HOCl (aq) + HCI(aq) - H2O(l) + Cl2 (g) 6Cl2(g) +.pdf
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HOCl (aq) + HCI(aq) -> H2O(l) + Cl2 (g) 6Cl2(g) + 12NaOH(aq) -> 10NaCl (aq) + 2NaCIO3(aq) + 6H2O(l) MgCO3(aq) +2HCI (aq) -> MgCl2(aq) + H2O(l) + CO2 (g) Solution HOCl (aq) + HCI(aq) -> H2O(l) + Cl2 (g) 6Cl2(g) + 12NaOH(aq) -> 10NaCl (aq) + 2NaCIO3(aq) + 6H2O(l) MgCO3(aq) +2HCI (aq) -> MgCl2(aq) + H2O(l) + CO2 (g).
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#!binbash# Decode a UDP packet raw binary dataDonelet offs=40.pdf
#!/bin/bash
# Decode a UDP packet raw binary dataDone
let offs=40
declare -i ws
declare -i end
declare -i rmndr
declare -i byteval
declare -i bitws
NetworkOrder16Bit() {
ws=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws*=256))
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws+=byteval))
}
NetworkOrder32Bit() {
ws=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws*=256))
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws+=byteval))
((ws*=256))
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws+=byteval))
((ws*=256))
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws+=byteval))
}
echo
echo
end=$offs+74
#Start with the destination MAC address
hexdump -s $offs -n 6 -e \'\"Ether Dest: \" 5/1 \"%02x:\" 1/1 \"%02x\ \"\' test2.pkts
((offs+=6))
# Then the source
hexdump -s $offs -n 6 -e \'\"Ether Src: \" 5/1 \"%02x:\" 1/1 \"%02x\ \"\' test2.pkts
((offs+=6))
# Next is the packet type, but its in network byte order so we can\'t
# use \'1/2 \"%04x\"\' - we may be run on a system with another byte order and you\'ll
# get different output
hexdump -s $offs -n 2 -e \'\"Ether Type: \" 2/1 \"%02x\" \"\ \"\' test2.pkts
((offs+=2))
# IP header
# Get the version/len value into a variable we can do arithmetic with
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
# The most significant 4 bits are the IP version
((bitws=byteval&0xF0))
((bitws/=16))
echo \"IP Version: $bitws\"
# Least significant 4 bits are the header length
((bitws=byteval&0x0F))
((bitws*=4))
echo \"Header Length: $bitws\"
# Type of service
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
# Precedence
((bitws=byteval&0xE0))
((bitws/=32))
echo \"Precedence: $bitws\"
# Delay
((bitws=byteval&0x10))
if (( bitws ))
then
echo \"Minimize delay\"
fi
# Throughput
((bitws=byteval&0x08))
if (( bitws ))
then
echo \"High throughput\"
fi
# Reliability
((bitws=byteval&0x08))
if (( bitws ))
then
echo \"High reliability\"
fi
# Cost
((bitws=byteval&0x08))
if (( bitws ))
then
echo \"Minimize cost\"
fi
# Message length - in network byte order
NetworkOrder16Bit
echo \"Message Length: $ws\"
# ID
hexdump -s $offs -n 2 -e \'\"ID: \" 2/1 \"%02x\" \"\ \"\' test2.pkts
((offs+=2))
# Flags
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
# DF
((bitws=byteval&0x40))
if (( bitws != 0))
then
echo \"Don\'t fragment\"
else
# More fragments
((bitws=byteval&0x20))
if (( bitws ))
then
echo \"More fragments\"
fi
# Fragment number
((ws=bitws&0x1F))
((ws*=256))
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((ws+=byteval))
echo \"Fragment number: $ws\"
fi
((offs+=1))
hexdump -s $offs -n 1 -e \'\"TTL: \" 1/1 \"%u\ \"\' test2.pkts
((offs+=1))
hexdump -s $offs -n 1 -e \'\"Protocol: \" 1/1 \"%u\ \"\' test2.pkts
((offs+=1))
hexdump -s $offs -n 2 -e \'\"Header checksum: \" 2/1 \"%02x\" \"\ \"\' test2.pkts
((offs.
Youd only need SOCl2 So d then na .pdf
This short document discusses the need for sulfuryl chloride (SOCl2) and sodium (Na) to complete some chemical process or reaction. Sodium is mentioned after "then na" which likely refers to adding sodium after the sulfuryl chloride. The document provides minimal context and it is difficult to determine the overall purpose or goal based on the limited information.
you can see the difference bw IE5 and IE6 is ver.pdf
you can see the difference b/w IE5 and IE6 is very high.. it means the element is
going to inert gas configuration after removing five e-s hence the element is nitrogen N and its
configuration is 1S2 2S2 2P3
Solution
you can see the difference b/w IE5 and IE6 is very high.. it means the element is
going to inert gas configuration after removing five e-s hence the element is nitrogen N and its
configuration is 1S2 2S2 2P3.
they have the same vapour pressure .pdf
This document states that two substances have the same vapour pressure. It provides no other context or details about the substances.
The elements As, Sb and Bi show no tendency to fo.pdf
The elements As, Sb and Bi show no tendency to form anion by gaining electrons .
This is probably due to the fact that increasing size of the atom makes it difficult for the nucleus
to hold extra electrons.
Solution
The elements As, Sb and Bi show no tendency to form anion by gaining electrons .
This is probably due to the fact that increasing size of the atom makes it difficult for the nucleus
to hold extra electrons..
taking the distance from point P in water for len.pdf
taking the distance from point P in water for length = 14 m time taken is = 14/5 =
2.8 hr and taking diagonal path in grassy plain = sqrt(15^2+11^2) time taken = 6.2003 hr
therefore total time taken is = 9.000358413 hr
Solution
taking the distance from point P in water for length = 14 m time taken is = 14/5 =
2.8 hr and taking diagonal path in grassy plain = sqrt(15^2+11^2) time taken = 6.2003 hr
therefore total time taken is = 9.000358413 hr.
