definition).
#This assignment requires you to
1. Read the Assignment 4 Notes
2. Watch the Assignment 4 Support video
3. Implement the following methods of the ListNode class
-custom constructor
-setters for next pointer and data
4. Implement the insert and remove method in the main program
5. Scan the given template to find the above //TODO and implement the code
needed
//TODO in ListNodecpp.h file
public: ListNode(T idata, ListNode<T> * newNext);
public: void setNext(ListNode<T> * newNext);
public: void setData(T newData);
// TODO in main program
void remove(ListNode<int> * &front,int value)
void insert(ListNode<int> * &front,int value)
# The driver is given ListNodeMain.cpp is given to you that does the following
tests
1. Declares a pointer called front to point to a ListNode of datatype integer
2. Constructs four ListNodes with data 1,2,4 and adds them to form a linked
list.
3. Inserts ListNode with data 3 to the list
4. Removes node 1 and adds it back to test removing and adding the first
element
5. Removes node 3 to test removing a middle node
6. Removes node 4 to test removing the last node
7. Attempt to remove a non existent node
8. Remove all existing nodes to empty the list
9. Insert node 4 and then node 1 to test if insertions preserve order
10.Print the list
Main.cpp
#include <iostream>
#include "ListNodecpp.h"
// REMEMBER each ListNode has two parts : a data field
// and an address field. The address is either null or points to the next node
//in the chain
//Requires: integer value for searching, address of front
//Effects: traverses the list node chain starting from front until the end comparing search value
with listnode getData. Returns the original search value if found, if not adds +1 to indicate not
found
//Modifies: Nothing
int search(ListNode<int> * front, int value);
//Requires: integer value for inserting, address of front
//Effects: creates a new ListNode with value and inserts in proper position (increasing order)in
the chain. If chain is empty, adds to the beginning
//Modifies: front, if node is added at the beginning.
//Also changes the next pointer of the previous node to point to the
//newly inserted list node. the next pointer of the newly inserted pointer
//points to what was the next of the previous node.
//This way both previous and current links are adjusted
//******** NOTE the use of & in passing pointer to front as parameter -
// Why do you think this is needed ?**********
void insert(ListNode<int> * &fr.
In the class we extensively discussed a generic singly linked list i.pdf
In the class we extensively discussed a generic singly linked list implemented as a node class.
Implement a generic node class called DoublyNode in which each node contains an element of
type E and each node is linked not only forward to the next element in the list but also backward
to the previous element in the list. Your implementation should adapt and implement all the
methods of generic Node including the following methods:
Constructor for DoublyNode
addNodeAfter, removeNodeAfter
getData, setData
getForeLink, setForeLink
getBackLink, setBackLink
listCopy
listCopyWithTail
listLength
listPart
listPosition
listSearch
Solution
import java.util.ListIterator;
import java.util.NoSuchElementException;
import java.util.Random;
public class DoublyNode {
private Node head;
private Node tail;
private int size;
public DoublyNode() {
size = 0;
}
private class Node {
E element;
Node getForeNode;
Node getBackNode;
public Node(E element, Node next, Node prev) {
this.element = element;
this.getForeNode = next;
this.getBackNode = prev;
}
}
public int listLength() { return size; }
public boolean isEmpty() { return size == 0; }
public void addFirst(E element) {
Node tmp = new Node(element, head, null);
if(head != null ) {head.getBackNode = tmp;}
head = tmp;
if(tail == null) { tail = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfter(E element) {
Node tmp = new Node(element, null, tail);
if(tail != null) {tail.getForeNode = tmp;}
tail = tmp;
if(head == null) { head = tmp;}
size++;
System.out.println(\"adding: \"+element);
}
public void addNodeAfterSpecifiedNode(E element, E tobeAddedAfter) {
Node prevTobeAddedAfter = listSearch(element);
Node afterNode = prevTobeAddedAfter.getForeNode;
Node tmpNode = new Node(element,prevTobeAddedAfter,afterNode);
tmpNode = prevTobeAddedAfter.getForeNode;
afterNode = tmpNode.getForeNode;
}
public void listCopy(){
System.out.println(\"iterating forward..\");
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getForeNode;
}
}
public Node listSearch(E item){
System.out.println(\"Searching Item \"+item);
Node tmp = head;
while(tmp != null){
System.out.println(tmp.element);
if(tmp.element == item) {
System.out.println(\"Item found \"+item);
return tmp;
}
tmp = tmp.getForeNode;
}
return null;
}
public void iterateBackward(){
System.out.println(\"iterating backword..\");
Node tmp = tail;
while(tmp != null){
System.out.println(tmp.element);
tmp = tmp.getBackNode;
}
}
public E removeFirst() {
if (size == 0) throw new NoSuchElementException();
Node tmp = head;
head = head.getForeNode;
head.getBackNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
public E removeNodeAfter() {
if (size == 0) throw new NoSuchElementException();
Node tmp = tail;
tail = tail.getBackNode;
tail.getForeNode = null;
size--;
System.out.println(\"deleted: \"+tmp.element);
return tmp.element;
}
}.
Write a function to merge two doubly linked lists. The input lists ha.pdf
Write a function to merge two doubly linked lists. The input lists have their elements in sorted
order, from lowest to highest. The output list should also be sorted from lowest to highest. Your
algorithm should run in linear time on the length of the output list. Provide an algorithm for your
function Implement and show some samples of your running function
Solution
The algorithm for LinkedList MergeSort is as follows.
The trick in this algorithm is to use a local list to store the value which is pointing to the actual
list to be returned as a result of the function
Step1: START
Step2: GET inputs of list1 and list2
Step3: INITIALIZE mergelist
STEP4: SET mylist = mergelist
Step5: WHILE list1 OR list2 is EMPTY
DO
IF (list1 AND list2) are NOT EMPTY
IF list1.value > list2.value
mylist.next = list2
ELSE
mylist.next = list1
ELSE IF list1 is EMPTY
mylist.next = list2
ELSE
mylist.next = list1
Step6: RETURN mergelist
Step7: STOP
Sample program for the same implemented in C++
//====================================================================
========
// Name : DoublyLinkedList.cpp
// Author : Kaju
// Version : 0.1
// Copyright : This is just an example code
// Description : MergeSort in C++, Ansi-style
//====================================================================
========
/*
* C++ Program to Implement Doubly Linked List
*/
#include
#include
#include
/*
* Node Declaration
*/
using namespace std;
// struct declaration for node which will hold the integer data with links to previous data and next
data
struct node
{
int data;
struct node *next;
struct node *prev;
};
/*
Class Declaration
*/
class DoublyLinkedList
{
private:
struct node *start; // collection of all the nodes
public:
void create(int value);
int peek();
int delete_head();
void display();
int count();
void mergeSort(DoublyLinkedList list1, DoublyLinkedList list2);
DoublyLinkedList()
{
start = NULL;
}
};
/*
* Add data into the list
*/
void DoublyLinkedList::create(int value)
{
struct node *s, *temp;
temp = new(struct node);
temp->data = value;
temp->next = NULL;
if (start == NULL)
{
temp->prev = NULL;
start = temp;
}
else
{
s = start;
while (s->next != NULL)
s = s->next;
s->next = temp;
temp->prev = s;
}
}
/*
* Deletion of the first element from the list
* store the first element in a temp node and then remove it from start.
*/
int DoublyLinkedList::delete_head()
{
struct node *tmp, *q;
int value;
tmp = start;
if(start->next!=NULL)
{
start = start->next;
start->prev = NULL;
}
else
start = NULL;
value = tmp->data;
free(tmp);
return value;
}
/*
* return the first element of Doubly Link List
*/
int DoublyLinkedList::peek()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
}
}
/*
* Display elements of Doubly Link List
*/
void DoublyLinkedList::display()
{
struct node *q;
if (start == NULL)
{
cout<<\"List is empty\"<data;
q = q->next;
if(q != NULL)
{
cout<<\", \";
}
}
cout<<\"]\"<next;
cnt++;
}
return cnt;
}
/*
* MergeSort - takes two input lists and then based on the.
