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Hi I have met this function but I didn't understand how it came with this answer!
1/2(1+1/2+1/4+...+(1/2)^k-1) = 1/2( 1-(1/2)^k / 1-1/2)
Solution
sum of terms in a geomentric progression a, ar, ar^2,ar^3,.......ar^n-1 = a(1 - r^m)/(1 - r)
applying it here with r=1/2,a =1/2. n =k, you get it

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Hi I have met this function but I didnt understand how it came wit.pdf

  • 1. Hi I have met this function but I didn't understand how it came with this answer! 1/2(1+1/2+1/4+...+(1/2)^k-1) = 1/2( 1-(1/2)^k / 1-1/2) Solution sum of terms in a geomentric progression a, ar, ar^2,ar^3,.......ar^n-1 = a(1 - r^m)/(1 - r) applying it here with r=1/2,a =1/2. n =k, you get it