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I have a homework problem that I do not know how to begin. I must evaluate integral (4/3x+7)
dx. I think u= 3x+7 but beyond that I am just lost. Would du = 4x? Please help.
Solution
yeah, u = 3x + 7 du = 3 dx then substitute it, int 4 dx / ( 3x + 7) = int 4 du / 3 u =
4/3 int du/u = 4/3 ln u = 4/3 ln ( 3x + 7) + C

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