P R E S S U R E
T E M P E R T U R E
A
V O L U M E
H E A T
Gas Laws:
Pressure, Volume,
and Temperature
Opening thoughts…
Have you
ever:
Seen a hot air balloon?
Had a soda bottle spray all over you?
Baked (or eaten) a nice, fluffy cake?
These are all examples of gases at work!
Properties of Gases
You can predict the behavior of
gases based on the following
properties:
Pressure
Volume
Amount (moles)
Temperature
Properties
and
Measuring
Variables
Gases
Characteristics of Gases
Kinetic Molecular Theory
 Gases are composed of a large number
of particles that behave like hard,
spherical objects in a state of constant,
random motion.
 These particles move in a straight line
until they collide with another particle or
the walls of the container
Kinetic Molecular Theory
 These particles are much smaller than
the distance between particles. Most of
the volume of the gas is therefore empty
space
 There is no force of attraction between
gas particles or between the particles
and the walls of the container
Kinetic Molecular Theory
 Collisions between gas particles or
collisions with the walls of the container
are perfectly elastic.
 The average kinetic energy of a
collection of gas particles depends on
the temperature of the gas and nothing
else.
STP
Standard Temperature & Pressure
0°C 273.15 K
1 atm 101.325 kPa
-OR-
STP
II. The Gas Laws
BOYLE’S
CHARLES
GAY-LUSSAC’S
The LAWS
A. Boyle’s Law- Robert Boyle
P
V
Volume
(mL)
Pressure
(torr)
P·V
(mL·torr)
10.0 760.0 7.60 x 103
20.0 379.6 7.59 x 103
30.0 253.2 7.60 x 103
40.0 191.0 7.64 x 103
A. Boyle’s Law
The pressure and volume
of a gas are inversely
related
• at constant mass & temp
P
V
P V = P V
1 1 2 2
A. Boyle’s Law Equation
A 2.0 L party balloon at 98kPa is
taken to the top of the mountain
where the pressure is 75 kPa.
Assume the temperature is the
same. What is the new volume of the
balloon?
A. Boyle’s Law Equation
Given:
P1= 98 kPa
V1= 2.0 L
P2= 75 kPa
V2=
P1V1=P2V2
____ ____
P2
P2
= 98 kPa. 2.0 L
___________
75 kPa
= 196 kPa.L
___________
75 kPa
= 2.61 L
2.61 L
2.0 L
98 kPa
75 kPa
V
T
B. Charles’ Law- Jacques Charles
Volume
(mL)
Temperature
(K)
V/T
(mL/K)
40.0 273.2 0.146
44.0 298.2 0.148
47.7 323.2 0.148
51.3 348.2 0.147
V
T
B. Charles’ Law
The volume and absolute
temperature (K) of a gas
are directly related
• at constant mass &
pressure
V V
T T
=
1
1
2
2
A. Charles Law Equation
A gas inside the cylinder with a
movable piston is to be heated to
315ºC. The volume of gas in the
cylinder is 0.30L at 25ºC. What is the
final volume?
1. Boyle’s Law Equation
A weather balloon containing 35.0L
of helium at 98kPa is released and
rises. Find out the volume of the
balloon when the atmospheric
pressure is 25.0kPa?
2. Charles Law Equation
An open 2.05L plastic pop container
is removed from a refrigerator at 5°C
and allowed to warm up to 21°C on a
kitchen counter. What volume of air
will leave the container as it warms?
I have learned that ……
Assignment
1. A 325 ml of Chlorine under a pressure of 680 mmHg
are placed into a container under the pressure of 1210
mmHg. What is the volume of the container?
Solve the following problems involving
Boyle’s and Charles Law
2. A balloon contains 7.2 L of He. The pressure is
reduced to 2 atm and the balloon expands to occupy a
volume of 25.1 L. What was the initial pressure exerted
on the balloon?
3. Calculate the decrease in temperature when 2.0 L at
20ºC is compressed to 1.0 L?
4. At 27ºC a gas has a volume of 6.0 L. What will the
volume be at 150ºC?
Reminder!
Bring the following materials
to be used for tomorrow’s
experiment:
Group 1 and Group 3
1. 25 ml syringe
2. Ruler
3. Glue stick
4. Two 1/8 Illustration board
5. Glue gun
6. Marker and White Cartolina
Reminder!
Bring the following materials
to be used for tomorrow’s
experiment:
Group 2 and Group 4
1. Rubber Balloon
2. Tap Water
3. Hot Water
4. Cold Water
5. Thermometer
6. Tape Measure
7. Marker and White Cartolina
Gas Laws:
Pressure, Volume,
and Temperature

