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3er. y 4to. grado
32
MATEMÁTICA
EXPERIENCIA 9
SECUNDARIA
Actividad 6
Elaboramos un cono-
maceta para la conservación
de plantas oriundas
de nuestro Perú
MATEMÁTICA
Semana 32
ACTIVIDAD 6
¿QUÉ ES UN CONO?
¿CÓMO SE GENERA UN CONO?
es un círculo
𝝅= 3,14
FÓRMULAS DEL CONO
AREA LATERAL:
AL = 𝝅 𝐫 g
AREA TOTAL:
AT = 𝝅 𝐫 g + 𝛑 𝐫𝟐
AT = 𝝅 𝐫 (g + 𝐫)
VOLUMEN:
V =
𝟏
𝟑
𝛑 𝐫𝟐
𝐡
h
𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐
𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐
AT = 𝝅 𝐫 (g + 𝐫)
h
𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐
𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐
AT = 𝝅 𝐫 (g + 𝐫)
h
𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐
𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐
AT = 𝝅 𝐫 (g + 𝐫)
h
𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐
𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐
AT = 𝝅 𝐫 (g + 𝐫)
h
𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐
𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐
AT = 𝝅 𝐫 (g + 𝐫)
h
𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐
𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐
AT = 𝝅 𝐫 (g + 𝐫)
h
𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐
𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐
AT = 𝝅 𝐫 (g + 𝐫)
h
𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐
𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐
AT = 𝝅 𝐫 (g + 𝐫)
a) Se construyó uniendo su
área lateral con un círculo
b) Forma antes de ser armado c) Partes del Cono
Altura: 20 cm
Radio: 7,5 cm
Diámetro: 15 cm
Generatriz: 21,5 cm
Ya no es un sólido, ahora es una figura plana.
Tiene la forma de una porción de un círculo.
Esta pieza obtenida se le llama Sector
circular.
A los lados que estaban unidos e les
llama Generatriz.
Las medidas son las mismas.
CONCLUSION: Para construir un cono
es necesario utilizar un sector circular.
Hipotenusa
… Y YA VIENE LA
SEGUNDA PARTE DEL
VIDEO
GRACIAS POR VER EL VIDEO
¡SUSCRÍBETE!
Autor : Eduardo Plasencia Alvarado.
Doctor en Educación.
Especialista en Ciencias Matemáticas.
Visita : www.epamatematicas.blogspot.pe
MATEMATICA FACIL

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Experiencia 9 act.6 3°y4°

  • 1. 3er. y 4to. grado 32 MATEMÁTICA EXPERIENCIA 9 SECUNDARIA Actividad 6 Elaboramos un cono- maceta para la conservación de plantas oriundas de nuestro Perú
  • 3.
  • 4.
  • 5.
  • 6. ¿QUÉ ES UN CONO?
  • 7. ¿CÓMO SE GENERA UN CONO?
  • 8.
  • 11. FÓRMULAS DEL CONO AREA LATERAL: AL = 𝝅 𝐫 g AREA TOTAL: AT = 𝝅 𝐫 g + 𝛑 𝐫𝟐 AT = 𝝅 𝐫 (g + 𝐫) VOLUMEN: V = 𝟏 𝟑 𝛑 𝐫𝟐 𝐡
  • 12.
  • 13. h 𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐 𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐 AT = 𝝅 𝐫 (g + 𝐫)
  • 14. h 𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐 𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐 AT = 𝝅 𝐫 (g + 𝐫)
  • 15. h 𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐 𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐 AT = 𝝅 𝐫 (g + 𝐫)
  • 16. h 𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐 𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐 AT = 𝝅 𝐫 (g + 𝐫)
  • 17. h 𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐 𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐 AT = 𝝅 𝐫 (g + 𝐫)
  • 18. h 𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐 𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐 AT = 𝝅 𝐫 (g + 𝐫)
  • 19. h 𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐 𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐 AT = 𝝅 𝐫 (g + 𝐫)
  • 20. h 𝟖𝟏 = 𝟕𝟐 + 𝒓𝟐 𝟖𝟏 − 𝟕𝟐 = 𝒓𝟐 AT = 𝝅 𝐫 (g + 𝐫)
  • 21.
  • 22.
  • 23.
  • 24.
  • 25.
  • 26. a) Se construyó uniendo su área lateral con un círculo b) Forma antes de ser armado c) Partes del Cono
  • 27. Altura: 20 cm Radio: 7,5 cm Diámetro: 15 cm Generatriz: 21,5 cm
  • 28. Ya no es un sólido, ahora es una figura plana. Tiene la forma de una porción de un círculo. Esta pieza obtenida se le llama Sector circular. A los lados que estaban unidos e les llama Generatriz. Las medidas son las mismas. CONCLUSION: Para construir un cono es necesario utilizar un sector circular.
  • 29.
  • 31. … Y YA VIENE LA SEGUNDA PARTE DEL VIDEO
  • 32.
  • 33.
  • 34. GRACIAS POR VER EL VIDEO ¡SUSCRÍBETE! Autor : Eduardo Plasencia Alvarado. Doctor en Educación. Especialista en Ciencias Matemáticas. Visita : www.epamatematicas.blogspot.pe MATEMATICA FACIL