Evaluate whether above integral converge or not. if not, evaluate it. thank you e infinity 1 / x(ln
x)2 d x
Solution
Substitute y= lnx then dy= (1/x) dx I= integral( dy/y^2)) From y= lne to ln (inf) =
-1/y from y= 1 to infinity =0-(-1) =1.
Evaluate whether above integral converge or not. if not, evaluate it.pdf
1. Evaluate whether above integral converge or not. if not, evaluate it. thank you e infinity 1 / x(ln
x)2 d x
Solution
Substitute y= lnx then dy= (1/x) dx I= integral( dy/y^2)) From y= lne to ln (inf) =
-1/y from y= 1 to infinity =0-(-1) =1