PH3 Phosphine H3N ammonia H3PO2 Hypophosphorus.pdf
PH3: Phosphine H3N: ammonia H3PO2: Hypophosphorus Acid CuSO4: Copper
Sulphate P2O2: Phosphorus Dioxide H2SO5:Peroxymonosulfuric acid Titanium(IV) Oxide:
TiO2
Solution
PH3: Phosphine H3N: ammonia H3PO2: Hypophosphorus Acid CuSO4: Copper
Sulphate P2O2: Phosphorus Dioxide H2SO5:Peroxymonosulfuric acid Titanium(IV) Oxide:
TiO2.
order is 3 and it is a linear .pdf
The document discusses an order that is 3 and linear. It states that the order is 3 and describes it as being linear. No other information is provided.
Recommended
#!binbash# Decode a UDP packet raw binary dataDonelet offs=40.pdf
#!/bin/bash
# Decode a UDP packet raw binary dataDone
let offs=40
declare -i ws
declare -i end
declare -i rmndr
declare -i byteval
declare -i bitws
NetworkOrder16Bit() {
ws=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws*=256))
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws+=byteval))
}
NetworkOrder32Bit() {
ws=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws*=256))
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws+=byteval))
((ws*=256))
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws+=byteval))
((ws*=256))
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
((ws+=byteval))
}
echo
echo
end=$offs+74
#Start with the destination MAC address
hexdump -s $offs -n 6 -e \'\"Ether Dest: \" 5/1 \"%02x:\" 1/1 \"%02x\ \"\' test2.pkts
((offs+=6))
# Then the source
hexdump -s $offs -n 6 -e \'\"Ether Src: \" 5/1 \"%02x:\" 1/1 \"%02x\ \"\' test2.pkts
((offs+=6))
# Next is the packet type, but its in network byte order so we can\'t
# use \'1/2 \"%04x\"\' - we may be run on a system with another byte order and you\'ll
# get different output
hexdump -s $offs -n 2 -e \'\"Ether Type: \" 2/1 \"%02x\" \"\ \"\' test2.pkts
((offs+=2))
# IP header
# Get the version/len value into a variable we can do arithmetic with
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
# The most significant 4 bits are the IP version
((bitws=byteval&0xF0))
((bitws/=16))
echo \"IP Version: $bitws\"
# Least significant 4 bits are the header length
((bitws=byteval&0x0F))
((bitws*=4))
echo \"Header Length: $bitws\"
# Type of service
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
# Precedence
((bitws=byteval&0xE0))
((bitws/=32))
echo \"Precedence: $bitws\"
# Delay
((bitws=byteval&0x10))
if (( bitws ))
then
echo \"Minimize delay\"
fi
# Throughput
((bitws=byteval&0x08))
if (( bitws ))
then
echo \"High throughput\"
fi
# Reliability
((bitws=byteval&0x08))
if (( bitws ))
then
echo \"High reliability\"
fi
# Cost
((bitws=byteval&0x08))
if (( bitws ))
then
echo \"Minimize cost\"
fi
# Message length - in network byte order
NetworkOrder16Bit
echo \"Message Length: $ws\"
# ID
hexdump -s $offs -n 2 -e \'\"ID: \" 2/1 \"%02x\" \"\ \"\' test2.pkts
((offs+=2))
# Flags
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((offs+=1))
# DF
((bitws=byteval&0x40))
if (( bitws != 0))
then
echo \"Don\'t fragment\"
else
# More fragments
((bitws=byteval&0x20))
if (( bitws ))
then
echo \"More fragments\"
fi
# Fragment number
((ws=bitws&0x1F))
((ws*=256))
byteval=`hexdump -s $offs -n 1 -e \'1/1 \"%u\"\' test2.pkts`
((ws+=byteval))
echo \"Fragment number: $ws\"
fi
((offs+=1))
hexdump -s $offs -n 1 -e \'\"TTL: \" 1/1 \"%u\ \"\' test2.pkts
((offs+=1))
hexdump -s $offs -n 1 -e \'\"Protocol: \" 1/1 \"%u\ \"\' test2.pkts
((offs+=1))
hexdump -s $offs -n 2 -e \'\"Header checksum: \" 2/1 \"%02x\" \"\ \"\' test2.pkts
((offs.
Youd only need SOCl2 So d then na .pdf
This short document discusses the need for sulfuryl chloride (SOCl2) and sodium (Na) to complete some chemical process or reaction. Sodium is mentioned after "then na" which likely refers to adding sodium after the sulfuryl chloride. The document provides minimal context and it is difficult to determine the overall purpose or goal based on the limited information.
you can see the difference bw IE5 and IE6 is ver.pdf
you can see the difference b/w IE5 and IE6 is very high.. it means the element is
going to inert gas configuration after removing five e-s hence the element is nitrogen N and its
configuration is 1S2 2S2 2P3
Solution
you can see the difference b/w IE5 and IE6 is very high.. it means the element is
going to inert gas configuration after removing five e-s hence the element is nitrogen N and its
configuration is 1S2 2S2 2P3.
they have the same vapour pressure .pdf
This document states that two substances have the same vapour pressure. It provides no other context or details about the substances.
The elements As, Sb and Bi show no tendency to fo.pdf
The elements As, Sb and Bi show no tendency to form anion by gaining electrons .
This is probably due to the fact that increasing size of the atom makes it difficult for the nucleus
to hold extra electrons.
Solution
The elements As, Sb and Bi show no tendency to form anion by gaining electrons .
This is probably due to the fact that increasing size of the atom makes it difficult for the nucleus
to hold extra electrons..
taking the distance from point P in water for len.pdf
taking the distance from point P in water for length = 14 m time taken is = 14/5 =
2.8 hr and taking diagonal path in grassy plain = sqrt(15^2+11^2) time taken = 6.2003 hr
therefore total time taken is = 9.000358413 hr
Solution
taking the distance from point P in water for length = 14 m time taken is = 14/5 =
2.8 hr and taking diagonal path in grassy plain = sqrt(15^2+11^2) time taken = 6.2003 hr
therefore total time taken is = 9.000358413 hr.
PH3 Phosphine H3N ammonia H3PO2 Hypophosphorus.pdf
PH3: Phosphine H3N: ammonia H3PO2: Hypophosphorus Acid CuSO4: Copper
Sulphate P2O2: Phosphorus Dioxide H2SO5:Peroxymonosulfuric acid Titanium(IV) Oxide:
TiO2
Solution
PH3: Phosphine H3N: ammonia H3PO2: Hypophosphorus Acid CuSO4: Copper
Sulphate P2O2: Phosphorus Dioxide H2SO5:Peroxymonosulfuric acid Titanium(IV) Oxide:
TiO2.
order is 3 and it is a linear .pdf
The document discusses an order that is 3 and linear. It states that the order is 3 and describes it as being linear. No other information is provided.
