This document involves solving a system of equations for the forces and torques acting on a structure. It finds that the vertical forces are yb = 32.5 tons, ye = 53.125 tons, and yh = 34.375 tons by setting the sum of the torques equal to zero at two points and the sum of the vertical forces equal to the total load. It verifies the solution by checking the sum of torques at a third point is also equal to zero.

2. ∑Fx = zero
10-Xb+20=0
Xb=30

3. ∑Fy = zero
yb+ye+yh=15+20+15+20*3+10*1
yb+ye+yh=120

4. ∑M@d from left side = zero
-15*3+yb*2-20*1=0
yb=32.5 ton

5. ∑M@d from right side = zero
-ye*1 + 15*2 + 20*3*2.5 +
10*1*4.5 - yh*5 = 0
ye + 5yh = 225

6. yb + ye + yh=120 yb=32.5 ton
ye + yh = 87.5 eq 1
ye + 5yh = 225 eq 2
from eq 1&2 ye = 53.125 yh = 34.375

7. ∑M@h = ????
-15*8 + 32.5*7 – 20*6 + 53.125*4
– 15*3 – 20*3*2.5 – 10*1*0.5
= zero ✓