Find the current through a 5-H inductor if the voltage across it is Also find the energy stored within 0 < t < 5s. Assume i(0)=0. 3012 t0 v(t) , Solution Here in the equation we have, Ldi/dt= v(t). or di/dt=v(t)/L. Sub the values we have di/dt=30t 2 /5. or di/dt=6t 2. Now inorder to find the current we have to integrate on bothsides of the above expression. or i=6t 3 /3. i=2t 3. Ampere. Now the energy stored E=1/2LI 2 = 1/2*5*(2t 3 ) 2 =1/2*20*4t 6 =[ 1/2*20*4*5 6 ]=156.25kwatts.[sub the value of t=5s] .