Nope. When an atom is ionized it only affects the.pdf
Nope. When an atom is ionized it only affects the electrons in the electron cloud,
which is outside the nucleus. Let me know if this doesn\'t clear things up.
Solution
Nope. When an atom is ionized it only affects the electrons in the electron cloud,
which is outside the nucleus. Let me know if this doesn\'t clear things up..
L2^12 .pdf
This mathematical expression involves taking the length L and dividing it by the square root of 2. The expression is evaluating the square root of 2 applied to the length L. This can be used to calculate the diagonal length of a square with side length L.
In Atmospehere Pressure = 105760 = 0.138 Atmo.pdf
In Atmospehere : Pressure = 105/760 = 0.138 Atmosphere In Pascals: Pressure =
0.138 x 1.013 x 10^5 = 13995.4Pa
Solution
In Atmospehere : Pressure = 105/760 = 0.138 Atmosphere In Pascals: Pressure =
0.138 x 1.013 x 10^5 = 13995.4Pa.
H2SO4 is a strong electrolyte. It dissociates alm.pdf
H2SO4 is a strong electrolyte. It dissociates almost completely in water while rest
four compounds don\'t dissolve in water completely.
Solution
H2SO4 is a strong electrolyte. It dissociates almost completely in water while rest
four compounds don\'t dissolve in water completely..
DE is positive in exothermic reactions .pdf
DE is positive in exothermic reactions. Exothermic reactions release energy to the surroundings, so the system's energy decreases. Therefore, the change in energy (DE) for exothermic reactions is positive as energy is lost from the system.
The yield to maturity (YTM) is the measure of bonds rate of return t.pdf
The yield to maturity (YTM) is the measure of bonds rate of return that considers both the
interest income and any capital gain or loss. it should be noted that yield to maturity is not same
as current yield as current yield is the annual interest dividend by the bonds current value and
does not account for capital gain or loss.
YTM is important because it compare a bonds expected return with those of other securities
available in the market. YTM considers the three sources of potential return from a bond (coupon
payments, capital gains, and reinvestment returns which helps investors in Understanding how
yields vary with market prices (that as bond prices fall, yields rise; and as bond prices rise, yields
fall).it also helps investors to anticipate the effects of market changes on their portfolios. The
yield to maturity is expressed as an annual percentage rate
The following formula can be used to find out its approximate value:
APPROX YTM=C+F-P/n/F+P/2
Where
C=coupon value
F=face value
P=market price
And n=years to maturity
Solution
The yield to maturity (YTM) is the measure of bonds rate of return that considers both the
interest income and any capital gain or loss. it should be noted that yield to maturity is not same
as current yield as current yield is the annual interest dividend by the bonds current value and
does not account for capital gain or loss.
YTM is important because it compare a bonds expected return with those of other securities
available in the market. YTM considers the three sources of potential return from a bond (coupon
payments, capital gains, and reinvestment returns which helps investors in Understanding how
yields vary with market prices (that as bond prices fall, yields rise; and as bond prices rise, yields
fall).it also helps investors to anticipate the effects of market changes on their portfolios. The
yield to maturity is expressed as an annual percentage rate
The following formula can be used to find out its approximate value:
APPROX YTM=C+F-P/n/F+P/2
Where
C=coupon value
F=face value
P=market price
And n=years to maturity.
TDS (Total Dissolved Solids ) is a measure of the combined content o.pdf
Total dissolved solids is a measure of inorganic and organic substances in a liquid. The most accurate method to determine TDS involves evaporating the liquid and measuring the mass of residues, which in this case was found to be 22g. Total suspended solids refer to suspended or colloidal particles, which were calculated to be 25g.
magnesium oxide + water = magnesium hydroxideMgO (s) + H2O (l) =.pdf
magnesium oxide + water => magnesium hydroxide
MgO (s) + H2O (l) => Mg(OH)2 (s)
Solution
magnesium oxide + water => magnesium hydroxide
MgO (s) + H2O (l) => Mg(OH)2 (s).
Meiosis, inheritance and variationThe uniqueness and similarities.pdf
Meiosis, inheritance and variation:
The uniqueness and similarities within the closely related family members occurs because of
inherit traits in the form of genes are passing from one generation to another generation.
This gene passing from our ancestral parents to our parents is called as heredity. Replication is a
process of duplication of DNA. That occurs during the S phase of Eukaryotic cell cycle.
In identical small organisms these genes pass from one generation to next by duplication of their
genetic information and then splitting into two identical organisms. In complex organisms
specialized sex cells called gametes carry half of the genetic information. These gametes from
both male and female organisms combine each other and produce new organisms. The gametes
produced process is termed as meiosis.
Meiosis:
During this process 1 diploid cell which contains 46 chromosomes undergoes cell division into 2
cycles. In which only once DNA replication is takes place. it results 4 haploid daughter cells.
The zygote is formed from the combination of both an egg and a sperm cells. Zygotes have same
number of chromosomes it is due to the halving nature of the number of chromosomes in sexual
reproduction. This critical character stabilize chromosome numbers from one generation to next
generation.
Phases of meiosis:
Interphase: In this the DNA is prepared for replication. After completion of replication process
the structure of each chromosomes compressed into 2 identical chromatids.
Prophase I : In this chromosomes structure appeared as in X - Shaped. The homologous
chromosomes are pair up each other and crossing over takes placed. In this the DNA was
exchanged. the nuclear membrane was completely dissolved at end of this stage. The
Microtubules can attach to the chromosomes.
Metaphase I: The synopsized chromosomes are aliened at equator of the cell. The chromosomes
are aliened randomly in which different combinations each time meiosis occurs.
Anaphase I: During this phase the molecules of chromosomes separates and migrates towards to
2 poles of cell.
Telophase I or Cytokinesis: In this the cell divides into two daughter cells.
Prophase II : Same as Prophase I. But the DNA does not replicate again.
Metaphase II: The chromosomes aliened at equator, again the alignment is random.
Anaphase II: The chromosomes separates and migrates towards to 2 poles of cell.
Telophase II: The nucleoplasm is reformed and the cytoplasm is divides into 2 haploid daughter
cells and finally 4 new haploid daughter cells is formed.
Genetic variation is increased by meiosis due to the independent assortment nature in meiosis.