C Exam Help
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Dividing a linked list into two sublists of almost equal sizesa. A.pdf
Dividing a linked list into two sublists of almost equal sizes
a. Add the operation divideMid to the class linkedListType as follows:
Consider the following statements:
unorderedLinkedList myList;
unorderedLinkedList subList;
Suppose myList points to the list with elements 34 65 27 89 12 (in this order). The statement:
myList.divideMid(subList); divides myList into two sublists: myList points to the list with the
elements 34 65 27,
and subList points to the sublist with the elements 89 12.
b. Write the definition of the function template to implement the operation divideMid. Also,
write a program to test your function. The header files linkedList.h and unorderedLinkedList.h
are supplied. Your test program should produce output similar to this:
Turn in:
linkedList.h with modifications
Your test program.
(C++)
Required code is below:
#ifndef H_UnorderedLinkedList
#define H_UnorderedLinkedList
#include \"linkedList.h\"
using namespace std;
template
class unorderedLinkedList: public linkedListType
{
public:
bool search(const Type& searchItem) const;
//Function to determine whether searchItem is in the list.
//Postcondition: Returns true if searchItem is in the
// list, otherwise the value false is
// returned.
void insertFirst(const Type& newItem);
//Function to insert newItem at the beginning of the list.
//Postcondition: first points to the new list, newItem is
// inserted at the beginning of the list,
// last points to the last node in the
// list, and count is incremented by 1.
void insertLast(const Type& newItem);
//Function to insert newItem at the end of the list.
//Postcondition: first points to the new list, newItem
// is inserted at the end of the list,
// last points to the last node in the
// list, and count is incremented by 1.
void deleteNode(const Type& deleteItem);
//Function to delete deleteItem from the list.
//Postcondition: If found, the node containing
// deleteItem is deleted from the list.
// first points to the first node, last
// points to the last node of the updated
// list, and count is decremented by 1.
};
template
bool unorderedLinkedList::
search(const Type& searchItem) const
{
nodeType *current; //pointer to traverse the list
bool found = false;
current = this->first; //set current to point to the first
//node in the list
while (current != NULL && !found) //search the list
if (current->info == searchItem) //searchItem is found
found = true;
else
current = current->link; //make current point to
//the next node
return found;
}//end search
template
void unorderedLinkedList::insertFirst(const Type& newItem)
{
nodeType *newNode; //pointer to create the new node
newNode = new nodeType; //create the new node
newNode->info = newItem; //store the new item in the node
newNode->link = this->first; //insert newNode before first
this->first = newNode; //make first point to the
//actual first node
this->count++; //increment count
if (this->last == NULL) //if the list was empty, newNode is also
//the last node in the list
this->l.
C++ problemPart 1 Recursive Print (40 pts)Please write the recu.pdf
C++ problem
Part 1: Recursive Print (40 pts)
Please write the recursive List reverse print function, whose iterative version we wrote in class.
Below are the function signatures for the functions you are going to need:
public:
/**Additional Operations*/
void print_reverse();
//Wrapper function that calls the reverse helper function to print a list in reverse
//prints nothing if the List is empty
private:
void reverse(Nodeptr node);
//Helper function for the public printReverse() function.
//Recursively prints the data in a List in reverse.
Why do we need the private helper function here?
Since we are going to be reversing our list node by node, in a recursive fashion, we want to pass
a one node at a time to our reverse function.
However, since our nodes are private, we cannot access them if we call the function inside of
main.
Add these function signatures to your List.h file along with your other function prototypes inside
the class definition.
Make sure that you place the reverse function inside the private portion of your List class
definition and the print_reverse function prototype to the public portion of your List class
definition.
Now, implement these two functions inside of List.h, under your section for additional
operations.
Important: Test each function carefully inside of your ListTest.cpp to make sure that it is
working properly.
Part 2: Adding an Index to Your List Nodes (20 pts)
Next, you will add the following functions to your List.h
/**Accessor Functions*/
int get_index();
//Indicates the index of the Node where the iterator is currently pointing
//Nodes are numbered from 1 to length of the list
//Pre: length != 0
//Pre: !off_end()
...
int List::get_index()
{
//Implement the function here
}
/**Manipulation Procedures*/
void scroll_to_index(int index);
//Moves the iterator to the node whose index is specified by the user
//Pre: length != 0
...
void scroll_to_index(int index)
{
//Implement function here
}
Part 3: Implementing Search as Part of Your List (40 pts)
Now, we are going to add two search functions to our List so that we can search for elements in
our List.
The first of these functions is going to be a simple linear search function.
You will need to add the following function prototype and function definition to your List.h:
/**Additional Operations*/
int linear_search(listitem item);
//Searchs the list, element by element, from the start of the List to the end of the List
//Returns the index of the element, if it is found in the List
//Returns -1 if the element is not in the List
//Pre: length != 0
...
int List::linear_search(listitem item)
{
//Implement the function here
}
You are also going to add a function to perform recursive binary search on your List.
You will need to add the following function prototype and function definition to your List.h:
int binary_search(int low, int high, listitem item);
//Recursively searchs the list by dividing the search space in half
//Returns the index of the element, if it is fo.
STAGE 2 The Methods 65 points Implement all the methods t.pdf
STAGE 2: The Methods (65 points) Implement all the methods that are marked as Left as
Exercise. The Driver program only works when you have done all the methods. I have added the
template of all the methods with a placeholder value as return types of the methods. For example,
return 0 if method returns an int value.
List of the methods left as exercise are as follows: /** Create a list from an array of objects */
@SuppressWarnings("unchecked") public MyLinkedList(E[] objects) /** Add a new element at the
specified index in this list in ascending order */ public void addInOrder(E e) /** Check to see if this
list contains element e */ public boolean contains(E e) /** Remove all the occurrences of the
element e * from this list. Return true if the element is * removed. */ public boolean removeAll(E e)
/** Remove the first occurrence of the element e * from this list. Return true if the element is *
removed. */ public boolean remove(E e) /** Return the element at the specified index */ public E
get(int index) /** Return the index of the head matching element in * this list. Return -1 if no match.
*/ public int indexOf(Object e) /** Return the index of the last matching element in * this list. Return
-1 if no match. */ public int lastIndexOf(E e) /** Replace the element at the specified position * in
this list with the specified element. */ public E set(int index, E e) /** Print this list using recursion */
public void printList() /** Returns an array containing all of the elements * in this collection; * the
runtime type of the returned array is that of * the specified array. */ public <E> E[] toArray(E[]
array) /** Split the original list in half. The original * list will continue to reference the * front half of
the original list and the method * returns a reference to a new list that stores the * back half of the
original list.
public class MyLinkedList<E extends Comparable<E>> {
private Node<E> head, tail;
private int size = 0; // Number of elements in the list
public MyLinkedList() {
head=tail=null;
size=0;
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node<E> newNode = new Node<>(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node<E> newNode = new Node<>(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = newNode; // tail now points to the last node
}
size++; // Incr.
Hi,I have added the methods and main class as per your requirement.pdf
Hi,
I have added the methods and main class as per your requirement. it is working fine now.
Highlighted the code changes.
MyLinkedListTest.java
public class MyLinkedListTest {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
MyLinkedList list = new MyLinkedList();
list.addFirst(\"AAAAA\");
list.add(\"1\");
list.add(\"2\");
list.add(\"3\");
list.addLast(\"ZZZZZ\");
System.out.println(\"Linked List Elements : \"+list.toString());
System.out.println(\"First element: \"+list.getFirst());
System.out.println(\"Second element: \"+list.getLast());
System.out.println(\"Removed First Element: \"+list.removeFirst());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed Last Element: \"+list.removeLast());
System.out.println(\"Now Linked List Elements : \"+list.toString());
System.out.println(\"Removed all element: \");
list.removeAll();
System.out.println(\"Now Linked List Elements : \"+list.toString());
}
}
MyLinkedList.java
public class MyLinkedList extends MyAbstractList {
private Node head, tail;
/** Create a default list */
public MyLinkedList() {
}
/** Create a list from an array of objects */
public MyLinkedList(E[] objects) {
super(objects);
}
/** Return the head element in the list */
public E getFirst() {
if (size == 0) {
return null;
}
else {
return (E)head.element;
}
}
/** Return the last element in the list */
public E getLast() {
if (size == 0) {
return null;
}
else {
return (E)tail.element;
}
}
/** Add an element to the beginning of the list */
public void addFirst(E e) {
Node newNode = new Node(e); // Create a new node
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // the new node is the only node in list
tail = head;
}
/** Add an element to the end of the list */
public void addLast(E e) {
Node newNode = new Node(e); // Create a new for element e
if (tail == null) {
head = tail = newNode; // The new node is the only node in list
}
else {
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
/** Add a new element at the specified index in this list
* The index of the head element is 0 */
public void add(int index, E e) {
if (index == 0) {
addFirst(e);
}
else if (index >= size) {
addLast(e);
}
else {
Node current = head;
for (int i = 1; i < index; i++) {
current = current.next;
}
Node temp = current.next;
current.next = new Node(e);
(current.next).next = temp;
size++;
}
}
/** Remove the head node and
* return the object that is contained in the removed node. */
public E removeFirst() {
if (size == 0) {
return null;
}
else {
Node temp = head;
head = head.next;
size--;
if (head == null) {
tail = null;
}
return (E)temp.element;
}
}
/** Remove all elements from list */
public void removeAll() {
while(true) {
if (size == 0) {
break;
}
else {
Node temp = head;
head =.
