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Green House Effect and
   Global Warming
Do you believe that the planet is
           warming?
1. Yes
2. No




                    0%     0%

                    1       2
If you believe that the planet is warming, do you
 believe that human activity has contributed to the
                       warming?
1. Yes                        100%
2. No




                                           0%

                                1            2
Do you believe that there is a lot of
 controversy in the scientific community abut
      climate change (global warming)?
1. Yes                       80%
2. No




                                     20%




                            1          2
Simplest Picture
 How can we calculate a planet’s
  temperature?
 Assume on average that the energy that is
  coming to us from the sun (mostly in the
  form of visible light) is balanced by radiation
  from the planet (mostly in the form of
  infrared light) (EQUILIBRIUM)
 If we are radiating faster than we receive
  energy we will cool down.
 If we are receiving energy faster than we
  reradiate it, we heat up.
 Eventually we will come to a new
  equilibrium at a new temperature.
How much power do we get?
 We know that 99.98% of the energy flow
  coming to the earth is from the sun. (We will
  ignore the other .02%, mostly geothermal.)
 At a distance the of 1A.U. (1 astronomical
  unit is the distance from the sun to the
  earth) the energy from the sun is 1368 W/m 2
  on a flat surface (solar constant).
Solar Constant
Measured Solar Constant
Reconstructed Solar Constant
 Power we get form the
  sun is the solar
  constant, S, times an
  area equal to a flat
  circle with the radius of
  the earth.
 P=Sπ(RE)2
 Note: Energy is not
  uniformly distributed
  because earth’s
  surface is curved.
How much energy do we lose?
 Start simple: In equilibrium, we lose exactly
  as much as we get, but we reradiate the
  energy from the entire surface if the earth.
                     P=σeAET4
 where AE=4π (RE)2
Energy balance




πR S = eσ (4πR )T
  2
  E
                2
                E
                    4


S
   = eσT 4
4
Still an energy balance equation,
but on a per - sqaure meter basis
 The factor of 4 accounts for two effects:
  – 1) Half of the earth is always in the dark (night)
    so it does not receive any input from the sun.
    (factor of 2)
  – 2) The earth is a sphere so the sun’s light is
    spread out more than if it was flat. (another
    factor of two.)
  – Note: This equation works for any planet, not
    just earth, if we know the value of S for that
    planet. (easy since it just depends on the
    distance from the sun)
Subtleties in the equation.
 First, we need to know the emissivity, e. For
  planets like earth that radiate in the infrared, this is
  very close to 1.
 Second, not all of the light from the sun is
  absorbed. A good fraction is reflected directly
  back into space and does not contribute to the
  energy balance. For earth it is approximately 31%
  of light is reflected.
 Thus the correct value for S/4 is
  0.69*(1368/4)=235W/m2.
Calculate an approximate global
       average temperature

              s
                = σeT  4

              4
                     −8
235W / m = (5.67 × 10 W / m K )(1)T
        2                  2 4      4