The reshuffling process of genes in meiosis is increasing the genetic variation in a population.
Solution
Meiosis, inheritance and variation:
The uniqueness and similarities within the closely related family members occurs because of
inherit traits in the form of genes are passing from one generation to another generation.
This gene passing from our an.
Inter-Process-Communication (or IPC for short) are mechanisms provid.pdf
Inter-Process-Communication (or IPC for short) are mechanisms provided by the kernel to allow
processes to communicate with each other.
The types of inter process communication on Linux OS are:
The following IPC mechanisms are supported by Windows:
1. Clipboard - The clipboard acts as a central depository for data sharing among applications.
When a user performs a cut or copy operation in an application, the application puts the selected
data on the clipboard in one or more standard or application-defined formats. Any other
application can then retrieve the data from the clipboard, choosing from the available formats
that it understands.
2. File Mapping - File mapping enables a process to treat the contents of a file as if they were a
block of memory in the process\'s address space. The process can use simple pointer operations
to examine and modify the contents of the file. When two or more processes access the same file
mapping, each process receives a pointer to memory in its own address space that it can use to
read or modify the contents of the file.
3. Mailslot - Mailslots provide one-way communication. Any process that creates a mailslot is a
mailslot server. Other processes, called mailslot clients, send messages to the mailslot server by
writing a message to its mailslot.
4. RPC - RPC enables applications to call functions remotely. Therefore, RPC makes IPC as easy
as calling a function. RPC operates between processes on a single computer or on different
computers on a network.
5. Windows Socket - Windows Sockets is a protocol-independent interface capable of supporting
current and emerging networking capabilities.
The following IPC mechanisms are supported by Mac OS:
1. Mach Ports : Mach 3.0 is capable of running as a stand-alone kernel, with other traditional OS-
services like IO, file systems and networking stack running as user mode.It is much faster to
make a direct call between linked components than it is to send messages or do RPC between
separate tasks.
2. Apple Events : Universally supported by GUI applications on Mac OS for remote
control.Operations like opening or telling an application to open a file or quit etc can be done
using these.
3. Pasteboard - Copy Paste , Drag and drop done between applications is performed using this
technique.
4. Distributed Objects - Remote messaging feature of Cocoa to call an object in different Cocoa
applicaton.
Windows server uses the best technique to manage IPC because
a) It provides an efficient way for two or more processes on the same computer to share data.
b) It is capable of supporting current and emerging networking capabilities, such as quality of
service monitoring, robust asynchronous communication, I/O completion ports for superior
performance, and protocol-specific network
features.
=> Multiprocessing : refers to the use of two or morecentral processing units (CPU) within a
single computer system.All the operating systems provide support for multiprocessing.
Windows manages.
B)120.0° note So3 is sp2-hybridized and adopts .pdf
B)120.0° note: So3 is sp2-hybridized and adopts a trigonal planar geometry.
Solution
B)120.0° note: So3 is sp2-hybridized and adopts a trigonal planar geometry..
imple cellular phones that do very little over voice and text line o.pdf
imple cellular phones that do very little over voice and text line of work generally include one
process unit that handles everything - computer programme (keyboard, display), RF process,
battery management, etc.
These ar SoC - Systems on Chip and ar nearer to microcontrollers than microprocessors as a
result of they decide to do everything - from process, to device interfacing, to memory, to
program and knowledge storage, etc - on one chip.
Smartphones have multiple microprocessors and microcontrollers in them. the most processor
could be a chip with a bus to speak with memory on separate chips (though usually contained
within the same IC package), and busses to speak with the remainder of the devices. they
typically contain a number of the controllers, like the show controller, so that they have a number
of the options of microcontrollers, however they\'re still additional chip than microcontroller.
The cellular chipset typically includes a microprocessor/microcontroller that basically blurs the
lines. the newest generation of smartphones usually tend additional toward microprocessors for
the RF chipset, thus on provide the manufacturer flexibility by mistreatment software package
style instead of hardware style for a few options, however they are doing have additional items
of the hardware interface (rf, etc) on the chip itself.
The rest of the phone has many microcontrollers. These management the touchscreen, audio,
sensors, cameras, etc.
So it depends on the kind of phone you are thinking of. an easy phone uses a microcontroller. a
posh phone uses each.
Solution
imple cellular phones that do very little over voice and text line of work generally include one
process unit that handles everything - computer programme (keyboard, display), RF process,
battery management, etc.
These ar SoC - Systems on Chip and ar nearer to microcontrollers than microprocessors as a
result of they decide to do everything - from process, to device interfacing, to memory, to
program and knowledge storage, etc - on one chip.
Smartphones have multiple microprocessors and microcontrollers in them. the most processor
could be a chip with a bus to speak with memory on separate chips (though usually contained
within the same IC package), and busses to speak with the remainder of the devices. they
typically contain a number of the controllers, like the show controller, so that they have a number
of the options of microcontrollers, however they\'re still additional chip than microcontroller.
The cellular chipset typically includes a microprocessor/microcontroller that basically blurs the
lines. the newest generation of smartphones usually tend additional toward microprocessors for
the RF chipset, thus on provide the manufacturer flexibility by mistreatment software package
style instead of hardware style for a few options, however they are doing have additional items
of the hardware interface (rf, etc) on the chip itself.
The rest of the phone has many microcontrollers..
Given DataConsider MTU in Bit IP header16-bit Header320 bit.pdf
Given Data:
Consider MTU in Bit
IP header:16-bit
Header:320 bit
Appended header:420 bit
Target maximum packet size of:1500 bit
420 header bits for the transport layer, 320 header bits for the IP layer.
so total header=740
Bit to delivered at destination=1500-740=760
Solution
Given Data:
Consider MTU in Bit
IP header:16-bit
Header:320 bit
Appended header:420 bit
Target maximum packet size of:1500 bit
420 header bits for the transport layer, 320 header bits for the IP layer.
so total header=740
Bit to delivered at destination=1500-740=760.
Features that PLSQL shares with other standard programming language.pdf
Features that PL/SQL shares with other standard programming languages:
Solution
Features that PL/SQL shares with other standard programming languages:.
Draw two electron arrow towards Zn. somewhere in the middle between .pdf
Draw two electron arrow towards Zn. somewhere in the middle between zinc and oxygen ...make
sure it connects the zinc in the templet.