Demo Teaching.ppt

  • 2.
    P R ES S U R E
  • 3.
    T E MP E R T U R E A
  • 4.
    V O LU M E
  • 5.
  • 6.
  • 7.
    Opening thoughts… Have you ever: Seena hot air balloon? Had a soda bottle spray all over you? Baked (or eaten) a nice, fluffy cake? These are all examples of gases at work!
  • 8.
    Properties of Gases Youcan predict the behavior of gases based on the following properties: Pressure Volume Amount (moles) Temperature
  • 9.
  • 10.
    Characteristics of Gases KineticMolecular Theory  Gases are composed of a large number of particles that behave like hard, spherical objects in a state of constant, random motion.  These particles move in a straight line until they collide with another particle or the walls of the container
  • 11.
    Kinetic Molecular Theory These particles are much smaller than the distance between particles. Most of the volume of the gas is therefore empty space  There is no force of attraction between gas particles or between the particles and the walls of the container
  • 12.
    Kinetic Molecular Theory Collisions between gas particles or collisions with the walls of the container are perfectly elastic.  The average kinetic energy of a collection of gas particles depends on the temperature of the gas and nothing else.
  • 13.
    STP Standard Temperature &Pressure 0°C 273.15 K 1 atm 101.325 kPa -OR- STP
  • 14.
    II. The GasLaws BOYLE’S CHARLES GAY-LUSSAC’S The LAWS
  • 15.
    A. Boyle’s Law-Robert Boyle P V Volume (mL) Pressure (torr) P·V (mL·torr) 10.0 760.0 7.60 x 103 20.0 379.6 7.59 x 103 30.0 253.2 7.60 x 103 40.0 191.0 7.64 x 103
  • 16.
    A. Boyle’s Law Thepressure and volume of a gas are inversely related • at constant mass & temp P V P V = P V 1 1 2 2
  • 17.
    A. Boyle’s LawEquation A 2.0 L party balloon at 98kPa is taken to the top of the mountain where the pressure is 75 kPa. Assume the temperature is the same. What is the new volume of the balloon?
  • 18.
    A. Boyle’s LawEquation Given: P1= 98 kPa V1= 2.0 L P2= 75 kPa V2= P1V1=P2V2 ____ ____ P2 P2 = 98 kPa. 2.0 L ___________ 75 kPa = 196 kPa.L ___________ 75 kPa = 2.61 L 2.61 L 2.0 L 98 kPa 75 kPa
  • 19.
    V T B. Charles’ Law-Jacques Charles Volume (mL) Temperature (K) V/T (mL/K) 40.0 273.2 0.146 44.0 298.2 0.148 47.7 323.2 0.148 51.3 348.2 0.147
  • 20.
    V T B. Charles’ Law Thevolume and absolute temperature (K) of a gas are directly related • at constant mass & pressure V V T T = 1 1 2 2
  • 21.
    A. Charles LawEquation A gas inside the cylinder with a movable piston is to be heated to 315ºC. The volume of gas in the cylinder is 0.30L at 25ºC. What is the final volume?
  • 22.
    1. Boyle’s LawEquation A weather balloon containing 35.0L of helium at 98kPa is released and rises. Find out the volume of the balloon when the atmospheric pressure is 25.0kPa?
  • 23.
    2. Charles LawEquation An open 2.05L plastic pop container is removed from a refrigerator at 5°C and allowed to warm up to 21°C on a kitchen counter. What volume of air will leave the container as it warms?
  • 24.
    I have learnedthat ……
  • 25.
    Assignment 1. A 325ml of Chlorine under a pressure of 680 mmHg are placed into a container under the pressure of 1210 mmHg. What is the volume of the container? Solve the following problems involving Boyle’s and Charles Law 2. A balloon contains 7.2 L of He. The pressure is reduced to 2 atm and the balloon expands to occupy a volume of 25.1 L. What was the initial pressure exerted on the balloon? 3. Calculate the decrease in temperature when 2.0 L at 20ºC is compressed to 1.0 L? 4. At 27ºC a gas has a volume of 6.0 L. What will the volume be at 150ºC?
  • 26.
    Reminder! Bring the followingmaterials to be used for tomorrow’s experiment: Group 1 and Group 3 1. 25 ml syringe 2. Ruler 3. Glue stick 4. Two 1/8 Illustration board 5. Glue gun 6. Marker and White Cartolina
  • 27.
    Reminder! Bring the followingmaterials to be used for tomorrow’s experiment: Group 2 and Group 4 1. Rubber Balloon 2. Tap Water 3. Hot Water 4. Cold Water 5. Thermometer 6. Tape Measure 7. Marker and White Cartolina
  • 28.

Editor's Notes

  • #13 A perfectly elastic collision is defined as one in which there is no loss of kinetic energy in the collision.
  • #14 refers to the nominal conditions in the atmosphere at sea level. Standard temperature and pressure are standard sets of conditions for experimental measurements to be established to allow comparisons to be made between different sets of data.
  • #18 196 kPa.L 2.61 L
  • #19 196 kPa.L 2.61 L