The document discusses a nonhomogeneous Poisson process with a specific mean value function. It calculates the probability of 'n' events occurring between time t = 4 and t = 5, finding the rate parameter (lambda) to be 88/3. The final probability expression is given by e^(-88/3)*(88/3)^n/n!.

1. Events occur according to a nonhomogeneous Poisson process whose mean value function is
given by: m(t) = t2 + 2t. What is the probability that n events occur between t = 4 and t = 5?
Solution
When I integrate I obtain 88/3 as lamda. Then I would say e^(-88/3)*(88/3)^n/n!
which is the definition of Poisson or probability of n events with 88/3 as lamda.