Solution
Draw two electron arrow towards Zn. somewhere in the middle between zinc and oxygen ...make
sure it connects the zinc in the templet..
Confidence IntervalCI = xSolutionConfidence IntervalCI = x.pdf
This document discusses confidence intervals but provides limited information. It states that a confidence interval is equal to x but does not define or explain the variable x. No other details are given about how to calculate or interpret confidence intervals.
A)2moles of calcium reacts with 1mole of O2 to fo.pdf
A)2moles of calcium reacts with 1mole of O2 to form 2moles of calcium oxide.
no.of terms of particular element on right side should be equal to left side here it is equal hence
the equation is balanced B)1mole of methane reacts with 2moles of O2 to form 2moles of
carbondioxide and 2moles of water
Solution
A)2moles of calcium reacts with 1mole of O2 to form 2moles of calcium oxide.
no.of terms of particular element on right side should be equal to left side here it is equal hence
the equation is balanced B)1mole of methane reacts with 2moles of O2 to form 2moles of
carbondioxide and 2moles of water.
AnswerTwo Yellow colored and two ebony colored fruit flies are pr.pdf
Answer:
Two Yellow colored and two ebony colored fruit flies are provided as mentioned in the question.
It is not known to us, of them, which one is the dominant trait for the body color character.
Case 1: Cross #1
Yellow colored fruit flies are crossed with ebony colored fruit flies and as a result all progeny
obtained in the F1 generation are of a single color- Ebony. This observation leads to the
impression that Ebony coloration is the dominant trait whereas Yellow is the recessive trait.
Both the parents are homozygous for the trait and are pure breeding varieties. If that would not
have been the case, in the F1 generation itself two variants- both Ebony and Yellow colored
progeny would have appeared.
According to Mendelian laws,
Let, \'Y\' be the factor responsible for Ebony coloration and \'y\' be the factor responsible for
Yellow coloration.
Thus, in the parental generation,
Genotype of the parent having Ebony coloration (homozygous pure breeding variety) - YY
Genotype of the parent having Yellow coloration (homozygous pure breeding variety) - yy
Hence, genotype of the progeny in F1 generation - Yy
Case 2 : Cross #2
In the present case it was observed that 113 Yellow fruit flies were obtained and 120 Ebony fruit
flies were obtained in the F1 generation as a result of a cross between an ebony & another yellow
fruit fly. So, in the F1 generation, both the variants were obtained almost approximately in 1:1
phenotypic ratio. Since both the variants were obtained, it may be concluded that parent bearing
ebony coloration was heterozygous whereas the yellow colored fly was a pure breeding variety.
Thus,
Genotype of the parent having Ebony coloration - Yy (heterozygous)
Genotype of the parent having Yellow coloration -yy (homozygous)
Ebony colored parent gives rise to two types of gametes- one bearing \'Y\' factor and the other
bearing \'y\' factor. Yellow colored parent gives rise to only gametes bearing \'y\' factor.
Gametes
Y
y
y
Yy (heterozygous ebony)
yy (homozygous yellow)
y
Yy
yy
Progeny obtained in the F1 generation have genotype Yy ( heterozygous ebony) and
yy(homozygous yellow).
Case 3: Cross #3
Two ebony offspring are crossed having genotype \'Yy\'.
Genotype of the progeny in F2 generation can be obtained by using checkerboard-
Gametes
Y
y
Y
YY (homozygous Ebony)
Yy (heterozygous ebony)
y
Yy (heterozygous ebony)
yy (homozygous yellow)
Thus, phenotypic rato between Ebony & Yellow colored fruit fly -3:1 (Ebony: Yellow)
Genotypic ratio in F2 generation - YY: Yy : yy - 1: 2: 1
Case 4 :Cross #4
Mating is performed between Ebony colored fruit fly #3 having genotype \'Yy\' and Ebony
colored fruit fly #2 having genotype \'YY\'. #3 ebony colored fly gives rise to to different types
of gametes- one bearing \'Y\' allele and the other bearing \'y\' allele for body color character.
The genotype and the phenotype of the progeny in this case can be obtained using checkerboard.
Gametes
Y
y
Y
YY ( homozygous ebony)
Yy (heterozygous ebony)
Y
YY
Yy
Th.
answer B) Cl - FF creates strong dipole momentfor a, trigonal pl.pdf
answer B) Cl - F
F creates strong dipole moment
for a, trigonal planar, dipole moment is distributed equally.
C, linear, also distributed equally
D) linear
E) tetrahedral, distributed equally
Solution
answer B) Cl - F
F creates strong dipole moment
for a, trigonal planar, dipole moment is distributed equally.
C, linear, also distributed equally
D) linear
E) tetrahedral, distributed equally.
ANSWER The events occuring in Complex I in order are 3, 2, 1, 4NA.pdf
ANSWER: The events occuring in Complex I in order are 3, 2, 1, 4
NADH is oxidized to NAD+ by reducing FMN to FMNH2 while oxidising Fe+2 to Fe+3 for the
electron transport. Finally the CoQ is reduced to CoQH2 after which the electron enters in
Complex II
Solution
ANSWER: The events occuring in Complex I in order are 3, 2, 1, 4
NADH is oxidized to NAD+ by reducing FMN to FMNH2 while oxidising Fe+2 to Fe+3 for the
electron transport. Finally the CoQ is reduced to CoQH2 after which the electron enters in
Complex II.
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Nope. When an atom is ionized it only affects the.pdf
Nope. When an atom is ionized it only affects the electrons in the electron cloud,
which is outside the nucleus. Let me know if this doesn\'t clear things up.
Solution
Nope. When an atom is ionized it only affects the electrons in the electron cloud,
which is outside the nucleus. Let me know if this doesn\'t clear things up..
L2^12 .pdf
This mathematical expression involves taking the length L and dividing it by the square root of 2. The expression is evaluating the square root of 2 applied to the length L. This can be used to calculate the diagonal length of a square with side length L.
In Atmospehere Pressure = 105760 = 0.138 Atmo.pdf
In Atmospehere : Pressure = 105/760 = 0.138 Atmosphere In Pascals: Pressure =
0.138 x 1.013 x 10^5 = 13995.4Pa
Solution
In Atmospehere : Pressure = 105/760 = 0.138 Atmosphere In Pascals: Pressure =
0.138 x 1.013 x 10^5 = 13995.4Pa.
