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Events occur according to a nonhomogeneous Poisson process whose mean value function is
given by: m(t) = t2 + 2t. What is the probability that n events occur between t = 4 and t = 5?
Solution
When I integrate I obtain 88/3 as lamda. Then I would say e^(-88/3)*(88/3)^n/n!
which is the definition of Poisson or probability of n events with 88/3 as lamda.

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  • 1. Events occur according to a nonhomogeneous Poisson process whose mean value function is given by: m(t) = t2 + 2t. What is the probability that n events occur between t = 4 and t = 5? Solution When I integrate I obtain 88/3 as lamda. Then I would say e^(-88/3)*(88/3)^n/n! which is the definition of Poisson or probability of n events with 88/3 as lamda.