This document presents an identity for cubic triples, showing that (3aw + w)3 + (-w ± w√1 + 12a(3a2 + 3a + 1)/2)3 = (-w ± w√1 + 12a(3a2 + 3a + 1)/2 + w)3. The identity was written by José Acevedo Jiménez.

1. Identity of cubic triples
(3𝑎𝑤 + 𝑤)3
+ (
−𝑤 ± 𝑤√1 + 12𝑎(3𝑎2 + 3𝑎 + 1)
2
)
3
= (
−𝑤 ± 𝑤√1 + 12𝑎(3𝑎2 + 3𝑎 + 1)
2
+ 𝑤)
3
By: José Acevedo Jiménez.