H2SO4 is a strong electrolyte. It dissociates alm.pdf
H2SO4 is a strong electrolyte. It dissociates almost completely in water while rest
four compounds don\'t dissolve in water completely.
Solution
H2SO4 is a strong electrolyte. It dissociates almost completely in water while rest
four compounds don\'t dissolve in water completely..
DE is positive in exothermic reactions .pdf
DE is positive in exothermic reactions. Exothermic reactions release energy to the surroundings, so the system's energy decreases. Therefore, the change in energy (DE) for exothermic reactions is positive as energy is lost from the system.
The yield to maturity (YTM) is the measure of bonds rate of return t.pdf
The yield to maturity (YTM) is the measure of bonds rate of return that considers both the
interest income and any capital gain or loss. it should be noted that yield to maturity is not same
as current yield as current yield is the annual interest dividend by the bonds current value and
does not account for capital gain or loss.
YTM is important because it compare a bonds expected return with those of other securities
available in the market. YTM considers the three sources of potential return from a bond (coupon
payments, capital gains, and reinvestment returns which helps investors in Understanding how
yields vary with market prices (that as bond prices fall, yields rise; and as bond prices rise, yields
fall).it also helps investors to anticipate the effects of market changes on their portfolios. The
yield to maturity is expressed as an annual percentage rate
The following formula can be used to find out its approximate value:
APPROX YTM=C+F-P/n/F+P/2
Where
C=coupon value
F=face value
P=market price
And n=years to maturity
Solution
The yield to maturity (YTM) is the measure of bonds rate of return that considers both the
interest income and any capital gain or loss. it should be noted that yield to maturity is not same
as current yield as current yield is the annual interest dividend by the bonds current value and
does not account for capital gain or loss.
YTM is important because it compare a bonds expected return with those of other securities
available in the market. YTM considers the three sources of potential return from a bond (coupon
payments, capital gains, and reinvestment returns which helps investors in Understanding how
yields vary with market prices (that as bond prices fall, yields rise; and as bond prices rise, yields
fall).it also helps investors to anticipate the effects of market changes on their portfolios. The
yield to maturity is expressed as an annual percentage rate
The following formula can be used to find out its approximate value:
APPROX YTM=C+F-P/n/F+P/2
Where
C=coupon value
F=face value
P=market price
And n=years to maturity.
TDS (Total Dissolved Solids ) is a measure of the combined content o.pdf
Total dissolved solids is a measure of inorganic and organic substances in a liquid. The most accurate method to determine TDS involves evaporating the liquid and measuring the mass of residues, which in this case was found to be 22g. Total suspended solids refer to suspended or colloidal particles, which were calculated to be 25g.
magnesium oxide + water = magnesium hydroxideMgO (s) + H2O (l) =.pdf
magnesium oxide + water => magnesium hydroxide
MgO (s) + H2O (l) => Mg(OH)2 (s)
Solution
magnesium oxide + water => magnesium hydroxide
MgO (s) + H2O (l) => Mg(OH)2 (s).
Meiosis, inheritance and variationThe uniqueness and similarities.pdf
Meiosis, inheritance and variation:
The uniqueness and similarities within the closely related family members occurs because of
inherit traits in the form of genes are passing from one generation to another generation.
This gene passing from our ancestral parents to our parents is called as heredity. Replication is a
process of duplication of DNA. That occurs during the S phase of Eukaryotic cell cycle.
In identical small organisms these genes pass from one generation to next by duplication of their
genetic information and then splitting into two identical organisms. In complex organisms
specialized sex cells called gametes carry half of the genetic information. These gametes from
both male and female organisms combine each other and produce new organisms. The gametes
produced process is termed as meiosis.
Meiosis:
During this process 1 diploid cell which contains 46 chromosomes undergoes cell division into 2
cycles. In which only once DNA replication is takes place. it results 4 haploid daughter cells.
The zygote is formed from the combination of both an egg and a sperm cells. Zygotes have same
number of chromosomes it is due to the halving nature of the number of chromosomes in sexual
reproduction. This critical character stabilize chromosome numbers from one generation to next
generation.
Phases of meiosis:
Interphase: In this the DNA is prepared for replication. After completion of replication process
the structure of each chromosomes compressed into 2 identical chromatids.
Prophase I : In this chromosomes structure appeared as in X - Shaped. The homologous
chromosomes are pair up each other and crossing over takes placed. In this the DNA was
exchanged. the nuclear membrane was completely dissolved at end of this stage. The
Microtubules can attach to the chromosomes.
Metaphase I: The synopsized chromosomes are aliened at equator of the cell. The chromosomes
are aliened randomly in which different combinations each time meiosis occurs.
Anaphase I: During this phase the molecules of chromosomes separates and migrates towards to
2 poles of cell.
Telophase I or Cytokinesis: In this the cell divides into two daughter cells.
Prophase II : Same as Prophase I. But the DNA does not replicate again.
Metaphase II: The chromosomes aliened at equator, again the alignment is random.
Anaphase II: The chromosomes separates and migrates towards to 2 poles of cell.
Telophase II: The nucleoplasm is reformed and the cytoplasm is divides into 2 haploid daughter
cells and finally 4 new haploid daughter cells is formed.
Genetic variation is increased by meiosis due to the independent assortment nature in meiosis.
The reshuffling process of genes in meiosis is increasing the genetic variation in a population.
Solution
Meiosis, inheritance and variation:
The uniqueness and similarities within the closely related family members occurs because of
inherit traits in the form of genes are passing from one generation to another generation.
This gene passing from our an.
Inter-Process-Communication (or IPC for short) are mechanisms provid.pdf
Inter-Process-Communication (or IPC for short) are mechanisms provided by the kernel to allow
processes to communicate with each other.
The types of inter process communication on Linux OS are:
The following IPC mechanisms are supported by Windows:
1. Clipboard - The clipboard acts as a central depository for data sharing among applications.
When a user performs a cut or copy operation in an application, the application puts the selected
data on the clipboard in one or more standard or application-defined formats. Any other
application can then retrieve the data from the clipboard, choosing from the available formats
that it understands.
2. File Mapping - File mapping enables a process to treat the contents of a file as if they were a
block of memory in the process\'s address space. The process can use simple pointer operations
to examine and modify the contents of the file. When two or more processes access the same file
mapping, each process receives a pointer to memory in its own address space that it can use to
read or modify the contents of the file.