Write a Java Class to Implement a Generic Linked ListYour list mus.pdf
Write a Java Class to Implement a Generic Linked List
Your list must be implemented as a singly-linked list of generic nodes, where each Node object
has two instance variables: an object of the “type variable” class, and a pointer to the next node
on the list.
Your class will contain separate methods to handle each of the operations read from a data file
(see II., below)
Your class will also override toString() to return the objects on the list in the order in which they
occur.
Write a Test Class for Your LinkedList Class
Your main method will read list operation instructions from a data file, until end-of-file and call
the appropriate LinkedList method to execute each one.
After each operation is executed, print out the operation and the updated list.
The data file to be used is on the class web site and the operations are:
APPEND X - Append object X to the end of the list
ADD N X - Insert object X as the new Nth element in the list, increasing the size of the list by 1
E.g. Suppose the list is:
head -> 1 -> 2 -> 3 -> 4->null
After ADD 3 7 it would be:
head -> 1 -> 2 -> 7 -> 3 -> 4->null
DELETE N – Remove the Nth object from the list
SWAP M N - Interchange the positions of the Mth and Nth
objects on the list
For credit, the two nodes must actually \"trade places\" in the list, and not merely swap their data
values
REVERSE - Reverse the order of the objects on the list
This must be done by reversing the order of the nodes themselves, rather than by swapping the
data stored
To get credit for your reverse() method, it must use either one of these 2 algorithms:
For each node on the list except the current “head”
node, delete the node and insert it as the new head
Use your swap() method
6. CLEAR – Clear the list (make it empty)
No credit will be given for programs that use any additional data structures – either from the Java
API or programmer defined -, other than your own LinkedList class
txt file:
Solution
//Java Program to Implement Singly Linked List
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
/* Class Node */
class Nodes
{
protected Object data;
protected Nodes next;
/* Constructor */
public Nodes()
{
next = null;
data = null;
}
/* Constructor */
public Nodes(Object d,Nodes n)
{
data = d;
next = n;
}
/* Function to set link to next Node */
public void setLink(Nodes n)
{
next = n;
}
/* Function to set data to current Node */
public void setData(Object d)
{
data = d;
}
/* Function to get link to next node */
public Nodes getLink()
{
return next;
}
/* Function to get data from current Node */
public Object getData()
{
return data;
}
}
/* Class linkedList */
class linkList
{
protected Nodes start;
protected Nodes end ;
public int size ;
/* Constructor */
public linkList()
{
start = null;
end = null;
size = 0;
}
/* Function to check if list is empty */
public boolean isEmpty()
{
return start == null;
}
/* Function to get size of list */
public int getSize()
{
return .
Given below is the completed implementation of MyLinkedList class. O.pdf
Given below is the completed implementation of MyLinkedList class. Other classes are not
modified and remain same as in question - MyList, MyAbstractList, TestMyLinkedList.
The output of TestMyLinkedList is shown below. Please don\'t forget to rate the answer if it
helped. Thank you very much.
Since the MyList is not completely pasted in the question ... giving the complete class file below
MyList.java
public interface MyList> extends java.lang.Iterable
{
// Add a new element at the end of this list
public void add (E e);
// Add a new element at specified index in this list
public void add (int index, E e);
// Return true if this list contains the element
public boolean contains (E e);
// Return the element at the specified index
public E get (int index);
// Return the index of the first matching element
// Return -1 if no match.
public int indexOf (E e);
// Return the index of the last matching element
// Return -1 if no match.
public int lastIndexOf (E e);
E remove(int index);
void clear();
E set(int index, E e);
}
MyLinkedList.java
public class MyLinkedList> extends MyAbstractList
implements Comparable>
{
private Node head, tail; // head and tail pointers
// Create a default list
public MyLinkedList()
{
}
public int size()
{
return size;
}
// Need this for implementing Comparable
public int compareTo (MyLinkedList e)
{
return(size() - e.size());
}
// Create a list from an array of objects
public MyLinkedList (E[] objects)
{
super(objects); // Passes the array up to abstract parent
}
// Return the head element in the list
public E getFirst()
{
if (size == 0)
{
return null;
}
else
{
return head.element;
}
}
// Return the last element in the list
public E getLast()
{
if (size == 0)
{
return null;
}
else
{
return tail.element;
}
}
// Add an element to the beginning of the list
public void addFirst (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
newNode.next = head; // link the new node with the head
head = newNode; // head points to the new node
size++; // Increase list size
if (tail == null) // new node is only node
{
tail = head;
}
}
// Add an element to the end of the list
public void addLast (E e)
{
// Create a new node for element e
Node newNode = new Node(e);
if (tail == null)
{
head = tail = newNode; // new node is only node
}
else
{
tail.next = newNode; // Link the new with the last node
tail = tail.next; // tail now points to the last node
}
size++; // Increase size
}
// Remove the head node and
// return the object from the removed node
public E removeFirst()
{
if (size == 0)
{
return null;
}
else
{
Node temp = head;
head = head.next;
size--;
if (head == null)
{
tail = null;
}
return temp.element;
}
}
// Remove the last node and return the object from it
public E removeLast()
{
if (size == 0)
{
return null;
}
else if (size == 1)
{
Node temp = head;
head = tail = null;
size = 0;
return temp.element;
}
else
{
Node current = head;
for (int i = 0; i < size - 2; i++)
{
current = current.next;
}
Node temp = tail;
tai.
Using the provided table interface table.h and the sample linked lis.pdf
Using the provided table interface table.h and the sample linked list code linkedList.c, complete
an implementation of the Table ADT. Make sure that you apply the concepts of design by
contract (DbC) to your implementation.
Once you have fully implemented the table, create a main.c file that implements a testing
framework for your table.
Your table implementation must ensure that values inserted are unique, and internally sorted
within a linked list.
table.h
linkedList.c
Solution
khsdg
#include
#include
typedef enum BOOL { false, true } bool;
// Linked list node definition
typedef struct Node node;
struct Node
{
int number;
node *next;
};
static node *top = NULL;
// used to track where we are for the list traversal methods
static node *traverseNode = NULL;
// \"destroy\" will deallocate all nodes in a linked list object
// and will set \"top\" to NULL.
void destroy()
{
node *curr = top;
node *temp = NULL;
while ( curr != NULL )
{
// flip order to see it blow up...
temp = curr;
curr = curr->next;
free( temp );
}
top = NULL;
}
// \"build\" will create an ordered linked list consisting
// of the first \"size\" even integers.
void build( int size )
{
node *newNode = NULL;
int i = 0;
// make sure we don\'t have a list yet
destroy();
for ( i=size ; i>0 ; i-- )
{
newNode = malloc( sizeof( node ) );
newNode->number = i*2;
newNode->next = top;
top = newNode;
}
}
// starts a list traversal by getting the data at top.
// returns false if top == NULL.
bool firstNode( int *item )
{
bool result = false;
if ( top )
{
*item = top->number;
traverseNode = top->next;
result = true;
}
return result;
}
// gets the data at the current traversal node and increments the traversal.
// returns false if we\'re at the end of the list.
bool nextNode( int *item )
{
bool result = false;
if ( traverseNode )
{
*item = traverseNode->number;
traverseNode = traverseNode->next;
result = true;
}
return result;
}
// \"print\" will output an object\'s entire linked list
// to the standard output device -- one \"number\" per line.
void print()
{
int value;
if ( firstNode( &value ) )
{
do
{
printf( \"%d\ \", value );
} while ( nextNode( &value ) );
}
}
int main( int argc, char *argv[] )
{
build( 10 );
print();
destroy();
build( 5 );
build( 20 );
print();
destroy();
return 0;
}.