          T = 4.14 ×10 K
            4          9


            T = 254 K
Is this a reasonable answer.
 254 K is -19°C or -2°F.
 It is in the right ballpark, and it just represents and
  average including all latitudes including the poles,
  BUT, the actual average global surface
  temperature is about 287K.
Note: This is a zero-dimensional model since we
  have taken the earth as a point with no structure.
  If we look at the earth from space with an infrared
  camera, we would see the top of the atmosphere,
  and 254K is not a bad estimate.
Why is the estimate 33°C too low at
            the surface?
 Just as different rooms in a house may have
  different temperatures, the earth actually has
  many different regions (tropic, polar, forest, desert,
  high altitude, low altitude, etc.) which have
  different temperatures.
 Full scale models must account for all of this, but
  require large computers to solve the models.
 We will lump our planet into two regions, an
  atmosphere and the ground. The results are
  simple, yet account for much of the observed
  phenomena.
 As we saw in the section on light, most of
  the light from the sun is in the visible
  spectrum. This light passes right through
  the atmosphere with very little absorbed.
 The light that the earth emits is in the
  infrared. A large part of this get absorbed by
  the atmosphere (Water Carbon Dioxide,
  etc).
 The atmosphere acts like a nice blanket for
  the surface.
 Without our blanket, the surface of the earth
  would be quite cold.
 The difference between our 254K estimate and
  the 287K actual surface temperature is due to
  naturally occurring greenhouse gasses.
 The predominant greenhouse gasses are water
  vapor and to a much lesser extent, carbon
  dioxide.
 Note: during the last ice age the average global
  temperature was 6°C lower than today.
  Without a natural greenhouse effect, the
  temperature would be 33°C lower.
 With the atmosphere present, the surface must
  radiate at a higher σeT4 since not as much energy is
  escaping.
 In addition a lot of the energy absorbed by the
  atmosphere is reradiated back to the earth, further
  driving up the temperature.
Simple two level model
 Incoming energy to the surface/atmosphere
  is still 235 W/m2.
 Outgoing energy has two parts: One is
  infrared radiation from the atmosphere, the
  other is infrared radiation from the surface.
 Notes:1) The temperatures of the
  atmosphere and the surface do not have to
  be the same.
 2)The sum of the two outgoing energy fluxes
  must still equal the incoming energy fluxes.
 Note that the arrow representing the IR from
  the surface tapers as it passes through the
  atmosphere. This is to indicate that part of
  the energy is being absorbed. The amount
  depends on the concentration of
  greenhouse gasses.
 The emissivity of a particular gas also
  reflects the amount of energy that a
  particular gas will absorb. We may also call
  it the absorptivity.
 If we start with a surface radiation of
                 Ps=σTs4
 and we absorb an amount
             Pabsorbed= ea σTs4
 We have a total surface radiation actually
  reaching space of
                 Ps=(1-ea)σTs4
 In addition to this we have power radiated
  directly from the atmosphere:
                 P a = e σT a 4
Total power radiated to space
Power radiated to space = (1-e a)σTs4 + eσTa4
                 OR since ea = e
Power radiated to space = σTs4 - eσ(Ts4 -Ta4)


 Note: Assuming that Ts>Ta ,the second term
  on the RHS is negative. This means that the
  surface temperature must higher than in the
  absence of the atmosphere in order to
  radiate enough energy to stay in equilibrium.
 Notes:
 1) For a given concentration of greenhouse
  gasses (i.e. given e) a colder atmosphere
  actually enhance the greenhouse effect.
 2) If e=0, we recover our old result of no
  atmosphere.
More complete picture.
 A 2005 study suggest that currently we
  receive approximately 0.85 W/m 2 more than
  we are radiating.

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Global Warming Belief and Controversy Survey