3. Mailslot - Mailslots provide one-way communication. Any process that creates a mailslot is a
mailslot server. Other processes, called mailslot clients, send messages to the mailslot server by
writing a message to its mailslot.
4. RPC - RPC enables applications to call functions remotely. Therefore, RPC makes IPC as easy
as calling a function. RPC operates between processes on a single computer or on different
computers on a network.
5. Windows Socket - Windows Sockets is a protocol-independent interface capable of supporting
current and emerging networking capabilities.
The following IPC mechanisms are supported by Mac OS:
1. Mach Ports : Mach 3.0 is capable of running as a stand-alone kernel, with other traditional OS-
services like IO, file systems and networking stack running as user mode.It is much faster to
make a direct call between linked components than it is to send messages or do RPC between
separate tasks.
2. Apple Events : Universally supported by GUI applications on Mac OS for remote
control.Operations like opening or telling an application to open a file or quit etc can be done
using these.
3. Pasteboard - Copy Paste , Drag and drop done between applications is performed using this
technique.
4. Distributed Objects - Remote messaging feature of Cocoa to call an object in different Cocoa
applicaton.
Windows server uses the best technique to manage IPC because
a) It provides an efficient way for two or more processes on the same computer to share data.
b) It is capable of supporting current and emerging networking capabilities, such as quality of
service monitoring, robust asynchronous communication, I/O completion ports for superior
performance, and protocol-specific network
features.
=> Multiprocessing : refers to the use of two or morecentral processing units (CPU) within a
single computer system.All the operating systems provide support for multiprocessing.
Windows manages.
B)120.0° note So3 is sp2-hybridized and adopts .pdf
B)120.0° note: So3 is sp2-hybridized and adopts a trigonal planar geometry.
Solution
B)120.0° note: So3 is sp2-hybridized and adopts a trigonal planar geometry..
imple cellular phones that do very little over voice and text line o.pdf
imple cellular phones that do very little over voice and text line of work generally include one
process unit that handles everything - computer programme (keyboard, display), RF process,
battery management, etc.
These ar SoC - Systems on Chip and ar nearer to microcontrollers than microprocessors as a
result of they decide to do everything - from process, to device interfacing, to memory, to
program and knowledge storage, etc - on one chip.
Smartphones have multiple microprocessors and microcontrollers in them. the most processor
could be a chip with a bus to speak with memory on separate chips (though usually contained
within the same IC package), and busses to speak with the remainder of the devices. they
typically contain a number of the controllers, like the show controller, so that they have a number
of the options of microcontrollers, however they\'re still additional chip than microcontroller.
The cellular chipset typically includes a microprocessor/microcontroller that basically blurs the
lines. the newest generation of smartphones usually tend additional toward microprocessors for
the RF chipset, thus on provide the manufacturer flexibility by mistreatment software package
style instead of hardware style for a few options, however they are doing have additional items
of the hardware interface (rf, etc) on the chip itself.
The rest of the phone has many microcontrollers. These management the touchscreen, audio,
sensors, cameras, etc.
So it depends on the kind of phone you are thinking of. an easy phone uses a microcontroller. a
posh phone uses each.
Solution
imple cellular phones that do very little over voice and text line of work generally include one
process unit that handles everything - computer programme (keyboard, display), RF process,
battery management, etc.
These ar SoC - Systems on Chip and ar nearer to microcontrollers than microprocessors as a
result of they decide to do everything - from process, to device interfacing, to memory, to
program and knowledge storage, etc - on one chip.
Smartphones have multiple microprocessors and microcontrollers in them. the most processor
could be a chip with a bus to speak with memory on separate chips (though usually contained
within the same IC package), and busses to speak with the remainder of the devices. they
typically contain a number of the controllers, like the show controller, so that they have a number
of the options of microcontrollers, however they\'re still additional chip than microcontroller.
The cellular chipset typically includes a microprocessor/microcontroller that basically blurs the
lines. the newest generation of smartphones usually tend additional toward microprocessors for
the RF chipset, thus on provide the manufacturer flexibility by mistreatment software package
style instead of hardware style for a few options, however they are doing have additional items
of the hardware interface (rf, etc) on the chip itself.
The rest of the phone has many microcontrollers..
Given DataConsider MTU in Bit IP header16-bit Header320 bit.pdf
Given Data:
Consider MTU in Bit
IP header:16-bit
Header:320 bit
Appended header:420 bit
Target maximum packet size of:1500 bit
420 header bits for the transport layer, 320 header bits for the IP layer.
so total header=740
Bit to delivered at destination=1500-740=760
Solution
Given Data:
Consider MTU in Bit
IP header:16-bit
Header:320 bit
Appended header:420 bit
Target maximum packet size of:1500 bit
420 header bits for the transport layer, 320 header bits for the IP layer.
so total header=740
Bit to delivered at destination=1500-740=760.
Features that PLSQL shares with other standard programming language.pdf
Features that PL/SQL shares with other standard programming languages:
Solution
Features that PL/SQL shares with other standard programming languages:.
Draw two electron arrow towards Zn. somewhere in the middle between .pdf
Draw two electron arrow towards Zn. somewhere in the middle between zinc and oxygen ...make
sure it connects the zinc in the templet.
Solution
Draw two electron arrow towards Zn. somewhere in the middle between zinc and oxygen ...make
sure it connects the zinc in the templet..
Confidence IntervalCI = xSolutionConfidence IntervalCI = x.pdf
This document discusses confidence intervals but provides limited information. It states that a confidence interval is equal to x but does not define or explain the variable x. No other details are given about how to calculate or interpret confidence intervals.
A)2moles of calcium reacts with 1mole of O2 to fo.pdf
A)2moles of calcium reacts with 1mole of O2 to form 2moles of calcium oxide.
no.of terms of particular element on right side should be equal to left side here it is equal hence
the equation is balanced B)1mole of methane reacts with 2moles of O2 to form 2moles of
carbondioxide and 2moles of water
Solution
A)2moles of calcium reacts with 1mole of O2 to form 2moles of calcium oxide.
no.of terms of particular element on right side should be equal to left side here it is equal hence
the equation is balanced B)1mole of methane reacts with 2moles of O2 to form 2moles of
carbondioxide and 2moles of water.
AnswerTwo Yellow colored and two ebony colored fruit flies are pr.pdf
Answer:
Two Yellow colored and two ebony colored fruit flies are provided as mentioned in the question.