C Homework Help
I am Andrew O. I am a C Homework Expert at programminghomeworkhelp.com. I hold a master’s in Programming from, the University of Southampton, UK. I have been helping students with their homework for the past 10 years. I solve homework related to C.
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You can also call on +1 678 648 4277 for any assistance with C Homework.
To complete the task, you need to fill in the missing code. I’ve inc.pdf
To complete the task, you need to fill in the missing code. I’ve included code to create an
Iterator. An Iterator is an object that iterates over another object – in this case, a circular linked
list. You can use the .next() method to advance the Iterator to the next item (the first time you
call it, the iterator will travel to node at index 0). Using iterator’s .remove() removes the node the
iterator is currently at. Say that we had a CircularLinkedList that looked like this: A ==> B ==>
C ==> D ==> E ==> Calling .next() three times will advance the iterator to index 2. Calling
.remove() once will remove the node at index 2. A ==> B ==> D ==> E ==> Calling .remove()
once more will remove the node now at index 2. A ==> B ==> E ==> The Iterator methods
handle wrapping around the CircularLinkedList. Be sure to create the iterator using l.iterator()
and after you’ve added all the nodes to the list, where l is your CircularLinkedList
Solution
import java.util.Iterator;
class CircularLinkedList implements Iterable {
// Your variables
// You can include a reference to a tail if you want
Node head;
int size; // BE SURE TO KEEP TRACK OF THE SIZE
// implement this constructor
public CircularLinkedList() {
head=null;
}
// writing helper functions for add and remove, like the book did can help
// but remember, the last element\'s next node will be the head!
// attach a node to the end of the list
// Be sure to handle the adding to an empty list
// always returns true
public boolean add(E e) {
Node newNode=new Node(e);
if(size==0){
head=newNode;
}
else{
Node last=getNode(size-1);
last.next=newNode;
}
newNode.next=head; //last element node is set to head
size++;
return true;
}
// need to handle
// out of bounds
// empty list
// adding to front
// adding to middle
// adding to \"end\"
// REMEMBER TO INCREMENT THE SIZE
public boolean add(int index, E e){
if(index>size) return false;
Node tmp=new Node(e);
if(index==0){
tmp.next=head;
Node last=getNode(size-1);
head=tmp;
last.next=head;
}
else {
Node curr=getNode(index-1);
tmp.next=curr.next;
curr.next=tmp;
}
size++;
return true;
}
// I highly recommend using this helper method
// Return Node found at the specified index
// be sure to handle out of bounds cases
private Node getNode(int index ) {
Node prev=head;
for(int i=0;isize) {
e=null;
}
else if(index==0){
e = head.getElement();
Node last=getNode(size-1);
head=head.next;
last.next=head;
size--;
}
else{
Node prev=getNode(index-1);
Node curr=getNode(index);
e=curr.getElement();
prev.next=curr.next;
size--;
}
return e;
}
// Turns your list into a string
// Useful for debugging
public String toString(){
Node current = head;
StringBuilder result = new StringBuilder();
if(size == 0){
return \"\";
}
if(size == 1) {
return head.getElement().toString();
}
else{
do{
result.append(current.getElement());
result.append(\" ==> \");
current = current.next;
} while(current != head);
}
return result.toString();
}
public Iterator iterator() {
return new ListIterator();
}
/.
Node file code below#ifndef NODE_H#define NODE_H#include .pdf
Node file code below
#ifndef NODE_H
#define NODE_H
#include
using namespace std;
// the node
class Node{
public:
int value;
// Array of pointers to the next nodes (which may be located at various levels)
// next[i] is the next link for level i
// the size of this vector determines the number of levels that the current node is part of
vector next;
vector prev; // previous links for each level the node is part of
Node(int val, int level){
value = val;
next = vector(level+1, nullptr); // initialize array of pointers to nulls
prev = vector(level+1, nullptr); // initialize array of pointers to nulls
};
};
#endif
SKIPLIST.H FILE CODE BELOW
#include
#include
#include
#include
#include
#include
#include "Node.h"
#ifndef SKIPLIST_H
#define SKIPLIST_H
using namespace std;
class SkipList{
public:
// Maximum allowed level index
int MAXIMUM_ALLOWED_LEVEL_INDEX;
// current maximum level amongst the inserted nodes
int currentHighestLevelIndex;
// the head node's next links are connected to the first node at every level
Node *head;
Node* tail; // last node at every level
SkipList(int maxLevels){
MAXIMUM_ALLOWED_LEVEL_INDEX = maxLevels;
// initially we have the bottom-most level only
currentHighestLevelIndex = 0;
// create the header node, value is irrelevant (as long as it doesn't match an inserted value -
NO REPEATS), number of next links is important (initially this node is the first node at every
level)
head = new Node(INT_MIN, MAXIMUM_ALLOWED_LEVEL_INDEX);
tail = new Node(INT_MAX, MAXIMUM_ALLOWED_LEVEL_INDEX); // last nodes at
each level
// connect head to tail at every level
for(int i = 0; i <= MAXIMUM_ALLOWED_LEVEL_INDEX; i++){
head->next[i] = tail; // head's prev is null
tail->prev[i] = head; // tail's next is null
}
}
int RandomLevel(){
float probablity = (float)rand()/RAND_MAX; // flip a coin
int lvl = 0;
while (probablity < 0.5 && lvl < MAXIMUM_ALLOWED_LEVEL_INDEX){
lvl++; // landed heads so increase level by 1
probablity = (float)rand()/RAND_MAX; // flip a coin again
}
return lvl;
}
Node* CreateNode(int value, int level){
// create a new node with next links for every level that this node will be part of
// it will use these links to connect to the next node at each level
return new Node(value, level);
}
void InsertElement(int value){
Node *current = head; // start at head node
vector update(MAXIMUM_ALLOWED_LEVEL_INDEX+1, nullptr); // this will hold the
nodes that need updating at every level after the insert takes place
for (int i = currentHighestLevelIndex; i >= 0; i--){ // start at the highest level and move
down so that more nodes may be skipped
// for level i, if value is to be inserted here then find out where (i.e. after which node)
while (current->next[i] != nullptr && current->next[i]->value < value){
current = current->next[i];
}
// found the node after which the value is to be placed at level i
update[i] = current;
// move down a level, if possible
}
// at level 0, where current is pointing to by the end of the preceding loop, move over.
