Cheryl Haworth lifted a total weight of 155 kilograms in an Olympic clean-and-jerk event. This included a 15 kg bar and plates weighing 25 kg (lifted 4 times) and 20 kg (lifted 2 times). An expression to calculate the total weight lifted is 15 + (4 x 25) + (2 x 20) = 155 kg. The document then discusses using the distributive property to solve equations by distributing multiplication to terms within parentheses. It provides examples such as 10(5 + 8) = 10(5) + 10(8) = 50 + 80 = 130. Students will learn to use the distributive property and solve one-step equations by isolating

1. Bell Ringer
• In an Olympic clean-and-jerk event, Cheryl Haworth lifted one
15 kilogram bar, four plates that weighed 25 kilograms and 2
plates that each weighed 20 kilograms. Write and evaluate an
expression to find the total weight lifted.

2. Bell Ringer
• In an Olympic clean-and-jerk event, Cheryl Haworth lifted one
15 kilogram bar, four plates that weighed 25 kilograms and 2
plates that each weighed 20 kilograms. Write and evaluate an
expression to find the total weight lifted.
• 15 + (4 x 25) + (2 x 20)
• 155 kg

3. Where we were…
• Commutative Property of Addition
• Associative Property of Addition
• Identity Property of Addition
• Distributive Property
• Properties worksheet

4. Where we are…
• Students will learn to…
• Use the distributive property to solve problems.
• Solve one-step equations

5. Distributive Property
• When you multiply a factor by a sum (or difference), the
product is the same as multiplying the factor by each term and
then adding (or subtracting) the products.
• Arithmetic Example Algebra
• 4(5 + 9) = 4(5) + 4(9) p(x + q) = px + pq
• 4(14) = 20 + 36
• 56 = 56

6. Distributive Property
• 10(5 + 8)
• 3 (9 + 11)

7. Distributive Property
• 10(5 + 8)
• (10 x 5) + (10 x 8)
• 50 + 80
• 130
• 3 (9 + 11)
• (3 x 9) + (3 x 11)
• 27 + 33
• 60

8. Can you use the Distributive
Property to solve this problem?
• 3(87)
• 3(80 + 7)
• 240 + 21
• 261

9. Writing equations
• A number plus six equals 45.
• y + 6 = 45
• A number minus 12 equals 10.
• n – 12 = 10
• Seven added to a number equals 100.
• x + 7 = 100
• 20 subtracted from a number equals 7.
• n – 20 = 7

10. Key Vocabulary for Solving
Equations
• Inverse operation
• Zero Pairs
• Isolate
• Addition Property of Equality
• If you add the same value to each side of an equations, the two
sides remain equal.
• Subtraction Property of Equality
• If you subtract the same value from each side of an equation, the
two sides remain equal.

11. Solving Equations Algebraically
• y + 6 = 45 Goal: Isolate the variable
Question: How can get the
variable by itself?
Think… What is the inverse operation of addition?
or
Think… What is the opposite of adding 6?
or
Think… What is a zero pair to +6?

12. Solving Equations Algebraically
• y + 6 = 45
• -6 -6
• y = 39
Goal: Isolate the variable
Subtract 6 from both sides
Think… What is the inverse operation of addition?
or
Think… What is the opposite of adding 6?
or
Think… What is a zero pair to +6?

13. Solving Equations Algebraically
• n – 12 = 10 Goal: Isolate the variable
Question: How can get the
variable by itself?
Think… What is the inverse operation to…?
or
Think… What is the opposite of… ?
or
Think… What is a zero pair of…?

14. Solving Equations Algebraically
• n – 12 = 10
• + 12 + 12
• n = 22
Goal: Isolate the variable
Add 12 to both sides
Think… What is the inverse operation to…?
or
Think… What is the opposite of… ?
or
Think… What is a zero pair of…?