It is not known to us, of them, which one is the dominant trait for the body color character.
Case 1: Cross #1
Yellow colored fruit flies are crossed with ebony colored fruit flies and as a result all progeny
obtained in the F1 generation are of a single color- Ebony. This observation leads to the
impression that Ebony coloration is the dominant trait whereas Yellow is the recessive trait.
Both the parents are homozygous for the trait and are pure breeding varieties. If that would not
have been the case, in the F1 generation itself two variants- both Ebony and Yellow colored
progeny would have appeared.
According to Mendelian laws,
Let, \'Y\' be the factor responsible for Ebony coloration and \'y\' be the factor responsible for
Yellow coloration.
Thus, in the parental generation,
Genotype of the parent having Ebony coloration (homozygous pure breeding variety) - YY
Genotype of the parent having Yellow coloration (homozygous pure breeding variety) - yy
Hence, genotype of the progeny in F1 generation - Yy
Case 2 : Cross #2
In the present case it was observed that 113 Yellow fruit flies were obtained and 120 Ebony fruit
flies were obtained in the F1 generation as a result of a cross between an ebony & another yellow
fruit fly. So, in the F1 generation, both the variants were obtained almost approximately in 1:1
phenotypic ratio. Since both the variants were obtained, it may be concluded that parent bearing
ebony coloration was heterozygous whereas the yellow colored fly was a pure breeding variety.
Thus,
Genotype of the parent having Ebony coloration - Yy (heterozygous)
Genotype of the parent having Yellow coloration -yy (homozygous)
Ebony colored parent gives rise to two types of gametes- one bearing \'Y\' factor and the other
bearing \'y\' factor. Yellow colored parent gives rise to only gametes bearing \'y\' factor.
Gametes
Y
y
y
Yy (heterozygous ebony)
yy (homozygous yellow)
y
Yy
yy
Progeny obtained in the F1 generation have genotype Yy ( heterozygous ebony) and
yy(homozygous yellow).
Case 3: Cross #3
Two ebony offspring are crossed having genotype \'Yy\'.
Genotype of the progeny in F2 generation can be obtained by using checkerboard-
Gametes
Y
y
Y
YY (homozygous Ebony)
Yy (heterozygous ebony)
y
Yy (heterozygous ebony)
yy (homozygous yellow)
Thus, phenotypic rato between Ebony & Yellow colored fruit fly -3:1 (Ebony: Yellow)
Genotypic ratio in F2 generation - YY: Yy : yy - 1: 2: 1
Case 4 :Cross #4
Mating is performed between Ebony colored fruit fly #3 having genotype \'Yy\' and Ebony
colored fruit fly #2 having genotype \'YY\'. #3 ebony colored fly gives rise to to different types
of gametes- one bearing \'Y\' allele and the other bearing \'y\' allele for body color character.
The genotype and the phenotype of the progeny in this case can be obtained using checkerboard.
Gametes
Y
y
Y
YY ( homozygous ebony)
Yy (heterozygous ebony)
Y
YY
Yy
Th.
answer B) Cl - FF creates strong dipole momentfor a, trigonal pl.pdf
answer B) Cl - F
F creates strong dipole moment
for a, trigonal planar, dipole moment is distributed equally.
C, linear, also distributed equally
D) linear
E) tetrahedral, distributed equally
Solution
answer B) Cl - F
F creates strong dipole moment
for a, trigonal planar, dipole moment is distributed equally.
C, linear, also distributed equally
D) linear
E) tetrahedral, distributed equally.
ANSWER The events occuring in Complex I in order are 3, 2, 1, 4NA.pdf
ANSWER: The events occuring in Complex I in order are 3, 2, 1, 4
NADH is oxidized to NAD+ by reducing FMN to FMNH2 while oxidising Fe+2 to Fe+3 for the
electron transport. Finally the CoQ is reduced to CoQH2 after which the electron enters in
Complex II
Solution
ANSWER: The events occuring in Complex I in order are 3, 2, 1, 4
NADH is oxidized to NAD+ by reducing FMN to FMNH2 while oxidising Fe+2 to Fe+3 for the
electron transport. Finally the CoQ is reduced to CoQH2 after which the electron enters in
Complex II.
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Preparation and standardization of the following : Tonic, Bleaches, Dentifrices and Mouth washes & Tooth Pastes, Cosmetics for Nails.
PCOS corelations and management through Ayurveda.
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Main Java[All of the Base Concepts}.docx
This is part 1 of my Java Learning Journey. This Contains Custom methods, classes, constructors, packages, multithreading , try- catch block, finally block and more.
The History of Stoke Newington Street Names
Presented at the Stoke Newington Literary Festival on 9th June 2024
www.StokeNewingtonHistory.com
Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
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This presentation was provided by Steph Pollock of The American Psychological Association’s Journals Program, and Damita Snow, of The American Society of Civil Engineers (ASCE), for the initial session of NISO's 2024 Training Series "DEIA in the Scholarly Landscape." Session One: 'Setting Expectations: a DEIA Primer,' was held June 6, 2024.Recently uploaded (20)
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The simplified electron and muon model, Oscillating Spacetime: The Foundation...
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A Survey of Techniques for Maximizing LLM Performance.pptx
A Survey of Techniques for Maximizing LLM Performance.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Chapter 4 - Islamic Financial Institutions in Malaysia.pptx
Assessment and Planning in Educational technology.pptx
Assessment and Planning in Educational technology.pptx
Pride Month Slides 2024 David Douglas School District
Pride Month Slides 2024 David Douglas School District
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Pollock and Snow "DEIA in the Scholarly Landscape, Session One: Setting Expec...
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HOCl (aq) + HCI(aq) - H2O(l) + Cl2 (g) 6Cl2(g) +.pdf
- 1. HOCl (aq) + HCI(aq) -> H2O(l) + Cl2 (g) 6Cl2(g) + 12NaOH(aq) -> 10NaCl (aq) + 2NaCIO3(aq) + 6H2O(l) MgCO3(aq) +2HCI (aq) -> MgCl2(aq) + H2O(l) + CO2 (g) Solution HOCl (aq) + HCI(aq) -> H2O(l) + Cl2 (g) 6Cl2(g) + 12NaOH(aq) -> 10NaCl (aq) + 2NaCIO3(aq) + 6H2O(l) MgCO3(aq) +2HCI (aq) -> MgCl2(aq) + H2O(l) + CO2 (g)