Similar to Im creating a skip list program for my Algorithms and Advanced Data.pdf (20)
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Revisiting a data structures in detail with linked list stack and queue
Revisiting a data structures in detail with linked list stack and queue
This assignment and the next (#5) involve design and development of a.pdf
This assignment and the next (#5) involve design and development of a.pdf
In the class we extensively discussed a generic singly linked list i.pdf
In the class we extensively discussed a generic singly linked list i.pdf
Write a function to merge two doubly linked lists. The input lists ha.pdf
Write a function to merge two doubly linked lists. The input lists ha.pdf
Dividing a linked list into two sublists of almost equal sizesa. A.pdf
Dividing a linked list into two sublists of almost equal sizesa. A.pdf
C++ problemPart 1 Recursive Print (40 pts)Please write the recu.pdf
C++ problemPart 1 Recursive Print (40 pts)Please write the recu.pdf
STAGE 2 The Methods 65 points Implement all the methods t.pdf
STAGE 2 The Methods 65 points Implement all the methods t.pdf
Hi,I have added the methods and main class as per your requirement.pdf
Hi,I have added the methods and main class as per your requirement.pdf
Write a Java Class to Implement a Generic Linked ListYour list mus.pdf
Write a Java Class to Implement a Generic Linked ListYour list mus.pdf
Given below is the completed implementation of MyLinkedList class. O.pdf
Given below is the completed implementation of MyLinkedList class. O.pdf
Using the provided table interface table.h and the sample linked lis.pdf
Using the provided table interface table.h and the sample linked lis.pdf
To complete the task, you need to fill in the missing code. I’ve inc.pdf
To complete the task, you need to fill in the missing code. I’ve inc.pdf
Node file code below#ifndef NODE_H#define NODE_H#include .pdf
Node file code below#ifndef NODE_H#define NODE_H#include .pdf
More from arkmuzikllc
Here is selection filepublic class Selection { public static in.pdf
Here is selection file:
public class Selection { public static int select(int[] array, int n, int k)
{ return select(array, 0, n - 1, k); }
private static int select(int[] array, int left, int right, int k) { // complete this function } }
here is MedianOfMedians file:
public class MedianOfMedians { private static void insertionSort(int[] arr, int left, int right)
{ for (int i = left + 1; i <= right; i++) {
int j = i, temp = arr[j];
while (j > left && temp < arr[j - 1])
{ arr[j] = arr[j - 1];
j--; }
arr[j] = temp;
}
}
public static int select(int[] array, int n, int k) { return select(array, 0, n - 1, k); }
private static int select(int[] array, int left, int right, int k) { // complete this function
} }
here is Partition file needed to code this correctly
public class Partition {
static Random rand = new Random(System.currentTimeMillis());
protected static void swap(int[] array, int x, int y) { int temp = array[x];
array[x] = array[y];
array[y] = temp; }
public static int generateRandomPivot(int[] array, int left, int right)
{ return left + rand.nextInt(right - left + 1); }
public static int generateMedianOf3Pivot(int[] array, int left, int right) {
int mid = left + (right - left) / 2;
if (array[left] > array[mid]) swap(array, left, mid);
if (array[left] > array[right]) swap(array, left, right);
if (array[mid] > array[right]) swap(array, mid, right); return mid; }
public static int[] partition(int[] array, int left, int right, int pivotIndex) { // complete this
function } } 1.2 Part 2: Selection Algorithms In the second part, you are going to implement the
Selection algorithm for finding the kth smallest number in an array. For the pivot, you are going
to use a random one. Your task is to implement the following: - Quick-Selection Algorithm (File:
Selection) Implement select(int [] array, int left, int right, int k). For pivot generation, call the
function generateRandomPivot(int [] array, int left, int right). Since partition returns two indexes,
you must the appropriate quick-select algorithm from the notes that utilizes both the indexes. -
Median of Medians Algorithm (File: MedianOfMedians) Implement select(int [] array, int left,
int right, int k). Since partition returns two indexes, you must modify the median of medians
quick-select algorithm from the notes to utilize both the indexes - this modification is simple
(essentially copy and paste the final recursive part) if you have completed the randomized quick-
select.
- Partition Algorithm (File: Partition) Implement partition(int [] array, int left, int right, int
pivotIndex) using the partition method in notes that returns two indexes lower PartitionIndex and
upper PartitionIndex. Your code must satisfy all the criteria of a partition - linear time and in-
place. Additionally, it must scan the array no more than once. Otherwise, no credits will be
given..
Help me with these multiple-choice questions. Please dont use chat .pdf
Help me with these multiple-choice questions. Please don't use chat GPT. 8) Which of the
following are properties of relations? A) Each attribute has the same name. B) No two rows in a
relation are identical. C) There are multivalued attributes in a relation. D) All columns are
numeric. 9) The entity integrity rule states that: A) no primary key attribute can be null. B)
referential integrity must be maintained across all entities. C) each entity must have a primary
key. D) a primary key must have only one attribute. 10) The states that no primary key attribute
may be null. A) referential integrity constraint B) entity integrity rule C) partial specialization
rule D) range domain rule
11) An Internal schema describes the A) high-level description of the whole database B) views
of different user groups C) physical storage structures of the database D) none of the above 12)
A data manipulation language is used for A) specifying how primary and candidate keys should
be created B) specifying database retrievals and updates C) specifying database conceptual
schemas D) specifying user views and storage structures E) none of the above 13) In
Client/Server architecture, the middle tier is used to A) run application programs and storing
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Hello I am stuck in my code I know is everything is goid but I think.pdf
Hello I am stuck in my code I know is everything is goid but I think I am doing something wrong
with the numbers. Help please. It's written in Coral Coding language.
Here's the question:
On a piano, a key has a frequency, say f0. Each higher key (black or white) has a frequency of
f0 * rn, where n is the distance (number of keys) from that key, and r is 2(1.0/12.0). Given an
initial key frequency, output that frequency and the next 4 higher key frequencies.
Output all frequencies with five digits after the decimal point, which can be achieved as follows:
Put frequency to output with 5 decimal places
Ex: If the input is:
440.0
(which is the A key near the middle of a piano keyboard), the output is:
440.00000 466.16376 493.88330 523.25113 554.36526
Note: Use one statement to compute r = 2(1.0/12.0) using the RaiseToPower() function. Then
use that r in subsequent statements that use the formula fn = f0 * rn with n being 1, 2, 3, and
finally 4.
Here's my code:
float r
float f0
float f1
float f2
float f3
float f4
f0 = 440.0
r = RaiseToPower(2, 1.0 / 12.0)
f1 = f0 * r
f2 = f1 * r
f3 = f2 * r
f4 = f3 * r
Put f0 to output with 5 decimal places
Put " " to output
Put f1 to output with 5 decimal places
Put " " to output
Put f2 to output with 5 decimal places
Put " " to output
Put f3 to output with 5 decimal places
Put " " to output
Put f4 to output with 5 decimal places
I know if I put 44.0 in input I get the answer my only problem is for example if I put 22. 0 I get
440.00000 466.16376 493.88330 523.25113 554.36526 but the expected output is 220.00000
233.08188 246.94165 261.62557 277.18263..
HeadWallRam Inc. has expanded its reach globally and needs to re-lay.pdf
HeadWallRam Inc. has expanded its reach globally and needs to re-layout it is IP architecture.
The executive team has hired you as a consultant to propose a greenfield network design.
Follow all the same guidlines, restrictions and provisions from Lab Report writing. Include the
following information:
Full IP documentation (not just an IP Grid).
Network Diagram from Draw.io
VyOS route configuration (i.e the "set protocols static" commands) that would be used to
impliment all route entries in all routers. ONLY include the route commands
ISP provides a single DHCP public IP address
Plan for ONE connection to the internet connected to the US site
Interior IP ranges that the company uses (172.18.128.0/17)
Plan a STAR topology for the network core between sites
Plan for networks needed for connections between sites
Plan for all pieces of equipment to be located at one of the Head-Wall-Ram sites (No routers in
space)
Think about WHY you were called in and plan for that too!
US site has five subdivisions: Sales (40 hosts), Technical (600 hosts), Support (300 hosts), Local
Management (150 hosts), Global Management (300 hosts)
China site has six subdivisions: Manufacturing (800 hosts), Sales (20 hosts), Technical (1200
hosts), Support (50 hosts), Legal (40 hosts), R&D (200 hosts)
Europe site has seven subdivisions: Manufacturing (80 hosts), Sales (20 hosts), Technical (400
hosts), Support (40 hosts), Legal (30 hosts), R&D (200 hosts), Management (10 hosts).
HINT For i = 1 , . . . ,n, let S[i] be the max sum ending with A[i].pdf
HINT: For i = 1 , . . . ,n, let S[i] be the max sum ending with A[i] while allowing size-1 gaps.
Derive a recurrence for S[i] Problem 4. Max sum with 1-gaps Given a length- n array of integers
A[1n], we would like to find maximum sum which could be obtained by adding elements in a
subsequence of A if we are allowed to start anywhere in A but once we start, we can either take
the element after the previously selected element or the one after, i.e, gaps of length at most 1 are
allowed in the subsequence. More formally, given A find the maximum S such that there is an
integer 0mn and indices 1i1<.
Hi, I need some assistance with this UML use case diagram. I manage .pdf
Hi, I need some assistance with this UML use case diagram. I manage to brainstorm on what
needs to be in diagram, but I'm unsure if what I started off with is correct. Below is an image of
what I have so far using the template:
My notes:
Actors:
Customer (Student)
- Represents the individuals who are taking driving lessons and using the DriverPass system
for online training, reservations, and interactions.
Administrator (IT Officer)
- Represents the IT officer, Ian, who has administrative privileges to manage and maintain the
system.
Secretary
- Represents the secretary responsible for managing appointments and customer interactions.
DMV (External System) - Is this a stick figure ?
- Represents the external DMV system, which provides updates and notifications related to
driving rules and policies.
Use Cases:
Login
- Allows customers, administrators, and the secretary to log into the system with their
respective credentials.
- Actors: Customer, Administrator, Secretary
Access Training Resources
- Enables customers to access online driver training resources and practice tests.
- Actors: Customer
Schedule Driving Lesson
- Allows customers to schedule on-the-go driving lessons, specifying date, time, and driver
preferences.
