EARTH GEOMETRY
Locating Places on the
Earth
Two places on the same
longitude but different
latitudes.
Both south of equator?
 If yes, subtract the
latitudes, to find
difference.
Both north of equator?
 If yes, subtract the
latitudes to find the
difference.
One south of equator &
another north?
 If yes, add the
latitudes
Two places on the same
latitude but different
longitudes.
Both east of Greenwich?
 If yes, subtract
longitudes
Both west of Greenwich?
 If yes, subtract
longitudes
One east & another west?
 If yes, add longitudes
Distance Along Places
The circle of latitude
∅° 𝑁 𝑜𝑟 ∅° 𝑆 has radius 𝑟 =
𝑅𝑐𝑜𝑠∅, where R=radius of
the Earth.
Arc length=
2𝜋𝑟𝜃
360
Examples.
1.Given that the radius of the
earth is 6400km, find
(i)The length of the parallel
latitude 30°𝑁
(ii)The shortest distance
along the surface of the
earth from town Q
(30°𝑁,10°𝐸)to town P
(30°𝑁,50°𝑊
Solution
(i)
Given that R=6400km
∅ = 30° 𝑁, ∅ = 30°
Length=2𝜋𝑟
r=Rcos∅
=2×
22
7
× 6400 × 𝑐𝑜𝑠30
=34,839km
(ii)
2𝜋𝑟𝜃
360
=
2×
22
7
×6400×𝑐𝑜𝑠30×60
360
=
5806𝑘𝑚
𝜃 = 10 + 50 = 60°
r=Rcos∅

Earth geometry

  • 1.
    EARTH GEOMETRY Locating Placeson the Earth Two places on the same longitude but different latitudes. Both south of equator?  If yes, subtract the latitudes, to find difference. Both north of equator?  If yes, subtract the latitudes to find the difference. One south of equator & another north?  If yes, add the latitudes
  • 2.
    Two places onthe same latitude but different longitudes. Both east of Greenwich?  If yes, subtract longitudes Both west of Greenwich?  If yes, subtract longitudes One east & another west?  If yes, add longitudes Distance Along Places The circle of latitude ∅° 𝑁 𝑜𝑟 ∅° 𝑆 has radius 𝑟 = 𝑅𝑐𝑜𝑠∅, where R=radius of the Earth. Arc length= 2𝜋𝑟𝜃 360
  • 3.
    Examples. 1.Given that theradius of the earth is 6400km, find (i)The length of the parallel latitude 30°𝑁 (ii)The shortest distance along the surface of the earth from town Q (30°𝑁,10°𝐸)to town P (30°𝑁,50°𝑊 Solution (i) Given that R=6400km ∅ = 30° 𝑁, ∅ = 30° Length=2𝜋𝑟 r=Rcos∅ =2× 22 7 × 6400 × 𝑐𝑜𝑠30 =34,839km (ii) 2𝜋𝑟𝜃 360 = 2× 22 7 ×6400×𝑐𝑜𝑠30×60 360 = 5806𝑘𝑚 𝜃 = 10 + 50 = 60° r=Rcos∅