The document describes a geometric distribution problem where a state trooper checks cars for speeding and the probability of catching a speeding teenager is 47%. The question asks for the probability that the first speeding teenager caught is the third car of the day. Using the geometric distribution formula of P(x)=(p)(q)^(x-1), where p is the probability of success (47%) and q is the probability of failure (1-p or 53%), the solution is calculated as P(3)=0.47*(0.53)^2=0.132023 or a 13.2% probability.

1. Geometric Distribution By Kyle Sawin

2. The problem A Statey is camping on the side of a straight side road and checks for passing cars speeds. In his experience the chance of catching a teenager speeding is 47% chance. Find the probability that the first teenager caught speeding is the third person of the day.

3. Step One First you use the formula of P(x)=p(q) Where q=1-p. X-1 P(3)= .47 X (.53) 2 X=number caught=3 p=probability=.47 q=1-p=.53

4. The Answer P(3)= .47 X (.53) =.132023 So the chance of the statey catching his first teenager on his third person of the day is 13.2% 2 THE END