- Actors: Customer
Manage Appointments
- Allows customers to view, modify, or cancel their scheduled driving lesson appointments.
- Actors: Customer
Remote System Management
- Enables the administrator (IT Officer, Ian) to remotely access the system for maintenance,
updates, and adjustments.
- Actors: Administrator
Track User Activity
- Tracks user interactions and activities within the system, including reservations, changes, and
cancellations.
- Actors: Administrator
Connect to DMV - How do I show the connection between DMV and Administrator?
- Establishes a connection to the DMV external system to receive updates, notifications, and
compliance information.
- Actors: Administrator
User Registration
- Allows new customers to register on the system by providing their personal information.
- Actors: Customer
Password Reset
- Allows users (customers) to reset their password in case they forget it, using their registered
email address.
- Actors: Customer
System Reporting
- Provides access to system reports, including activity logs, reservation history, and user
statistics.
- Actors: Administrator
Do I need to show the relationships?.
Give an NFA that recognizes the language (10 + 110 + 101) and then .pdf
Give an NFA that recognizes the language (10 + 110 + 101)* and then convert it to an equivalent
DFA
A solution I had in mind was making an NFA for each subtopic, and what I had was essentially:
For 10: q0 on a 1 moves to q1, which epsilon transitions to q2, and q2 transitions to accepting
state 3 on a 1
For 110: q0 on a 1 moves to q1, which epsilon transitions to 2, and q2 transitions to q4 on input
1, q4 goes to q5 on epsilon, and q5 goes to q6 on input 0
For 101: q0 goes to q1 on 1, q1 to q2 on epsilon, q2 to q3 on input 0, q4 to q5 on input epsilon,
q5 to q6 on input 1.
How would I go about linking these seperate NFA's together? My instinct was that they should
just flow into one another, maybe with just epsilon transitions?.
IN JAVA BJP5 Exercise 6.19 leetSpeak LanguageType Java file pr.pdf
IN JAVA
BJP5 Exercise 6.19: leetSpeak Language/Type: Java file processing Scanner Author: Marty
Stepp (on 2019/09/19) Write a method leetSpeak that accepts two parameters: a Scanner
representing an input file, and a PrintStream representing an output file. Your method should
convert the input file's text to "leet speak" (aka 1337 speak), an internet dialect where various
letters are replaced by other letters/numbers. Output the leet version of the text to the given
output file. Preserve the original line breaks from the input. Also wrap each word of input in
parentheses. Perform the following replacements: For example, if the input file lincoln.txt
contains the following text: four score and seven years ago our fathers brought forth on this
continent a new nation And your method is called in the following way: Scanner input = new
Scanner(new File("lincoln.txt")); PrintStream output = new PrintStream(new File("leet.txt"));
leetSpeak(input, output); Then after the call, the output file leet.txt should contain the following
text: (four) (scor3) (4nd) (s3v3n)(y34rz)(4g) (Our) (f47h3rz) (brough7) (for7h) (0n) (7hiz)
(c0n7in3n7) (4) (n3w) (n47ion) You may assume that each token from the input file is separated
by exactly one space. Hint: You may want to use the String object's replace method, which is
used as follows: String str = "mississippi"; str = str.replace("s", "*"); // str = "mi**i**ippi" Type
your solution here:.
Goal Create a hypothetical threat assessment based on vulnerabilities.pdf
Goal: Create a hypothetical threat assessment based on vulnerabilities you expect to find when
you perform your actual scans against the clients network. Procedure: Assume the scenarios
below are what you are most likely to encounter when you begin your actual work. Deliverable:
Provide a spreadsheet or document showing the following items. Make sure you factor in the
appropriate context. For example, if you think you might be able to penetrate the APOLLO
system, evaluate those risks according to that systems sensitivity and criticality. Description of
the vulnerability Operating systems/versions affected Risks of attempting to exploit (e.g., might
crash the host or lock out an account) Risk (what could you or a threat actor do upon successful
exploitation)? Identify as many attack vectors as you can. Examples: launch an attack on
internal systems, obtain password hashes, crack passwords, access other systems, move laterally,
and so on). Identify potential blocking mechanisms such as AV software or IDS/IPS, and how
you might try to bypass them. Document how you plan on cracking passwords. This will depend
on the source systems course, but you should be ready for whatever you run into. Include online
tools as well. Remediation action CVSS score Scenario 5: Web server is exposing sensitive
data Scenario 6: Web application has broken access control Scenario 7: Oracle WebLogic Server
vulnerable to CVE-2020-14882 Scenario 8: Misconfigured cloud storage (AWS security group
misconfiguration, lack of access restrictions) Scenario 9: Microsoft Exchange Server vulnerable
to CVE-2021-26855.
import React, { useEffect } from react;import { BrowserRouter as.pdf
import React, { useEffect } from 'react';
import { BrowserRouter as Router, Route, Routes, Link, useLocation, Outlet, Navigate } from
'react-router-dom'; // Added useLocation
import { App } from './App';
import Cookies from 'js-cookie';
import LoginButton from './authentication/LoginButton'; // Import the LoginButton component
import { useAuth0 } from '@auth0/auth0-react';
const isAuthenticated = true;
export default function RouterPage() {
useEffect(() => {
// Fetch the userId from the Flask backend
fetch('http://localhost:5000/callback', {
method: 'GET',
credentials: 'include', // Important for sending cookies across origins
})
.then(response => response.json())
.then(data => {
// Assuming the userId is returned in the data object
const userId = data.userId;
Cookies.set('userId', userId, { expires: 7 });
})
.catch((error) => console.error('Error:', error));
}, []);
// These could be different components for your different pages
const Title = ({ isAuthenticated }) => (
TasktasticTest Environment
{isAuthenticated ? (
Logout
) : (
)}
);
return (.
im solving tha m-puzzel sliding tail problem where m = n^2 - 1 I ha.pdf
i'm solving tha m-puzzel sliding tail problem where m = n^2 - 1 I have made this code using
python using A* with taking into considration the Misplaced, Euclidean, and Manhattan
heuristics to the problem.
however i want it to work for 3*3 and 4*4 and 5*5 and 6*6 matrix it did worked for 3*3 but not
with the rest i couldnot run it ( you can just change the value of n in the code) is the problem
form the code or my device code not run it dou to time and memory considretion
import heapq
import random
class PuzzleNode:
def __init__(self, state, g_cost, heuristic, parent=None):
self.state = state # 2D array representing the puzzle state
self.g_cost = g_cost # cost to reach this state from the initial state
self.heuristic = heuristic # heuristic value
self.parent = parent # reference to the parent node
def f_cost(self):
# The total cost is the sum of g_cost and heuristic value
return self.g_cost + self.heuristic
def __lt__(self, other):
# Comparing nodes based on f_cost and depth for priority queue
if self.f_cost() == other.f_cost():
return self.g_cost > other.g_cost # For tie-breaking, prefer nodes with lower depth
return self.f_cost() < other.f_cost()
def generate_successors(node):
# Generate successor nodes by sliding tiles in four directions
successors = []
empty_x, empty_y = find_empty_space(node.state)
for dx, dy in [(0, 1), (0, -1), (1, 0), (-1, 0)]:
new_x, new_y = empty_x + dx, empty_y + dy
if 0 <= new_x < len(node.state) and 0 <= new_y < len(node.state[0]):
new_state = [row[:] for row in node.state]
new_state[new_x][new_y], new_state[empty_x][empty_y] =
new_state[empty_x][empty_y], new_state[new_x][new_y]
successors.append(PuzzleNode(new_state, node.g_cost + 1, 0)) # The heuristic will be
calculated separately
return successors
def misplaced_tiles_heuristic(current_state, goal_state):
# Calculate the Misplaced Tiles heuristic value
h = 0
for i in range(len(current_state)):
for j in range(len(current_state[0])):
if current_state[i][j] != goal_state[i][j] and current_state[i][j] != 0:
h += 1
return h
def manhattan_distance_heuristic(current_state, goal_state):
# Calculate the Manhattan Distance heuristic value
h = 0
for i in range(len(current_state)):
for j in range(len(current_state[0])):
if current_state[i][j] != 0:
x, y = find_tile_position(current_state[i][j], goal_state)
h += abs(i - x) + abs(j - y)
return h
def euclidean_distance_heuristic(current_state, goal_state):
# Calculate the Euclidean Distance heuristic value
h = 0
for i in range(len(current_state)):
for j in range(len(current_state[0])):
if current_state[i][j] != 0:
x, y = find_tile_position(current_state[i][j], goal_state)
h += ((i - x) ** 2 + (j - y) ** 2) ** 0.5
return h
def find_empty_space(state):
# Helper function to find the position of the empty space (0) in the state
for i in range(len(state)):
for j in range(len(state[0])):
if state[i][j] == 0:
return i, j
def find_tile_position(tile, state):
# Helper function to find the position of a tile in the state
for i in rang.
if any additional information is required let me know Work through t.pdf
if any additional information is required let me know Work through the tasks sequentially
(implement and test). Only move on to a task when you are positive that the previous one has
been completed correctly, Remember that the names of classes and methods must exactly match
those in this specification (FUNCTION NAMES, PARAMETER TYPES, RETURNS, PRE
AND POST CONDTTIONS MUST MATCH EXACTLY. Remember, you must thoroughly
document your codellt Task 1: Modify the Character class
operator!= epost : displays Character data in the form: "[name_] is a Level [level]] [race_].
