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Dynamic Modeling II Outline ,[object Object],[object Object],[object Object],[object Object],[object Object]
Calcium Ion Channel in Cells Consider a Model of a Calcium Ion Channel in a cell membrane Channel has three States ,[object Object],[object Object],[object Object],Inactive Open Closed k + 1 K + 2 K - 2 K - 1 x i  = fraction of channels in a given state i Ca 2+ Ca 2+ =Ca 2+ d Ca 2+ Low High
Fast & Slow Timescales If the time scale of activation is much faster than that of inactivation we can use these two different timescales to simplify the problem. k 1 >>k 2 Scale time by the slow reaction constant: Substitute into equations and look for “small parameter”  <<1 ratio of slow to fast timescales
Slow Timescale Analysis continued The second equation becomes: Now allow     0 From either equation: “ rapid equilibrium” between the open and closed channels quasi-steady state
Slow timescale continued Rapid equilibrium between open and closed, now we need a differential equation independent of   Add the two equations: Let Combined fractions of open and closed channels Have to eliminate x o  from this
Slow Timescale Ion Channel From algebraic equation: y(0)=1 Differential Equation for y:
Fast Timescale Fast Timescale Differential Equations
Summary ,[object Object],[object Object],[object Object],[object Object],[object Object]
Another Example T o T R T wo T wi m w C pw m R C pR k w Heat Transfer across a reactor wall State Variables, T W  and T R , note T W  already lumped. Q R
Heat Transfer Continued Rearrange the Equations for T w  and T R [time] -1 Slow time scale Transfer Rate across wall small compared to the thermal mass of reactor
Heat Transfer Continued The Thermal Mass of Reactor is large compared to the wall,    is  ratio of wall to reactor thermal mass . The wall temperature is just the average at slow time scale.
Heat Transfer Continued Eliminate T W  by using the relationship from the previous result Now solve the ODE
Fast Timescale Allow     0 Ratio of rate of heat transfer to thermal mass of the wall is large. Now solve the ODE and substitute into AE Implicitly Q R  must also be slow

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Fast Slow Timescale Analysis.1

  • 1.
  • 2.
  • 3. Fast & Slow Timescales If the time scale of activation is much faster than that of inactivation we can use these two different timescales to simplify the problem. k 1 >>k 2 Scale time by the slow reaction constant: Substitute into equations and look for “small parameter”  <<1 ratio of slow to fast timescales
  • 4. Slow Timescale Analysis continued The second equation becomes: Now allow   0 From either equation: “ rapid equilibrium” between the open and closed channels quasi-steady state
  • 5. Slow timescale continued Rapid equilibrium between open and closed, now we need a differential equation independent of  Add the two equations: Let Combined fractions of open and closed channels Have to eliminate x o from this
  • 6. Slow Timescale Ion Channel From algebraic equation: y(0)=1 Differential Equation for y:
  • 7. Fast Timescale Fast Timescale Differential Equations
  • 8.
  • 9. Another Example T o T R T wo T wi m w C pw m R C pR k w Heat Transfer across a reactor wall State Variables, T W and T R , note T W already lumped. Q R
  • 10. Heat Transfer Continued Rearrange the Equations for T w and T R [time] -1 Slow time scale Transfer Rate across wall small compared to the thermal mass of reactor
  • 11. Heat Transfer Continued The Thermal Mass of Reactor is large compared to the wall,  is ratio of wall to reactor thermal mass . The wall temperature is just the average at slow time scale.
  • 12. Heat Transfer Continued Eliminate T W by using the relationship from the previous result Now solve the ODE
  • 13. Fast Timescale Allow   0 Ratio of rate of heat transfer to thermal mass of the wall is large. Now solve the ODE and substitute into AE Implicitly Q R must also be slow