  • 1. Green House Effect and Global Warming
  • 2. Do you believe that the planet is warming? 1. Yes 2. No 0% 0% 1 2
  • 3. If you believe that the planet is warming, do you believe that human activity has contributed to the warming? 1. Yes 100% 2. No 0% 1 2
  • 4. Do you believe that there is a lot of controversy in the scientific community abut climate change (global warming)? 1. Yes 80% 2. No 20% 1 2
  • 5.
  • 6. Simplest Picture  How can we calculate a planet’s temperature?  Assume on average that the energy that is coming to us from the sun (mostly in the form of visible light) is balanced by radiation from the planet (mostly in the form of infrared light) (EQUILIBRIUM)
  • 7.  If we are radiating faster than we receive energy we will cool down.  If we are receiving energy faster than we reradiate it, we heat up.  Eventually we will come to a new equilibrium at a new temperature.
  • 8. How much power do we get?  We know that 99.98% of the energy flow coming to the earth is from the sun. (We will ignore the other .02%, mostly geothermal.)  At a distance the of 1A.U. (1 astronomical unit is the distance from the sun to the earth) the energy from the sun is 1368 W/m 2 on a flat surface (solar constant).
  • 10.
  • 13.  Power we get form the sun is the solar constant, S, times an area equal to a flat circle with the radius of the earth.  P=Sπ(RE)2  Note: Energy is not uniformly distributed because earth’s surface is curved.
  • 14. How much energy do we lose?  Start simple: In equilibrium, we lose exactly as much as we get, but we reradiate the energy from the entire surface if the earth. P=σeAET4 where AE=4π (RE)2
  • 15. Energy balance πR S = eσ (4πR )T 2 E 2 E 4 S = eσT 4 4 Still an energy balance equation, but on a per - sqaure meter basis
  • 16.  The factor of 4 accounts for two effects: – 1) Half of the earth is always in the dark (night) so it does not receive any input from the sun. (factor of 2) – 2) The earth is a sphere so the sun’s light is spread out more than if it was flat. (another factor of two.) – Note: This equation works for any planet, not just earth, if we know the value of S for that planet. (easy since it just depends on the distance from the sun)
  • 17. Subtleties in the equation.  First, we need to know the emissivity, e. For planets like earth that radiate in the infrared, this is very close to 1.  Second, not all of the light from the sun is absorbed. A good fraction is reflected directly back into space and does not contribute to the energy balance. For earth it is approximately 31% of light is reflected.  Thus the correct value for S/4 is 0.69*(1368/4)=235W/m2.
  • 18. Calculate an approximate global average temperature s = σeT 4 4 −8 235W / m = (5.67 × 10 W / m K )(1)T 2 2 4 4 T = 4.14 ×10 K 4 9 T = 254 K
  • 19. Is this a reasonable answer.  254 K is -19°C or -2°F.  It is in the right ballpark, and it just represents and average including all latitudes including the poles, BUT, the actual average global surface temperature is about 287K. Note: This is a zero-dimensional model since we have taken the earth as a point with no structure. If we look at the earth from space with an infrared camera, we would see the top of the atmosphere, and 254K is not a bad estimate.
  • 20. Why is the estimate 33°C too low at the surface?  Just as different rooms in a house may have different temperatures, the earth actually has many different regions (tropic, polar, forest, desert, high altitude, low altitude, etc.) which have different temperatures.  Full scale models must account for all of this, but require large computers to solve the models.  We will lump our planet into two regions, an atmosphere and the ground. The results are simple, yet account for much of the observed phenomena.
  • 21.  As we saw in the section on light, most of the light from the sun is in the visible spectrum. This light passes right through the atmosphere with very little absorbed.  The light that the earth emits is in the infrared. A large part of this get absorbed by the atmosphere (Water Carbon Dioxide, etc).  The atmosphere acts like a nice blanket for the surface.
  • 22.  Without our blanket, the surface of the earth would be quite cold.  The difference between our 254K estimate and the 287K actual surface temperature is due to naturally occurring greenhouse gasses.  The predominant greenhouse gasses are water vapor and to a much lesser extent, carbon dioxide.  Note: during the last ice age the average global temperature was 6°C lower than today. Without a natural greenhouse effect, the temperature would be 33°C lower.
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  • 25.  With the atmosphere present, the surface must radiate at a higher σeT4 since not as much energy is escaping.  In addition a lot of the energy absorbed by the atmosphere is reradiated back to the earth, further driving up the temperature.
  • 27.  Incoming energy to the surface/atmosphere is still 235 W/m2.  Outgoing energy has two parts: One is infrared radiation from the atmosphere, the other is infrared radiation from the surface.  Notes:1) The temperatures of the atmosphere and the surface do not have to be the same.  2)The sum of the two outgoing energy fluxes must still equal the incoming energy fluxes.
  • 28.  Note that the arrow representing the IR from the surface tapers as it passes through the atmosphere. This is to indicate that part of the energy is being absorbed. The amount depends on the concentration of greenhouse gasses.  The emissivity of a particular gas also reflects the amount of energy that a particular gas will absorb. We may also call it the absorptivity.
  • 29.  If we start with a surface radiation of Ps=σTs4  and we absorb an amount Pabsorbed= ea σTs4  We have a total surface radiation actually reaching space of Ps=(1-ea)σTs4  In addition to this we have power radiated directly from the atmosphere: P a = e σT a 4
  • 30. Total power radiated to space Power radiated to space = (1-e a)σTs4 + eσTa4 OR since ea = e Power radiated to space = σTs4 - eσ(Ts4 -Ta4)  Note: Assuming that Ts>Ta ,the second term on the RHS is negative. This means that the surface temperature must higher than in the absence of the atmosphere in order to radiate enough energy to stay in equilibrium.
  • 31.  Notes:  1) For a given concentration of greenhouse gasses (i.e. given e) a colder atmosphere actually enhance the greenhouse effect.  2) If e=0, we recover our old result of no atmosphere.
  • 33.  A 2005 study suggest that currently we receive approximately 0.85 W/m 2 more than we are radiating.