InVitality: [vitality_] InMax Armor: [armor_] In [They are / They are not] an enemy. In" +1
isplay
the tally is zero. Nore: no pre-processing of the input string necessary, only uppercase input will
match. / tatlyRace epost: Outputs a report of the characters currently in the tavern in the form:
level is: [x] In [x] are enemies. \n Note that the average level should be rounded to the
NEAREST integer, and the enemy percentage should be rounded to 2 decimal places. Exanple
output: Humans: 3 Elves: 5 Dwarves: 8 Lizards: 6 Undead: The average level 1s: 7 46.67% are
enemies. *1
ereturn: The average level of all the characters in the Tavern epost: Computes the average level
of the Tavern rounded to the NEAREST integer. 1 calculateAvgLevel ereturn: The integer
enemy count of the Tavern getEnemycount ereturn: The percentage (double) of all the enemy
characters in the Tavern epost: Conputes the eneny percentage of the Tavern rounded up to 2
decinal places. **/ calculateEnemyPercentage eparam: A const reference to a string representing
a character Race with value in ["NONE", "HUMAN", "ELF", "DWARF", "LIZARD",
"UNDEAD"] ereturn: An integer tally of the number of characters in the Tavern of the given
race. If the argument string does not match one of the expected race values, the tally is zero.
NOTE: no pre-processing of the input string necessary. only uppercase input will match.
Task 3: Implement the Tavern class as a subclass of ArrayBag The Tavern is subclass of
ArrayBag that stores Character objects Data Types The Tavern class must have the following
pritate member tariables: - An integer sum of the levels of all the characters currently in the
tavern - An integer count of alt the characters currently in the Tavern that are marked as enemies
The Tavern class must have the following public member fiutctions: Constructor Defaute
constructor. Default-initializes all private members.
Work through the tasks sequentially (implement and test). Only move on to a task when you are
positive that the previous one has been completed correctly, Remember that the names of classes
and methods must exactly match those in this specification (FUNCTION NAMES,
PARAMETER TYPES, RETURNS, PRE AND POST CONDTTIONS MUST MATCH
EXACTLY. Remember, you must thoroughly document your codellt Task 1: Modify the
Character class
Task 3: Implement the Tavern class as a subclass of ArrayBag The Tavern is subclass of
ArrayBag .
I need help with providing a 2 page overview of the case study provi.pdf
I need help with providing a 2 page overview of the case study provided in pictures please!
asked that he come to his office. When Jenkins saw the office, he laughed and said, "Well
DeMur-or shall I say Maslick-I must say you have some admirers. As an American with African
roots, you should have expected some lighthearted ribbing about your conversion to that strange
religion of yours. Even you must admit that they do some weird things." Maalick replied, "No, I
must suy that I did not expect this!" Jenkins recognized that Maalick was angry and upset ower
the incident and promised to handle the situation. Over the next several months, Maalick
received a series of notes left on his desk and car referencing black cats, black magic, requests
for paim readings and notices about the disappearance of MarShawn DeMur. Not wanting to
cause any problems or be labeled as a troublemaker, Maalick ignored these incidents, thinking
that people would tire of the pranks and things would die down. However, on one occasion, he
found on his desk several sheets of what appeared to be chants with a title at the top that read -
Prayers for Black Folk:" Next to the pages was a book titled Myrical Practices from the Negro
Experionce. Maalick immediately took the materials to the HR department and met with Ford.
Ford told Maalick, "I have been out of the office a lot helping with the staffing of the new
Northwestern facility and had no idea you were having these kinds of problems. Do you have
any idea who is responsible for these actions?" "No I don't," said Maalick. "This is not the type
of behavior that is condoned at Treton. Don't worry, I will handle this immediately. I am so sorry
ahout all of this," said Ford. After Maalick left her office, Ford called a meeting of all
department heads and informed them of the situation. Ford immediately sent an c-mail to all
facility employees, reminding them of Treton's policies regarding discrimination and harassment
and the penalties associated with such actions. By the end of the day, all department heads met
with their employees with specitic wamings and orders for the behaviors to cease and desist. The
days following were a bit tense in the office but calm. Maalick was relieved to not find any more
notes or messages. Fond visited with Maalick on several oceasions to ensure that he was not
continuing to experience any problems. Maalick was happy to report that, in his opinion, all was
well. On Ford's last visit, Maalick took the opportunity to ask about two new systems manager
openings. Promotion to a systems manager position would assist Maalick's career goals for
advancenent with 'Treton. Fond sent Maalick the position description and encouraged him to
apply. After reviewing the systems manager job requirements, Maalick believed that he had
more than a good chance at a promotion. He spoke with Jenkins about the job duties and
reyuirements and expressed his interest in the position. Maalick was informed that at that time,
.
I keep getting NullPointerExcepetion, can someone help me with spinL.pdf
I keep getting NullPointerExcepetion, can someone help me with spinList(int numMoves) and
LinkedList altLists(LinkedList list)?
import java.util.NoSuchElementException;
public class LinkedList {
private class Node {
private T data;
private Node next;
private Node prev;
public Node(T data) {
this.data = data;
this.next = null;
this.prev = null;
}
}
private int length;
private Node first;
private Node last;
private Node iterator;
public LinkedList() {
first = null;
last = null;
length = 0;
iterator = null;
}
public LinkedList(T[] array) {
if (array == null) {
return;
}
if (array.length == 0) {
length = 0;
first = null;
last = null;
iterator = null;
} else {
for (T item : array) {
addLast(item);
}
iterator = null;
}
}
public LinkedList(LinkedList original) {
if (original == null) {
return;
}
if (original.length == 0) {
length = 0;
first = null;
last = null;
iterator = null;
} else {
Node temp = original.first;
while (temp != null) {
addLast(temp.data);
temp = temp.next;
}
iterator = null;
}
}
public T getFirst() throws NoSuchElementException {
if(first == null){
throw new NoSuchElementException("getFirst(): List has no element to access");
}
return first.data;
}
public T getLast() throws NoSuchElementException {
if (last == null){
throw new NoSuchElementException("getLast(): List has no element to access");
}
return last.data;
}
public T getIterator() throws NullPointerException {
if (iterator == null){
throw new NullPointerException("getIterator(): There is no iterator to access");
}
return iterator.data;
}
public int getLength() {
return length;
}
public boolean isEmpty() {
return length == 0;
}
public boolean offEnd() {
return iterator == null;
}
public void addFirst(T data) {
if (length == 0){
first = last = new Node(data);
} else {
Node fill = new Node(data);
fill.next = first;
first.prev = fill;
first = fill;
}
length++;
}
public void addLast(T data) {
if (length == 0) {
first = last = new Node(data);
} else {
Node fill = new Node (data);
fill.prev = last;
last.next = fill;
last = fill;
}
length++;
}
public void addIterator(T data) throws NullPointerException{
if(iterator == null) {
throw new NullPointerException("addIterator(): Can't add the node because iterator points
to null");
} else if(iterator == last){
addLast(data);
} else{
Node fill = new Node(data);
iterator.next.prev = fill;
fill.prev = iterator;
fill.next = iterator.next;
iterator.next = fill;
length++;
}
}
public void removeFirst() throws NoSuchElementException {
if (length == 0) {
throw new NoSuchElementException("removeFirst(): Cannot remove from an empty
List");
} else if(length == 1) {
first = last = null;
} else {
first = first.next;
first.prev = null;
}
length--;
}
public void removeLast() throws NoSuchElementException {
if (length == 0){
throw new NoSuchElementException("removeLast(): Cannot remove from an empty
List");
} else if (length == 1){
first = last = null;
}else{
last = last.prev;
last.next = null;
}
length--;
}
public void removeIterator() throws NullPointerE.
I have been tasked to write a code for a Singly Linked list that inc.pdf
I have been tasked to write a code for a Singly Linked list that includes the following: Implement
a singly linked list class with the following methods: - `void insertAtBeginning(int value)`:
Inserts a new node with the given value at the beginning of the list. - `void insertAtEnd(int
value)`: Inserts a new node with the given value at the end of the list. - `void deleteNode(int
value)`: Deletes the first occurrence of a node with the given value. - `void display()`: Displays
the elements of the linked list. I have everything EXCEPT for the deleteNode. I have it included,
but it is throwing an error....I just need a little extra help to fix that part. My Code: #
#include
using namespace std;
class Node { //user defined type.
public: // public class modifier to access the class node.
int value;
Node* next;
};
void display(Node *head) {
if(head == NULL){
cout << "NULL" << endl;
}
else {
cout << head->value << endl;
display(head->next);
}
}
void insertAtBeginning(Node**head, int newValue){
// Steps to add a Node to the beginning of the linked list
//1. Prepare a newNode
Node * newNode = new Node();
newNode ->value = newValue;
//2. Put it in front of the current head
newNode->next = *head;
//3. Move head of the list to point to the newNode
*head= newNode;
}
void insertAtEnd(Node**head, int newValue) {
//1.Prepare a newNode
Node* newNode= new Node();
newNode ->value = newValue;
newNode->next = NULL;
//2. If Linked list is empty, newNode will be a head node
if(*head ==NULL){
*head = newNode;
return;
}
//3. Find last node
Node* last= *head;
while(last->next!=NULL){
last=last->next;
}
//4. Insert newNode after last node (at the end of List)
last->next =newNode;
}
void deleteNode(Node**before_del){
Node* temp;
temp = before_del->next;
before_del->next = temp->next;
delete temp;
}
int main()
{
Node* head=new Node();
Node* second=new Node();
Node* third=new Node();
Node* fourth=new Node();
head->value = 7;
head->next = second;
second->value = 12;
second->next = third;
third->value = 15;
third->next = fourth;
fourth->value = 20;
fourth->next = NULL;
insertAtBeginning(&head, 4);
insertAtBeginning(&head, 6);
insertAtEnd(&head, 23);
del(&head(15)->next);
display(head);
}.
I am trying to pass a date to a function in postgres.My function w.pdf
I am trying to pass a date to a function in postgres.
My function was working correctly. But then I had to introduce date as an input parameter. Ever
since I have introduced the date,
the function is giving an empty result set. Here is my code below, with new addition of date
related code highlighted in bold. Am I missing
something? Do I need to declare the date maybe?
CREATE OR REPLACE FUNCTION public.path_optimization(input_date date)
RETURNS TABLE(area_id_ uuid, result_uuids text[])
LANGUAGE plpgsql
AS $function$
DECLARE
r RECORD;
BEGIN
-- Iterate through the records in pma_ranked
FOR r IN SELECT areaid, max_uuid FROM pma_ranked LOOP
--RAISE NOTICE 'Processing areaid: %, max_uuid: %', r.areaid, r.max_uuid;
RETURN QUERY
EXECUTE
'
WITH RECURSIVE
tree AS (
SELECT
g."centerPoint"::GEOMETRY AS vtcs,
NULL::GEOMETRY AS segment,
ARRAY[g.uuid] AS uuids
FROM
potential_missed_areas AS g
WHERE
g."areaID" = $1
AND g.uuid = $2
AND g.status = ''approved''
AND g."createdAt" = $3
UNION ALL
SELECT
ST_Union(t.vtcs, v."centerPoint"),
ST_ShortestLine(t.vtcs, v."centerPoint"),
t.uuids || v.uuid
FROM
tree AS t
CROSS JOIN LATERAL (
SELECT
g.uuid,
g."centerPoint"
FROM
potential_missed_areas AS g
WHERE
g."areaID" = $1
AND g.status = ''approved''
AND g."createdAt" = $3
AND NOT g.uuid = ANY(t.uuids)
ORDER BY
t.vtcs <-> g."centerPoint"
LIMIT
1
) AS v
),
NumberedRows AS (
SELECT
$1,uuids,
ROW_NUMBER() OVER () AS RowNum
FROM tree
WHERE segment IS NOT NULL
)
SELECT
$1,uuids
FROM NumberedRows
WHERE RowNum = (SELECT MAX(RowNum) FROM NumberedRows);
'
USING r.areaid, r.max_uuid,input_date;
END LOOP;
END;
$function$
;
Here is how I am calling the function:
select * from public.path_optimization('2023-10-04'::date).
How can an event such as the terrorist attacks of September 2001 aff.pdf
How can an event such as the terrorist attacks of September 2001 affect consumer and business
confidence and the economy?
10
Respond to 2 classmates
(10 points possible)
How can an event such as the terrorist attacks of September 2001 affect consumer and business
confidence and the economy?
10
Respond to 2 classmates
(10 points possible)0
4 of 1. a thed is being ball 5. morinative +. Tise Cone Dave Ean. 1 bo fone The 5. Sacteriritoe
ably 1. fle miner antal a. a cosonoclen s. a dopentiks. 4. net dor.
8. Jessic, an employee of Kim's Rentarant, believes that ber enployer has violated her rights in
the workplace. Lanoin The tranch of law dealing with the definition and enforterment of all
peivate er public rights in Pars 1 Name: Class Date Evam 1 2. admininerative law. b. civid law.
c. constitusional taw. if foderal law. a. a case docidod by the Finois Supreme Court. b. a nule
creslod by a Hiliness state administrative apeacy. c. a provision in the fllinois constiturion. x. an
equihable remedy. b. an unelococeblic demant. E. a nemody at law. d. beyoed the court's
antherity. 11. The United Sates Supreme Coun does ner have eripinal juridvanen in my case. a.
True b. False 12. Milo files a sait apainst Nick in an Ohio stace court, noceng that Nisk opvrates
a Web sine thoogh which Ohio arives from 2. anythiag an Obio rscident has doee. b. Nikk's Web
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the cave is being heard foet the firat time. b. the coun has a unizue method of dexiding whether
na hear a case. c. the coun has urnetual pescedural niles. 4. tece subjest matoer of the auit is
intertsting and aew. a. has a sudficiem stake in the matter. h. has jurisdicticen. Pave 2 Name
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not include county ordinances. a. True b. False 2. The stability and predictability of the law are
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state legislatures and comprise one of the sources of American law. a. True b. False 4. The term
common law refers to law that is common throughout the world. a. True b. False Indicate the
answer choice that best completes the statement or answers the question. 5. In Benny v. City Car
Dealership, a state supreme court held that a minor could cancel a contract for the sale of a car.
Now a trial court in the same state is deciding Dora v. Even Steven Auto Deals, Inc, a case with
similar facts. Under the doctrine of stare decisis, the trial court is likely to a. allow the minor to
cancel the contract. b. disregard the Benny case. c. order the minor to cancel the contract. d.
require the minor to fulfill the contract. 6. Martin Luther King, Jr. played a singular role in the
most significant social movement in the histor.
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The objective of the technical document is to provide a high-level overview of the chat console
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communication between clients.
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- 1. I'm creating a skip list program for my Algorithms and Advanced Data Structure class. I was tasked with implementing a find & add method for the skiplist. Here is my program, I'm running into a segmentation fault when I add my second value into the skiplist. My first issue that I fixed was that I wasn't checking the first node in the list to see if it was nullptr, but that was not my only issue apparently. Add Method: void SkipList::add(const ElemType &el) { // Create a new node with the given element Node *newNode = new Node(el); // Get the height of the new node int newHeight = newNode->nodeHeight; // If the height of the new node is greater than the current list height, // update the list height. if (newHeight > listHeight) { listHeight = newHeight; } // Array to keep track of nodes to update Node *update[MAX_NUM_LISTS]; // Start from the top level Node *current = head[listHeight - 1]; // Initialize current correctly // If the list is empty, assign the first node to head if (head[0] == nullptr) { head[0] = newNode; } else {
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